XML Publisher and the type formula

Hi,
I am trying to develop an XML Publisher template for the Ebusiness Suit's Accounts Receivable RAXINV report. I have noticed that in the XML I generated running the report as type XML. It generates the XML tags but they contain no data for the column type formula. Can anyone recommend a way of getting around this?
Regards,
Mark

Hi Tim,
Thanks for you reply. Yes the XML Tags had been set for the formula columns.
Could you tell me in Oracle Report in the Data Model, if a column of type of formula has a PL/SQL formula that returns a result will that result be displayed when the report is exported as XML?
Thanks,
Mark

Similar Messages

XML Publisher and the Oracle Shipping Transactions Form

I am running 11.5.10.2. I need to print Simplified Chinese characters in a document. We converted to the UTF-8 character set so the server can render these on forms and such. I am using Oracle Reports 6i to produce a report, but due to the limitations with this product it will not produce PDF output with Chinese characters. XML Publisher however works great. The concurrent manager is set so the report produces XML which is then set to the template and out comes a really cool looking layout with Chinese that can be viewed, printed, or e-mailed anywhere.
Now I have put this report into a document set so it can be printed from the Shipping Transactions form. But it does not work. There is no output. Metalink Note:312194.1 states development only supports XSL-FO and this will not be available until R12.
Is this really true? Has anyone else come across this? Any suggestions on how to get around this?

Hi
Im assuming you are using the EBusiness Suite becasue of your reference to AR and AP modules. If so getting using an ORacle Report as a datasource for XMLP to format is pretty straightforward. There is a white paper on metalink describe the complete process - Note 295409.1. This will be available on the public site soon http://www.oracle.com/technology/products/applications/publishing/index.html
As for AR and AP, there is no reason at all why you can not use XMLP with the existing Oracle Reports in those modules. You will start to see more and more modules providing embedded reporting functionality in the EBS based on XMLP technologies.
Regards
Tim

When running an xml publisher report the xml output leads to 9 mb and the excel output file leads to 20 mb.But the output records is originally 4000 records. When copy to new excel it is showing 3.5 mb only. Does anyone knows the answer for this issue?

When running an xml publisher report the xml output leads to 9 mb and the excel output file leads to 20 mb. The records contained in excel file is 4000 records. When taking the excel records and copy to new excel file the excel file size is 3.5 mb only.Why does the oracle software generates 20mb file?
Does any one knows the answer please advice?

Hello,
This issue is because the Excel output from BI Publisher is MHTML (XML Publisher generates XHTML) not binary .xls.
MHTML and XHTML are more verbose formats than binary .xls.
It will be large because the current Excel output is just an HTML and not compressed like PDF. Please use the workaround (save it as .xls file). This is a known limitation of RTF layout templates.
BI Publisher Enterprise has a new feature True Excel Templates. The layouts generate binary Excel output.
Excel Output File Size Generated By BI Publisher is Very Large (Doc ID 760437.1)
Bogdan

Sales - Quoting Functionality - XML Publisher and XSL.

Hi ,
We have changed output in Quoting to use XML Publisher instead of Reports Server.
How can we view the XML tags to create the XSL file?
Its possible to see XML output from PO's , SOA's etc when printed vis Concurrent Mgr and Oracle Forms but the raw XML is not available when using in Sales and Printing a Quote ( uses sample xsl in XML Publisher at the moment...Am formatting this.. but have no raw xml).
Any ideas?
Cheers
Stephen

I know what I can do in RTF and maybe it´s enough:
1. Ensure you are using both tabs of the help text, you can start in Status Bar and continue with Help Key.
2. You can also use multiple fields one after another.
3. If you fill all of that and need more space I would consider moving the function out into its own XSL template and register it as a sub template and reference it from your main template. This is especially useful if you are going to need the same function across multiple templates.
My problem was why I can´t use XSL-FO - XML in XMLSPY, have´nt anybody tried to go out of the WORD-RTF and code som XSL? Maybe it´s not possible and I have to use WORD-RTF.
/Daniel

Reg:Integrating XML Publisher and OA Framework

I am trying to Integrating XML Publisher and OA Framework, i got
C:\Framework\Jdeveloper\jdevhome\jdev\myprojects\xxxmlrep\oracle\apps\ak\webui\EmpCO.java
Error(84,7): class OADBTransactionImpl not found in class xxxmlrep.oracle.apps.ak.webui.EmpCO
Error(87,7): class OADBTransactionImpl not found in class xxxmlrep.oracle.apps.ak.webui.EmpCO
Error(88,7): class OADBTransactionImpl not found in class xxxmlrep.oracle.apps.ak.webui.EmpCO
Error(90,5): variable TemplateHelper not found in class xxxmlrep.oracle.apps.ak.webui.EmpCO
Error(83,5): variable TemplateHelper not found in class xxxmlrep.oracle.apps.ak.webui.EmpCO
source code is
/*===========================================================================+
| Copyright (c) 2001, 2005 Oracle Corporation, Redwood Shores, CA, USA |
| All rights reserved. |
+===========================================================================+
| HISTORY |
+===========================================================================*/
package xxxmlrep.oracle.apps.ak.webui;
import java.io.ByteArrayInputStream;
import java.io.ByteArrayOutputStream;
import javax.servlet.ServletOutputStream;
import javax.servlet.http.HttpServletResponse;
import oracle.apps.fnd.common.VersionInfo;
import oracle.apps.fnd.framework.OAException;
import oracle.apps.fnd.framework.server.OAApplicationModuleImpl;
import oracle.apps.fnd.framework.webui.OAControllerImpl;
import oracle.apps.fnd.framework.webui.OAPageContext;
import oracle.apps.fnd.framework.webui.beans.OAWebBean;
import oracle.cabo.ui.data.DataObject;
import oracle.xml.parser.v2.XMLNode;
* Controller for ...
public class EmpCO extends OAControllerImpl
private static final int DEPTH = 4;
private static final int APP_ID = 20035;
private static final String APP_NAME = "AK";
private static final String TEMPLATE_CODE = "XXEMP_JDEV";
private static final int BUFFER_SIZE = 32000;
public static final String RCS_ID="$Header$";
public static final boolean RCS_ID_RECORDED =
VersionInfo.recordClassVersion(RCS_ID, "%packagename%");
* Layout and page setup logic for a region.
* @param pageContext the current OA page context
* @param webBean the web bean corresponding to the region
public void processRequest(OAPageContext pageContext, OAWebBean webBean)
super.processRequest(pageContext, webBean);
OAApplicationModuleImpl am= (OAApplicationModuleImpl)pageContext.getApplicationModule(webBean);
am.invokeMethod("initEmpVO");
am.invokeMethod("getEmpDataXML");
* Procedure to handle form submissions for form elements in
* a region.
* @param pageContext the current OA page context
* @param webBean the web bean corresponding to the region
public void processFormRequest(OAPageContext pageContext, OAWebBean webBean)
super.processFormRequest(pageContext, webBean);
OAApplicationModuleImpl am= (OAApplicationModuleImpl)pageContext.getApplicationModule(webBean);
String event = pageContext.getParameter("event");
if("GenerateReport".equals(event))
DataObject sessionDictionary = (DataObject)pageContext.getNamedDataObject("_SessionParameters");
HttpServletResponse response = (HttpServletResponse)sessionDictionary.selectValue(null,"HttpServletResponse");
try {
ServletOutputStream os = response.getOutputStream();
String contentDisposition = "attachment;filename=EmpReport.pdf";
response.setHeader("Content-Disposition",contentDisposition);
response.setContentType("application/pdf");
XMLNode xmlNode = (XMLNode) am.invokeMethod("getEmpAM");
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
xmlNode.print(outputStream);
ByteArrayInputStream inputStream = new ByteArrayInputStream(outputStream.toByteArray());
ByteArrayOutputStream pdfFile = new ByteArrayOutputStream();
TemplateHelper.processTemplate(
((OADBTransactionImpl)pageContext.getApplicationModule(webBean).getOADBTransaction()).getAppsContext(),
APP_NAME,
TEMPLATE_CODE,
((OADBTransactionImpl)pageContext.getApplicationModule(webBean).getOADBTransaction()).getUserLocale().getLanguage(),
((OADBTransactionImpl)pageContext.getApplicationModule(webBean).getOADBTransaction()).getUserLocale().getCountry(),
inputStream,
TemplateHelper.OUTPUT_TYPE_PDF,
null,
pdfFile);
byte[] b = pdfFile.toByteArray();
response.setContentLength(b.length);
os.write(b, 0, b.length);
os.flush();
os.close();
catch(Exception e)
response.setContentType("text/html");
throw new OAException(e.getMessage(), OAException.ERROR);
pageContext.setDocumentRendered(false);
thank in advance
}

User,
This code snippet may help:
while (myQuestionIsAboutOAFramework)
user.askQuestionInProperForum(Constants.OAFrameworkForum);
public class Constants
public static string OAFrameworkForum = "http://forums.oracle.com/forums/forum.jspa?forumID=210";
}John

Difference between XML Publisher and BI Publisher

Dear Members,
Recently I've started using XML Publisher Desktop V 5.5 with Oracle Applications V 11.5.10.2
In many forums and sites, most of the users are referring as XML Publisher or BI Publisher. Can any one please explain me the below points:
1/ What is the difference between XML Publisher and BI Publisher.
2/ Can I use BI Publisher with Oracle Applications V 11.5.10.2? If YES what I need to do to use BI Publisher?
Your inputs will be of great help to me.
Many thanks in advance.
Best Regards,
Arun Reddy D.

In the main page of this forum, there are announcements... check "Naming and Versioning" -- might help you.

I've lost my access code for my device and the type of device is the iPad Mini

I lost my access code from may device and the type of device is the ipad mini

iOS: Device disabled after entering wrong passcode
http://support.apple.com/kb/ht1212
How can I unlock my iPad if I forgot the passcode?
http://tinyurl.com/7ndy8tb
How to Reset a Forgotten Password for an iOS Device
http://www.wikihow.com/Reset-a-Forgotten-Password-for-an-iOS-Device
Using iPhone/iPad Recovery Mode
http://ipod.about.com/od/iphonetroubleshooting/a/Iphone-Recovery-Mode.htm
Saw this solution on another post about an iPad in a school enviroment. Might work on your iPad so you won't lose everything.
~~~~~~~~~~~~~
‘iPad is disabled’ fix without resetting using iTunes
Today I met my match with an iPad that had a passcode entered too many times, resulting in it displaying the message ‘iPad is disabled – Connect to iTunes’. This was a student iPad and since they use Notability for most of their work there was a chance that her files were not all backed up to the cloud. I really wanted to just re-activate the iPad instead of totally resetting it back to our default image.
I reached out to my PLN on Twitter and had some help from a few people through retweets and a couple of clarification tweets. I love that so many are willing to help out so quickly. Through this I also learned that I look like Lt. Riker from Star Trek (thanks @FillineMachine).
Through some trial and error (and a little sheer luck), I was able to reactivate the iPad without loosing any data. Note, this will only work on the computer it last synced with. Here’s how:
1. Configurator is useless in reactivating a locked iPad. You will only be able to completely reformat the iPad using Configurator. If that’s ok with you, go for it – otherwise don’t waste your time trying to figure it out.
2. Open iTunes with the iPad disconnected.
3. Connect the iPad to the computer and wait for it to show up in the devices section in iTunes.
4. Click on the iPad name when it appears and you will be given the option to restore a backup or setup as a new iPad (since it is locked).
5. Click ‘Setup as new iPad’ and then click restore.
6. The iPad will start backing up before it does the full restore and sync. CANCEL THE BACKUP IMMEDIATELY. You do this by clicking the small x in the status window in iTunes.
7. When the backup cancels, it immediately starts syncing – cancel this as well using the same small x in the iTunes status window.
8. The first stage in the restore process unlocks the iPad, you are basically just cancelling out the restore process as soon as it reactivates the iPad.
If done correctly, you will experience no data loss and the result will be a reactivated iPad. I have now tried this with about 5 iPads that were locked identically by students and each time it worked like a charm.
~~~~~~~~~~~~~
Try it and good luck. You have nothing more to lose if it doesn't work for you.
 Cheers, Tom

Creating a structure, knowing the name and the type of the components

hi, following problem:
i have uploaded an excel file from a different system with the information about the names and the types of the components of several structures.
how can i create a structure with this informatin on my system?

ok, i think i have to give you some more details:
i want to update a table from a table saved on another system using a report.
(only inserts are important, no updates)
the problem is, that tables may not have the same components.
therefore i have created several excel sheets with following content (using mehtod gui_download):
name1      ; name2        ; name3....                 | name of the component
typ1         ; typ2           ; typ3 ...                     | type of the component
content11 ; content12   ; content13
content21 ; content22   ; content23
uploading the file into table <uploadtable>
now need dynamic structure: let' s say dynamicwa
name1   typ1
name2   type2
then: loop at <uploadtable> into dynamicwa.
            move-corresponding dynamicwa to destinationwa.
            insert destination_wa into destination_table.
        endloop.
but how can i create this dynamicwa?
Message was edited by: Michael
        Michael Dirndorfer

I have a 4th gen iPad and the type face on the keyboard has been replaced with small squares. How do I fix this?

I have a 4th gen iPad and the type face on the keyboard has been replaced with small squares. How do I fix this?

Try this - Reset the iPad by holding down on the Sleep and Home buttons at the same time for about 10-15 seconds until the Apple Logo appears - ignore the red slider - let go of the buttons. (This is equivalent to rebooting your computer.) No data/files will be erased. http://support.apple.com/kb/ht1430
 Cheers, Tom

XML Publisher with output type EXCEL is taking time to finish than for PDF

Hi Guru's,
I got a strange problem.
When i submit a report by choosing output format type as EXCEL, it is taking much time to complete. The same report if i choose PDF finishing in half of the time of EXCEL report. Also when we go with "view output" it is taking 4 mins to show the output. Total number of records existed are 6000 only.
Please suggest me the solutions or alternatives if any.
Thanks in advance and waiting for your response.
Regards,
Phani Reddy

it is taking much time to complete. The same report if i choose PDF finishing
in half of the time of EXCEL report. Excel is a complicated and proprietary file format. Whilst I know nothing about XML Publisher I do know that putting any sort of output into Excel format takes a long time. It's because it has to be done on a cell-by-cell basis. It's much faster to blat stuff out row-by-row.
Cheers, APC
Blog : http://radiofreetooting.blogspot.com/

XML Publisher and Application Engine in Peoplesoft

How do i write a simple application engine program for an XML Publisher report in Peoplesoft?
Thanks in advance.
Message was edited by:
user611481

Create sample output data in xml format and create a data source type rowset.
create the report defination with above data source.
Create a AE and create the rowset by using peoplecode, run the xmlp report by using PeopleCode and publish it in PeopleCode.

PROBLEM WITH XML PUBLISHER AND GRAPH NOT DISPLAYING IN ORACLE APPS

Hi
All you XML Gurus here. I have a problem, When i create a report in XML Publisher desktop i can see a graph im putting into the report on preview and works fine. But when i upload the report as a rtf file into Oracle applications i can see everything else the table logo and stuff .. But just not the Graph Itself when run on the concurrant manager....
Problem number 2
Is there a way that i can use XML Desktop and create a line graph with 2 lines rather than 1 plotting
here is my xml for graph i have made with one line
chart:
<Graph>
<Title text="" visible="true" horizontalAlignment="CENTER"/>
<LocalGridData colCount="{count(.//SELF_OTHERS)}" rowCount="1">
<RowLabels><Label></Label></RowLabels>
<ColLabels>
<xsl:for-each select=".//SELF_OTHERS"> <Label><xsl:value-of select="BEHAVIOUR"/></Label>
</xsl:for-each>
</ColLabels>
<DataValues>
<RowData>
<xsl:for-each select=".//SELF_OTHERS"> <Cell><xsl:value-of select="SCORE"/></Cell>
</xsl:for-each> </RowData>
</DataValues>
</LocalGridData>
</Graph>
All help would be much appreciated to my 2 problems....
Thanks
Sha

Hi All
Will post solution tomorrow or Monday on blog. Heres the chart XML for now.
chart:
<Graph graphType="LINE_VERT_ABS"><LegendArea visible="true" />
<LocalGridData colCount="{count(xdoxslt:group(.//SALE, 'YEAR'))}" rowCount="3">
<RowLabels>
<Label>SOFTWARE</Label>
<Label>HARDWARE</Label>
<Label>SERVICES</Label>
</RowLabels>
<ColLabels>
<xsl:for-each-group select=".//SALE" group-by="YEAR" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<Label>
<xsl:value-of select="current-group()/YEAR" />
</Label>
</xsl:for-each-group>
</ColLabels>
<DataValues>
<RowData>
<xsl:for-each-group select=".//SALE" group-by="YEAR" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<Cell>
<xsl:value-of select="sum(current-group()/SOFTWARE)" />
</Cell>
</xsl:for-each-group>
</RowData>
<RowData>
<xsl:for-each-group select=".//SALE" group-by="YEAR" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<Cell>
<xsl:value-of select="sum(current-group()/HARDWARE)" />
</Cell>
</xsl:for-each-group>
</RowData>
<RowData>
<xsl:for-each-group select=".//SALE" group-by="YEAR" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<Cell>
<xsl:value-of select="sum(current-group()/SERVICES)" />
</Cell>
</xsl:for-each-group>
</RowData>
</DataValues>
</LocalGridData>
</Graph>
with the following data
<?xml version="1.0" encoding="UTF-8"?>
<SALES>
     <SALE>
          <YEAR>2006</YEAR>
          <SOFTWARE>1200</SOFTWARE>
          <HARDWARE>850</HARDWARE>
          <SERVICES>2000</SERVICES>
     </SALE>
     <SALE>
          <YEAR>2007</YEAR>
          <SOFTWARE>1000</SOFTWARE>
          <HARDWARE>800</HARDWARE>
          <SERVICES>1100</SERVICES>
     </SALE>
     <SALE>
          <YEAR>2008</YEAR>
          <SOFTWARE>900</SOFTWARE>
          <HARDWARE>1200</HARDWARE>
          <SERVICES>1500</SERVICES>
     </SALE>
</SALES>
The latest Template Builder makes this a cinch!
Regards
Tim
http://blogs.oracle.com/xmlpublisher

XML attributes and object types

I want to create an XML Document of the following form
<family>
<parent attr1="val1">
<child attr2="val2" attr3="val3"/>
</parent>
</family>
Using object table and object type (for the child element), I am able to produce the following XML Document (with a "select * from family" query)
<family> 
<parent> 
<attr1>val1</attr1>
<child>
<attr2>val2</attr2>
<attr3>val3</attr3>
</child>
</parent>
</family>
The question is: how am I going to query these data so that the "attr" elements are mapped to attributes (using XSU only, without XSLT)?
I have already tried the following:
1. Using
SELECT attr1 as "@attr1",
f.child.attr2 "@attr2",
f.child.attr3 "@attr3"
FROM family f
all the attributes are obviously appended to the "parent" element.
2. Using nested table for "child" and the following query
SELECT attr1 as "@attr1",
CURSOR (
SELECT n.child.attr2 as "@attr2", n.child.attr3 as "@attr3"
FROM TABLE(f.child n)
) AS "child"
FROM family f
I am getting the following document
<family>
<parent attr1="val1">
<child>
<child_ROW attr2="val2" attr3="val3"/>
</child>
</parent>
</family>
Is there a smart SQL query to produce the desired document? What data types
is it recommended to use to define my db schema (object types, nested tables...)?
Thank you in advance
null

Finally, I got the desired XML format output from relational tablse using schema based XMLType views.
Wherein I created Object Types from relational table, generated the schema for the Object type, registered the schema and finally created XMLType Views for populating the XML data from Relational Tables.
I guess, you all might aware of my problem, where I got struck. Instead of printing the data in XML format I am successful in generating the XML format data Using the Query Select from BLABLA_Type_view* . I am able to print the number of rows, that I require which is in the fallowing format.
Column Name
1. SYS.XMLTYPE ----- As a row
The view I am querying for is printing the data in a string format, where in I got to do the fallowing query
SELECT SYS.XMLTYPE.getStringVal(OBJECT_VALUE) FROM BLABLA_Type_view. Which ultimately gave me the required data in XML format with tags.
Thanks for every one who tried to give a try to solve, especially "mdrake"

Question about xml schemas and the use of unqualified nested elements

Hello,
I have the following schema:
<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
    xmlns="http://xml.netbeans.org/examples/targetNS"
    targetNamespace="http://xml.netbeans.org/examples/targetNS"
    elementFormDefault="unqualified">
    <xsd:element name="name" type="xsd:string"/>
    <xsd:element name="age" type="xsd:int"/>
    <xsd:element name="person">
        <xsd:complexType>
            <xsd:sequence>
                <xsd:element ref="name"/>
                <xsd:element ref="age"/>
               <xsd:element name="height" type="xsd:int"/>
            </xsd:sequence>
        </xsd:complexType>
    </xsd:element>
</xsd:schema>I am just wondering why would someone have a nested element that is unqualified? here the "height" element.
Can anyone explain this to me please?
Thanks in advance,
Julien.
here is an instance xml document
<?xml version="1.0" encoding="UTF-8"?>
<person xmlns='http://xml.netbeans.org/examples/targetNS'
xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance'
xsi:schemaLocation='http://xml.netbeans.org/examples/targetNS file:/E:/dev/java/XML/WebApplicationXML/web/newXMLSchemaThree.xsd'>
<name>toto</name>
<age>40</age>
<height>180</height>
</person>

Don't worry about it.
There are two different styles of schemas. In one style, you define the elements, attributes, etc. at the top, and then use the "ref" form to refer to them. (I call this the "global" style.) The other style is to define elements inline where they are used. ("local" style)
Within some bounds, they work the same and which you use is a choice of you and the tools that generate the schemas.
A warning about the local style. It is possible to define an element in two different locations in the schema that are different. It will get past all schema validation, but it seems wrong to my sense of esthetics. With the global style, this will not happen.
So, how did this happen? Probably one person did the schema when it only had a name and age. Then, someone else added the height element. They either used a different tool, or preferred the other style. I'm aware of no difference in the document you have described between the two styles.
Dave Patterson

Problem to validate XML document if the type of root element is abstract

I have the following XML document:
<?xml version="1.0" encoding="UTF-8"?>
<ct013/>
It corresponds to the following XSD Schema:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
     <xs:element name="ct013" type="foo"/>
     <xs:complexType abstract="true" name="foo"/>
     <xs:complexType name="fixedType">
          <xs:complexContent>
               <xs:restriction base="foo"/>
          </xs:complexContent>
     </xs:complexType>
</xs:schema>
Please take attention to the fact that the type of root element of that BDD is abstract.
XML Schema provides a mechanism to force substitution for a particular element or type. When an element or type is declared to be "abstract", it cannot be used in an instance document. When an element is declared to be abstract, a member of that element's substitution group must appear in the instance document. When an element's corresponding type definition is declared as abstract, all instances of that element must use xsi:type to indicate a derived type that is not abstract.
Declaring an element as abstract requires the use of a substitution group. Declaring a type as abstract simply requires the use of a type derived from it (and identified by the xsi:type attribute) in the instance document.
For more information of using abstract types please see chapter 4.7 Abstract Elements and Types of XML Schema Part 0: Primer Second (http://www.w3.org/TR/xmlschema-0/#abstract).
In this case there is Oracle bug when I try to validate this XML document using Oracle XDK:
String validate(String xml, String schema)
throws XSDException, XMLParseException, SAXException, IOException
System.setPropert("oracle.xml.parser.debugmode", "true");
XSDValidator xsdValidator = new XSDValidator();
XMLError xmlError = new XMLError();
xmlError.setErrorHandler(new DocErrorHandler());
XMLDocument xmlDocument = parseXMLDocument(xml);
XMLDocument schemaXMLDocument = parseXMLDocument(schema);
XMLSchema xmlSchema = (XMLSchema) new XSDBuilder().build(schemaXMLDocument, null);
xsdValidator.setError(xmlError);
xsdValidator.setSchema(xmlSchema);
xsdValidator.validate(xmlDocument);
return getValidationError(xsdValidator);
I get the following error:
Can't find resource for bundle oracle.xml.mesg.XMLResourceBundle, key XSD-2046.
I tried to validate this XML document using two other libraries - XSD Schema Validator (http://apps.gotdotnet.com/xmltools/xsdvalidator/Default.aspx) and xsdvalid-29 (http://www.w3.org/XML/Schema#XSDValid). Both libraries pointed me on the error that the type of root element is abstract and it cannot be used for doing validation.
I think that Oracle should return me explaining message but not to throw exception.
Am I right? Is there really Oracle bug or I miss something?
Any help, hits, advices would be gratfully apriciated.

Define Element1 as follows:
<xs:element name="Element1">
<xs:complexType>
<xs:complexContent>
<xs:restriction base="xs:string"/>
</xs:complexContent>
</xs:complexType>
</xs:element>
Does the XML document get validated if the element is specified as
<Element1></Element1>

XML Publisher and the type formula

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