Whats wrong with this logic - Why the error, out of bounds

Hi there,
I have this code that I am trying to work out with some logic I have put together, as shown below, but I get an error message saying "Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -29
":" What I am basically trying to do is print out a string which has both numbers and words into a vertical dialog window with the appropriate words next to their corresponding numbers.
{code}
A = "91011Word121314Sentence151617";
int start = 9;
int end = 17;
// Considering that we are on the first iteration
for(int i = start; i <= end; i++)
String a2 = "" + i; // convert the integer 9 into a string
int a1 = A.indexOf(a2); // get the index of 9 in the string A
int a3 = a2.length(); // get the length of 9
int a4 = a1 + a3; // the index of 9 plus its length is "equivalent" to the index of the next number in A -- 1
String a5 = "" + (i+1); // convert the next integer 10 into a string
int a6 = A.indexOf(a5); // get the index of 10 in the string A -- 1
add += a2 + " " + A.substring(a4,a6) + "\n";
/** Following the logic I would expect that at the end of the first iteration the String "add" should contain,
just 9 followed by a space, and the A.substring(1,1) would return nothing since there is no word in the
middle then there will be a new line */
{code}
However, I ended up getting a string index out of bounds exception. I would appreciate it if someone could explain to me why that would be so.
Thanks

define wrote:
for(int i = start; i <= end; i++)
That should probably be "i < end". This program seems very fragile btw. No checking if indexOf() return numbers less than zero, and ambiguous data..
To improve your code, you should use better variable names. Also, it's better to use String.valueOf(i) instead of "" + i
Edited by: paul.miner on Dec 7, 2007 8:53 PM - Typos

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        UTL_FILE.FCLOSE(v_file);
    END;
    Procedure created.
    SQL> exec baninst1.PAY_CSV(2009,1);
    BEGIN baninst1.PAY_CSV(2009,1); END;
    ERROR at line 1:
    ORA-20003: File could not be opened or operated on as requested.
    ORA-06512: at "BANINST1.PAY_CSV", line 45
    ORA-06512: at line 1Edited by: user5737516 on Nov 18, 2009 9:16 AM
    Edited by: user5737516 on Nov 18, 2009 9:18 AM
    Edited by: user5737516 on Nov 18, 2009 9:20 AM
    Edited by: user5737516 on Nov 18, 2009 9:35 AM

  • Fed up! dont know whats wrong with this code

    import java.io.*;
    import java.net.*;
    import java.awt.*;
    public class machine {
         private String machine_name;
         private String IP_address;
         public static void main(String[] args) throws IOException {
                   machine server = new machine();
                   server.machine_name = "SERVER1";
                   server.IP_address   = "192.168.0.1";
                   InputStreamReader reads_incoming = null;
                   // Reads incoming Bytes
                   PrintWriter sends_outgoing = null;
                   Socket ping_socket         = null;
                   try{
                        ping_socket = new Socket(server.machine_name , 7);
                        sends_outgoing = new PrintWriter(ping_socket.getOutputStream(),true);
                        reads_incoming = new InputStreamReader(ping_socket.getInputStream());
                   catch (UnknownHostException e){
                        //report error to sole text box
                   catch (IOException e)
                        //similar
                   /* Need a string to send some arbitrary bytes to SERVER1
                    * using IP_address instead , as this field in this implementation
                   while(true)
                        sends_outgoing.println(server.IP_address);
                        if(ping_socket.getInputStream() != null)
                             System.out.print("Server is up");
    }

    same... i am not very experienced, and try and uses this as training... but as new to java programming i could still mention about 5 things that might be wrong with this code... so a deeper explanation would be nice...
    while(true) { } for example seems like a nice way to make infinite loop that can suck your memory out of your computer pretty fast :-) newb

  • Whats wrong with this javascript

    <html>
    <head>
    <script type="text/javascript">
    function gup( name )
      var regexS = "[\\?&]"+name+"=([^&#]*)";
      var regex = new RegExp( regexS );
      var tmpURL = window.location.href;
      var results = regex.exec( tmpURL );
    alert("Hello");
    alert('hello');
      if( results == null )
        return "";
      else
        return results[1];
    </script>
    </head>
    <body>
    windows.alert("Hello");
    gup('_id7');
    <iframe
    var frank_param = javascript:gup('_id7');
    window.alert(tmpURL );
    alert("Hello");
    alert(frank_param);
      src="http://129.312.120.36:8992/GemLogin-ViewController-context-root/faces/login.jsp?_id7="+'javascript:parent.gup('_id7')'+"&_id8="+'javascript:gup('_id8')'"
       width="980"
      height="500"
      scrolling = "no"
      frameborder="0">
    </iframe>
    </body>
    </html>None of the alert get executed. and more over I am not able to build the src= .... Url successfully. Whats wrong with syntax ??
    thanks,
    pp

    <html>
    <head>
    <script type="text/javascript">
    function gup( name )
      var regexS = "[\\?&]"+name+"=([^&#]*)";
      var regex = new RegExp( regexS );
      var tmpURL = window.location.href;
      var results = regex.exec( tmpURL );
    alert("Hello");
    alert('hello');
      if( results == null )
        return "";
      else
        return results[1];
    </script>
    </head>
    <body>
    windows.alert("Hello");
    gup('_id7');
    <iframe
    var frank_param = javascript:gup('_id7');
    window.alert(tmpURL );
    alert("Hello");
    alert(frank_param);
      src="http://129.312.120.36:8992/GemLogin-ViewController-context-root/faces/login.jsp?_id7="+'javascript:parent.gup('_id7')'+"&_id8="+'javascript:gup('_id8')'"
       width="980"
      height="500"
      scrolling = "no"
      frameborder="0">
    </iframe>
    </body>
    </html>None of the alert get executed. and more over I am not able to build the src= .... Url successfully. Whats wrong with syntax ??
    thanks,
    pp

  • What is wrong with this website? The client is being VERY vague

    I'm kind of annoyed because whenever I call him, he just says something is wrong with it but won't say EXACTLY what. This is my first project, so it isn't going to be great, which is probably why the first guy is a minecraft server host. You gotta start somewhere though, and at least I get paid. There is something that is a bit off, but I don't know what it is, and neither does the guy... Have any feedback? The blank spot in the middle for the home page is an embedded YouTube video of their server and the blank tiles below show live server status for each server, but they didn't show up in the picture.

    You mentioned server status being on the website which probably means you need to send some sort of message of reliability, I'm not really seeing that here.
    The whole site doesn't look very modern - and maybe that's the point, with it being for MineCraft - but if so the MineCraft card has been over played here.
    I'd lose a lot of the gunge, the shadows and lighting effects/filters & use more solid, less in your face colours - the yellow and green you have chosen really don't go.
    Generally use the MineCraft visual language much more sparsely. To finish on a positive I like the layout, keep that.
    Like you said, it's a first go - in that case it's class. My first was certainly a lot worse than this, mostly everything just needs dialing down. Stay away from filters and effects and just concentrate on the layout, the typography, using the right colour, etc. at first.
    Hope this helps,
    Charles

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