Which one is efficient???

I have a text file with huge data. I need to generate Oracle report from this file.
I have two options...
1. Creating External table and query the data from external table
2. Directly accessing data from text file.
Which one is efficient?
Thank you,
Prasad

hello,
i guess that depends on
a) how often your data changes
b) how often your report is run
c) how often the format of the data changes
d) is creating the report the only use for that file
if you have one single file that does not change and you want to use the data from other applications, i would load it intot he database. also if you generate a lot of reports off that data, going the database route would possibly be the best one.
on the other hand if creating a report off this data is more of an one-off thing and you might create a new version once in a while but don't need the data for anything else, you might want to access the data directly.
overall it's a performance vs. work issue. you will have to invest a bit of work to load the data into the database, but will have a much better performance if you use the data heavily, but if you only use it once in a while you might not want to invest in creating loader scripts or setting up a warehousebuilder mapping.
regards,
philipp

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Which one better to use - jsp:useBean or import statement

Hi,
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I'm debating between a Macbook Air or a Macbook Pro which one would you suggest?

I'm debating between a Macbook Air (MC965LL/A) or a Macbook Pro (MD313LL/A) which one would you suggest?
I will be using this for college and taking it to class with me. My biggest fear is that I may be too hard on the Air and damage it, but I like that it is lighter and looks cooler. But which one do you believe is more logical and provides the best computer quality overall?

This is an objective comparison,
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Pro 13 "(16:10 format) 1280 x 800 = 1,024,000 pixels
Air 13 "(16:10 format) 1440 x 900 = 1,296,000 pixels
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And so the challenge back in a tie: Pro 1 - Air 1
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I guess that's the case to score another point: Pro 4 - 5 Air
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i hope it can help you ti choose
Francesco

Which one is fast?

public class Point2D {
    private int x, y;
    public Point2D() { x = 0; y = 0; }
    //public Point2D() { this(0,0); }
    public Point2D(int x, int y) {this.x = x; this.y = y;}
    public int getX() {return x;}
    public int getY() {return y;}
    public void setX(int x) {this.x = x;}
    public void setY(int y) {this.y = y;}
}the constructors below both work:
public Point2D() { x = 0; y = 0; }
//public Point2D() { this(0,0); }
which one should be more efficient?
thanks

A good compiler would generate the same code for both
forms of no argument constructor.
public class b {
int x,y;
public b(int x,int y) { this.x=x; this.y=y;}
public b(int x) { this(x,0); }
public b() { x=0; y=0;} //
public static void main(String args[] ) {
     b w0,w1;
}With SUN JDK 1.4.2_03:
javap -private -c b
Compiled from "b.java"
public class b extends java.lang.Object{
int x;
int y;
public b(int,int);
Code:
   0:     aload_0
   1:     invokespecial     #1; //Method java/lang/Object."<init>":()V
   4:     aload_0
   5:     iload_1
   6:     putfield     #2; //Field x:I
   9:     aload_0
   10:     iload_2
   11:     putfield     #3; //Field y:I
   14:     return
public b(int);
Code:
   0:     aload_0
   1:     iload_1
   2:     iconst_0
   3:     invokespecial     #4; //Method "<init>":(II)V
   6:     return
public b();
Code:
   0:     aload_0
   1:     invokespecial     #1; //Method java/lang/Object."<init>":()V
   4:     aload_0
   5:     iconst_0
   6:     putfield     #2; //Field x:I
   9:     aload_0
   10:     iconst_0
   11:     putfield     #3; //Field y:I
   14:     return
public static void main(java.lang.String[]);
Code:
   0:     return
}

What series to buy for this use... really want the lenovo but not sure which one

i am doubting between t400/t400s and x200/x200s
what am i using it for:
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- email
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- i really need to be able to use it in light environmenst & outdoors as i like to be in the sun :-)
for personal use:
- viewing streaming full screen video (like a tv show i missed or you tube movies)
- download movies (using quickpar/winrar to unpack and view on tv through external harddrive)
- occasional photo editing again using photoshop (i whatch the pics on tv)
- the longest possible battery time
- bright enough to experience great outdoor perfomance
- fast
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any more???
i trust this well informed community can help me out as i can't get good info through (online) resellers
thanks
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T400s, X200 and X200s are mainly built for road warriors where they don't want to carry extra weight and yet still have a powerful enough laptop for their light photoshop work, document processing, HD movies, powerpoint and publisher, etc.
For outdoors you should look to the new 'Special series of X200t (t for tablet)' which has this new screen that is specifically designed for people whom use their laptop in the outdoor environment providing maximum brightness and minimal reflectivity.
http://www.thinkpads.com/wp-content/uploads/2009/09/lenovo_thinkpad_x200_tablet_outdoor-viewable-scr...
For movies and streaming hd movies, any of these laptop would be sufficient, as T8xxx, T9xxx Penryn processors are have SSE 4 included that have special algorithm that increases processor efficiency for HD movie decoding. Also Intel X4500 MHD integrated graphics card are specifically designed for blu ray and hd movie decoding without using CPU resources.
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The T400s have built in displayport out, which is missing in the T400, while the X200 and X200s can use this port only through the ultrabase dock.
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Regards,
Jin Li
May this year, be the year of 'DO'!
I am a volunteer, and not a paid staff of Lenovo or Microsoft

Suppose one lack records having in BDC uplaod,which one can i propose uploa

Suppose one lack records having in BDC uplaod,which one can i propose uploading these records?call transaction or session method which one is better?How?

Hi Hassan,
The Session method is better and used for processing large amount of data and it will give error log itself if any comes. and the other thing is you can run session method in background but call transaction is not possible to run in background.
Session method can handle multiple transactions at a time, while in call transaction , only one at a time.
But call transaction is much faster than Session.
Database update is synchronous in Session,while it is either synchronous or asynchronous in Call Transaction.
here is the exact differences..
Call transaction:
Session is used to handle larger amount of data and error handling in implicit, while in call transaction, you have to explicitly handle error situation.
1.Synchronous Processing
2.You can update the database both synchronously and asynchrounously.
3.Transfer of data for individual transaction
4.No batch input session is created.
5.Faster than other batch input techniques.
6.No automatic error log and restart capability is available here.
7.Not recommended for bulk data transfer
Session.
1.Asynchronous Processing
2.Synchronous database updates
3.Transfer of data for multiple transaction
4.Batch input sesssion is created here.
5.Automatic error handling and efficient restart capability incase of error transaction.
6.SAP's standard approach for data transfer
7.Highly recommended for Bulk data transfer.
8.Execution is slower than CALL TRANSACTION.
for details you can go thru this link
BDC
Please go thru this link.
Reagrds,
Amit.
Reward points if useful

Undo_tablespace and undo_retetion or tune the query which one to increase

hi all,
In my logs file s
ORA-01555 caused by SQL statement below (SQL ID: 9nc0n06yryhbk, Query Duration=165122 sec, SCN: 0x05ff.062f3363):
Tue Feb 5 02:26:39 2008
SELECT /*+ FIRST_ROWS */ /*+ ORDERED */ B.GID ,K.ELEMENT_TYPE ,K.DATA_SOURCE_GID ,K.PROD_ID ,K.OPTION_CD ,K.MCC ,K.SPN ,K.REGION_CD ,K.WW_CD ,K.COUNTRY_CD ,K.ERROR ,B.GBATCH_ID
,B.PERIOD_SEQ_NUM ,B.ACTION ,B.ERROR B_ERROR ,B.COST ,B.INPUT_FILE_ROW_NUM ,B.ACTION_STATUS ,B.ACTION_TIMESTAMP FROM T_INPUT_BUCKET B, T_COS_INPUT_KEY K WHERE B.ACTION_STATUS =
'initial' AND B.GINPUT_KEY_ID = K.GID AND B.GBATCH_ID = :B1 AND ROWNUM < 8001
Tue Feb 5 02:35:21 2008
Thread 2 advanced to log sequence 42907
Mon Feb 4 09:10:55 2008
ORA-01555 caused by SQL statement below (SQL ID: 9nc0n06yryhbk, Query Duration=104081 sec, SCN: 0x05ff.05ebc008):
Mon Feb 4 09:10:55 2008
SELECT /*+ FIRST_ROWS */ /*+ ORDERED */ B.GID ,K.ELEMENT_TYPE ,K.DATA_SOURCE_GID ,K.PROD_ID ,K.OPTION_CD ,K.MCC ,K.SPN ,K.REGION_CD ,K.WW_CD ,K.COUNTRY_CD ,K.ERROR ,B.GBATCH_ID
,B.PERIOD_SEQ_NUM ,B.ACTION ,B.ERROR B_ERROR ,B.COST ,B.INPUT_FILE_ROW_NUM ,B.ACTION_STATUS ,B.ACTION_TIMESTAMP FROM T_INPUT_BUCKET B, T_COS_INPUT_KEY K WHERE B.ACTION_STATUS =
'initial' AND B.GINPUT_KEY_ID = K.GID AND B.GBATCH_ID = :B1 AND ROWNUM < 8001
Mon Feb 4 09:14:08 2008
===============================================
and my undo_retention
Current usage:
UNDO_01 96736 11596 12 88
UNDO_02 96736 9357 10 90
NAME TYPE VALUE
undo_management string AUTO
undo_retention integer 36000
can anyone please guide me which one is best to increase undo_retention or undo_tablespace
or tune the query?
my database version is
Oracle Database 10g Enterprise Edition Release 10.2.0.2.0 - 64bi
PL/SQL Release 10.2.0.2.0 - Production
"CORE 10.2.0.2.0 Production"
TNS for HPUX: Version 10.2.0.2.0 - Production
NLSRTL Version 10.2.0.2.0 - Production
thanks in advance

IMO best is to
1) tune the query to minimize time and resource use;
2) set the undo_retention to size the undo tablespace for the required 'consistent read' rebuild requirements;
3) set the retention guarantee appropriately
4) size the undo tablespace based on the required size, probably dictated by 2)
Why is this an 'either one or other' question? When driving a car and looking for best fuel efficiency, you tune up the car, drive properly AND use the right fuel. You don't just pick one and leave it at that.

Which query is efficient?

Hi all,
I have 2 queries which produce same output on test data. But i am not confident which is a better one or efficient one.
How can I measure the efficiency of these programs?
Query1:
SELECT TAB1.A, TAB1.B
FROM TAB1
LEFT OUTER JOIN (SELECT * FROM TAB2 WHERE d=-1) t2
ON TAB1.a = T2.c;
Query2:
SELECT TAB1.A, TAB1.B, TAB2.e
FROM TAB1
LEFT OUTER JOIN TAB2 ON TAB1.a = TAB2.c AND TAB2.d=-1;
Thanks
Edited by: KinsaKaUy? on 10-Oct-2011 02:00

But there should be at least a difference?
I am worried if I cut n paste the same program?
ok I will try again. brb
| Id | Operation                         | Name         | Rows | Bytes | Cost |
|   0 | SELECT STATEMENT                  |              |    15 | 2640 |     6 |
|   1 | NESTED LOOPS                     |              |       |       |       |
|   2 |   NESTED LOOPS                    |              |    15 | 2640 |     6 |
|   3 |    NESTED LOOPS OUTER             |              |     6 |   942 |     5 |
|   4 |     NESTED LOOPS OUTER            |              |     6 |   822 |     4 |
|   5 |      NESTED LOOPS                 |              |     6 |   654 |     3 |
|   6 |       NESTED LOOPS                |              |     6 |   444 |     2 |
|   7 |        TABLE ACCESS BY INDEX ROWID| CI_CASE_CHAR |     7 |   259 |     1 |
|   8 |         INDEX SKIP SCAN           | XT222P0      |     7 |       |     1 |
|   9 |        TABLE ACCESS BY INDEX ROWID| CI_CASE_CHAR |     1 |    37 |     1 |
| 10 |         INDEX RANGE SCAN          | XT222P0      |     1 |       |     1 |
| 11 |       TABLE ACCESS BY INDEX ROWID | CI_CASE      |     1 |    35 |     1 |
| 12 |        INDEX UNIQUE SCAN          | XT220P0      |     1 |       |     1 |
| 13 |      TABLE ACCESS BY INDEX ROWID | CI_CASE_CHAR |     1 |    28 |     1 |
| 14 |       INDEX RANGE SCAN            | XT222P0      |     1 |       |     1 |
| 15 |     TABLE ACCESS BY INDEX ROWID   | CI_SP        |     1 |    20 |     1 |
| 16 |      INDEX UNIQUE SCAN            | XM226P0      |     1 |       |     1 |
| 17 |    INDEX RANGE SCAN               | XT221P0      |     3 |       |     1 |
| 18 |   TABLE ACCESS BY INDEX ROWID     | CI_CASE_LOG |     3 |    57 |     1 |
| Id | Operation                         | Name         | Rows | Bytes | Cost |
|   0 | SELECT STATEMENT                  |              |    15 | 2640 |     6 |
|   1 | NESTED LOOPS                     |              |       |       |       |
|   2 |   NESTED LOOPS                    |              |    15 | 2640 |     6 |
|   3 |    NESTED LOOPS OUTER             |              |     6 |   942 |     5 |
|   4 |     NESTED LOOPS OUTER            |              |     6 |   822 |     4 |
|   5 |      NESTED LOOPS                 |              |     6 |   654 |     3 |
|   6 |       NESTED LOOPS                |              |     6 |   444 |     2 |
|   7 |        TABLE ACCESS BY INDEX ROWID| CI_CASE_CHAR |     7 |   259 |     1 |
|   8 |         INDEX SKIP SCAN           | XT222P0      |     7 |       |     1 |
|   9 |        TABLE ACCESS BY INDEX ROWID| CI_CASE_CHAR |     1 |    37 |     1 |
| 10 |         INDEX RANGE SCAN          | XT222P0      |     1 |       |     1 |
| 11 |       TABLE ACCESS BY INDEX ROWID | CI_CASE      |     1 |    35 |     1 |
| 12 |        INDEX UNIQUE SCAN          | XT220P0      |     1 |       |     1 |
| 13 |      TABLE ACCESS BY INDEX ROWID | CI_CASE_CHAR |     1 |    28 |     1 |
| 14 |       INDEX RANGE SCAN            | XT222P0      |     1 |       |     1 |
| 15 |     TABLE ACCESS BY INDEX ROWID   | CI_SP        |     1 |    20 |     1 |
| 16 |      INDEX UNIQUE SCAN            | XM226P0      |     1 |       |     1 |
| 17 |    INDEX RANGE SCAN               | XT221P0      |     3 |       |     1 |
| 18 |   TABLE ACCESS BY INDEX ROWID     | CI_CASE_LOG |     3 |    57 |     1 |
I guess they are identical :)
Edited by: KinsaKaUy? on Oct 10, 2011 2:40 AM

Which statement is efficient?

Which statement is efficient?
1. SELECT MSG_ID,IP_ADDRESS,DATETIME INTO V_MSG_ID,V_IP_ADDRESS,V_DATETIME
       FROM (SELECT * FROM INCOMING_MSG_IDX ORDER BY LAST_CHECKTIME)
         WHERE STATUS = 4 AND MSG_TYPE >= LOW_MSG_TYPE AND MSG_TYPE <=
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2.   SELECT MSG_ID,IP_ADDRESS,DATETIME INTO V_MSG_ID,V_IP_ADDRESS,V_DATETIME
         FROM INCOMING_MSG_IDX
           WHERE STATUS = 4 AND MSG_TYPE BETWEEN LOW_MSG_TYPE AND
             UP_MSG_TYPE AND ROWNUM =1
                  ORDER BY LAST_CHECKTIME

jetq wrote:
Which statement is efficient?If more than one row satisfies your filter predicates in the WHERE clause then your question is irrelevant since the two statements are not equal.
The first one obeys the ORDER and returns the first entry ordered by LAST_CHECKTIME that passes the predicates.
The second one returns an arbitrary row that passes the predicates, because ROWNUM is applied before the ORDER BY, and therefore the two statements are not equal.
Regards,
Randolf
Oracle related stuff blog:
http://oracle-randolf.blogspot.com/
SQLTools++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676/
http://sourceforge.net/projects/sqlt-pp/

HT1349 How do you get help from apple if you don't know where to find the serial number of my "product." I don't know if they mean my itunes program, my iphone, my computer, which one, the number on the computer (is there one), or something in Windows or

How are you supposed to get help from Apple if you don't know what your serial number is? They say to input the serial number of the "product" that you are asking about. Since my problem is how to deauthorize/authorize computers, and they are saying I have more than 5 (which I have never owned more than 5 computers in my life), I can't imagine what serial number they mean. Does it mean your desktop computer? If so, which one? Do they mean your device? LIke your iPhone, iPod or whatever? Do they mean the software ON one of your computers and/or devices? If so, which program, and on which computer/device?
We have three operational computers, one does not have iTunes on it. Since Apple is saying I have more than 5 authorized computers, and I can't imagine what they are, I am afraid to deauthorize all my computers. See what I mean? I just wanted to ask the question about how I can find out WHICH computers Apple thinks I have authorized, so I can decide if it's safe to deauthorize them all or not. I only know of 2 computers that have iTunes on them, so how can there be 5? We also have 2 iPhones and 2 iPods in this family, but one of the iPhones has his own apple id. He may have been using mine, since his computer died. I read that those don't count as "computers" to the 5. Do they, then?
Help! I can't contact apple because I have no idea what they mean about serial number. I doubt they would help me anyway. In order to get the serial number off my desktop computer (that has iTunes on it already), I will have to move furniture, so I don't want to if that's not it. Is there some way to find the serial number in the software, either on my desktop or my iPhone?

sunshinecowgill wrote:
We have three operational computers, one does not have iTunes on it. Since Apple is saying I have more than 5 authorized computers, and I can't imagine what they are, I am afraid to deauthorize all my computers. See what I mean? I just wanted to ask the question about how I can find out WHICH computers Apple thinks I have authorized, so I can decide if it's safe to deauthorize them all or not.
You could have more 5 computers authorized if you ever, for example, reformatted a hard drive or replaced a hard drive without deauthorizing the computer first. Apple's system would see that as a different computer, even though you don't. There's nothing to be afraid of in deauthorizing everything and the reauthorizing what you actually have. You won't lose any data. Mistimp is correct, they can't tell you which computers are authorized.

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Hi,
I am a newbie and would like to install Oracle 8.1.7 on RedHat Linux,
so RedHat 6.2 or RedHat 7.0
which one is the easier installation for
me(both new in Oracle & Linux)?
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<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Matt:
Hi,
I am a newbie and would like to install Oracle 8.1.7 on RedHat Linux,
so RedHat 6.2 or RedHat 7.0
which one is the easier installation for
me(both new in Oracle & Linux)?
Many thanks,
Matt<HR></BLOCKQUOTE>
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null

I created a slide show in imovie for my daughters 21st with voice overs from friends and family which was all working fine but now the voice recordings are not playing at all. Obviously some setting has changed but I can't find which one.

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Adobe Cloud has 2 different Muse programs.... how do I know which one is the newer better version?

So I am new to Muse, and my Adobe Cloud has 2 different programs from Muse... how do I know which one is the newer better version?
One Must program (Muse CC 2014.2) has a black background when working on it... it looks like other Adobe programs such as Photoshop.
The other one is light color (Muse CC) very similar to the black color Muse on functions.....
One of the difference I notice is that the light color Muse has a few widgets in the library, while the black background Muse seems to have an empty library
So... why are there 2 different Muse programs in my Adobe Cloud?

Hi
The latest version of Muse is 2014.2, so you need to uninstall another version of Muse manually.
regarding the items in Library, you can add items in your library manually, as shown in this article
Adobe Muse Help | Organizing and reusing design elements using Library panel
Please let me know if you have any other query.

Which one is efficient???

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