A simple web server !!! Help needed ...
Well, I was trying to create a simple web server. It just accept a request from a browser and send a response.
But I just cannot send the response to the browser. I am able to receive the request from the browser. Can anyone give me a clue what is wrong or what i have to do in order to send response to the browser? I am really puzzled !!!
Here is the code
=============
package service;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Listener implements Runnable {
private InputStream is;
private OutputStream os = null;
boolean connected = false;
ServerSocket server=null;
Socket client=null;
public Listener() throws SocketException, IOException {
server = new ServerSocket(2772);
client = server.accept();
System.out.println("Connected to :" + client.getInetAddress().getHostAddress() + " @" + client.getPort());
is = client.getInputStream();
os = client.getOutputStream();
Thread t = new Thread(this);
t.start();
public void run() {
String b = "";
while(true) {
try {
int c = is.read();
if (c!=-1) {
b +=(char)c;
System.out.print((char)c);
} else {
System.out.println(b);
break;
//System.out.println(b);
if (b.contains("keep-alive") && !connected) {
connected = true;
System.out.println("request recieved sending response");
String lineSep = System.clearProperty("line.separator");
String data = "<html><head><title>URA DHURA</title></head><body>HHH</body></html>";
String res = "HTTP/1.1 200 OK" + lineSep + "Connection: close" + lineSep + "Date: Thu, 06 Aug 1998 12:00:15 GMT" + lineSep;
res = res + "Server: WebApplication" + lineSep + "Last-Modified: Mon, 22 Jun 1998 09:23:24 GMT" + lineSep + "Content-Length: " + (data.length()-1) + lineSep;
res = res + "Content-Type: text/html;" + lineSep + data;
System.out.println("<" + res + ">");
os.write(res.getBytes());
os.close();
// Thread.sleep();
} catch (IOException ex) {
Logger.getLogger(Listener.class.getName()).log(Level.SEVERE, null, ex);
=======
When ever i entered the url from the browser i get this output :
OUTPUT
======
Connected to :127.0.0.1 @2143
GET / HTTP/1.1
Host: localhost:2772
User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; bn-BD; rv:1.9.1.1) Gecko/20090715 Firefox/3.5.1
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip,deflate
Accept-Charset: UTF-8,*
Keep-Alive: 300
Connection: keep-aliverequest recieved sending response
<HTTP/1.1 200 OK
Connection: close
Date: Thu, 06 Aug 1998 12:00:15 GMT
Server: WebApplication
Last-Modified: Mon, 22 Jun 1998 09:23:24 GMT
Content-Length: 65
Content-Type: text/html;
<html><head><title>URA DHURA</title></head><body>HHH</body></html>>
===========
Can any one give a clue???
Thanks.
Well, I was trying to create a simple web server. It just accept a request from a browser and send a response.
But I just cannot send the response to the browser. I am able to receive the request from the browser. Can anyone give me a clue what is wrong or what i have to do in order to send response to the browser? I am really puzzled !!!
Here is the code
=============
package service;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.net.ServerSocket;
import java.net.Socket;
import java.net.SocketException;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Listener implements Runnable {
private InputStream is;
private OutputStream os = null;
boolean connected = false;
ServerSocket server=null;
Socket client=null;
public Listener() throws SocketException, IOException {
server = new ServerSocket(2772);
client = server.accept();
System.out.println("Connected to :" client.getInetAddress().getHostAddress() " @" client.getPort());
is = client.getInputStream();
os = client.getOutputStream();
Thread t = new Thread(this);
t.start();
public void run() {
String b = "";
while(true) {
try {
int c = is.read();
if (c!=-1) {
b =(char)c;
System.out.print((char)c);
} else {
System.out.println(b);
break;
//System.out.println(b);
if (b.contains("keep-alive") && !connected) {
connected = true;
System.out.println("request recieved sending response");
String lineSep = System.clearProperty("line.separator");
String data = "<html><head><title>URA DHURA</title></head><body>HHH</body></html>";
String res = "HTTP/1.1 200 OK" lineSep "Connection: close" lineSep "Date: Thu, 06 Aug 1998 12:00:15 GMT" lineSep;
res = res "Server: WebApplication" lineSep "Last-Modified: Mon, 22 Jun 1998 09:23:24 GMT" lineSep "Content-Length: " (data.length()-1) lineSep;
res = res "Content-Type: text/html;" lineSep + data;
System.out.println("<">");
os.write(res.getBytes());
os.close();
// Thread.sleep();
} catch (IOException ex) {
Logger.getLogger(Listener.class.getName()).log(Level.SEVERE, null, ex);
{code}
=======
When ever i entered the url from the browser i get this output :
OUTPUT
======
Connected to :127.0.0.1 @2143
GET / HTTP/1.1
Host: localhost:2772
User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; bn-BD; rv:1.9.1.1) Gecko/20090715 Firefox/3.5.1
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,/;q=0.8
Accept-Language: en-us,en;q=0.5
Accept-Encoding: gzip,deflate
Accept-Charset: UTF-8,*
Keep-Alive: 300
Connection: keep-aliverequest recieved sending response
<HTTP/1.1 200 OK
Connection: close
Date: Thu, 06 Aug 1998 12:00:15 GMT
Server: WebApplication
Last-Modified: Mon, 22 Jun 1998 09:23:24 GMT
Content-Length: 65
Content-Type: text/html;
<html><head><title>URA DHURA</title></head><body>HHH</body></html>>
===========
Hello endasil,
Actually I got a sudden idea of developing a web application which allows the content to be accessed from a web browser. Its user interface will be accessible through browser. Of course you can say I could use PHP, JSP as the frontend and at the back end USE the application.
But I just want to explore and learn.
Any way,
Thank you for your reply.
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Dear Community!
I would like to use a Cisco router as simple web-server hosting an automatic proxy configuration script file. Is is possible to configure HTTP AAA to allow access without username / password authentication?
See the test configuration below:
aaa new-model
aaa authentication login CISCO_HTTP_AUTH none
aaa authorization exec CISCO_HTTP_AUTH none
aaa authorization commands 15 CISCO_HTTP_AUTH none
access-list 99 permit host [***Host IP***]
ip http server
ip http access-class 99
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ip http authentication aaa command-authorization 15 CISCO_HTTP_AUTH
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Router#dir
Directory of flash:/
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33030140 bytes total (10170568 bytes free)
Router#
Thanks in advance!
Regards
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Based on my limited knowledge I would think that is it.
But then on that same server when I enter the domain name into safari it just goes out and does a google search on the name. Clearly the linkage is not being made.
Safari works for surfing, so it appears the basic network settings work.
When I go to 10.0.1.255 I get the Welcome to OS X Server page.
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> Now, I don't want to put the news text in
> the html code. Rather, I'd like the code to somehow take
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overwrite on the host
> server so that changes are seen in browsers.
You can do this with a server-side include. The first thing
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http://foundationphp.com/ -
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PowerBook G4 17" Mac OS X (10.4.8) G4 Xserve 1GHz, 1.5GB RAM, 10.3.9 ServerThey've never heard of a G4? That's shocking, perhaps you shouldn't go there anymore :P.
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I am bit new to BI Publisher,I have done plenty of Oracle reports 6i and 10g.
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Sysdate Sysdate Sysdate
16-Oct-08 16-Oct-08 16-Oct-08
step 1) I will write the following query in the Data Model and store/save it.
select sysdate ,sysdate,sysdate from dual.
Step 2) In the layout model I want to use .rtf layout .So in the MS word .rdf document I create /insert
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SunnyI added a useless parameter just so you could see where parms should go...
Datatemplate:
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<properties>
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</parameters>
<dataQuery>
<sqlStatement name="QUERYNAME">
<![CDATA[
select sysdate SYSDATE1
, sysdate SYSDATE2
, sysdate SYSDATE3
from dual
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]]>
</sqlStatement>
</dataQuery>
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<element name="SYSDATE1" dataType="varchar2" value="SYSDATE1"/>
<element name="SYSDATE2" dataType="varchar2" value="SYSDATE2"/>
<element name="SYSDATE3" dataType="varchar2" value="SYSDATE3"/>
</group>
</dataStructure>
<dataTrigger name="afterReportTrigger" source="A_SIMPLE_REPORT.afterreport()"/>
</dataTemplate>
XML OUPUT:
<?xml version="1.0" encoding="UTF-8" ?>
<A_SIMPLE_REPORT>
<LIST_G_UPPERGROUP>
<G_UPPERGROUP>
<SYSDATE1>2008-10-16T18:20:19.000-05:00</SYSDATE1>
<SYSDATE2>2008-10-16T18:20:19.000-05:00</SYSDATE2>
<SYSDATE3>2008-10-16T18:20:19.000-05:00</SYSDATE3>
</G_UPPERGROUP>
</LIST_G_UPPERGROUP>
</A_SIMPLE_REPORT>
Hope this helps,
Scott
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Problem with clustering with JBoss server---help needed
Hi,
Its a HUMBLE REQUEST TO THE EXPERIENCED persons.
I am new to clustering. My objective is to attain clustering with load balencing and/or Failover in JBoss server. I have two JBoss servers running in two diffferent IP addresses which form my cluster. I could succesfully perform farm (all/farm) deployment
in my cluster.
I do believe that if clustering is enabled; and if one of the server(s1) goes down, then the other(s2) will serve the requests coming to s1. Am i correct? Or is that true only in the case of "Failover clustering". If it is correct, what are all the things i have to do to achieve it?
As i am new to the topic, can any one explain me how a simple application (say getting a value from a user and storing it in the database--assume every is there in a WAR file), can be deployed with load balencing and failover support rather than going in to clustering EJB or anything difficult to understand.
Kindly help me in this mattter. Atleast give me some hints and i ll learn from that.Becoz i could n't find a step by step procedure explaining which configuration files are to be changed to achieve this (and how) for achiving this. Also i could n't find Books explaining this rather than usual theorectical concepts.
Thanking you in advance
with respect
abhiramihi ,
In this scenario u can use the load balancer instead of fail over clustering .
I would suggest u to create apache proxy for redirect the request for many jboss instance.
Rgds
kathir
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How to handle help function type in a dynpro
Hello I've made a button with the functiontype H ( Help Function) and now I'd like to react on this button. But in the POV AND POH I can't call a module, because for this I need an input-/outputfield. (FIELD "FIELDNAME" MODULE "MODULENAME"). My quest
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Can't edit masks or shapes after creation..?
I have no idea why... it used to work fine. When I make a mask, and finish connecting it, I can't edit it afterwards...I can't select anything, any of the corners, I can move it around but that's about it. Yes I'm using the right tool, and I have han
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Where are the iBooks bookmark stored ?
Well I had like to know where they are stored ? in your mobileme accounts ? In you itunes account ? Where ?