XSL ?? value-of

Question

hi all
i need to prepare a style sheet, where my xml document looks like this ..
<dir>
<person>
<name> xyz </name>
<age> 00 </age>
</person>
<person>
<occupation> idle </occupation>
<person>
</dir>
essentially, i need to output this file in a table format using xsl. however i see that xsl has value-of select clause, but where u shud know what is the tag name.
If i am not sure of the tag names as above, does xsl still help me to output this file as a table ..
i hope i am clear
tnx

Answer 1

hi,
sorry i am in my badass day - i apologize for my harsh answer.
here is your XSL: i use HTML output because it is more relevant for building tables, but you can replace this with | - or _ if you wish...
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
     <xsl:output method="html"/>
     <xsl:template match="dir">
          <xsl:apply-templates select="person"/>
     </xsl:template>
     <xsl:template match="person">
          <p>Person:
               <table border="1">
                    <xsl:apply-templates/>
               </table>
          </p>
     </xsl:template>
     <xsl:template match="person/*">
          <tr>
               <td>
                    <xsl:value-of select="local-name(.)"/>
               </td>
               <td>
                    <xsl:value-of select="."/>
               </td>
          </tr>
     </xsl:template>
</xsl:stylesheet>