Why Object is a super class in java?

hi all i have got one basic doubt in java. why Object class is a super class in java. C++ is also a object oriented language but there there is no concept of making object as a super class, but in java why we are having that. thanks

Personally, I find the fact that C++ (and Delphi) DOES NOT have a common base class something of an inconvenience at times. The reason is that Java is an (almost) pure Object Oriented language, while C++ and Delphi are partially-object-oriented additions to C and Pascal respectively.
RObin

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  • Super class for java Language

    which is the super class for java Language...
    this is an interview question .
    I SAY Object is the super class for java Language ...
    then he asked whether object class will extend ??
    i say Yes it will implectly extend ...
    then he whether each and every class will extend object
    i say yes ...
    then he asked multiple inheritance is possible in java ...
    i say no ...
    then how will say object class will extend in each and every class....
    hai friends if there is any solution tell mem
    by
    dhana

    which is the super class for java Language...
    this is an interview question .
    I SAY Object is the super class for java Language
    ge ...If you mean the ultimate parent of all classes, yes.
    (Although it's not the parent of interfaces.)
    then he asked whether object class will extend ??
    i say Yes it will implectly extend ...Not sure what is meant by "will object extend."
    then he whether each and every class will extend
    object
    i say yes ...Correct.
    then he asked multiple inheritance is possible in
    java ...
    i say no ...Correct. At least in the usual sense. When people talk about multiple inheritance, the usually mean multiple inheritance of implementation, such as C++ supports. The ability to implement more than one interface in Java is sometimes referred to as multiple inheritance of interface. I don't know if that term is in common use outside of Java.
    then how will say object class will extend in each
    and every class....
    hai friends if there is any solution tell memMultiple inheritance means that a class' ancestors are not all in a straight line to the ultimate parent. That is, not all ancestors are parents or children of each other.
    You are you father's son, and he is his father's son, and so on. So your grandfather is your ancestor, and so is your father. This is not MI.
    You also have a mother. She's neither an ancestor nor a descendant of your father. That's MI.

  • Super Class of Java

    can any one tell what is the super class of JAVA?

    How can u assume a to be = b and then prove that a = b based on the assumption that a=b... --:)
    also 0 = 1 ....> which leaves Aryabhatta thinking why the Hell did I invented zero , when it will turn out to be 1 in future .:). no NOR gates required .. cool ... No boolean datatype required ....... rather no computer bo byte funda when 1 = 0 ..... Hurray so no Java ...... No Exceptions ..... So we would be only left with our old Crashproof Word Processor ( Commonly known as TypeWriter)

  • How to indicate the object of the super Class ?

    hello,
    I need to notify when one dialog is close to the class that generated it.
    Of course I do it from the method windowClosing() in the class WindowAdapter.
    But if I use "this" how parameter in the method, I noted the value is that of the inner anonymous class, and not that of the dialog class.
    I write down some code to reproduce the problem ....
    public ReferenceToTheSuperClass() {
            final SecondClass sc = new SecondClass(this);
            jButton1 = new javax.swing.JButton();
    //        final ReferenceToTheSuperClass xx = this;
            jButton1.setText("jButton1");
            jButton1.addActionListener(new java.awt.event.ActionListener() {
                public void actionPerformed(java.awt.event.ActionEvent evt) {
                     sc.checkSuper(xx);                    // work
                     sc.checkSuper(this);                   // not work
                     sc.checkSuper(super.getClass()); // not work
    }  // ReferenceToTheSuperClass
    class SecondClass {
        ReferenceToTheSuperClass superiorClass;
        public SecondClass(ReferenceToTheSuperClass supClass){
            superiorClass = supClass;
        public void checkSuper(Object o){
            if (o instanceof ReferenceToTheSuperClass){
                JOptionPane.showMessageDialog(null,"HELLO");
    } // SecondClass My ask is: It is possible to indicate the value of the instance of the super Class, inside one his anonynimous inner class?
    thank you
    regards
    tonyMrsangelo

    thank you for your kinkly answer jeverd,
    yes what you say is right, in this case the class is only nested (in the hurry I used a wrong word).
    About the sintax, I vould find only a short statement to use inside the inner anomymous class and, reading what you say, I can guess it is not possible to do it..
    again thank you
    regards
    tonyMrsangelo

  • Instantiation of similar object over a super class deciding the sub class

    Hello all
    First, sorry if I'm duplicating an already answered question. I didn't searched very deep.
    Initial position:
    I have 2 Object (A1 and A2) which share the most (about 90%) of their instance variables an the associated methods. The values of the instance variables are retrieved in the real implementation from a stream. Depending of the data of the stream, I have to instantiate either a A1 or A2 object.
    A test implementation (using an int in case of the stream):
    The super class A:
    package aaa;
    public class A
      protected int version = -1;
      protected String name = null;
      protected AE ae = null;
      protected A()
      protected A(int v)
        // Pseudo code
        if (v > 7)
          return;
        if (v % 2 == 1)
          this.version = 1;
        else
          this.version = 2;
      public final int getVersion()
        return this.version;
      public final String getName()
        return this.name;
      public final AE getAE()
        return this.ae;
    }The first sub class A1:
    package aaa;
    public final class A1 extends A
      protected A1(int v)
        this.version = v;
        this.name = "A" + v;
        this.ae = new AE(v);
    }The second subclass A2:
    package aaa;
    import java.util.Date;
    public final class A2 extends A
      private long time = -1;
      protected A2(int v)
        this.version = v;
        this.name = "A" + v;
        this.time = new Date().getTime();
        this.ae = new AE(v);
      public final long getTime()
        return this.time;
    }Another class AE:
    package aaa;
    public class AE
      protected int type = -1;
      protected AE(int v)
        // Pseudo code
        if (v % 2 == 1)
          this.type = 0;
        else
          this.type = 3;
      public final int getType()
        return this.type;
    }To get a specific object, I use this class:
    package aaa;
    public final class AFactory
      public AFactory()
      public final Object createA(int p)
        A a = new A(p);
        int v = a.getVersion();
        switch (v)
        case 1:
          return new A1(v);
        case 2:
          return new A2(v);
        default:
          return null;
    }And at least, a class using this objects:
    import aaa.*;
    public final class R
      public static void main(String[] args)
        AFactory f = new AFactory();
        Object o = null;
        for (int i = 0; i < 10; i++)
          System.out.println("===== Current Number is " + i + " =====");
          o = f.createA(i);
          if (o instanceof aaa.A)
            A a = (A) o;
            System.out.println("Class   : " + a.getClass().getName());
            System.out.println("Version : " + a.getVersion());
            System.out.println("Name    : " + a.getName());
            System.out.println("AE-Type : " + a.getAE().getType());
          if (o instanceof aaa.A2)
            A2 a = (A2) o;
            System.out.println("Time    : " + a.getTime());
          System.out.println();
    Questions:
    What would be a better way to encapsulate the logic into their respective objects ? Is there a way to let the super class A itself identify the type of the object and then extend from A to either A1 or A2 ?
    Thanks in advance
    Andreas

    Hello jduprez
    First, I would thank you very much for taking the time reviewing my problem.
    Just for the record: have you considered regular serialization? If you control the software at both ends of the stream, you could rely on standard serialization mechanism to marshall the objects and unmarshall them automatically.In my case, I can't control the other site of the stream. At the end, the data comes from a FileInputStream and there aren't objects on the other site, only pur binary data.
    - It seems you have one such factory class. Then you already have encapsulated the "determine class" logic, you don't need to add such logic in superclass A.I thought from an OO view, that the super class A is responsible of doing that, but that's where the problem starts. So at the end, it's better doing it in the factory class.
    - A itself encapsulates the logic to load its own values from the stream.
    - A1 and A2 can encapsulate the logic to load their own specific value from a stream (after the superclass' code has loaded the superclass' attributes values).
    My advise would be along the lines of:
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    .... // member variables
    public void load(InputStream is) {
    ... // assign values to A's member variables
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    public class A1 extends A {
    ... // A1-specific member variables
    public void load(InputStream is) {
    super.load(is);
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    public class AFactory {
    public A createA(InputStream is) {
    A instance;
    switch (is.readFirstByte()) {
    case A1_ID:
    a = new A1();
    break;
    case A2_ID:
    a = new A2();
    break;
    a.load(is);
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    The outcome is: you don't have to create a new A( ) to later create another instance, of a subclass.I like the idea. In the AFactory, is the "A instance;" read as "A a;" ?
    Is there a way to let the super class A itself identify the type of the object and then extend from A to either A1 or A2 ?Note I initially read this question as "can an instance of a class mutate into another class", to which the answer is no (an object has one single, immutable class; it is an instance of this class, and of any superclass and superinterface, but won't change its class at runtime).Yes, I have been thinking about a way for mutating into a subclass to keep the already initialized values from the A class without copying or parsing again. But preventing an instance of an A class will be my way. So, in this aspect, Java didn't changed in the last 10 years... It's a long time ago I've used Java for some real projects.
    You can, however, create an instance of another class, that copies the values off a priori A instance. Your example code was one way, another way could be to have a "copy constructor":
    public class A {
    public A(A model) {
    this.att1 = model.att1;
    this.att2 = model.att2;
    public class A1 {
    public A1(A model) {
    super(model);
    ... // do whatever A1-specific business
    )Still, I prefer my former solution less disturbing: I find the temporary A instance redundant and awkward.Nice to know. I prefer the first solution too.
    Thank you again for the help and advices. My mind is searching sometimes for strange solutions, where the real is so close ;-)
    Andreas

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  • What is the difference between acquiring lock on a CLASS and OBJECT (instance) of that class

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                        infile.close();
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                        throw new IOException(functionName + ": cannot close output file " + outputFilename, ex);
              return(retVal);
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                   String  inputFilename //the name of the file to read.
              , int     lineNumber    //1 based number of the line to read from.
         ) throws IOException
              final String functionName = "FileIO.readLine";
              String outputLine = null;
              // reads the numbered "lineNumber" from "inputFilename".
              BufferedReader infile = null;
              try {
                   infile = new BufferedReader(new FileReader(new File(inputFilename)));
                   for(int i=1; i<lineNumber; ++i) infile.readLine();
                   outputLine = infile.readLine();
              } catch(IOException ex){
                   throw new IOException(functionName + ": cannot read input file " + inputFilename, ex);
              } finally {
                   try {
                        infile.close();
                   } catch(IOException ex){
                        throw new IOException(functionName + ": cannot close input file " + inputFilename, ex);
              return(outputLine);
         public static String readWord(
                   String inputFilename  //the name of the file to read.
              , int lineNumber        //1 based number of the line to read from.
              , int wordNumber        //0 based number of the word to read.
         ) throws IOException
              final String functionName = "FileIO.readWord";
              String outputWord = null;
              // reads the numbered space-seperated "wordNumber" from the numbered "lineNumber" of "inputFilename"
              try {
                   String[] words = FileIO.readLine(inputFilename, lineNumber).split(" ");
                   if (wordNumber>0 && wordNumber<words.length) outputWord = words[wordNumber-1];
              } catch(IOException ex){
                   throw new IOException(functionName + ": cannot read input file " + inputFilename, ex);
              return(outputWord);
    }Design notes... FileIO is a generic helper class... there is nothing specific to Airports, flights, or any other "domain" specific stuff in it... so it's re-usable... you can keep it and reuse it on other projects, or even share it with your friends.
    So... The airport class will just call the static methods on FileIO like this    ....
        int lineNumber=1;
        int wordNumber=1;
        String airportCode = FileIO.readWord(airportsFilename, lineNumber, wordNumber);
        ....How's that?
    corlettk: my now mandatory edit.

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