Web Start Examples Help

Hi, I am slowly learning Java and would like to play with some of the examples that are in the Java Web Start.
When I try and compile the code however I get a lot of error messages (Cannot resolve symbol). Am I missing some other file that I need to include with the examples in order to run it?
Thanks,
- Mark

Dude, Have you declared all the variables used in the program? Did you check for typo? And please read those error message carefully to get more clues.
Post your future Java programming related questions to 'New to Java Programming' forum. You will get more responses.

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Router password and web start up help

(WRT300N) when i start installing the router cd and i get to step 9 a window pops up asking for a password i put admin but nothing works
i also try to put 192.168.1.1. for my webstart config but it gives me DNS Server Error
Please Help,
GOD Bless, Thanx!

how do i change the password i put things in but it just pops up again
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Java Web Start application doesn't run in Tomcat

I successfully did a Java Web Start example for me to learn then I tried another one where I encountered an error:
This is what Tomcat 6.0.18 says. The deploy is successful but when I try to run the web start application
with this htmlcode
<A href="http://localhost:8080/ConvertorValutar/app/launch.jnlp">I get this error witch leads me to think that it can't find the jar correct ?
type Status report
message /convertorvalutar/
description The requested resource (/convertorvalutar/) is not available.Appendix:
This is how I am doing the JAR
jar cfvm convertorvalutar.jar myManifest2.mf Java*.class IRata*.class The myManifest2.mf is
Main-class: JavaWebStart_Convertor witch is the main class
This way I am doing the WAR:
del *.war /F /Q
jar cfv convertorvalutar.war app/* WEb-INF/*This is the correct directory structure
│   faWar.bat
│   convertorvalutar.war
│
├───app
│       ConvertorValutar.jar
│       launch.jnlp
│
└───WEB-INF
    │   web.xml
    │
    └───lib
            jnlp-servlet.jarThis is the web.xml
<?xml version="1.0" encoding="iso-8859-1"?>
<!DOCTYPE web-app
PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>

<web-app>
     <servlet>
          <servlet-name>JnlpDownloadServlet</servlet-name>
          <servlet-class>jnlp.sample.servlet.JnlpDownloadServlet</servlet-class>
     </servlet>
     <servlet-mapping>
          <servlet-name>JnlpDownloadServlet</servlet-name>
          <url-pattern>*.jnlp</url-pattern>
     </servlet-mapping>
</web-app>
</web-app>This is the jnlp:
<?xml version="1.0" encoding="UTF-8"?>
<jnlp codebase="http://localhost:8080/convertorvalutar/app">
<information>
     <title>Convertor Valutar</title>
     <vendor>remus.dragos</vendor>
     <description>Simple Java Web Start Example</description>
</information>
<resources>
     <j2se version="1.5+"/>
     <jar href="ConvertorValutar.jar"/>
</resources>
<application-desc main-class="JavaWebStart_Convertor"/>
</jnlp>Where is the problem?
Edited by: remus.dragos on Dec 9, 2008 7:14 PM

I did checked the names again and I found that the makeJar.bat had an "issue".
It missed the del *.jar and I had 2 uppercase letters like ConvertorValutar, instead of convertorvalutar.jar.
After that I rebuild the war and deployed and it works :)
Thanks.

Please help me. I am getting an error while launching an web start applic

I am getting the following error while launching an java web start apllication.
Exception in thread"javaWSApplicationMains"java.lan.NoClassDefFound:SimpleSerial.
The jnlp file i have used is as follows:
<?xml version="1.0" encoding="utf-8"?>

<jnlp spec="1.0+" codebase="http://zycomm:8080" href="Aeon.jnlp">
<information>
<title>Aeon HHBM Manager</title>
<vendor>ME</vendor>
<description>Aeon HHBM Manager</description>
</information>
<offline_allowed/>
<resources>
<j2se version="1.4+"/>
<jar href="aeon.jar"/>
</resources>
<application-desc main-class="Aeon_PManager" />
<component-desc/>
</jnlp>
The java code is as follows:
SimpleSerial.java
import java.io.*;
//import java.lang.*;
//import java.lang.ClassNotFoundException;
Interface class for SimpleSerial.
If you don't know what an interface is, don't worry. An interface defines the functions
that can be called by implementors of this class. Currently there are two implementors,
SimpleSerialNative, and SimpleSerialJava. There might be more in the future.
SimpleSerialNative requires the file "SimpleSerialNative.dll" to be in the same folder as your Java
project file. It's that simple.
SimpleSerialJava requires the correct installation of Sun's Javacomm communication package. It's much
more powerful, but it can be tricky for the newcomer to configure, and use.
If you have problems with one, why don't you try the other.
A VERY SIMPLE IMPLEMENTATION:
public static void main(String args[]) {
SimpleSerial ss; // delcare the SimpleSerial object
ss = new SimpleSerialNative(2); // The argument is the commport number. There is no Comm0.
ss.writeByte((byte)'a'); // write a byte to the serial port
// Give the PIC chip time to digest the byte to make sure it's ready for the next byte.
try { Thread.sleep(1); } catch (InterruptedException e) {}
ss.writeByte((byte)'!'); // write another byte to the serial port
String inputString = ss.readString(); // read any string from the serial port
System.out.println("I read the string: " + inputString);
A few important things to note:
1. When you write data to the serial port, it just writes the data, whether or not the PIC chip is
ready to receive data. There's no handshaking or signaling. If you send data and the PIC chip
isn't ready for it, it will be ignored. Some PIC chips have a hardware UART which will buffer a
few bytes of data for later retrieval. But this isn't a cure-all. If the buffer fills up, it
creates an error condition which prevents further data from being read. You need to include
custom PIC code to reset the error flag.
2 In contrast to the PIC chip, the computer has a rather large hardware buffer. If the PIC chip
sends serial data to your computer when you're not around to read it, it gets stored.
3. If you make a call to readByte(), and there's no data to be read, readByte() waits until there
is data. If you want to know how much data (if any) is available, make a call to available().
4. Conversely, if you make a call to readBytes() or readString() and there's no data to be read,
readBytes() returns a byte array of zero length, and readString() returns and empty string.
5. If you want to use Sun's JavaComm package instead of this code, subsitute your calls to
new SimpleSerialNative(2);
with
new SImpleSerialJava(2);
public interface SimpleSerial {
// These are copied right out of WINBASE.H
// Most applications should be fine with the defaults.
public static final int NOPARITY = 0;
public static final int ODDPARITY = 1;
public static final int EVENPARITY = 2;
public static final int MARKPARITY = 3;
public static final int SPACEPARITY = 4;
public static final int ONESTOPBIT = 0;
public static final int ONE5STOPBITS = 1;
public static final int TWOSTOPBITS = 2;
Returns the number of bytes available at the time of this call.
It's possible there are more bytes by the time readByte() or
readBytes() is executed. But there will never be fewer.
public int available();
public void waitForData(int n);
public boolean writeString(String string);
returns TRUE if port is fully operationsal
returns FALSE if there is a problem with the port
public boolean isValid();
Be sure to close your serial port when done. Note that port is
automatically closed on exit if you don't close it yourself
public void close();
Reads a single byte from the input stream.
Return value will be from -128 to 127 (inclusive)
If no data at serial port, waits in routine for data to arrive.
Use available() to check how much data is available.
If error, returns 256.
public int readByte();
Reads all the bytes in the serial port.
If no bytes availble, returns array with zero elements.
Never waits for data to arrive
public byte[] readBytes();
Reads bytes from serial port and converts to a text string.
DO NOT use this routine to read data. Char->Byte converstion
does strange things when the values are negative. For non-
text values, use readBytes() above
public String readString();
Writes a single byte to the serial port.
This writes the data, whether the PIC is ready to receive or not.
Be careful not to overwhelm the PIC chip with data.
On pics without a hardware UART, the data will be ignored.
On pics with a hardware UART, overflowing will loose data AND require
the UART on the PIC to be reset. You can reset the UART in PIC code,
or manually turn the PIC off and then on.
NOTE: A byte has a value in the range of -128 to 127
NOTE: If you want to write a character, you need to cast it to a byte,
for example: simpleSerial.writeByte((char)'b');
public boolean writeByte(byte val);
For more advanced use. Gets the input stream associated with serial port
public InputStream getInputStream();
For more advanced use. Gets the output stream associated with serial port
public OutputStream getOutputStream();
Please help I am the beginner in web start.Please

Notes:
1) Please use the code tags when posting code or JNLP/HTML. It helps to retain indentation and avoids asterisks and plus sings being interpreted as formatting marks. To do that, select the code/JNLP etc. and click the CODE button seen on the Plain Text tab of the message posting form.
2) That launch file is invalid. You might check it (and the project in general) using JaNeLA.
3) The only place that SimpleSerial class could be, that the JRE would find, is in the root of aeon.jar. Is it actually there?

Java Web Start- Cannot launch Application. Pls help

HI
Ia m beginner in java web start. I creaate a simple swing application and try to launch it through web start. But I failed. My application jar file (sample.jar)contains only class files. No menifest file. Then I sign my "sample.jar" file and placed inside tomcat server: "webapps/root/WebStart/Sample". I also placed the "sample.jnlp" file in the above directory.The name of my main class is :"Sample" .Here is the content of sample.jnlp:
<?xml version="1.0" encoding="UTF-8"?>
<jnlp spec="1.0+"
codebase="http://165.231199.164:8080"
>
<information>
<title>Sample Launching Test</title>
<vendor>FMO</vendor>
<homepage href="www.sun.com" />
<description>Demonstration of JNLP</description>
</information>
<offline-allowed/>
<security>
<all-permissions/>
</security>
<resources>
<j2se version="1.2+" />
<jar href="/WebStart/Sample/sample.jar"/>
</resources>
<application-desc main-class="Sample" />
</jnlp>Whenever I try to launch this application from the browser , it shows me following :
An error occurred while launching/running the application.
Title: Sample Launching Test
Vendor: FMO
Category: Unexpected Error
RED
Anybody pls help me here about how to Launch my application. Am I missing something?

I fixed the porblem by modifying the sample.jnlp file. Here is the latest version:
<?xml version="1.0" encoding="UTF-8"?>
<jnlp codebase=http://[my-ip-address]:8080/WebStart/Sample>
<href="sample.jnlp">
<information>
<title>Sample Launching Test</title>
<vendor>FMO</vendor>
<homepage href="www.sun.com" />
<description>Demonstration of JNLP</description>
<offline-allowed/>
</information>
<security>
<all-permissions/>
</security>
<resources>
<j2se version=1.4+ />
<jar href="sample.jar"/>
</resources>
<application-desc main-class="Sample" />
</jnlp>

How can I open help file (HTML or .chm) from Java Web Start (new to JAVA)

Hi All,
Im trying to open the help file of my application.
When trying to access the help file from the GUI (pressing F1 for launching the help file), I'm geting the an error, something like:
"Can't show help URL: jar:file:C:\Documents and Settings\%USER%\Application Data\Sun\Java\Deployment\javaws\cache\http\Dlocalhost\P7001\DMwebstart\RMjar-name!/com/resources/helpFiles/MyHelpFile.html"
It seems that the file which is packed in a jar, was downloaded to the Java Web Start cache directory:
C:\Documents and Settings\%USER%\Application Data\Sun\Java\Deployment\javaws\cache\http\Dlocalhost\P7001\DMwebstart
The code which is activated when launching the help file is:
try
            ResourceBundle resourceBundle = DoubleResourceBundle.getBundle("Resource", "ResourceImpl");
            RuntimeUtil.launchFile(new File(resourceBundle.getString("help.file")));
        } catch (IOException e)
            // TODO Auto-generated catch block
            e.printStackTrace();
        }where the property "help.file" is in some property file in the resource bundle named "Resource", and looks like this :
help.file="com/trax/docs/help/global/MyHelpFile.html"
The function "RuntimeUtil.launchFile" knows how to launch any file in its default application, and indeed it does launches the html, when giving it an absolute path to the file on my PC, as "C:\Helpfiles\MyHelpFile.html" as such:
RuntimeUtil.launchFile("C:\Helpfiles\MyHelpFile.html");My question is :
The application is going to be deployed on a Customer PC. How can I access the html file from the code, with a relative path and not its absolute path on the customer pc, which I can't know?
I found these restrictions regarding web start:
(copied from "http://rachel.sourceforge.net/"):
*Rule 1: Java Archives only. No loose files.* All your resources have to be packaged in Java Archives (jar) if you want to have
them delivered to the user's machine and kept up-to-date automatically by Java Web Start.
*Rule 2: No file paths.* You can't use absolute or relative file paths to locate your
jars holding your resources (e.g. <code>jar:file:///c:/java/jws/.cache/resources.jar</code>).
Absolute file paths won't work because you never know where Java Web Start
will put your jar on the user's machine. Relative file paths won't work because Java Web Start
mangles the names of your jars (e.g. <code>venus.jar</code> becomes <code>RMvenus.jar</code>)
and every JNLP client implementation has the right to mangle your names
in a different way and you, therefore, can't predict the name with
which your jar will be rechristend and end up on the user's machine in
the application cache.Seems complex or impossible, to perform a simple task like opening a file.
Please advise (I'm new to Java and Web Start).
BTW, I'm working with IntelliJ IDEA 5.0.
Thanks,
Zedik.
{font:Tahoma}{size:26pt}
{size}{font}

the follwing method i have used to open html file ...
so to access html file i am shipping resources folder with jar file ..
private void openHtmlPages(String pageName) {
     String cmd[] = new String[2];
     String browser = null;
     File file = null;
     if(System.getProperty("os.name").indexOf("Linux")>-1) {
          file = new File("/usr/bin/mozilla");
          if(!file.exists() ) {
          }else     {
               browser = "mozilla";
     }else {
          browser = "<path of iexplore>";
     cmd[0] = browser;
     File files = new File("");
     String metaData = "/resources/Help/Files/"+pageName+".html"; // folder inside jar file
     java.net.URL url = this.getClass().getResource(metaData);
     String fileName = url.getFile();
     fileName = fileName.replaceAll("file:/","");
     fileName = fileName.replaceAll("%2520"," ");
     fileName = fileName.replaceAll("%20"," ");
     fileName = fileName.replaceAll("jarfilename.jar!"," ").trim();
     cmd[1] = fileName;
     try{
          Process p = Runtime.getRuntime().exec(cmd);
     }catch(java.io.IOException io){
               //Ignore
can anyone give me the solution..???
Regards
Ganesan S

Help needed in web service example. Thank!!!

Hi,
I tested WebLogic 6.1 message-style web service example. For the
ProducerClient.java example, I tested successfully. But for
the ConsumerClient.java example, I kept getting error messages.
Can any expert offers some explanation or advice? Need to
show my boss the cool thing. Any help is highly appreciated.
Thanks.
David
The server-side message is:
Servlet failed with Exception
java.lang.NullPointerException
at weblogic.soap.server.servlet.QueueReceiveAdapter.doPost(QueueReceiveA
dapter.java:124)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:760)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at weblogic.servlet.internal.ServletStubImpl.invokeServlet(ServletStubIm
pl.java:263)
at weblogic.servlet.internal.ServletStubImpl.invokeServlet(ServletStubIm
pl.java:200)
at weblogic.servlet.internal.WebAppServletContext.invokeServlet(WebAppSe
rvletContext.java:2390)
at weblogic.servlet.internal.ServletRequestImpl.execute(ServletRequestIm
pl.java:1959)
at weblogic.kernel.ExecuteThread.execute(ExecuteThread.java:137)
at weblogic.kernel.ExecuteThread.run(ExecuteThread.java:120)
>
The client-side message:
Server returned HTTP response code: 500 for URL: http://localhost:70
01/msg/receiveMsg
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLCon
nection.java:674)
at sun.net.www.protocol.http.HttpURLConnection.getHeaderFieldKey(HttpURL
Connection.java:1163)
at weblogic.soap.WebServiceProxy.getSessionCookie(WebServiceProxy.java:5
09)
at weblogic.soap.WebServiceProxy.receive(WebServiceProxy.java:477)
at weblogic.soap.WebServiceProxy.invoke(WebServiceProxy.java:431)
at weblogic.soap.SoapMethod.invoke(SoapMethod.java:186)
at ConsumerClient.main(ConsumerClient.java:52)

Hi,
I tested WebLogic 6.1 message-style web service example. For the
ProducerClient.java example, I tested successfully. But for
the ConsumerClient.java example, I kept getting error messages.
Can any expert offers some explanation or advice? Need to
show my boss the cool thing. Any help is highly appreciated.
Thanks.
David
The server-side message is:
Servlet failed with Exception
java.lang.NullPointerException
at weblogic.soap.server.servlet.QueueReceiveAdapter.doPost(QueueReceiveA
dapter.java:124)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:760)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
at weblogic.servlet.internal.ServletStubImpl.invokeServlet(ServletStubIm
pl.java:263)
at weblogic.servlet.internal.ServletStubImpl.invokeServlet(ServletStubIm
pl.java:200)
at weblogic.servlet.internal.WebAppServletContext.invokeServlet(WebAppSe
rvletContext.java:2390)
at weblogic.servlet.internal.ServletRequestImpl.execute(ServletRequestIm
pl.java:1959)
at weblogic.kernel.ExecuteThread.execute(ExecuteThread.java:137)
at weblogic.kernel.ExecuteThread.run(ExecuteThread.java:120)
>
The client-side message:
Server returned HTTP response code: 500 for URL: http://localhost:70
01/msg/receiveMsg
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLCon
nection.java:674)
at sun.net.www.protocol.http.HttpURLConnection.getHeaderFieldKey(HttpURL
Connection.java:1163)
at weblogic.soap.WebServiceProxy.getSessionCookie(WebServiceProxy.java:5
09)
at weblogic.soap.WebServiceProxy.receive(WebServiceProxy.java:477)
at weblogic.soap.WebServiceProxy.invoke(WebServiceProxy.java:431)
at weblogic.soap.SoapMethod.invoke(SoapMethod.java:186)
at ConsumerClient.main(ConsumerClient.java:52)

First Timer Need Help using Java Web Start

                    The following Error Message was thrown when I tried to launch an app
          using Java Web Start...
An error occurred while launching/running the application.
Title: Swing Application - Hello World
Vendor: Ramanujam
Category: Download Error
Bad MIME type returned from server when accessing resource: http:\\localhost:8000\test/SimpleExample.jnlp - text/html
          My JNLP file
<?xml version="1.0" encoding="utf-8"?>

<jnlp codebase="http:\\localhost:8000\test" href="SimpleExample.jnlp">
     <information>
          <title>Swing Application - Hello World</title>
          <vendor>Ramanujam</vendor>
          <description>Test JWS</description>
          <description kind="short">Test JWS</description>
          <offline-allowed/>
     </information>
     <resources>
          <j2se version="1.4"/>
          <jar href="test.jar"/>
     </resources>
     <application-desc main-class="JWSTest"/>
</jnlp>
               The exception thrown :
NLPException[category: Download Error : Exception: null : LaunchDesc: null ]
     at com.sun.javaws.cache.DownloadProtocol.doDownload(Unknown Source)
     at com.sun.javaws.cache.DownloadProtocol.isLaunchFileUpdateAvailable(Unknown Source)
     at com.sun.javaws.LaunchDownload.getUpdatedLaunchDesc(Unknown Source)
     at com.sun.javaws.Launcher.downloadResources(Unknown Source)
     at com.sun.javaws.Launcher.handleApplicationDesc(Unknown Source)
     at com.sun.javaws.Launcher.handleLaunchFile(Unknown Source)
     at com.sun.javaws.Launcher.run(Unknown Source)
     at java.lang.Thread.run(Thread.java:536)
Also, How to configure MIME mapping for .jnlp files on J2EE server (I do not have another server) and if there is a need, how do i deploy the jar and the jnlp file on J2EE server?
Kindly help.....

Hi,
I have the same problem, but I do have configured the webserver (Apache 2) correctly and the server is NOT returning a 404 error.
To check this I used the a tcp monitor (Apache Axis).
The error message in Java Webstart is identical to the one discribed above.
In the tcp monitor I see the following :
HTTP/1.1 200 OK
Date: Tue, 19 Nov 2002 15:16:57 GMT
Server: Apache/2.0.43 (Win32)
Last-Modified: Tue, 19 Nov 2002 15:13:58 GMT
ETag: "44eb-300-bebdba39"
Accept-Ranges: bytes
Content-Length: 768
Keep-Alive: timeout=15, max=97
Connection: Keep-Alive
Content-Type: application/x-java-jnlp-file
<?xml version="1.0" encoding="utf-8"?>
<jnlp spec="1.0+" codebase="http://ns003:88/ns" href="jviews.jnlp">
<information>
<title>JViews TWD Demo Applicatie</title>
<vendor>Cap Gemini Ernst & Young</vendor>
<homepage href="default.html"/>
</information>
<resources>
<j2se version="1.3"/>
<jar href="jviewsapplet.jar"/>
</resources>
<application-desc main-class="JViewsClient"/>
</jnlp>
Any idea?
Cheers, Joost

Help with Java Web Start

Hi everybody,
I have a simple Java application that has a JFrame containing a TextField displaying some text inside it. I am using the NetBeans IDE. I am trying to Enable Java Web start for this application. The steps I have taken upto now are:
1. Right click on Project, Java Web Start -> Enable Java Web Start. This created the jnlp file.
2. In the Resources section, I added the jar file for swing. ( I am not sure if I have to add the path for jnlp.jar etc, or are these found automatically?)
3. Right click on Project, Java Web Start -> Deploy with Java Web Start. This launches the browser with the Click me link, but on clicking this link, I get the following error.
description The server encountered an internal error () that prevented it from fulfilling this request.
exception
javax.servlet.ServletException: Wrapper cannot find servlet class jnlp.sample.servlet.JnlpDownloadServlet or a class it depends on
     org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)
     org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)
     org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:856)
     org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.processConnection(Http11Protocol.java:744)
     org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:527)
     org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)
     org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)
     java.lang.Thread.run(Thread.java:534)
root cause
java.lang.ClassNotFoundException: jnlp.sample.servlet.JnlpDownloadServlet
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1332)
     org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1181)
     org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:105)
     org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:148)
     org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:856)
     org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.processConnection(Http11Protocol.java:744)
     org.apache.tomcat.util.net.PoolTcpEndpoint.processSocket(PoolTcpEndpoint.java:527)
     org.apache.tomcat.util.net.LeaderFollowerWorkerThread.runIt(LeaderFollowerWorkerThread.java:80)
     org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:684)
     java.lang.Thread.run(Thread.java:534)I have all the jnlp files in my jdk directory, and I am not sure why it can't find it. Is there something I am missing?
Thanks
George

I am not sure what it has to do with servlets, I just followed a tutorial on using Netbeans with Java Web Start, and did only the steps as mentioned in my first post. And ended up with the error.
Anyways, I added the jnlp jar files(jnlp.jar, jnlp-servlet.jar, jardiff.jar) in the WEB-INF/lib directory. And it seems to deploying it now. I can get my application to load on clicking on the "Click me" link. But the controls on my application don't seem to be working.
Also, when I try to Right click on my project -> Java Web Start -> Run with Java Web Start, I get the following error message,
javaws-run: C:\Documents and Settings\Lux\Visualization\nbproject\build-jaws-impl.xml:36: Execute failed: java.io.IOException: CreateProcess: C:\j2sdk1.4.2_13\bin\javaws "file:///C:/Documents and Settings/Lux/Visualization/Visualization.jnlp" error=2
BUILD FAILED (total time: 0 seconds)
Any help appreciated.
Thanks.
George

If I set Firefox as my default web browser, the help links on Adobe Dreamweaver and Flash's welcome screens don't connect to the help pages on Adobe's site. It just links to Firefox's start page and stops. The links work properly if Safari is set to the d

If I set Firefox as my default web browser, the help links on Adobe Dreamweaver and Flash's welcome screens don't connect to the help pages on Adobe's site. It just links to Firefox's start page and stops. The links work properly if Safari is set to the default browser. Please help.
== URL of affected sites ==
http://www.adobe.com

Hello,
Many site issues can be caused by corrupt cookies or cache. In order to try to fix these problems, the first step is to clear both cookies and the cache.
Note: ''This will temporarily log you out of all sites you're logged in to.''
To clear cache and cookies do the following:
#Go to Firefox > History > Clear recent history or (if no Firefox button is shown) go to Tools > Clear recent history.
#Under "Time range to clear", select "Everything".
#Now, click the arrow next to Details to toggle the Details list active.
#From the details list, check ''Cache'' and ''Cookies'' and uncheck everything else.
#Now click the ''Clear now'' button.
Further information can be found in the [[Clear your cache, history and other personal information in Firefox]] article.
Did this fix your problems? Please report back to us!
Thank you.

Hi... How to start the application for Web Services Example...

Hi all,
I want to develop one application for a example of Web services. From J2ME i have to request and get aresponse from other platform like VB.net using Web Service APIs. Any one help me to give one example for this topic.
Thanks in advance,
Regards
Dhana

Hi,
I read the demo program. Sorry i am unable understand the concept what is going on in the program. I saw other examples with XML codings with parsing but in this no XML codings are there. I am unable to understand the concept what is going on in J2ME with web services. Give me a simple example if u did any application related to this topic. I have to receive today from the website(web server). Help me...
Regards,
Dhana

Very urgent !! pls help!! web start for applet vs Japplet..

this does not work with web start. but if i chnge it to Applet , it works fine..
Why?
public class NewJApplet extends javax.swing.JApplet {
   public void paint (java.awt.Graphics g)
     g.drawString ("Hello world!", 45, 30);
     System.out.println ("singhhhHello world!");
}

actually it does... there is option you may give in the jnlp that it's not application rather it's an applet. Though it's not highly recommended.
BTW. i am having another problem .. if anyone know about it...
In NetBeans IDE 5.5, i have enabled "java Web Start"
but when ever i tried to run via web start it asks me "please select a main Class" alert.
what is it.
thnx

Help configuring Web Start / Java Preferences to include JRE 1.3.1

(Mac OS X 10.4.9, Java Preferences ver 11.5.0)
I have Java 1.5.0, 1.4.2, and 1.3.1 installed on new Intel Mac Pro. When I try to access a "legacy" intranet application (AppWorx) that requires JRE 1.3.1, I get an error message:
An error occurred while launching/running the application.
Title: AISX AppWorx Client
Vendor: AppWorx Corporation
Category: System Configuration
The application has requested a version of the JRE (version 1.3.1 1.3.0) that currently is not locally installed. Java Web Start is unable to automatically download and install the requested version. This JRE must be installed manually.
These are the installed Java versions:
l /System/Library/Frameworks/JavaVM.framework/Versions
total 40
lrwxr-xr-x 1 root wheel 5 Feb 26 17:04 1.3@ -> 1.3.1
drwxr-xr-x 8 root wheel 272 Feb 20 07:25 1.3.1/
lrwxr-xr-x 1 root wheel 5 Feb 26 17:04 1.4@ -> 1.4.2
drwxr-xr-x 8 root wheel 272 Feb 20 07:24 1.4.2/
lrwxr-xr-x 1 root wheel 5 Feb 26 17:04 1.5@ -> 1.5.0
drwxr-xr-x 8 root wheel 272 Feb 20 07:25 1.5.0/
drwxr-xr-x 5 root wheel 170 Mar 19 09:20 A/
lrwxr-xr-x 1 root wheel 1 Feb 26 17:04 Current@ -> A
lrwxr-xr-x 1 root wheel 3 Feb 26 17:04 CurrentJDK@ -> 1.5
The .jnlp file specifies JRE 1.3.0 or 1.3.1:
<resources>
<j2se version="1.3.1 1.3.0"/>
<jar href="UserWorx.jar"/>
<jar href="AppWorxLang.jar"/>
<extension name="AppWorxClientExtensions" href="../AppWorxClientExtensions.jnlp">
</extension>
<extension name="AppWorxClientSSLExtensions" href="../AppWorxClientSSLExtensions.jnlp">
</extension>
<extension name="AppWorxClientJHExtensions" href="../AppWorxClientJHExtensions.jnlp">
</extension>
</resources>
<security> <all-permissions/> </security>
When I launch J2SE 5.0 "Java Preferences.app", it only says 1.5.0 and 1.4.2 are installed.
How do I configure the 1.5 Java Web Start to recognize 1.3.1 ??

thanks Andrew. The Apple version of Java Control Panel for 1.5 doesn't have an equivalent to "JNLP Preferences" tab ... that's exactly what I'm looking for ...
Well - I think I found the answer to my problem:
http://developer.apple.com/java/faq/development.html#anchor1 says "Please note that Java 1.3 is not supported on Intel-based Macs; J2SE 1.4 and 5.0 (1.5) are supported. "
oh well ...

Please Help ! Problems with Web Start and HTTPS

Hi everyone,
my Web Start application crashes with a SSLPeerUnverifiedException when I
try to connect to the server with HTTPClient :
// proxy settings
HTTPConnection.setProxyServer(ipProxy, portProxy);
// connection
HTTPConnection con = new HTTPConnection("https", serverName, -1);
// Post (then there is a SSLPeerUnverifiedException....)
HTTPResponse rsp = con.Post("/myurl.jsp, toSend, ct_hdr);
My application runs in a secure environnement configured by the javaws.policy :
grant codeBase "file:${jnlpx.home}/javaws.jar" {
permission java.security.AllPermission;
and the ${user.home}.java.policy (shared by another application, an applet I think) :
keystore "file:${user.home}/xxxxxxxxxxxxxxxxxxxxx.p7c";
grant codebase "https://xxxxxxxxxxxxxxx/-" signedby "xxxxxxxxxx" {
permission java.lang.RuntimePermission "usePolicy";
permission java.lang.RuntimePermission "accessDeclaredMembers";
permission java.lang.RuntimePermission "setIO";
permission java.lang.RuntimePermission "modifyThread";
permission java.lang.RuntimePermission "stopThread";
permission java.lang.RuntimePermission "accessClassInPackage.sun.security.provider";
permission java.lang.RuntimePermission "loadLibrary.*";
permission java.security.SecurityPermission "insertProvider.SUN";
permission java.security.SecurityPermission "insertProvider.JCRYPTO";
permission java.security.SecurityPermission "insertProvider.JCRYPTO_PKCS11";
permission java.security.SecurityPermission "putProviderProperty.JCRYPTO";
permission java.security.SecurityPermission "putProviderProperty.JCRYPTO_PKCS11";
permission java.security.SecurityPermission "removeProviderProperty.JCRYPTO";
permission java.security.SecurityPermission "removeProvider.JCRYPTO";
permission java.security.SecurityPermission "removeProvider.JCRYPTO_PKCS11";
permission java.security.SecurityPermission "removeProvider.SUN";
permission java.util.PropertyPermission "*", "read,write";
permission java.io.FilePermission "<<ALL FILES>>", "write,read,delete";
permission java.net.NetPermission "specifyStreamHandler";
permission java.net.SocketPermission "localhost:1024-", "listen";
permission java.net.SocketPermission "*", "connect,accept,listen,resolve";
permission java.awt.AWTPermission "accessClipboard";
permission java.lang.RuntimePermission "queuePrintJob";
permission java.lang.reflect.ReflectPermission "suppressAccessChecks";
permission java.awt.AWTPermission "showWindowWithoutWarningBanner";
grant codebase "file:/myApplication/-" {
permission java.security.AllPermission;
In this file (.java.policy) when I replace "codebase "https://xxxxxxxxxxxxxxx/-""
by "codebase "http://xxxxxxxxxxxxxxx/-"" everything works fine !! It's very very
very very strange...
my application is launched by Web Start 1.2 and use JRE 1.4.1
Any ideas ? Please, I become crazy...

try using URLConnection instead of HTTPConnection.

Java Web Start help needed about writing files?

Hi there! I have this java web start app. i have implemented the File Open service succesfully using the JNLP API but i cant seem to get the File Save Service to work. Basically I have an object in the system which I want it to be serialised to a file on the user's desktop.
       FileSaveService fss;
         try {
             fss = (FileSaveService)ServiceManager.lookup
                                   ("javax.jnlp.FileSaveService");
         } catch (UnavailableServiceException e) {
            fss = null;
        if (fss != null) {
            try {
            FileContents fc = null;
            FileContents newfc = fss.saveFileDialog(null, null,
            fc.getInputStream(), "newFileName.txt");
            FileIO io = new FileIO();
            io.write("new123.nod", r.getTree()); /// my object is r.getTree() !!!
            } catch (Exception e) {
                  e.printStackTrace();
        }My Object (r.getTree) is basically an array. But I cant save it because the saveFileDialog method accepts ObjectInputStream as a parameter?! Any ideas? Thanks!
Edited by: player123 on Jun 11, 2009 8:56 AM

does anyone know? It actually doesnt even open the Save dialog?? why is that?

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