Filename search for import?

I have a folder of 700 images open in the import dialog.  I want to select out specific images (056, 072, 310, 078, 511, etc) that the bride has selected for editing, and make a catalog.  How do you search for a filename during import?  I don't want to scroll through and hunt for them one by one because her list is not in numerical order.

Import them, select them, and then export as catalog (file menu).
You can not create a catalog from the import dialog box.
If you don't want them in the original catalog, simply delete them. Alternatively, you could create a new catalog, then import them into the new catalog.

Similar Messages

  • In Lr 3.6 how can I search for filenames ending with a # character ?

    The text search seems to treat the # character in some mysterious way so as to not select the files that have it in their name. I cannot find any explanation for this in the documentation. Is there some other character(s) that I have to put beside the # to make it register as a normal character ?
    My specific problem is that I need to locate a bunch of files in my catalog that have names ending with a # character. I want to rename those files in a way that removes the trailing # but not other # characters that separate key parts of the file names. If I can't do that then I want to select that group of files and produce .xmp files for them (I don't normally use .xmp files) so that I can rename the files outside Lr and import them again complete with all previous tweaks and metadata.
    I dare say that I would not choose to name files this way if I started again but I've got far too many to change now. 
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    I'm using Lr 3.6 on Mac OSX 10.6.8
    cheers,
    - Alan

    You guys beat me to the answer, which I discovered more by accident than good management.
    Firstly, I had used the # characters because they looked good in list views such as in Windows Explorer or the Mac Finder. That was from before I got into using Lr and I was trying and using several different programs to manage my photos. Then I found that trailing # characters prevented Lr from recognizing the number at the "end" of the file name and so I wanted to delete them.
    Secondly, I got into the Lr rename facility initially to replace what I did with Downloader Pro before switching from Windows to Mac and subsequently found that there is no way to delete a trailing character, but it helped establish in my mind that to Lr the "filename" was just the first part of the name before the full stop and the extension (e.g. .cr2 or .nef or .jpg). Try it - there is a "filename" token for setting up a naming structure that ignores the extension and its full stop.
    This was further reinforced in Library Grid View where the filename and the extension are separated and the extension is not displayed.
    So having used F2 (rename) before I got around to playing with the text search I was set up for failure. Looking for {filename ends with #} or {filename ends with #.} failed because it found nothing as none of my files had a # or #. after the filename extension, and looking for {filename contains #} also failed because it found all of my files instead of just those with the trailing #. I wrongly thought that Lr had trouble seeing a # in the text search.
    Now I have been able to find and select all files with a trailing # in the base part of the filename by looking for {filename contains #.} and generate current .xmp files for them. Then I went outside Lr and used a utility file renamer to get rid of the offending # for the image files and the .xmp files in bulk. Then I re-synchronized the folder(s) in Lr to import those renamed files back into Lr along with all of the metadata, and get rid of the old files from the catalog. Had those files been a part of a collection or stack then I suspect that membership of the collection or stack would have been lost but it kept the keywords, ratings, labels, and image tweaks. Then I got rid of the .xmp files again because I prefer to work without them (less clutter and less chance of other software separating them from the image files).
    So much easier than doing it the hard way
    Thanks for your help.
    - Alan

  • Search for a file with part of a filename in a given folder.

    How can I search for a file with part of a filename in a given folder?
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  • How can one search for a filename anywhere on the Mac?

    How can one search for a filename anywhere or everywhere on the Mac?

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  • When importing files, my view window to search for files is really small, how do I make it bigger so I can actually search for files?

    When importing files, my view window to search for files is really small, how do I make it bigger so I can actually search for files?

    How big this is depends on the size of your screen. On a 13" it is really small. But you can improve things a bit. Click the green button to make the import window fill the screen.
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    when i search for mp3 files spotlight shows id3 tags instead of filenames as it used to do !!! I DONT want that .. how can i disable it !!!!!???????

    Sorry, my handful of mp3's had the file name as the id3 tag name.
    So, I am seeing the same thing as you.
    Oddly, a while back I was trying to help someone out in Mountain Lion that wanted to see the id3 tags in the Finder.
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  • Search for specific filename

    after AtomicParsley has tagged an MP4 file (which i have done from an applescript), it appends a random string to the end of the file, like "-temp-12345"
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  • "Searching for movie data in file [filename]" and iDVD hangs.

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    Scott

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    You'll need to reset some Preferences.

  • FTP List search for file in XI JavaMapping

    I wonder if anyone has ever done a JavaMap in XI with a FTP List search for e.g. filename*.xml
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    well, i think the best solution would be make a recursive search through the directory tree. I don't know if you are familiar to this, but the functions that searches for the file would look like this:
    public String searchFile(String name) {
      File[] roots = File.listRoots();   // List all file roots (in windows the different units, c:, d:, etc.)
      for (int i = 0 ; i < roots.length() ; i++) {
        String aux = recursiveSearch(roots, name);
    if (aux != null) {   // If the "recursiveSearch" returns something different than null is that the file is founded, so we return the path.
    return aux;
    return null; // If we get there nothing has been found
    private String recursiveSearch(File f, String name) {   // f is the directory to search for the file with name "name"
    File[] childs = f.listFiles();
    for (int i = 0 ;i < childs.length ; i++) {
    if (childs[i].isDirectory()) {  // If that is a directory we search inside
    String aux = recursiveSearch(childs[i], name);
    if (aux != null) {   // We have found it inside this directory
    return aux;
    } else {  // Is a regular file
    if (name.compareTo(childs[i].getName()) == 0) {   // If the file is what we want we return his path
    return childs[i].getCanonicalPath();
    // If we get here is because the file is not inside the directory or any subdirectory on it
    return null;
    You should just call the function searchFile(name) with the name of the file you want to search. If it finds one with this name it will return his absolute path, and if he doesn't the desired file he will return null.
    If you don't understand anything just ask.
    (Note: i have not tested this code, so can be some mistakes, but it think it is almost correct. mmmhh don't now why, but [ & ] appear in my code as < & >. Just replace them.).
    Hope that helps.
    Zerjio

  • How to search for file in a directory or subdirectories?

    I need ur help urgently. I'm currently doing a java project in which the program should be able to do file searching.
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    But the problem is that my program is only able to search in the C drive only.
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    Can you help me to solve this problem? I'm really looking forward for your reply.
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    import java.awt.*;
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         public static void main(String args[]) throws IOException
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              while(true)
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                             boolean test = false;
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    well, i think the best solution would be make a recursive search through the directory tree. I don't know if you are familiar to this, but the functions that searches for the file would look like this:
    public String searchFile(String name) {
      File[] roots = File.listRoots();   // List all file roots (in windows the different units, c:, d:, etc.)
      for (int i = 0 ; i < roots.length() ; i++) {
        String aux = recursiveSearch(roots, name);
    if (aux != null) {   // If the "recursiveSearch" returns something different than null is that the file is founded, so we return the path.
    return aux;
    return null; // If we get there nothing has been found
    private String recursiveSearch(File f, String name) {   // f is the directory to search for the file with name "name"
    File[] childs = f.listFiles();
    for (int i = 0 ;i < childs.length ; i++) {
    if (childs[i].isDirectory()) {  // If that is a directory we search inside
    String aux = recursiveSearch(childs[i], name);
    if (aux != null) {   // We have found it inside this directory
    return aux;
    } else {  // Is a regular file
    if (name.compareTo(childs[i].getName()) == 0) {   // If the file is what we want we return his path
    return childs[i].getCanonicalPath();
    // If we get here is because the file is not inside the directory or any subdirectory on it
    return null;
    You should just call the function searchFile(name) with the name of the file you want to search. If it finds one with this name it will return his absolute path, and if he doesn't the desired file he will return null.
    If you don't understand anything just ask.
    (Note: i have not tested this code, so can be some mistakes, but it think it is almost correct. mmmhh don't now why, but [ & ] appear in my code as < & >. Just replace them.).
    Hope that helps.
    Zerjio

  • How to search for particular string in array?

    I am struggling to figure out how to search array contents for a string and then delete the entry from the array if it is found.
    The code for a program that allows the user to enter up to 20 inventory items (tools) is posted below; I apologize in advance for it as I am also not having much success grasping the concept of OOP and I am certain it is does not conform although it all compiles.
    Anyway, if you can provide some assistance as to how to go about searching the array I would be most grateful. Many thanks in advance..
    // ==========================================================
    // Tool class
    // Reads user input from keyboard and writes to text file a list of entered
    // inventory items (tools)
    // ==========================================================
    import java.io.*;
    import java.text.DecimalFormat;
    public class Tool
    private String name;
    private double totalCost;
    int units;
      // int record;
       double price;
    // Constructor for Tool
    public Tool(String toolName, int unitQty, double costPrice)
          name  = toolName;
          units = unitQty;
          price = costPrice;
       public static void main( String args[] ) throws Exception
          String file = "test.txt";
          String input;
          String item;
          String addItem;
          int choice = 0;
          int recordNum = 1;
          int qty;
          double price;
          boolean valid;
          String toolName = "";
          String itemQty = "";
          String itemCost = "";
          DecimalFormat fmt = new DecimalFormat("##0.00");
          // Display menu options
          System.out.println();
          System.out.println(" 1. ENTER item(s) into inventory");
          System.out.println(" 2. DELETE item(s) from inventory");
          System.out.println(" 3. DISPLAY item(s) in inventory");
          System.out.println();
          System.out.println(" 9. QUIT program");
          System.out.println();
          System.out.println("==================================================");
          System.out.println();
          // Declare and initialize keyboard input stream
          BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
          do
             valid = false;
             try
                System.out.print(" Enter an option > ");
                input = stdin.readLine();
                choice = Integer.parseInt(input);
                System.out.println();
                valid = true;
             catch(NumberFormatException exception)
                System.out.println();
                System.out.println(" Only numbers accepted. Try again.");
          while (!valid);
          while (choice != 1 && choice != 2 && choice != 9)
                System.out.println(" Not a valid option. Try again.");
                System.out.print(" Enter an option > ");
                input = stdin.readLine();
                choice = Integer.parseInt(input);
                System.out.println();
          if (choice == 1)
             // Declare and initialize input file
             FileWriter fileName = new FileWriter(file);
             BufferedWriter bufferedWriter = new BufferedWriter(fileName);
             PrintWriter dataFile = new PrintWriter(bufferedWriter);
             do
                addItem="Y";
                   System.out.print(" Enter item #" + recordNum + " name > ");
                   toolName = stdin.readLine();
                   if (toolName.length() > 15)
                      toolName = toolName.substring(0,15); // Convert to uppercase
                   toolName = toolName.toUpperCase();
                   dataFile.print (toolName + "\t");
                   do
                      valid = false;
                      try
                         // Prompt for item quantity
                         System.out.print(" Enter item #" + recordNum + " quantity > ");
                         itemQty = stdin.readLine();
                         // Parse integer as string
                         qty = Integer.parseInt (itemQty);
                         // Write item quantity to data file
                         dataFile.print(itemQty + "\t");
                         valid=true;
                      catch(NumberFormatException exception)
                         // Throw error for all non-integer input
                         System.out.println();
                         System.out.println(" Only whole numbers please. Try again.");
                   while (!valid);
                   do
                      valid = false;
                      try
                         // Prompt for item cost
                         System.out.print(" Enter item #" + recordNum + " cost (A$) > ");
                         itemCost = stdin.readLine();
                         // Parse float as string
                         price = Double.parseDouble(itemCost);
                         // Write item cost to data file
                         dataFile.println(fmt.format(price));
                         valid = true;
                      catch(NumberFormatException exception)
                         // Throw error for all non-number input (integers
                      // allowed)
                         System.out.println();
                         System.out.println(" Only numbers please. Try again.");
                   while (!valid);
                   // Prompt to add another item
                   System.out.println();
                   System.out.print(" Add another item? Y/N > ");
                   addItem = stdin.readLine();
                   while ((!addItem.equalsIgnoreCase("Y")) && (!addItem.equalsIgnoreCase("N")))
                      // Prompt for valid input if not Y or N
                      System.out.println();
                      System.out.println(" Not a valid option. Try again.");
                      System.out.print(" Add another item? Y/N > ");
                      addItem = stdin.readLine();
                      System.out.println();
                   // Increment record number by 1
                   recordNum++;
                   if (addItem.equalsIgnoreCase("N"))
                      System.out.println();
                      System.out.println(" The output file \"" + file + "\" has been saved.");
                      System.out.println();
                      System.out.println(" Quitting program.");
            while (addItem.equalsIgnoreCase("Y"));
    // Close input file
    dataFile.close();
       if (choice == 2)
       try {
          Read user input (array search string)
          Search array
          If match found, remove entry from array
          Confirm "deletion" and display new array contents
       catch block {
    } // class
    // ==========================================================
    // ListToolDetails class
    // Reads a text file into an array and displays contents as an inventory list
    // ==========================================================
    import java.io.*;
    import java.util.StringTokenizer;
    import java.text.DecimalFormat;
    public class ListToolDetails {
       // Declare variable
       private Tool[] toolArray; // Reference to an array of objects of type Tool
       private int toolCount;
       public static void main(String args[]) throws Exception {
          String line, name, file = "test.txt";
          int units, count = 0, record = 1;
          double price, total = 0;
          DecimalFormat fmt = new DecimalFormat("##0.00");
          final int MAX = 20;
          Tool[] items = new Tool[MAX];
          System.out.println("Inventory List");
          System.out.println();
          System.out.println("REC.#" + "\t" + "ITEM" + "\t" + "QTY" + "\t"
                + "PRICE" + "\t" + "TOTAL");
          System.out.println("\t" + "\t" + "\t" + "\t" + "PRICE");
          System.out.println();
          try {
             // Read a tab-delimited text file of inventory items
             FileReader fr = new FileReader(file);
             BufferedReader inFile = new BufferedReader(fr);
             StringTokenizer tokenizer;
             while ((line = inFile.readLine()) != null) {
                tokenizer = new StringTokenizer(line, "\t");
                name = tokenizer.nextToken();
                try {
                   units = Integer.parseInt(tokenizer.nextToken());
                   price = Double.parseDouble(tokenizer.nextToken());
                   items[count++] = new Tool(name, units, price);
                   total = units * price;
                } catch (NumberFormatException exception) {
                   System.out.println("Error in input. Line ignored:");
                   System.out.println(line);
                System.out.print(" " + count + "\t");
                System.out.print(line + "\t");
                System.out.print(fmt.format(total));
                System.out.println();
             inFile.close();
          } catch (FileNotFoundException exception) {
             System.out.println("The file " + file + " was not found.");
          } catch (IOException exception) {
             System.out.println(exception);
          System.out.println();
       //  Unfinished functionality for displaying "error" message if user tries to
       //  add more than 20 tools to inventory
       public void addTool(Tool maxtools) {
          if (toolCount < toolArray.length) {
             toolArray[toolCount] = maxtools;
             toolCount += 1;
          } else {
             System.out.print("Inventory is full. Cannot add new tools.");
       // This should search inventory by string and remove/overwrite matching
       // entry with null
       public Tool getTool(int index) {
          if (index < toolCount) {
             return toolArray[index];
          } else {
             System.out
                   .println("That tool does not exist at this index location.");
             return null;
    }  // classData file contents:
    TOOL 1     1     1.21
    TOOL 2     8     3.85
    TOOL 3     35     6.92

    Ok, so you have an array of Strings. And if the string you are searching for is in the array, you need to remove it from the array.
    Is that right?
    Can you use an ArrayList<String> instead of a String[ ]?
    To find it, you would just do:
    for (String item : myArray){
       if (item.equals(searchString){
          // remove the element. Not trivial for arrays, very easy for ArrayList
    }Heck, with an arraylist you might be able to do the following:
    arrayList.remove(arrayList.indexOf(searchString));[edit]
    the above assumes you are using 1.5
    uses generics and for each loop
    [edit2]
    and kinda won't work it you have to use an array since you will need the array index to be able to remove it. See the previous post for that, then set the value in that array index to null.
    Message was edited by:
    BaltimoreJohn

  • PSE10 Crashes when searching for duplicate photos

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    System Architecture: Intel CPU Family:6 Model:5 Stepping:2 with MMX, SSE Integer, SSE FP
    Built-in Memory: 3.8GB
    Free Memory: 705.3MB
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