While loop not performing correctly

Question

When I enter ANY number, the second while loop in the code below executes. It should not execute when 117, 239, 298, 326, or 445 is entered. I can't seem to figure out why this does not work, and I do not know what else to try.
Hope someone can just give some assistance. Thank you!
If I need to supply the entire program, just let me know.
while(! done)
               try
                    System.out.println("Enter the flight number");
                    entry = keyboard.nextInt();
                    while((entry != 117) || (entry != 239) || (entry != 298) || (entry != 326) || (entry!= 445))
                         System.out.println("Flight number must be 117, 239, 298, 326, 445");
                         System.out.println("Please try again");
                         entry = keyboard.nextInt( );
                         done = true;
               catch(InputMismatchException e)
                    keyboard.nextLine();
                    System.out.println("Not the correct entry");
                    System.out.println("Please try again");
          }

Answer 1

JosAH wrote:
paulcw wrote:
The outer loop loops on "not done", but in the body of that loop, done is unconditionally set to true. So the outer loop will only run once. Therefore it's pointless. I'm guessing that you meant to only set done to true if the user inputs "quit" or something.The 'not done' loop will iterate again if the user supplied incorrect input (not an int).Man that's a confusing flow of control. So if the user types in anything other than a number, it's causes a parse error (basically) and the exception causes it to skip the command to stop, and that makes it loop again.
So apparently 3/4 of the people looking at that code didn't get it at first.
It reminds me of the veda about Mel.
Come up with something clearer.