5.6.1 Unary Numeric Promotion

Question

can anyone explain why 5.6.1 is written so differently to 5.6.2? is this an equivalent simpler formulation of 5.6.1, or have i missed something?
...type:
* If the operand is of a reference type, unboxing conversion is performed. Then:
* If the operand is of compile-time type byte, short, or char, unary numeric promotion...
here's 5.6.1 and 5.6.2 from adding_generics-2_4ea:
5.6.1 Unary Numeric Promotion
Some operators apply unary numeric promotion to a single operand, which must produce a value of a numeric type:
* If the operand is of compile-time type Byte, Short, Character, or Integer it is subjected to unboxing conversion. The result is then promoted to a value of type int by a widening conversion (?5.1.2) or an identity conversion.
* Otherwise, if the operand is of compile-time type Long, Float, or Double it is subjected to unboxing conversion.
* Otherwise, if the operand is of compile-time type byte, short, or char, unary numeric promotion promotes it to a value of type int by a widening conversion (?5.1.2).
* Otherwise, a unary numeric operand remains as is and is not converted.
In any case, value set conversion (?5.1.8) is then applied.
5.6.2 Binary Numeric Promotion
When an operator applies binary numeric promotion to a pair of operands, each of which must denote a value of a numeric type, the following rules apply, in order, using widening conversion (?5.1.2) to convert operands as necessary:
* If any of the operands is of a reference type, unboxing conversion is performed. Then:
* If either operand is of type double, the other is converted to double.
* Otherwise, if either operand is of type float, the other is converted to float.
* Otherwise, if either operand is of type long, the other is converted to long.
* Otherwise, both operands are converted to type int.
After the type conversion, if any, value set conversion (?5.1.8) is applied to each operand.

Answer 1

5.6.1 operates on two types, 50602 operates on one type.