Wm_concat(column_name) order by [SOLVED]

Question

The question is based on a other thread:
column values separated by ,
Aketi Jyuuzou Posted: Nov 23, 2007 3:17 AM
with the next statement there will be 4 records displayed
(there are 4 columns for this constraint)
select constraint_name, wm_concat(column_name) over(order by position) as column_names
from user_cons_columns
where constraint_name='EUL5_DOC_UK_2'
1 EUL5_DOC_UK_2     DOC_EU_ID
2 EUL5_DOC_UK_2     DOC_EU_ID,DOC_NAME
3 EUL5_DOC_UK_2     DOC_EU_ID,DOC_NAME,DOC_BATCH
4 EUL5_DOC_UK_2     DOC_EU_ID,DOC_NAME,DOC_BATCH,DOC_FOLDER_ID
is it possible to select only the last (4) record?
Thanks in advance..

Answer 1

Note that wmsys.wm_concat is undocumented and unsupported.
It looks like the script below, which I use to show me the constraints on a table, might be useful to you:
column "Constraint" format a20
column "Kolom(men)" format a40
column "Soort" format a11
column "Verwijst naar" format a23
column "Inhoud check constraint" format a36 truncate
accept P_TABEL char prompt 'Van welke tabel wil je de constraints zien? '
set verify off
select c.constraint_name "Constraint"
     , case c.constraint_type
       when 'P' then 'Primary key'
       when 'U' then 'Unique key'
       when 'R' then 'Foreign key'
       when 'C' then 'Check'
       else 'Anders: ' || c.constraint_type
       end "Soort"
     , rtrim(cc.cols,',') "Kolom(men)"
     , case when c.r_owner is not null then c.r_owner || '.' || c.r_constraint_name end "Verwijst naar"
     , c.search_condition "Inhoud check constraint"
  from user_constraints c
     , ( select constraint_name
              , p
              , c cols
           from user_cons_columns
          where table_name = upper('&&P_TABEL')
          model
                partition by (constraint_name)
                dimension by (nvl(position,row_number() over (partition by constraint_name order by null)) p)
                measures (column_name c)
                ( c[any] order by p desc = c[cv()] || ',' || c[cv()+1]
       ) cc
where c.constraint_name = cc.constraint_name
   and cc.p = 1
order by
       case c.constraint_type
       when 'P' then 1
       when 'U' then 2
       when 'R' then 3
       when 'C' then 4
       else 5
       end
     , c.constraint_name
undefine P_TABEL
set verify onGroet,
Rob.