Which thread would start first and why

Question

Could anybody advise me as to which thread would start first
new thread(new Runnable(){
public void run(){
TestThread t1 = new Thread();
t1.start();
}).start();
I would have guessed that the outer one but it seems to be happeneing otherwise.

Answer 1

new thread(new Runnable(){
    public void run(){
        TestThread t1 = new Thread();
        t1.start();
}).start();The outer one's start() method is called.
At some point after that, the new thread (not Thread, thread) created by calling outer's start will call outer's run(), which calls inner's start(), which gives us another thread (not Thread).
At this point, outer's start() and run() have both been called, an inner's start() has been called. Both outer and inner are threads that exist and are eligible for cycles. Inner's run() may be called immediately or later.
From now on, we can't predict (priority and synchronization aside) what order the threads will execute in. So if inner's run's first statement is System.err.println("inner") and outer's first statement after starting inner is System.err.println("outer") then we could see either
inner
outer
or
outer
inner
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