JTable - programmatically setting the left column and top row

Question

I have a JTable in a JScrollPane. I would like to be able to programmatically scroll the table so that a certain column is shown as the left most column in the table, and/or a certain row is shown as the first visible row in the table.
This is to allow a user to enter a value for the column or row that the want to be on the left or top of the viewport (ie, it is up to the user how they want to move the initially see the table).
Any help would be much appreciated,
Cheers, Sean

Answer 1

Here is one way to do it:
1) use the getCellRect(row,column,false) to get a rectangle for the cell you wish to display in the upper left corner
2) use the getVisibleRect() method to get the viewport
3) set the viewport x and y coordinate to be the same as the cell x,y coordinate
4) use the scrollRectToVisible method to scroll to the desired area
For example:
Rectangle cellRect=myTable.getCellRect(5,10,false);
Rectangle vis=myTable.getVisibleRect();
vis.x=cellRect.x;
vis.y=cellRect.y;
myTable.scrollRectToVisible(vis);
Caveat: posted code has not been tested!
;o)
V.V.