Zip ,winrar files

I get from my friends attachments paled I zip or winrar but on downloding it cannot be accessed .please let me know if there is anyway I can overcome this.

Greetings,
This may help.
http://www.notebooks.com/2010/05/11/how-to-download-and-open-zip-files-on-ipad/
Cheers,
M.

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Cannot open winrar files on ios7

Cannot open winrar files in ios7!

Natively, iOS only handles zip files (I beleive). you may need to check the app store for an app that handles winrar

Help with util.zip up files... does not work

I am writing a program so my mum can zip up new photos she takes and then send them to me. The program creates a html file for the webpage plus a smaller version of her original photo and places them all in a 1 folder with a new name. Al this part works... I want to afterwards place my files in a zipped up folder that she can e-mail me with her normal client. How... I picked up this code on the net and have changed it to incoporate my parameters. The files which are created ..paths are (String in an String[]) I then send to my zipping method.
The zip file is created but does not work when I try to extract from it ??? I also know that the String [] works becuse I have made a loop to check its properties at each index.
what am I doing wrong?
This is a modified code I found on the internet but with no author??
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.*;
public class Test{
    private File zipDir;
    private String[] filename;
    public Test(String[] recivedFilename){
        filename = recivedFilename;
        try {
            ZipOutputStream zos = new
                    ZipOutputStream(new FileOutputStream("c:\\curDir.zip"));
            from,
            zipDir("c:\\batviapictures\\", zos);
            zos.close();
        } catch(Exception e) {
            //handle exception
    public void zipDir(String dir2zip, ZipOutputStream zos) {
        try {File
            zipDir = new File(dir2zip);
            String[] dirList = filename;
            byte[] readBuffer = new byte[2156];
            int bytesIn = 0;
            //loop through dirList, and zip the files
            for(int i=0; i<dirList.length; i++) {
                File f = new File(zipDir, dirList);
if(f.isDirectory()) {
String filePath = f.getPath();
zipDir(filePath, zos);
continue;
FileInputStream fis = new FileInputStream(f);
ZipEntry anEntry = new ZipEntry(f.getPath());
zos.putNextEntry(anEntry);
while((bytesIn = fis.read(readBuffer)) != -1) {
zos.write(readBuffer, 0, bytesIn);
fis.close();
catch(Exception e) {

I make no guarantees that this will completely solve all your problems, but I just know these calls are needed but missing from your OP:
try {
    ZipOutputStream zos = new
                    ZipOutputStream(new FileOutputStream("c:\\curDir.zip"));
                    from,
                    zipDir("c:\\batviapictures\\", zos);
    zos.flush(); // ADD THIS after all files have been written to the zos
    zos.close();
} catch(Exception e) {
    //handle exception
}And
while((bytesIn = fis.read(readBuffer)) != -1) {
    zos.write(readBuffer, 0, bytesIn);
zos.closeEntry(); // ADD THIS after each file is written to the zos
fis.close();

Is it possible to zip a file and send it as an attachment in a mail?

Hi,
Is it possible to zip a file and send it as an attachment in a mail?

When you use OWA in something other than IE, you're using OWA lite and no--it is not possible to do either in OWA lite (well, new Exchange stuff makes my answer a little less emphatic but still: pretty much no). Thanks Microsoft. But this guy made it possible to mark unread/read and select all/none:
http://david-burger.blogspot.com/2008/07/firefox-greasemonkey-outlook-web-access_19.html

Wrong path when zip a file

When I try to Zip a file(backup.zip) everything is good except one thing.
When I use WinZip to unzip the file, the path for the file contains all subdirectories eg. c:\mycatalog\backup\db\data.data
I would like the path to be like: backup\db\data.data
The code:
pathName is "c:\mycatalog"
fileName is "backup"
public class Zip {
private static ZipOutputStream zos;
* Creates a Zip archive. If the name of the file passed in is a
* directory, the directory's contents will be made into a Zip file.
public static void makeZip(File pathName, String fileName)
throws IOException, FileNotFoundException
File file = new File(pathName,fileName);
zos = new ZipOutputStream(new FileOutputStream(pathName.toString()+"\\"+fileName+".lum"));
//Call recursion.
recurseFiles(file);
//We are done adding entries to the zip archive,
//so close the Zip output stream.
zos.close();
* Recurses down a directory and its subdirectories to look for
* files to add to the Zip. If the current file being looked at
* is not a directory, the method adds it to the Zip file.
private static void recurseFiles(File file)
throws IOException, FileNotFoundException
if (file.isDirectory()) {
//Create an array with all of the files and subdirectories
//of the current directory.
String[] fileNames = file.list();
if (fileNames != null) {
//Recursively add each array entry to make sure that we get
//subdirectories as well as normal files in the directory.
for (int i=0; i<fileNames.length; i++) {
recurseFiles(new File(file, fileNames));
//Otherwise, a file so add it as an entry to the Zip file.
else {
byte[] buf = new byte[1024];
int len;
//Create a new Zip entry with the file's name.
ZipEntry zipEntry = new ZipEntry(file.toString());
//Create a buffered input stream out of the file
//we're trying to add into the Zip archive.
FileInputStream fin = new FileInputStream(file);
BufferedInputStream in = new BufferedInputStream(fin);
zos.putNextEntry(zipEntry);
//Read bytes from the file and write into the Zip archive.
while ((len = in.read(buf)) >= 0) {
zos.write(buf, 0, len);
//Close the input stream.
in.close();
//Close this entry in the Zip stream.
zos.closeEntry();

Sorry, I want the path to be like: "\db\data.data"

How to zip multi files into one zip file in ABAP

hi all:
As you know, ABAP has CL_ABAP_GZIP class to support zip file function. But it only support one file zip. If I want to zip two files into one zip file, how to do it?
thanks.

Hi,
<li>If you know how to zip one file, to zip two files , you can follow the below steps.
DATA:g_zipper     TYPE REF TO cl_abap_zip.
"create our zipper object
CREATE OBJECT g_zipper.
"add 1st file to zip
CALL METHOD g_zipper->add
   EXPORTING
     name    = file_name
     content = content_x.
"add 2nd file to zip
CALL METHOD g_zipper->add
   EXPORTING
     name    = file_name
     content = content_y.
"save zip
CALL METHOD g_zipper->save
   RECEIVING
     zip = zip.
Thanks
Venkat.O

How to Zip server files(in a directory) and throwing back to client

Can someone tell me how to zip all the files in a particular directory of my web application and throwing back to client to give option for save that zipped file.
i have used the below used function to zip in servlet. But I cann't zip a particular directory of my application in server.
Please help
private void zipDir(String dir2zip, ZipOutputStream zos)
try
//create a new File object based on the directory we
// have to zip File
File fileDir2Zip = new File(dir2zip);
System.out.println("is directory ..."+fileDir2Zip.isDirectory());
//get a listing of the directory content
String[] dirList = fileDir2Zip.list();
for(int i = 0 ; i < dirList.length ; i++)
System.out.println("Dir list ..."+dirList);
byte[] readBuffer = new byte[2156];
int bytesIn = 0;
//loop through dirList, and zip the files
for(int i=0; i<dirList.length; i++)
File f = new File(fileDir2Zip, dirList[i]);
if(f.isDirectory())
//if the File object is a directory, call this
//function again to add its content recursively
String filePath = f.getPath();
zipDir(filePath, zos);
//loop again
continue;
//if we reached here, the File object f was not
//a directory
//create a FileInputStream on top of f
FileInputStream fis = new FileInputStream(f);
//create a new zip entry
ZipEntry anEntry = new ZipEntry(f.getPath());
//place the zip entry in the ZipOutputStream object
zos.putNextEntry(anEntry);
//now write the content of the file to the ZipOutputStream
while((bytesIn = fis.read(readBuffer)) != -1)
zos.write(readBuffer, 0, bytesIn);
System.out.println("Last");
//close the Stream
fis.close();
catch(Exception e)
e.printStackTrace();

Hi
Whatever file exist in directory should execute with out any condition because they delete all files after exection of my process chain. They are using another process chain once a day for deletion of all files in that directory.
So directory always contains fresh files.
Here by using routine in infopackge i am unable to run all files one by one at a time.
As of my knowledge by using infopackage we can run only one file at a time.
Here my question is , can we run more than one file in single run of infopackage?
or can we have any function module to run the infopackage from externally? so that i can use function module in abap program? any ideas..
Regards
Raju

How to Zip Excel files using File Adapter?

Hi,
We have tried to ZIP the Excel file with PayloadZipBean in File adapter. But we faced some issue while zipping.
We have seen some zunk data in excel file after zipping with PayloadZipBean. Someone please help how to zip Excel files in PI with File Adapter.
Regards,
Sreeramulu Konjeti.

Hi Sree,
If you are facing any issue with PayloadZipBean then you can use java mapping to Zip the files.
Please find the complete Java mapping code to zipt the file
http://www.sdn.sap.com/irj/scn/go/portal/prtroot/docs/library/uuid/50ce0433-4309-2b10-4bb4-d421e78463f7?quicklink=index&overridelayout=true

Operating system command to zip the file

Hi Experts,
I got proxy to file scenario, i can place the text file successfully in reciever side, i want to zip the file in reciever side using operating system command option in reciever Communication Channel.
Can anyone please give me the operating system command to create the zip file in reciever side.
Kind Regards,
Praveen.

Hi Praveen,
>>Can anyone please give me the operating system command to create the zip file in reciever side.
Why OS commands and not the PayloadZipModule?
If you need OS commands check this blog of Michal /people/michal.krawczyk2/blog/2007/02/08/xipi-command-line-sample-functions
Update
You can try this command too
cmd /C "jar cMf \\<folderpath>test1.zip \\<folderpath>*.*"
Regards
Suraj

Tablet Zip the file through the algorithm

My requirment is that I am to zip the file in xi and send to receiver using Soap Adapter. From Receiver again response will go to sender via XI. At the sender side again I want zipped file. Is it possible...
Do i need to unzip the file at receiver end to make a request.

Hi Jaideep,
Ya its possible. You can use the PayloadZipBean for the same. You can both zip and unzip the file using this bean. Use this blog for the same:
Working with the PayloadZipBean module of the XI Adapter Framework
And ya you will have to unzip the content of the file if you are to get back a response from the rceiver.
Regards,
Sanjeev.

How to zip one file i have on disk with java.util.zip

I don't know how to zip a file. I managed to do new html file, but i don't know how to zip it.
This is my code:
PrintWriter pw = new PrintWriter (new FileWriter(export), true);
Thanks!

heres a zipper class i wrote which i have butchered a bit to make more generic (its basic and at present only takes one zipentry etc, but very simple and should be easy to extend etc) Just pass it your file in its constructor and then call its zipme method. PS if it can be made better let me know so i can update my class, cheers.
import java.io.*;
import java.util.zip.*;
import java.awt.*;
class zipper
     public File file;
     public zipper(File f)
          file = new File(f);
     public void zipme()
          try
               FileInputStream fin = new FileInputStream(file);
               int a = (int)file.length();
               byte b[] = new byte[a];
               fin.read(b);
               ZipEntry k = new ZipEntry(fin.getName());//represents a single file in a zip archive!
               File newFile = new File("D:\\AZipFile.zip");
               ZipOutputStream zi = new ZipOutputStream(new FileOutputStream(newFile));
               zi.putNextEntry(k);
               zi.write(b,0,a);
               zi.close();
               fin.close();
          catch(FileNotFoundException e)
               //System.out.println("ERROR File not found");
          catch(IOException ee)
               //System.out.println("ERROR IO exception in Zipping file");
}

How to zip a file in abap

Hi folks,
plz help me out with the code to zip a file .I have a zip a file...Kindly help me out...I tried with ws_execute but unable to do ....
Regards,
Raj

Hi,
have a look at this:
abap gzip zip
https://www.sdn.sap.com/irj/sdn/wiki?path=/display/profile/gzip
Best regards.
Edited by: pablo casamayor on Mar 31, 2008 3:18 PM

Need advice about zip rar files

Here's wishing you all a very happy New Year!! Mr Greenhorn is back again! I have a question about zip and rar files. As some of you may remember, this is my first Mac, so I'm used to using the zip/rar programme on my old Windows O/S. Now I receive zip/rar files and can't open them. What is anyone's advice about downloading the zip/rar programme onto my Mac? Any particular pro's and con's? Any particular site to download from? Now my Mac has a compression programme included which converts files to zip files, but is that compatible to the actual zip/rar programme? And finally, where is the advantage to compressing files? Is it only for uploading or is there some benefit to having files 'compressed' on your actual laptop?

Hi There
Mac OS X has a built in Archive Utility which doesn't support .rar files. To uncompress rar files you will need a utility like RAR Expander or Stuffit Expander both are free. I suggest doing a search on MacUpdate (http://www.macupdate.com) or VersionTracker (http://www.versiontracker.com) to find a programme that you like.
I personally don't see any advantage with keeping compressed files on your laptop (unless the archives being used often for emailing, uploading to websites etc). Compressing files does save disk space but if you get to the point where you need to compress your files to gain disk space then I suggest buying an external HD or a bigger internal HD.
Hope this helps
J.C

How to extract ZIP/JAR files?

Hello,
How can I extract zip/jar files ?
Eric

If you are talking java, you can use the java.util.zip classes.
ZipFile, ZipEntry, ZipInputStream, ZipOutputStream
You can find lots of examples through google:
http://www.google.com/search?hl=en&q=java+zip+code+example&meta=Cheers,
evnafets

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Hello All,
is there anyway in java that i can
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thanks in advance.

Have you looked in the Java Documentation, for instance the java.util.zip package?

Zip ,winrar files

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