When one of contolfile is corrupt then how to recover the controlfile?
when one of contolfile is corrupt then how to recover the controlfile?
Let us say we have 3 control files and they are named as "cont01.ctl,cont02.ctl & cont02.ctl" and they are stored in three different mount points (/u01,/u02 & /u03)
first controlfile -> /u01/oradata/prod/cont01.ctl
second controlfile -> /u02/oradata/prod/cont02.ctl
third controlfile -> /u03/oradata/prod/cont03.ctl
1. According to the ALERT log file or any other source let us say the third controlfile got corrupted...
Now , what you can do is you have to shutdown the database and remove cont03.ctl and copy it form cont01.ctl or cont02.ctl :
$ cd /u03/oradata/prod
$ rm -rf cont03.ctl
$ cd /u01/oradata/prod
$ cp -r cont01.ctl /u03/oradata/prod/cont03.ctl
Now, you can go ahead and start the database. The database will start without any issue and it wil be ready for any operations on it..
2. Suppose all the files of the database got corrupted ... First of all you need to have backup of the database... the steps that are needed of this scenario are :
--> shutdown the database with abort option
--> Assuming its RMAN backup .. you have to first start the database in nomount state and you have to restore the contolfile from the last backup been taken and start the database in mount state and then perform the database recovery and open the database with resetlogs option(since you dont have current controlfile becoz you have restored it from a backup) :
Assuming its catalog:
$ rman target / catalog usr/pawd@tns
RMAN> STARTUP NOMOUNT;
RMAN> restore controfile (from autobackup) ; -- in case you have auto backup then use the autobackup option
RMAN> alter database mount ;
RMAN> recover database;
RMAN> alter database open resetlogs ;
After the database gets opened , immediately you have to take the backup..
Hope its clear...Cheers!
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