XSL file formatting

Question

XSL file formatting
Hi there.
I have problem with this files xsl, the problem is the output for the field date and number:
a) `2011-05-13T21:50:00` instead of `13/05/2001 21:50:00`
b) `.00` instead of `0`This is the output in XML:
<xml xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882" xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882" xmlns:rs="urn:schemas-microsoft-com:rowset" xmlns:z="#RowsetSchema">
     <s:Schema id="RowsetSchema">
          <s:ElementType name="row" content="eltOnly" rs:CommandTimeout="30">
               <s:AttributeType name="myDates" rs:number="6" rs:nullable="true" rs:writeunknown="true">
                    <s:datatype dt:type="dateTime" rs:dbtype="timestamp" dt:maxLength="16" rs:scale="0" rs:precision="19" rs:fixedlength="true"/>
               </s:AttributeType>
               <s:AttributeType name="Net" rs:number="29" rs:nullable="true" rs:writeunknown="true">
                    <s:datatype dt:type="number" rs:dbtype="numeric" dt:maxLength="19" rs:scale="2" rs:precision="10" rs:fixedlength="true"/>
               </s:AttributeType>
               <s:extends type="rs:rowbase"/>
          </s:ElementType>
     </s:Schema>
     <rs:data>
          <z:row myDates="2011-05-13T21:50:00" Net=".00" />
     </rs:data>
</xml>This output XML is generate with ASP code and saved in the csv format:
<!-- #include virtual="/_XML/adovbs.inc" -->
<%
filename = "titty.xml"
Set xmlDoc = CreateObject("MSXML2.DOMDocument.4.0")
Set xslDoc = CreateObject("MSXML2.DOMDocument.4.0")
%>
<%
sql = "SELECT * FROM tbl_login"
Set rs = objConn.Execute(sql)
rs.Save xmlDoc, 1
xmlDoc.Save Server.MapPath(filename)
rs.Close
Set rs = Nothing
%>
<%
Set oDOM = CreateObject("MSXML2.DOMDocument.4.0")
oDOM.async = False
oDOM.Load Server.Mappath(filename)
Set oXSL = CreateObject("MSXML2.DOMDocument.4.0")
oXSL.async = False
oXSL.Load Server.Mappath("Trasform_csv.xsl")
strTransform = oDOM.transformNode(oXSL)
Set fso = CreateObject("Scripting.FileSystemObject")
strPath = Server.Mappath("testme.csv")
Set file = fso.opentextfile(strPath, 2, True)
file.write strTransform
file.Close
Set file = Nothing
Set fso = Nothing
Set oDOM = Nothing
Set oXML = Nothing
Set oXSL = Nothing
%>The XSL file:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:s="uuid:BDC6E3F0-6DA3-11d1-A2A3-00AA00C14882"
xmlns:dt="uuid:C2F41010-65B3-11d1-A29F-00AA00C14882"
xmlns:rs="urn:schemas-microsoft-com:rowset"
xmlns:z="#RowsetSchema">
     <xsl:output omit-xml-declaration="yes"/>
     <xsl:template match="/">
          <!-- show a header by looking Schema element -->
          <xsl:for-each select="/xml/s:Schema/s:ElementType/s:AttributeType">
               <xsl:value-of select="@name"/>
               <xsl:choose>
                    <xsl:when test="position()!=last()">
                          <!-- xls -->
                         <xsl:text>     </xsl:text>
                         <!-- csv -->
                         <!--xsl:text>,</xsl:text-->
                    </xsl:when>
                    <xsl:otherwise>
                         <xsl:text>
</xsl:text>
                    </xsl:otherwise>
               </xsl:choose>
          </xsl:for-each>
          <!-- row data -->
          <xsl:for-each select="/xml/rs:data/z:row">
      <xsl:variable name="row" select="."/>
      <!-- for each column -->
               <xsl:for-each select="/xml/s:Schema/s:ElementType/s:AttributeType">
                  <!-- display each column if it exists -->
                 <xsl:variable name="columnName" select="@name"/>
                    <!-- go through all columns and display something that matches-->
                    <xsl:value-of select="$row/@*[name()=$columnName]" />
                    <!--xsl:value-of select="translate($row/@*[name()=$columnName],'.',',')" /-->
                    <xsl:if test="position()!=last()">
                        <!-- xls -->
                         <xsl:text>     </xsl:text>
                         <!-- csv -->
                         <!--xsl:text>,</xsl:text-->
                    </xsl:if>
         </xsl:for-each>
               <xsl:text>
</xsl:text>
       </xsl:for-each>
     </xsl:template>
</xsl:stylesheet>I need another output in the XML file:
<z:row myDates="13/05/2001 21:50:00" Net="0.00" />And in the CSV file:
13/05/2001 21:50:00, 0Can you help me?
Thanks in advance.
Cheers
Edited by: user6317803 on Aug 30, 2011 1:31 PM
Edited by: user6317803 on Aug 30, 2011 1:34 PM
Edited by: user6317803 on Aug 30, 2011 1:36 PM

Answer 1

Thanks for your answer, I use database MySQL.
This is the solution in the ASP code:
SELECT DATE_FORMAT(myDates, '%d/%m/%Y %H:%i:%s') myDates
         , REPLACE(NET,'.', ',') NETEdited by: user6317803 on Sep 1, 2011 9:09 AM
Edited by: user6317803 on Sep 1, 2011 9:12 AM