What is wrong with my tiny jdbc program? Help!!!

Question

Hi,
Would anyone diagnose the problem of my simple jdbc program?
The situation is :
a) local machine oracle thin driver connection; "lsnrctl" is running.
b) I can query the statement "select id from gameUser" from SQLPLUS logged in as "scott", with desirable result.
c) There are two code lines commented out in the code, if I uncomment them and instead comment out their counterparts and run the program, the "rset" would contain the result I want. But if I run the program unchanged, the output is only "hi".
d) If I change the query statement to a wrong column name or a wrong table name, there would be a sql exception. So I surmise that the connection with the database is successful. But how come there is no query result???
The follow is my coding.
import java.sql.*;
class dbAccess {
public static void main (String args []) throws SQLException
DriverManager.registerDriver (new oracle.jdbc.driver.OracleDriver());
try{
Connection conn = DriverManager.getConnection
("jdbc:oracle:thin:orcl", "scott", "tiger");
// ("jdbc:oracle:thin:orcl", "system", "manager");
Statement stmt = conn.createStatement();
ResultSet rset = stmt.executeQuery("select ID from scott.gameUser");
// ResultSet rset = stmt.executeQuery("select BANNER from SYS.V_$VERSION");
while (rset.next())
System.out.println (rset.getString(1)); stmt.close();
System.out.println("hi");
}catch (Exception e)
System.out.println(e.toString());
Thanks for help!

Answer 1

"local machine oracle thin driver connection;" means that my jdbc application uses Oracle thin driver to connect to a Oracle database. The database and the application are both on the same local machine.
"lsnrctl" is the command line program running to accept incomming request to connect to the database, it listens on the default 1521 port.
I inserted two rows into the table and I could query these two rows in SQLPLUS.
And I tried "select ID from gameUser", "select id from scott.gameUser" and various combination, it just won't retrieve the rows I inserted in the table.