Outer Join with the query

I have written the below query, our requirement is, Some employees have "Transport Allowance" but not "Project Allowance". For this, I tried to use OUTER JOIN with this query. But this query takes long time and failed. The following query works fine if the employee has both "Transport Allowance" and "Project Allowance" (without outer join) Now, I also need to retrieve the employees who have "Transport Allowance" but not "Project Allowance". How can I retrieve it?
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_types_x petf2
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entries_f peef2
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_element_entry_values_x peev2
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
,apps.pay_input_values_x pivf2
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.

I am using sames tables with alias to retrieve the columns values from the same table.
Here is my query.
SELECT DISTINCT papf.employee_number
, peev.screen_entry_value Transport_Allowance
,peev1.screen_entry_value Project_Allowance
FROM apps.per_all_people_f papf
,apps.per_all_assignments_f paaf
,apps.pay_element_types_x petf
,apps.pay_element_types_x petf1
,apps.pay_element_entries_f peef
,apps.pay_element_entries_f peef1
,apps.pay_element_entry_values_x peev
,apps.pay_element_entry_values_x peev1
,apps.pay_input_values_x pivf
,apps.pay_input_values_x pivf1
WHERE
papf.person_id = paaf.person_id
AND paaf.assignment_id = peef.assignment_id
AND paaf.assignment_id = peef1.assignment_id
AND paaf.business_group_id = papf.business_group_id
--Transport Allowance
AND peef.element_entry_id = peev.element_entry_id
AND petf.element_Name = 'Transport Allowance'
AND pivf.element_type_id =petf.element_type_id
AND pivf.name = 'Allowance'
AND peev.input_value_id= pivf.input_value_id
--Project Allowance
AND peef1.element_entry_id = peev1.element_entry_id
AND petf1.element_Name = "Project Allowance'
AND pivf1.element_type_id = petf1.element_type_id
AND pivf1.name = 'Allowance'
AND peev1.input_value_id = pivf1.input_value_id
AND (SYSDATE BETWEEN peev.effective_start_date AND peev.effective_end_date)
AND (SYSDATE BETWEEN peev1.effective_start_date AND peev1.effective_end_date)
AND (SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date)
ORDER BY papf.employee_number
Thanks in advance.

Similar Messages

Defaulting Null Values in an outer join to the last joined row's values.

I have a situation where I need to fill in the missing values from an outer join with the last values returned by the join.
The query is based on a date table, an organization table and a transaction table.
SELECT D.DATE_ID, O.ORG_ID, T.VALUE
FROM D_ORGANIZATION O, D_DATE D, F_TRANSACTION T
WHERE D.DATE_ID = T.DATE_ID(+)
AND T.ORG_ID = O.ORG_ID(+)
AND O.ORG_NAME = '&NAME'[
AND D.THE_DATE >= ADD_MONTHS( TO_DATE( '&&PERIOD_DATE', 'DD-MON-YYYY' ), -23 )
AND D.THE_DATE <= ADD_MONTHS( TO_DATE( '&&PERIOD_DATE', 'DD-MON-YYYY' ), 24 )
So the query will return all dates in the 4 year period, and where transactions exist the relevent value.
DATE_ID ORG_ID VALUE
38291     2 99.8
38321     2 45.1
38352
38383
38411
What I need to happen is:
DATE_ID ORG_ID VALUE
38291     2 99.8
38321     2 45.1
38352     2 45.1
38383 2 45.1
38411     2 45.1
Lag appears to be of no use because it will only pick up the last genuine value, so using
NVL(T.VALUE, LAG(T.VALUE,1) OVER ( .... )
Gives:
ATE_ID ORG_ID VALUE
38291     2 99.8
38321     2 45.1
38352     2 45.1
38383
38411
The length of the data gap can vary as constituent organisations don't all return their data at the same time, and there may be intermediate dates where no data is returned , but the value needs to be calculated.
What's going on here is that a gaph is being generated where the tool requires data points to plot the line, once the real data ends a bespoke trend calculations takes over based on the last value returned. I do not have access to the data warehousing options so a solution that doen't need them would be handy, but if not then options can be purchased.
The tool can't use PL/SQL, but is perhaps a bespoke function in order?

To do this wouldn't you need to know the data in advance? The real source table had 1800 organisations and 8,000,000 transactions.
I Tried this as well, creating a pl/sql package as follows.
create or replace PACKAGE stack AS
TYPE gnt_push_numbers IS TABLE OF NUMBER INDEX BY PLS_INTEGER;
TYPE gvt_push_varchars IS TABLE OF VARCHAR(1000) INDEX BY PLS_INTEGER;
gna_push_numbers gnt_push_numbers;
gva_push_varchars gvt_push_varchars;
FUNCTION PUSH ( pn_push_var NUMBER, pn_offset NUMBER) RETURN NUMBER DETERMINISTIC;
FUNCTION PUSH ( pv_push_var VARCHAR, pn_offset NUMBER) RETURN VARCHAR DETERMINISTIC;
FUNCTION POP_NUM ( pn_offset NUMBER) RETURN NUMBER DETERMINISTIC;
FUNCTION POP_VAR ( pn_offset NUMBER) RETURN VARCHAR DETERMINISTIC;
END stack;
CREATE OR REPLACE
PACKAGE BODY "STACK" AS
FUNCTION push(pn_push_var NUMBER, pn_offset NUMBER) RETURN NUMBER deterministic IS
BEGIN
gna_push_numbers(pn_offset) := pn_push_var;
RETURN pn_push_var;
END push;
FUNCTION push(pv_push_var VARCHAR, pn_offset NUMBER) RETURN VARCHAR deterministic IS
BEGIN
gva_push_varchars(pn_offset) := pv_push_var;
RETURN pv_push_var;
END push;
FUNCTION pop_num(pn_offset NUMBER) RETURN NUMBER deterministic IS
BEGIN
RETURN gna_push_numbers(pn_offset);
END pop_num;
FUNCTION pop_var(pn_offset NUMBER) RETURN VARCHAR deterministic IS
BEGIN
RETURN gva_push_varchars(pn_offset);
END pop_var;
END stack;
Unfortunately it appears to act before the rows are sorted, so will only work in specialised circumstances, in that you have to ensure the rows have been sorted before the function is used.
SELECT PUSH(COL), POP..(COL)
FROM ( SELECT etc.
Luckily the client decided they didn't want to mix their graphs any more so a more classic approach using a base table select for actuals and then a date table select with a sub-query columns for the projection provided a simple solution.

Maximum number of tables that can be outer joined with one table in a query

Hi All,
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
Thanks,
Srini

srinu2 wrote:
Iam new to sql, so can you please let me know What is the maximum number of tables that can be outer joined with one table in a query?
There is no limit to the number of tables you can outer join as long as you join them correctly.
SQL> with a as
2      (
3      select 1 id, 2 b_key, 3 c_key from dual union all
4      select 2 id, 1 b_key, 4 c_key from dual union all
5      select 3 id, 3 b_key, 1 c_key from dual union all
6      select 4 id, 4 b_key, 2 c_key from dual
7      ),
8      b as
9      (
10      select 1 id, 1 c_key2 from dual union all
11      select 2 id, 5 c_key2 from dual union all
12      select 3 id, 3 c_key2 from dual union all
13      select 4 id, 2 c_key2 from dual
14      ),
15      c as
16      (
17      select 1 key1, 1 key2, '1-1' dta from dual union all
18      select 1 key1, 2 key2, '1-2' dta from dual union all
19      select 1 key1, 3 key2, '1-3' dta from dual union all
20      select 1 key1, 4 key2, '1-4' dta from dual union all
21      select 2 key1, 1 key2, '2-1' dta from dual union all
22      select 2 key1, 2 key2, '2-2' dta from dual union all
23      select 2 key1, 3 key2, '2-3' dta from dual union all
24      select 2 key1, 4 key2, '2-4' dta from dual union all
25      select 3 key1, 1 key2, '3-1' dta from dual union all
26      select 3 key1, 2 key2, '3-2' dta from dual union all
27      select 3 key1, 3 key2, '3-3' dta from dual union all
28      select 3 key1, 4 key2, '3-4' dta from dual union all
29      select 4 key1, 1 key2, '4-1' dta from dual union all
30      select 4 key1, 2 key2, '4-2' dta from dual union all
31      select 4 key1, 3 key2, '4-3' dta from dual union all
32      select 4 key1, 4 key2, '4-4' dta from dual
33      )
34 select d.a_id, d.b_id, c.key1 as c_key1, c.key2 as c_key3, c.dta
35 from
36      c,
37      (
38      select
39          a.id as a_id, b.id as b_id, a.c_key, b.c_key2
40      from a, b
41      where a.b_key = b.id
42      ) d
43 where d.c_key = c.key1 (+)
44 and   d.c_key2 = c.key2 (+);
      A_ID       B_ID     C_KEY1     C_KEY3 DTA
         3          3          1          3 1-3
         4          4          2          2 2-2
         2          1          4          1 4-1
         1          2
SQL>

Outer join with effective date in peoplesoft query

Hi,
I'm trying to join two tables using outer join. Both tables are effective dated:
Dept_Tbl: dept_id, status, effdt
Tips_Tbl: dept_id, tips_id, effdt
Not all records in Dept_Tbl are in Tips_Tbl. I need to get all active depts and their most recent tips_id if they have one.
select a.dept_id, b.tips_id
from dept_tbl a, tips_tbl b
where a.status = 'Active'
and a.effdt =
(select max(a_ed.effdt) from dept_tbl a_ed
where a.dept_id = a_ed.dept_id
and a_ed.effdt <= SYSDATE)
and b.dept_id(+) = a.dept_id
and b.effdt =
(select max(b_ed.effdt) from tips_tbl b_ed
where b.dept_id = b_ed.dept_id
and b.tips_id = b_ed.tips_id
and b_ed.effdt <= SYSDATE)
The query only returns records that are in both tables.
Is there a way for outer join to work with effective dates?
Thanks in advance,
Reg

Here is an example of one solution. Note the use of NVL on both sides of the equal sign since both sides could be NULL in the case of the outer join
with dept_tbl as (select 1 dept_id, SYSDATE effdt FROM DUAL),
     tips_tbl as (select 1 dept_id, NULL effdt FROM DUAL)
select a.effdt
from dept_tbl a,
       tips_tbl b
where b.dept_id(+) = a.dept_id
   and NVL(b.effdt, SYSDATE) = NVL((select max(b_ed.effdt)
                                      from tips_tbl b_ed
                                     where b.dept_id = b_ed.dept_id
                                       and b_ed.effdt <= SYSDATE), SYSDATE);
EFFDT
5/7/2007 3:25:00 PM

Problem with outer join with filter on join column

Hi,
In physical layer I have one dimension and two facts, and there's an outer join between the facts.
dim_DATE ,
fact_1 ,
fact_2
Joins:
dim_DATE inner join fact_1 on dim_DATE.DATE = fact_1.DATE
fact_1 left outer join fact_2 on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
When I run a report with a date as a filter, OBIEE executes "optimized" physical SQL:
select fact1.X, fact2.Y
from
Fact_1 left outer join on fact_1.DATE = fact_2.DATE and fact_1.SOME_ID = fact_2.SOME_ID
where Fact_1.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD' )
and Fact_2.DATE = TO_DATE('2009-05-28' , 'YYYY-MM-DD')
The filter on Fact_2.DATE effectively replaces outer join with inner.
Is there a way to disable this "optimization", which is actually very good for inner joins, but doesn't allow outer joins?
Thanks in advance,
Alex
Edited by: AM_1 on Aug 11, 2009 8:20 AM

If you want to perform a Fact-based partitioning with OBIEE (two fact with the same dimension), you have to :
* create in your physical layer for each fact table the joins with the dimension
* create in the Business Model layer ONE star schema with ONE logical fact table containing the columns of your two physical fact table
In this way when you choose minimal one column of your fact1 and one column of your fact2, OBIEE will perform two query against each fact table/dimension, join them with an OUTER JOIN and your problem will disappear.
Cheers
Nico

Restriction to Left Outer Joins in PS Query

Hello I am trying to do Left Outer JOin in PS QUERY. I need to do dept tbl, job code tbl and locatable as left outer joins with JOB Table. Looks like in PS QUERY there is a error message saying as below. Can someone has any workaround to achieve this in PS QUERY. I know I can create a View and use that in PS QUERY but BUsiness Users are dependent on IT, so that doesn't work. Also, adding JOB table multiple times works but I am looking for better solution if anyone had come accorss working through PS QUERY Outer JOins.
Windows Internet Explorer
Left outer joins must be joined to the last record in the query. (139,290)
OK
Thanks,
SC.

Hi Mike,
According to your description, you want to improve the performance for your DAX query in SQL Server Analysis Service Tabular model, right? Here is a white paper describes strategies and specific techniques for getting the best performance from your tabular
models, including processing and partitioning strategies, DAX query tuning, and server tuning for specific workloads.
http://msdn.microsoft.com/en-us/library/dn393915.aspx
Since this is a complex DAX query, from a support perspective this is really beyond what we can do here in the forums. If you cannot determine your answer here or on your own, consider opening a support case with Microsoft. Visit this link to see the various
support options that are available to better meet your needs:
http://support.microsoft.com/default.aspx?id=fh;en-us;offerprophone
Regards,
Charlie Liao
TechNet Community Support

Outer Join with Where Clause in LTS

HI all,
I have a requirement like this in ANSI SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1 left outer join product_group p2 on p1.product_id = p2.product_id
and p2.product_group = 'NEW'
In Regular SQL:
select p1.product_id, p1.product_name, p2.product_group
from product p1, product_group p2
WHERE p1.product_id *= p2.product_id and p2.product_group = 'NEW'
In OBIEE, I am using a left outer join between these two in Logical table Source, and also, Gave
p2.product_group = 'NEW' in WHERE clause of LTS.
This doesn't seem to solve purpose.
Do you have any idea how to convert WHERE clause in physical query that OBIEE is generating to something like
product p1 left outer join product_group p2 on p1.product_id = p2.product_id AND p2.product_group = 'NEW'
I am using Version 10.1.3.4.1
Creating an Opaque view would be my last option though.

Hello
I have read your post and the responses as well. and I understand that you have issues with the Outer Join with where Clause in LTS.
Try this solution which worked for me (using your example ) -
1. In the Physical Layer created a Complex join between PRODUCT and PRODUCT_GROUP tables and use this join relationship :
PRODUCT.PROD_ID = PRODUCT_GROUP.PROD_ID AND PRODUCT_GROUP.GROUP_NAME = 'MECHANICAL'
2. In the General Tab of PRODUCT table LTS add PRODUCT_GROUP table and select Join Type as Left Outer Join.
3. Check Consistency and make sure there are no errors .
when you run a request you should see the following query generated -
select distinct T26908.PROD_ID as c1,
     T26908.PROD_NAME as c2,
     T26912.GROUP_NAME as c3
from
     PRODUCT T26908 left outer join PRODUCT_GROUP T26912 On T26908.PROD_ID = T26912.PROD_ID and T26912.GROUP_NAME = 'MECHANICAL'
order by c1, c2, c3
Hope this works for you. If it does please mark this response as 'Correct' .
Good Luck.

11g outer join with case statement - strange results.

Hello All,
I am experiencing a strange issues in 11g while using case statement.
I am not able to reproduce this using sample data. Not sure what is wrong.
I am not narrowing it to say the usage of case statemnt is giving wrong results, but that is my observation when I am doing trail and error testing.
Here are the details.
My Version
SQL> select * from v$version;
BANNER
Oracle Database 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
PL/SQL Release 11.2.0.2.0 - Production
CORE    11.2.0.2.0      Production
TNS for Linux: Version 11.2.0.2.0 - Production
NLSRTL Version 11.2.0.2.0 - Production
SQL> My Query
SELECT *
FROM (SELECT DISTINCT mf.schedule,
                        mf.cptcode,
                        NVL (mf.modifier, '00') modifier2,
                        CASE
                           WHEN mf.feetype = 'H'
                            AND mf.multiplier IS NOT NULL THEN
                              '      0.00'
                           WHEN (mf.feetype != 'H'
                              OR mf.feetype IS NULL)
                            AND mf.rbrvsvalue IS NOT NULL
                            AND mf.multiplier IS NOT NULL THEN
                              LPAD ( TRIM (TO_CHAR ( (mf.rbrvsvalue * mf.multiplier) / 100, 9999999.99)), 10)
                           ELSE
                              NULL
                        END
                           fee
          FROM provider.mpifee mf, mpi_udffee.udffeeactivecptcodes vld
         WHERE mf.schedule = 'SAPG1'
           AND mf.cptcode = vld.cptcode
           AND NVL (mf.modifier, 'NULL') = NVL (vld.modifier, 'NULL')) inline_fee,
       (SELECT arc.schedule col1, arc.procedurecode col2, NVL (arc.modifier, '00') AS col3
          FROM mpi_udffee.udffeeancfeedata arc
         WHERE monthofextract = '201202'
           AND arc.schedule = 'SAPG1'
           AND TRUNC (SYSDATE - 10) BETWEEN arc.recordeffectivedate AND arc.recordterminationdate) inline_data
WHERE inline_fee.schedule = inline_data.col1(+)
   AND inline_fee.cptcode = inline_data.col2(+)
   AND inline_fee.modifier2 = inline_data.col3(+);
In the above query the inline view inline_data returns zero rows. but NVL is still getting applied for col3 and I am getting 00 in the results( strange ).
Results:
SCHEDULE        CPTCO MODIFIER2 FEE             COL1 COL2 COL3
SAPG1           49590 00             667.32                  00
SAPG1           49611 00             781.03                  00
SAPG1           49905 00             443.79                  00
SAPG1           50205 00             883.56                  00
SAPG1           50220 00            1315.15                  00
SAPG1           50230 00            1638.74                  00
SAPG1           50234 00            1666.16                  00
SAPG1           50250 00            1566.14                  00
SAPG1           50327 00             262.04                  00
SAPG1           50541 00            1183.31                  00
SAPG1           50620 00            1156.88                  00
SAPG1           50650 00            1321.96                  00
497 rows selected.
Just the inline view inline_data,
SQL> SELECT arc.schedule col1, arc.procedurecode col2, NVL (arc.modifier, '00') AS col3
2            FROM mpi_udffee.udffeeancfeedata arc
3           WHERE monthofextract = '201202'
4             AND arc.schedule = 'SAPG1'
5             AND TRUNC (SYSDATE - 10) BETWEEN arc.recordeffectivedate AND arc.recordterminationdate;
no rows selectedMuch unusual thing is when I just remove the case statement from the inline view "inline_fee", I am getting right results,
SELECT *
FROM (SELECT DISTINCT mf.schedule,
                        mf.cptcode,
                        NVL (mf.modifier, '00') modifier2          <-- Removed Case statement here
          FROM provider.mpifee mf, mpi_udffee.udffeeactivecptcodes vld
         WHERE mf.schedule = 'SAPG1'
           AND mf.cptcode = vld.cptcode
           AND NVL (mf.modifier, 'NULL') = NVL (vld.modifier, 'NULL')) inline_fee,
       (SELECT arc.schedule col1, arc.procedurecode col2, NVL (arc.modifier, '00') AS col3
          FROM mpi_udffee.udffeeancfeedata arc
         WHERE monthofextract = '201202'
           AND arc.schedule = 'SAPG1'
           AND TRUNC (SYSDATE - 10) BETWEEN arc.recordeffectivedate AND arc.recordterminationdate) inline_data
WHERE inline_fee.schedule = inline_data.col1(+)
   AND inline_fee.cptcode = inline_data.col2(+)
   AND inline_fee.modifier2 = inline_data.col3(+);
SCHEDULE        CPTCO MODIFIER2 COL1 COL2 COL3
SAPG1           46730 00
SAPG1           46735 00
SAPG1           46748 00
SAPG1           46760 00
SAPG1           46942 00
SAPG1           46945 00
SAPG1           47015 00
SAPG1           47125 00
SAPG1           47350 00
SAPG1           47505 00
SAPG1           47553 00interestingly explain plan for both the statements are exactly same,
SELECT STATEMENT ALL_ROWSCost: 138 Bytes: 1,078,274 Cardinality: 11,471
     9 HASH JOIN RIGHT OUTER Cost: 138 Bytes: 1,078,274 Cardinality: 11,471
          2 PARTITION RANGE EMPTY Cost: 2 Bytes: 150 Cardinality: 3
               1 TABLE ACCESS FULL TABLE MPI_UDFFEE.UDFFEEANCFEEDATA Cost: 2 Bytes: 150 Cardinality: 3
          8 VIEW MPI_UDFFEE. Cost: 135 Bytes: 504,724 Cardinality: 11,471
               7 HASH UNIQUE Cost: 135 Bytes: 539,137 Cardinality: 11,471
                    6 HASH JOIN Cost: 134 Bytes: 539,137 Cardinality: 11,471
                         3 TABLE ACCESS FULL TABLE MPI_UDFFEE.UDFFEEACTIVECPTCODES Cost: 13 Bytes: 177,345 Cardinality: 25,335
                         5 PARTITION LIST SINGLE Cost: 120 Bytes: 600,600 Cardinality: 15,015 Partition #: 8
                              4 INDEX RANGE SCAN INDEX (UNIQUE) REPRICE.PK_MPIFEE Cost: 120 Bytes: 600,600 Cardinality: 15,015 Partition #: 9 Partitions accessed #11Is there anything wrong with the query? If not have anyone come across this issue or posted it as a bug or is there a patch?
Update:
when I set the parameter "_complex_view_merging"=false I am getting the right results even with case statement. But I don want to do some thing unsupported.
Are there any other viable solutions?
I appreciate the help.
Thanks,
G.
Edited by: Ganesh Srivatsav on Apr 10, 2012 12:37 PM

Hi Tubby,
Right, the query transformation is going wrong. Following is from trace,
SELECT "INLINE_FEE"."SCHEDULE" "SCHEDULE",
       "INLINE_FEE"."CPTCODE" "CPTCODE",
       "INLINE_FEE"."MODIFIER2" "MODIFIER2",
       "INLINE_FEE"."FEE" "FEE",
       "ARC"."SCHEDULE" "COL1",
       "ARC"."PROCEDURECODE" "COL2",
       CASE
          WHEN "ARC".ROWID IS NOT NULL THEN NVL ("ARC"."MODIFIER", '00')
          ELSE NULL
       END
          "COL3"
FROM (SELECT DISTINCT "MF"."SCHEDULE" "SCHEDULE",
                        "MF"."CPTCODE" "CPTCODE",
                        NVL ("MF"."MODIFIER", :B2) "MODIFIER2",
                        CASE
                           WHEN ("MF"."FEETYPE" = :B3
                             AND "MF"."MULTIPLIER" IS NOT NULL) THEN
                              :B4
                           WHEN ( ("MF"."FEETYPE" <> :B5
                                OR "MF"."FEETYPE" IS NULL)
                             AND "MF"."RBRVSVALUE" IS NOT NULL
                             AND "MF"."MULTIPLIER" IS NOT NULL) THEN
                              LPAD ( TRIM (TO_CHAR ( "MF"."RBRVSVALUE" * "MF"."MULTIPLIER" / :B6, :B7)), :B8)
                           ELSE
                              NULL
                        END
                           "FEE"
          FROM "PROVIDER"."MPIFEE" "MF", "MPI_UDFFEE"."UDFFEEACTIVECPTCODES" "VLD"
         WHERE "MF"."SCHEDULE" = 'SAPG1'
           AND "MF"."CPTCODE" = "VLD"."CPTCODE"
           AND NVL ("MF"."MODIFIER", 'NULL') = NVL ("VLD"."MODIFIER", 'NULL')) "INLINE_FEE",
       "MPI_UDFFEE"."UDFFEEANCFEEDATA" "ARC"
WHERE "INLINE_FEE"."SCHEDULE" = "ARC"."SCHEDULE"(+)
   AND "INLINE_FEE"."CPTCODE" = "ARC"."PROCEDURECODE"(+)
   AND "INLINE_FEE"."MODIFIER2" = CASE
                                     WHEN ("ARC".ROWID(+) IS NOT NULL) THEN NVL ("ARC"."MODIFIER"(+), '00')
                                     ELSE NULL
                                  END
   AND "ARC"."MONTHOFEXTRACT"(+) = '201202'
   AND "ARC"."SCHEDULE"(+) = 'SAPG1'
   AND TRUNC (SYSDATE-10) >= "ARC"."RECORDEFFECTIVEDATE"(+)
   AND TRUNC (SYSDATE-10) <= "ARC"."RECORDTERMINATIONDATE"(+)Does this refer to a specific bug?
Thanks,
G.

Outer join With a constant value

Hi all,
In one of query i have found out that the outer join with a constant value like
to_currency(+)='USD'
to_currency is a column name in a table.can any one please explain this outer join condtn.
Thanks in advance
Senthil

Hallo,
if you write var (+) = constant
var can be equal constant, and also can be null
Compare these 2 queries
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno(+) = 10EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7369     SMITH      CLERK      7902     17-Dez-1980     800          20
7499     ALLEN      SALESMAN      7698     20-Feb-1981     1600     300     30
7521     WARD      SALESMAN      7698     22-Feb-1981     1250     500     30
7566     JONES      MANAGER      7839     2-Apr-1981     2975          20
7654     MARTIN      SALESMAN      7698     28-Sep-1981     1250     1400     30
7698     BLAKE      MANAGER      7839     1-Mai-1981     2850          30
7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
7788     SCOTT      ANALYST      7566     19-Apr-1987     3000          20
7839     KING      PRESIDENT           17-Nov-1981     5000          10
7844     TURNER      SALESMAN      7698     8-Sep-1981     1500     0     30
7876     ADAMS      CLERK      7788     23-Mai-1987     1100          20
7900     JAMES      CLERK      7698     3-Dez-1981     950          30
7902     FORD      ANALYST      7566     3-Dez-1981     3000          20
7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
select e.* from scott.emp e, scott.dept d
where e.deptno = d.deptno(+)
and d.deptno = 10 EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7782     CLARK      MANAGER      7839     9-Jun-1981     2450          10
7839     KING      PRESIDENT           17-Nov-1981     5000          10
7934     MILLER      CLERK      7782     23-Jan-1982     1300          10
As you can see, this (+) is very important
Regards
Dmytro

Outer Join with an 'OR'

I have a very complicated query to construct that requires the use of 'AND', 'OR', and Outer Joins. Oracle's 9i documentation says you can't use an outer join with an 'OR'.
Can you suggest how I may return the correct records under the following conditions. There are 3 tables to join. Table A, Table B, and Table C. Tables A & B join with an = to common fields. The problem is with Table C.
The way the application was designed, it has to track a parent and child relationship. As such, the field to relate may exist in 1 of 2 fields. Let's see if I can draw it out for you.
Table A - Record 1
(ID = 1)
Table B - Record 1
(ID =1 [this relates to Table A.ID]
PID = 12345
CID = 67899
Site = A)
Table C - Record 1
(PID = 12345 [this relates to Table B.PID]
CID = 67899
Site = A)
Table C - Record 2
(PID = 67899 [This relates to Table B.CID]
CID = 12345
Site = A)
Now, I need to relate Table A to Table B where A.ID = B.ID AND
((B.PID = C.PID AND B.CID = C.CID)
OR
(B.CID = C.PID AND B.PID = C.CID))
AND
B.SITE = C.SITE
There may or may NOT be related records in Table C. That's the problem. This is where I need the outer join to get the all the records of the 1st two joins and only those that apply from the last join.
Your help will be greatly appreciated.

I'd create two queries, a join from b to c in each of those manners and then UNION ALL the results together.
drop table junk_a;
create table junk_a (
id number );
drop table junk_b;
create table junk_b (
id number,
pid number,
cid number,
site varchar2(80) );
drop table junk_c;
create table junk_c (
pid number,
cid number,
site varchar2(80) );
insert into junk_a values (1);
insert into junk_b values (1, 12345, 67899, 'A');
insert into junk_c values (12345, 67899, 'A');
insert into junk_c values (67899, 12345, 'A');
commit;
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid;
SELECT a.id,
       bc.pid,
       bc.cid,
       bc.site,
       bc.site_c
FROM junk_a a,
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.pid(+) = b.pid
   AND c.cid(+) = b.cid
UNION ALL
SELECT b.*,
       c.site AS site_c
FROM junk_b b,
       junk_c c
WHERE c.cid(+) = b.pid
   AND c.pid(+) = b.cid
       ) bc
WHERE bc.id(+) = a.id;

Outer join with BETWEEN clause

Hi All,
I have 2 tables (A and B) which i need to join. I need all records from table A and matching records from the table B. below is the structure.
TABLE A (total rows = 10)
ROW_WID
GL_DATE
LOCATION_CODE
TABLE B (total = 7)
ROW_WID
START_DATE
END_DATE
LOCATION_CODE
Initially, we were asked to join based on location_code. In the table B, some of the LOCATION_CODE are missing, which is present in table A.
We wrote below query
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
This gives 10 records, where 3 records have START_DATE and END_DATE NULL. because of outer join
It gave all records from the A table. It worked fine. Now i need to add one more condition where A.GL_DATE between B.START_DATE and B.END_DATE
If i write this
SELECT A.*, B.START_DATE, B.END_DATE
FROM A, B
WHERE A.LOCATION_CODE = B.LOCATION_CODE (+)
AND A.GL_DATE BETWEEN B.START_DATE and B.END_DATE
This gives me only 7 records. IS IT POSSIBLE TO ADD OUTER JOIN with BETWEEN clause.

Hi All,
I'm in a similar situation,
I have a complex query, everything is working fine, except this part (I will simplify everything, removing other stuffs because I need help only on the following condition)
SELECT *
from transaction t, card c
where c.card_id = t.card_id (+)
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') and ('01/01/2013,'dd/mm/yy')
How could i OUTER JOIN the between condition?
I tried with
and t.trn_date between to_date ('01/01/2012','dd/mm/yy') (+) and ('01/01/2013','dd/mm/yy') (+)
but returns a "missing expression" error.
Surely I'm missing some stupid thing about it, could you help me on this? (probably because I'm talking about parameters and I cannot put the outer join on a value)
How can I rewrite the condition in order to satisfy what I'm trying to accomplish?
Thanks in Advance,
Alex
Edited by: 981667 on 14-gen-2013 4.23
Edited by: 981667 on 14-gen-2013 4.24

How to achieve an outer join with existsNode() function

I have a requirement to do an outer join with existsNode() function in my where clause. At present my where clause for join is like below
WHERE A.SOME_ID= “XYZ”
AND existsNode (B.SOMEXML_FEILD , …. ) = 1
AND existsNode (C.SOMEOTHERXML_FEILD , …. ) = 1
In this case if the existsNode fails on B or C, I still want data from A to be selected. How to rewrite this query to achieve that? I kinda want to achieve an outer join

Hi,
is this what you are looking for:
SQL> with t as(select 1 id1,'A' name from dual union all
2            select 2 ,'B' name from dual union all
3            select 3,'C' from dual)
4      ,x as(select 1 id2,xmltype('<a>a</a>') xcol from dual union all
5            select 2 ,xmltype('<b>b</b>') xcol from dual)
6 select *
7 from t,x
8 where t.id1=x.id2(+)
9    and (existsNode(x.xcol,'/a')=1 or x.xcol is null);
       ID1 N        ID2 XCOL
         1 A          1 <a>a</a>
         3 C
SQL> spool off;

Case statement resulting into Left outer join with other tables

Hi All ,
I am facing a stuation where a Case statement on one of the logical columns in Answers is resulting into a left outer join with a table in the query.
If we remove the case stmt, the table is not being acessed.
The case stmt is a simple one and no other logical column is being accessed in the case stmt.
Please advice .
Thanks.

Hi Sai,
No ..we dont have any left outer join ...its just that I am selecting measure from F1 which has a confimred dimension D1 with F2.Now when I dont have case stmt on measure from F1(Case stmt is something like : CASE WHEN "- P table"."P Column" = 'Y' THEN 'Right' ELSE 'Wrong' END), then it doesnt query F2.
However as soon as I introduce the case stmt ,the query creates a left outer join with F2.
Thanks.

Content Tab: None of the fact tables are compatible with the query request

Hi All,
**One thing I am not clear yet of all my years with OBIEE is working with the content tab in BMM.**
I have made a rpd the joins in physical layer as shown below:
https://picasaweb.google.com/114804305606242416264/OBIEEError#5663056545119428530
And the BMM layer as:
https://picasaweb.google.com/114804305606242416264/OBIEEError#5663056519553812930
Error I am getting when i run a request from the 3 columns from the selected 3 tables is:
Dim - Comment Code Details
Fact - Complaint
Dim - Service Details
Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 14020] None of the fact tables are compatible with the query request Sr Num:[DAggr(Fact - Complaint.Sr Num by [ Dim - Service Details.Sr Cat Type Cd, Dim - Comment Code Details.Cmtcode name] )]. (HY000).
I get no error for consistency.. I read everywhere and I know i need to set the appropriate aggregation levels in the various dims and facts LTS properties to help OBIEE understanding our model, but how to do that.. how do i decide... how should I approach, what should be the aggregation level, what details.
When i click More button i see different options: Copy, Copy From, Get Levels, Check Level, what do these mean.
Aggregation Content, group by - Logical Level or Column which one should i choose and how should I decide.
Can anyone explain the Content Tab in details and from scratch with some example and why we get these errors.... I know many people who are well versed with many other things related to RPD but this. A little efforts of explaining from you guys will really be appreciated.
Thanks in advance,
Dev

Hi Deepak,
Option 1:
My tables in physical layer are joined as below:
D1--> F1 <--D2--> F2 <--D3
Same way i model it in BMM
D1--> F1 <-- D2--> F2 <--D3
Here D1 is non Conformed Dimension for F2 and D3 is non Conformed dim for F1. Later create Dimensional hierarchies, I tried setting up the content levels
I go Sources>content tab of Fact F1 I set
Dimensions----------- Logical level
D1---------------------- D1 Detail
D2---------------------- D2 Detail
D3---------------------- D3 Total
then, I go Sources>content tab of Fact F2 I set
Dimensions----------- Logical level
D1---------------------- D1 Total
D2---------------------- D2 Detail
D3---------------------- D3 Detail
Then, I also go in all the dimensions and set their content levels to Details, but it still gives me errors not sure where I am going wrong in setting the content levels.
I need to know whether the way I have modeled it in BMM is right,
Option 2:
I can combine the two facts in a single Logical Fact or the above design should also work.
(F1&F2)<--D1, D2 , D3 joined separately using complex logical joins.
what will be the content tab details?
Thanks,
Dev

SSMS 2012:XQuery-doing "Retriving Job Candidates with the query Method" in AdventuresWorks 2012. Unclosed quotation mark after string '//*:Name.First?

Hi all,
From Page 354 of the the Book "Pro T-SQL 2008 Programmer's Guide" written by Michael Coles (published by apress), I copied the following code (Listing 12-9 Retrieving Job Candidates with the query Method):
--Coles12_9.sql // saved in C:/Documemnts/SQL Server Management Studio
-- Coles Listing 12-9 Retrieving Job Candidates with the query Method
-- Doing XQuery and the xml Data Type in AdvantureWorks
-- 17 March 2015 1105 AM
USE AdventureWorks;
GO
SELECT Resume.query
N'//*:Name.First,
//*:Name.Middle,
//*:Name.Last,
//*:Edu.Level
FROM HumanResources.JobCandidate;
I executed this set of Listing 12-9 code in my SQL Server 2012 Management Studio and I got the following error messages:
Msg 105, Level 15, State 1, Line 4
Unclosed quotation mark after the character string '//*:Name.First,
//*:Name.Middle,
//*:Name.Last,
//*:Edu.Level
FROM HumanResources.JobCandidate;
Msg 102, Level 15, State 1, Line 4
Incorrect syntax near '//*:Name.First,
//*:Name.Middle,
//*:Name.Last,
//*:Edu.Level
FROM HumanResources.JobCandidate;
I am not able to figure out why I got the error messages. Please kindly help and advise me how to correct this set of sql codes.
Thanks in advance,
Scott Chang

Hi Scott,
I don't have that book at hand, but your problem is the "Unclosed quotationmark after the character string",as the error message shows. You have to enclose the 'XQUERY' string quotation in the
query().
SELECT jobcandidateid, Resume.query
N'//*:resume,
//*:Name.Middle,
//*:Name.Last,
//*:Edu.Level' --enclose the quotation here
FROM HumanResources.JobCandidate;
For XQUERY learning, here is a good
link.
If you have any question, feel free to let me know.
Eric Zhang
TechNet Community Support

Outer Join with the query

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