Xmlelement name

Question

Hi ,
i want to generate xml using xmlelement.
but the name (i.e string to be inserted as a tag) has a length more than 30.
So i am getting an error.
Can anyone suggest me how to get a tag with length more than 30 while using
XMLElement function.
Example:
1) Executes without any errors:
select distinct xmlelement("empdetails",
xmlelement("deptno",d.deptno),
(select xmlagg(xmlelement("emp",
xmlelement("012345678901234567890123456789",e.empno),
xmlelement("ename",e.ename)
from emp e
where e.deptno=d.deptno
)).extract ('/*').getStringVal() AS xml_row
from emp d;
2) This one gives the error: (length of tag for e.empno is 31)
select distinct xmlelement("empdetails",
xmlelement("deptno",d.deptno),
(select xmlagg(xmlelement("emp",
xmlelement("0123456789012345678901234567890",e.empno),
xmlelement("ename",e.ename)
from emp e
where e.deptno=d.deptno
)).extract ('/*').getStringVal() AS xml_row
from emp d
error:ORA-00972: identifier is too long
Regards,
Ravi Kumar M
Message was edited by:
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Answer 1

Any work arounds please ...
is it a limitation of xmlelement function ??