Xsl:include not resolving no matter HOW I load the xslt

Question

I cannot get *<xsl:include>* to work with XMLTRANSFORM in a PL/SQL environment in Oracle 11.2.0.3. I am exclusively working inside the database.
I have a base XSLT which includes another XSLT using xsl:include. I want to load the base XSLT as an XMLTYPE and have it transform another XML document, as if the entire XSLT were one large document.
I have loaded the base (base.xslt), the extension (include_with_base.xslt), and the combination of the two (entire_thing.xslt) in the XDB catalog. base.xslt has this statement inside its xsl:stylesheet node, attempting to include the other xslt:
*<xsl:include href="/public/include_with_base.xslt" />*
I have the xslts stored in XDB. This verifies they are intact:
1. The base xslt which has the xsl:include statement in it loads just fine.
select xdburitype('/public/base.xslt').getXML() from dual;
2. The extension which is the target of the include reference in the base xslt loads just fine.
select xdburitype('/public/include_with_base.xslt').getXML() from dual;
3. The combination of the two, where I cut-and-paste all children of xslt:stylesheet from include_with_base.xslt into the xslt:stylesheet node of base.xslt also loads just fine.
select xdburitype('/public/entire_thing.xslt').getXML() from dual;
However, when I try to execute a transformation of some test xml using base.xslt, it fails:
select XMLTRANSFORM(xdburitype('/public/xml_input.xml').getXML(), xdburitype('/public/base.xslt').getXML()) FROM dual;
When I try to execute the same transformation of the same test xml using entire_thing.xslt, it works:
select XMLTRANSFORM(xdburitype('/public/xml_input.xml').getXML(), xdburitype('/public/entire_thing.xslt').getXML()) FROM dual;
When I perform the transformation using altovaxml and the two xslts are in the same disk directory (and I use a relative reference with no path information rather than an absolute reference like I show in the examples above), the transformation works just fine.
What can I do to make XMLTRANSFORM work with an XSLT that has an essential <xsl:include ... /> reference in it?
Edited by: user11359697 on Apr 15, 2013 1:49 PM

Answer 1

For fun, here's an implementation of what I would call the "poor man" include.
The query takes the URI of the main stylesheet as input and recursively replaces all xsl:include directives with the content of the corresponding stylesheet.
It supports relative URIs.
Test case :
*/public/include1.xsl*
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:include href="./include2.xsl"/>
  <xsl:template name="test">
    <TEST/>
  </xsl:template>
</xsl:stylesheet>
{code}
*/public/include2.xsl*
{code:xml}
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template name="test2">
    <TEST2/>
  </xsl:template>
</xsl:stylesheet>
{code}
*/public/main.xsl*
{code:xml}
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:include href="./include1.xsl"/>
  <xsl:template match="/">
    <xsl:call-template name="test"/>
  </xsl:template>
</xsl:stylesheet>
{code}
and the query that rebuilds the complete stylesheet :
{code}
SQL> select xmlserialize(document      -- for display purpose
  2           xmlquery(
  3           'declare namespace xsl = "http://www.w3.org/1999/XSL/Transform"; (::)
  4            declare function local:include($href as xs:string) as element(xsl:stylesheet)
  5            {
  6              copy $d := fn:doc($href)/xsl:stylesheet
  7              modify (
  8                for $i in $d/xsl:include
  9                return replace node $i
10                       with local:include(resolve-uri($i/@href, $href))/child::*
11              )
12              return $d
13            }; (::)
14            local:include($main_xsl)'
15           passing '/public/main.xsl' as "main_xsl"
16           returning content
17           )
18         indent
19         )
20  from dual;
XMLSERIALIZE(DOCUMENTXMLQUERY(
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template name="test2" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <TEST2/>
  </xsl:template>
  <xsl:template name="test" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <TEST/>
  </xsl:template>
  <xsl:template match="/">
    <xsl:call-template name="test"/>
  </xsl:template>
</xsl:stylesheet>
{code}