What's the best way to know whether an application is running for the first time? (C#)

I seen suggestions like making a registry entry, or making an entry in the application specific settings file. But what's the best practice? I want to do some custom tasks if that is a first run.
Also, I am deploying my application using per machine MSI installer. So un-installation not deleting the user specific config files that's get created under AppData.
Thanks Prasad

Hello,
Whenever possible I prefer to avoid the registry. The following works once per user where we see if a specific folder exists or not, if it does not then do first time initialization work then set a setting in the project which causes a user config file to
be written to the location for storing user settings per user.
You first need to create a setting in the project, in this case I did
var config = ConfigurationManager.OpenExeConfiguration(ConfigurationUserLevel.PerUserRoamingAndLocal);
string configPath = config.FilePath.Replace("\\user.config", "");
if (System.IO.Directory.Exists(configPath) )
Console.WriteLine("This is not the first time");
else
// Do one time setup here
Properties.Settings.Default.FirstTimeValue = "1";
Properties.Settings.Default.Save();
Console.WriteLine("This was the first time");
Please remember to mark the replies as answers if they help and unmark them if they provide no help, this will help others who are looking for solutions to the same or similar problem.

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The best way to know if you a data in a table

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Message was edited by:
david_tyler

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I'm in the process of setting up a smaller (and cheaper) but somewhat similar setup to what you want to do, so maybe one example might help point you in the right direction. My needs consist of a centralized location for data storage, which will include iPhoto libraries (I keep two separate ones), iTunes (which I also want served to the home theater system), something other than my laptop to play internet videos and downloaded content on my TV, all with ideally the lowest cost and energy use possible.
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