How to find the total no of pages in script

hi
how to find the total no of pages in script

Hi
·     &SAPSCRIPT-FORMPAGES&:
This field contains a number representing the total number of pages of the currently formatted form (any output between START_FORM and END_FORM). The page counter mode (START, INC, HOLD) of the individual pages is ignored. You can use this symbol to formulate information like
Page x of y for your output.
·     &SAPSCRIPT-JOBPAGES&:
This field contains a number representing the total number of pages of all forms contained in the currently formatted print request, in other words, of all forms created using the OPEN_FORM, START_FORM.. ENDFORM, START_FORM.. END_FORM,..., CLOSE_FORM function modules.
When using the SAPSCRIPT-FORMPAGES or SAPSCRIPT-JOBPAGES symbols, SAPscript leads all output pages of the current form or current print request into main memory to replace the symbol by the appropriate value. For large output jobs, this can mean a very large amount of memory.
·     &PAGE&, &NEXTPAGE&
This symbols are initially converted using the options specified in the form of the page definition.
Reward all helpfull answers
Regards
Pavan

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Dear friends,
I provide full details here ,my database table structure ,data and stored procedure and my problem ,
please review it and provide the solution or any idea to solve my problem.
I am working on a project in which members are added in a tree pattern, and get the payment accordingly.
below is my table structure ,data and stored procedure
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ID varchar(30) NOT NULL,
ParentID varchar(30) NULL,
IsLeft tinyint NULL,
IsRight tinyint NULL,
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go
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ID ParentID IsLeft IsRight joingdate
Ramesh123 NULL NULL NULL 2014-01-03 16:31:15.000
Sonu Ramesh123 1 NULL 2014-01-03 16:45:21.000
Pawan kumar Ramesh123 NULL 1 2014-01-04 16:50:23.000
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Vineet123 Sonu NULL 1 2014-01-04 17:26:01.000
dev123 Ravi123 1 NULL 2014-01-05 19:35:16.000
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monu Pawan kumar 1 NULL 2014-01-05 17:32:58.000
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right side of given parent node after that all pairs are completed when one node added left side and one node added right side of parent node (1:1 ratio)
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3
so there is 3 pairs as shown in my figure.
when we execute my stored procedure for ParentID 'sonu' it would return following.
EXEC count_pairs 'sonu'
2
so there is 2 pairs as shown in my figure.
My problem is to find the query which can return the total number of pair under particular node any given parent node. day to
day maximum 5 pairs in a day please any one can suggest us
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
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Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
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FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
SELECT RecursiveMember.[ID], RecursiveMember.[ParentID], RecursiveMember.[IsLeft], RecursiveMember.[IsRight], Level + 1
FROM Associate_Income RecursiveMember
INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
SELECT @ParentSUM = @ParentSUM + COUNT([ParentID])
FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
,1 AS [Value]
FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
Jitendra Kumar Sr. Software Developer at Ruvixo Technologies 7895253402

I don't think this is homework, I am not sure how helpful it was by Kalman to merge the two threads. It appears that two different persons posted the questions. It could be though, that it is the same problem and Jitendra has taken over Chandra's
task.
However, I was not able to understand the problem nor the figure. And nor the definition of pairs in this context. My assumption is that what Jitendra posted is an abstraction of the actual problem in order to not reveal intellecutal property. Possibly this
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go
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SELECT 'Arti123', 'Pawan kumar', NULL, 1, '2014-01-05 19:54:35.000'
go
CREATE proc [dbo].[count_pairs]
@ParentID nvarchar(50)
as
begin
Declare @ParentSUM SMALLINT = 0
Declare @SubLeftID nvarchar(50)
Declare @SubRightID nvarchar(50)
SELECT @SubLeftID = CASE WHEN [IsLeft] = 1 THEN [ID] ELSE @SubLeftID END
,@SubRightID = CASE WHEN [IsRight] = 1 THEN [ID] ELSE @SubRightID END
FROM Associate_Income
WHERE ParentID = @ParentID
IF @SubLeftID IS NOT NULL AND @SubRightID IS NOT NULL AND EXISTS(SELECT 1 FROM Associate_Income WHERE [IsLeft] = 1 AND ParentID = @SubLeftID)
BEGIN
SET @ParentSUM = 1
;WITH Associate_Income_CTE AS
SELECT [ID], [ParentID], [IsLeft], [IsRight], 0 AS [Level]
FROM Associate_Income
WHERE [ParentID] = @ParentID
UNION ALL
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INNER JOIN Associate_Income_CTE AnchorMember
ON RecursiveMember.[ParentID] = AnchorMember.[ID]
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FROM
SELECT [ParentID]
,'IsLeft' AS [Direction]
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FROM Associate_Income
WHERE [IsLeft] = 1
AND [ID] <> @ParentID --AND [ID] NOT IN (@SubLeftID, @ParentID)
AND [ParentID] NOT IN (@ParentID, @SubLeftID)
UNION ALL
SELECT [ParentID]
,'IsRight' AS [Direction]
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FROM Associate_Income
WHERE [IsRight] = 1
AND [ParentID] <> @ParentID
) AS Associate_Income
PIVOT
MAX([Value]) FOR [Direction] IN ([IsLeft], [IsRight])
) PVT
WHERE [IsLeft] IS NOT NULL AND [IsRight] IS NOT NULL
END
SELECT @ParentSUM
END
go
EXEC count_pairs 'Ramesh123'
go
DROP PROCEDURE count_pairs
DROP TABLE Associate_Income
Erland Sommarskog, SQL Server MVP, [email protected]

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reward points if helpful....
Message was edited by:
raam

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