Accessing Parent Node of an XML through XSLT

Hi,
I want to loop at the child node and need to find out its parent node.
Kindly let me know how to traverse back using XSLT.
sample source structure:
<level1>
 <level2>
 <level 3>
 <part number> 123 </part number>
 </level3>
 <level3>
 <part number> 1 </part number>
 </part number> 2 </part number>
 </level3>
 </level2>
</level1>
target:
<group>
 <part Number> 123 </part number>
 <level3> </level3>
 <level2> </level2>
 <level1> </level1>
</group>
<group>
 <part Number> 1</part number>
 <level3> </level3>
 <level2> </level2>
 <level1> </level1>
</group>
<part Number> 2 </part number>
 <level3> </level3>
 <level2> </level2>
 <level1> </level1>
</group>
Kindly let me know how to traverse back by looping at the part number.
Regards,
Swaroopa

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package com.ibn.util;
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import java.net.MalformedURLException;
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thanks dude.
Did it the following was as i wanted to read the transformation output as well.
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    ByteArrayOutputStream result = new ByteArrayOutputStream();
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/people/jin.shin/blog/2006/02/07/multi-mapping-without-bpm--yes-it146s-possible
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Hi guys i am experiencing a slight problem with the creation of trees.Here is a clear explanation of my program.I created a program that generates edges from a set of datapoints then use each and every edge that is generated to create multiple trees with the edge as the rootnode for each and every tree.Everything up to so far everything went well but the problem comes when i want the program to pick every single tree and traverse through the set of generated edges to create the children of a tree.What it does at the moment for each tree is returning the a duplication of the parent node as the child nodes and that is a problem.Can anyone related with this problem help.Your help will be appreciated.
The code
TreeNode class
package SPO;
import java.util.*;
public class TreeNode
 Edge edge;
 TreeNode node;
 Vector childrens = new Vector();
 public TreeNode(Edge edge)
 this.edge = edge;
 public synchronized void insert(Edge edge)
 if(edge.fromNode == this.edge.toNode)
 if(node == null )
 node = new TreeNode(edge);
 childrens.add(node);
 else
 node.insert(edge);
 childrens.add(node);
Tree class
package SPO;
import java.util.*;
public class Tree
 TreeNode rootNode;
 public Tree()
 rootNode = null;
 public Tree[] createTrees(Vector initTrees,Vector edges)
 Tree [] trees = new Tree[initTrees.size()];
 for(int c = 0;c < trees.length;c++)
 trees[c] = (Tree)initTrees.elementAt(c);
 for(int i = 0;i < trees.length;i++)
 for(int x = 0;x < edges.size();x++)
 Vector temp = (Vector)edges.elementAt(x);
 for(int y = 0;y < temp.size();y++)
 trees.insertNode((Edge)temp.elementAt(y));
return trees;
public void printTree(Tree tree)
System.out.print("("+tree.rootNode.edge.fromNode.getObjName()+","+tree.rootNode.edge.toNode.getObjName()+")");
Vector siblings = tree.rootNode.childrens;
for(int i = 0; i < siblings.size();i++)
TreeNode node = (TreeNode)siblings.elementAt(i);
System.out.print("("+node.edge.fromNode.getObjName()+","+node.edge.toNode.getObjName()+")");
System.out.println();
public Vector initializeTrees(Vector edges)
Vector trees = new Vector();
for(int i = 0;i < edges.size();i++)
Vector temp = (Vector)edges.elementAt(i);
for(int j = 0;j < temp.size();j++)
Tree tree = new Tree();
tree.insertNode((Edge)temp.elementAt(j));
trees.add(tree);
return trees;
public synchronized void insertNode(Edge edge)
if(rootNode == null)
rootNode = new TreeNode(edge);
else
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EdgeGenerator class
package SPO;
import java.util.*;
import k_means.*;
public class EdgeGenerator
 public EdgeGenerator()
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//OrderPair orderPair = new OrderPair();
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Edge class
package SPO;
import k_means.*;
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if (x.getX() > y.getX())
this.fromNode = x;
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Entry Point
package SPO;
import java.util.*;
import k_means.*;
public class Tester {
 public static void main(String[] args)
 Vector dataPoints = new Vector();
 dataPoints.add(new DataPoint(140, "Orange"));
 dataPoints.add(new DataPoint(114.2, "Lemmon"));
 dataPoints.add(new DataPoint(111.5, "Coke"));
 dataPoints.add(new DataPoint(104.6, "Pine apple"));
 dataPoints.add(new DataPoint(94.1, "W grape"));
 dataPoints.add(new DataPoint(85.2, "Appletizer"));
 dataPoints.add(new DataPoint(84.8, "R Grape"));
 dataPoints.add(new DataPoint(74.2, "Sprite"));
 dataPoints.add(new DataPoint(69.2, "Granadilla"));
 dataPoints.add(new DataPoint(59, "Strawbery"));
 dataPoints.add(new DataPoint(45.5, "Stone"));
 dataPoints.add(new DataPoint(36.3, "Yam"));
 dataPoints.add(new DataPoint(27, "Cocoa"));
 dataPoints.add(new DataPoint(13.8, "Pawpaw"));
EdgeGenerator eg = new EdgeGenerator();
Vector edges = eg.createEdges(dataPoints);
Tree treeMaker = new Tree();
Vector partialTrees = treeMaker.initializeTrees(edges);
Tree [] trees = treeMaker.createTrees(partialTrees,edges);
for(int i = 0;i < trees.length;i++)
treeMaker.printTree(trees[i]);
The program output
Each and every "@" symbol represents the start of a tree
@(Orange,Lemmon)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)(Lemmon,Coke)
@(Orange,Coke)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)
@(Orange,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Orange,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Orange,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Orange,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Orange,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Orange,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Orange,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Orange,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Orange,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Orange,Cocoa)(Cocoa,Pawpaw)
@(Orange,Pawpaw)
@(Lemmon,Coke)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)(Coke,Pine apple)
@(Lemmon,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Lemmon,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Lemmon,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Lemmon,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Lemmon,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Lemmon,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Lemmon,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Lemmon,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Lemmon,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Lemmon,Cocoa)(Cocoa,Pawpaw)
@(Lemmon,Pawpaw)
@(Coke,Pine apple)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)(Pine apple,W grape)
@(Coke,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Coke,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Coke,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Coke,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Coke,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Coke,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Coke,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Coke,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Coke,Cocoa)(Cocoa,Pawpaw)
@(Coke,Pawpaw)
@(Pine apple,W grape)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)(W grape,Appletizer)
@(Pine apple,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(Pine apple,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Pine apple,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Pine apple,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Pine apple,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Pine apple,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Pine apple,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Pine apple,Cocoa)(Cocoa,Pawpaw)
@(Pine apple,Pawpaw)
@(W grape,Appletizer)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)(Appletizer,R Grape)
@(W grape,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(W grape,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(W grape,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(W grape,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(W grape,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(W grape,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(W grape,Cocoa)(Cocoa,Pawpaw)
@(W grape,Pawpaw)
@(Appletizer,R Grape)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)(R Grape,Sprite)
@(Appletizer,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(Appletizer,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Appletizer,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Appletizer,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Appletizer,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Appletizer,Cocoa)(Cocoa,Pawpaw)
@(Appletizer,Pawpaw)
@(R Grape,Sprite)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)(Sprite,Granadilla)
@(R Grape,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(R Grape,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(R Grape,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(R Grape,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(R Grape,Cocoa)(Cocoa,Pawpaw)
@(R Grape,Pawpaw)
@(Sprite,Granadilla)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)(Granadilla,Strawbery)
@(Sprite,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Sprite,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Sprite,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Sprite,Cocoa)(Cocoa,Pawpaw)
@(Sprite,Pawpaw)
@(Granadilla,Strawbery)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)(Strawbery,Stone)
@(Granadilla,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Granadilla,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Granadilla,Cocoa)(Cocoa,Pawpaw)
@(Granadilla,Pawpaw)
@(Strawbery,Stone)(Stone,Yam)(Stone,Yam)(Stone,Yam)
@(Strawbery,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Strawbery,Cocoa)(Cocoa,Pawpaw)
@(Strawbery,Pawpaw)
@(Stone,Yam)(Yam,Cocoa)(Yam,Cocoa)
@(Stone,Cocoa)(Cocoa,Pawpaw)
@(Stone,Pawpaw)
@(Yam,Cocoa)(Cocoa,Pawpaw)
@(Yam,Pawpaw)
@(Cocoa,Pawpaw)

Your program description makes no sense. What exactly is it supposed to do?
Your errors make no sense. What is it doing wrong?
Your program output makes no sense. Look up pre-order, in-order, and post-order notation for representing trees. Pick one of those that you think would be best. I would go with pre-order. Because what you are doing isn't understandable.
By the way, I think your concept of a tree is flawed. A node in a tree has 3 things. it has a reference to its parent, it has references to any of its children, and it has some key value that represents the node (if each node were represented by numbers, the value would be an integer or something). In the case of the root, its reference to its parent is null. I don't know what you are doing with your tree, but it is highly confusing.

BOM: Finding Children Nodes For a Given Parent Node

Hi,
I am trying to find the longest path for a particular BOM material. I am using the FM CS_BOM_EXPL_MAT_V2 to explode the BOM to get the materials (including children nodes etc.). I think, in this scenario, a recursive function would be the best way to go. The problem is to find the children nodes for a node in a particular level. Looking at the structure STPOX and the fields STUFE (Level), WGEXX (path) , TTIDX (index) and VWGEX (path, multi-level), I cannot find a logical way to link the children nodes to a parent node although visually I can see how things are connected when the FM returns the STB table..
For example: TBL_STB returns from FM:
STUFE     WEGXX     BMTYP     TTIDX     VWEGX     OJTXB
1     1     M     1     0     MATXX1
2     1     M     2     1     MATXX2
3(a)     1     M     3     1              MATXX3
4(c)     1     M     4     1              MATXX4
4(d)     2     M     4     1              MATXX5
3(b)     2     M     3     1              MATXX6
4(e)     3     M     5     2              MATXX7
4(f)     4     M     5     2              MATXX8
Visually, we can tell that Level 2 has one item 2, level 3 has 2 items, 3(a) and 3(b), Level 4 has 4 items where 4c and 4d are connected to 3a and 4e and 4f are connected to 3b.
Going through STPOX structure itself, how can we find out that 4c and 4d belongs to assembly 3a but 4e and 4f belong to 3b?? If someone can explain the uses of the differnet indicators in STPOX (or other) where I can find out the children from the parent, it would be greatly helpful to write the recursive function..
Thanks in advance..
P.S. I will give points out immediately for any useful answers..
Edited by: Shuvo Datta on Sep 10, 2008 6:17 PM

Figured it out myself

How to add an item object as a child for a specified parent node in AdvancedDataGrid in Flex?

Hi all,
This is the code, to add a object as a child into a specified parent node in AdvancedDataGrid in flex.
<?xml version="1.0" encoding="utf-8"?><mx:Application
xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" creationComplete="onCreationComplete()" width="100%" height="100%">
<mx:Script><![CDATA[
importmx.controls.Alert;
importmx.collections.IHierarchicalCollectionViewCursor;
importmx.collections.IHierarchicalCollectionView;
importmx.collections.ArrayCollection; [
Bindable]private var objectAC:ArrayCollection = newArrayCollection();
//This method is used to construct the ArrayCollection 'flatData'
private function onCreationComplete():void{
var objOne:Object = newObject(); objOne.name =
"Rani"; objOne.city =
"Chennai";objectAC.addItem(objOne);
var objTwo:Object = newObject(); objTwo.name =
"Rani"objTwo.city =
"Bangalore";objectAC.addItem(objTwo);
var objThree:Object = newObject(); objThree.name =
"Raja"; objThree.city =
"Mumbai";objectAC.addItem(objThree);
//This method is used to add one object as a child item for the parent node 'Rani'
private function addChildItem():void{
var dp:IHierarchicalCollectionView = groupedADG.dataProvider asIHierarchicalCollectionView;
varcurent:IHierarchicalCollectionViewCursor = groupedADG.dataProvider.createCursor();
var dummyParentNode:Object = {name:"Rani", city:"New Delhi"};
var obj:Object = null;
while(curent.current){
// To get the current node objectobj = curent.current;
// Add Child item, when depth = 1 and Node name should be "Rani"
if (curent.currentDepth == 1 && obj["GroupLabel"] == "Rani"){
dp.addChild(curent.current, dummyParentNode);
curent.moveNext();
groupedADG.dataProvider = dp;
groupedADG.validateNow();
groupedADG.dataProvider.refresh();
]]>
</mx:Script>
<mx:AdvancedDataGrid id="groupedADG" x="10" y="15" designViewDataType="tree" defaultLeafIcon="{null}" sortExpertMode="true" width="305" >
<mx:dataProvider>
<mx:GroupingCollection id="gc" source="{objectAC}">
<mx:grouping>
<mx:Grouping>
<mx:GroupingField name="name"/>
</mx:Grouping>
</mx:grouping>
</mx:GroupingCollection>
</mx:dataProvider>
<mx:columns>
<mx:AdvancedDataGridColumn headerText="Name" dataField="name"/>
<mx:AdvancedDataGridColumn headerText="City" dataField="city"/>
</mx:columns>
</mx:AdvancedDataGrid>
<mx:Button x="10" y="179" label="Open the folder 'Rani'. Then Click this Button" width="305" click="addChildItem()" />
</mx:Application>

Hi,
It's not possible to 'append' a StringItem or a TextField (or any other lcdui.Item object) to a Canvas or GameCanvas. You can only draw lines, draw images, draw text, etc etc, on a Canvas screen. So, you can only 'simulate' the look and feel of a TextField (on a Canvas) by painting it and adding source code for command handling (like key presses). However, this will be quite some work!!
lcdui.Item objects can only be 'appended' to a Form-like Displayable.
Cheers for now,
Jasper

How to avoid the selection of a Parent node and its child node at a time?

Example:
consider the below JTree.
Parent1
---->Parent2
-------->Child3
Parent3
---->Parent4
My requirement :
Parent1 and Parent3 can be selected at a time(using ctrl keys)
Parent2 and Parent4 can be selected at a time
Parent1 and Parent2 should not allowed to select at a time.
In general : A parent and any of its child should not be selected at a time.
How to achieve this? Anyone please help me.

Thanikai wrote:
I am very sorry.Whatever for? It's a valid question.
How do i implement a custom TreeSelectionModel?I would start by going through the source of DefaultTreeSelectionModel so see how the default selection is handled. Also probably check out JTree.EmptySelectionModel to see how selection is prevented.
Which methods to override?Methods in the class you choose to extend, obviously. But before that you need to firm up certain design decisions: if a parent node is selected and the user attempts to select one of its child nodes, do you select the child and deselect the parent or do nothing/ and vice versa.
etc.... may form the basis for a future, more specific question accompanied by a [_SSCCE_|http://mindprod.com/jgloss/sscce.html].
luck, db

Why we need to conver Context Node data into XML file----Export to Excel

Hi All,
Let me clarify my dought........today i have gone through the concept of "Exporting Context Data Using the Webdynpro Binary cache" in SAP Online Help.
From the SAP Online Help pdf document, i have found that, the context node data has been converted first in to XML file,after that file had been stored in the web dynpor binary cache...bla....bla.........
Here my qtn is why they had converted context node data into XML file. With out doing that can not we export context node data to excel file..?
Regards
Seshu
Edited by: Sesshanna D on Dec 19, 2007 7:25 AM

Hi Sesshanna,
it is not neccessary to do that but xml has the advantage, that it can be easily transformed into every output format that might occur in later project stages.
If it's simply about blowing out some Excel, I suggest using an OSS library such as jexcelAPI or Jakarta POI and building the Excel how you need it.
regards,
Christian

How to remove a node from a xml

Hi All,
I want to remove a node from my xml output. Can anyone suggest me how to get that? I want to implement this by using the ASSIGN activity.
My sample output is
<env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsa="http://www.w3.org/2005/08/addressing">
 <env:Header>
 <wsa:MessageID>urn:4EF1A350677C11E1BFA7794ED76B03EF</wsa:MessageID>
 <wsa:ReplyTo>
 <wsa:Address>http://www.w3.org/2005/08/addressing/anonymous</wsa:Address>
 </wsa:ReplyTo>
 </env:Header>
 <env:Body>
 <SiebelOrderQueryByExample_Output xmlns="http://siebel.com/asi/">
 <ListOfOrderInterface xmlns="http://www.siebel.com/xml/Siebel%20Order">
 <Orders>
 <Id>1-15IXJ</Id>
 <AccountId>1-2EE</AccountId>
 <OrderNumber>1012-1234</OrderNumber>
 <ListOfLineItems>
 <LineItems>
 <Id>1-15IYN</Id>
 <LineNumber>303</LineNumber>
 <OrderNumber>1012-1234</OrderNumber>
 <OrderHeaderId>1-15IXJ</OrderHeaderId>
 </LineItems>
 </ListOfLineItems>
 </Orders>
</ListOfOrderInterface>
 </SiebelOrderQueryByExample_Output>
 </env:Body>
</env:Envelope>
I want to delete the <ListOfLineItems>node from the xml above so that my resultant would be,
 <env:Envelope xmlns:env="http://schemas.xmlsoap.org/soap/envelope/" xmlns:wsa="http://www.w3.org/2005/08/addressing">
 <env:Header>
 <wsa:MessageID>urn:4EF1A350677C11E1BFA7794ED76B03EF</wsa:MessageID>
 <wsa:ReplyTo>
 <wsa:Address>http://www.w3.org/2005/08/addressing/anonymous</wsa:Address>
 </wsa:ReplyTo>
 </env:Header>
 <env:Body>
 <SiebelOrderQueryByExample_Output xmlns="http://siebel.com/asi/">
 <ListOfOrderInterface xmlns="http://www.siebel.com/xml/Siebel%20Order">
 <Orders>
 <Id>1-15IXJ</Id>
 <AccountId>1-2EE</AccountId>
 <OrderNumber>1012-1234</OrderNumber>
 </Orders>
</ListOfOrderInterface>
 </SiebelOrderQueryByExample_Output>
 </env:Body>
</env:Envelope>
Please suggest something Its urgent.
Thanks in Advance.

It goes something like this, taken from the above blog entry:
Removing a node from node-list
With the bpelx: extensions in BPEL you are able to insert and update nodes in a node list. A node-list is an XML message that contains a set of records. In this article I use the following example:
<BookList xmlns="http://message.vijfhuizen.com">
<Book>
<title>The Lord Of The Rings</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>Harry Potter</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>The Hobbit</title>
<author>J.R.R. Tolkien</author>
</Book>
<Book>
<title>Storm; Chronicals of Pandarve</title>
<author>Don Lawrence</author>
</Book>
</BookList>
For creating and updating node lists the bpelx: functions are enough to handle this. But when you want to remove a particular node, you can use the bpelx:remove function. But this function can only remove a node from a particular position. For example removing the second node you code:
<bpel:assign>
<bpelx:remove>
<bpelx:target variable="VarBookList" query="/Booklist/Book[2]" />
</bpelx:append>
</bpel:assign>
It is hard to code the bpelx:remove to create a xpath to dynamicly remove node. You would like to remove the second node based on the xpath:
/Booklist/Book[title="Harry Potter" and author="J.R.R. Tolkien"]
You can add the above xpath in the bpelx:remove, but you are not able to make this dynamically.
There is a solution. The trick is to create a stylesheet that copies the data into a new message, but removing that particular records. Create a stylesheet that does the normal copy of the XML message. Then add a <choose> element in the stylsheet to filter that particular record.
<xsl:template match="/">
<BookList>
<xsl:for-each select="/BookList/Book">
<xsl:choose>
<xsl:when test="title='Harry Potter' and author='J.R.R. Tolkien'"/>
<xsl:otherwise>
<Book>
<title>
<xsl:value-of select="title"/>
</title>
<author>
<xsl:value-of select="author"/>
</author>
</Book>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</BookList>
Now we have a XSL stylesheet that removes a particular record, but this is not variable. This can be done via XSLT parameters.
<xsl:param name="pTitle"/>
<xsl:param name="pAuthor"/>
<xsl:template match="/">
<BookList>
<xsl:for-each select="/BookList/Book">
<xsl:choose>
<xsl:when test="title=$pTitle and author=$pAuthor"/>
<xsl:otherwise>
<Book>
<title>
<xsl:value-of select="title"/>
</title>
<author>
<xsl:value-of select="author"/>
</author>
</Book>
</xsl:otherwise>
</xsl:choose>
</xsl:for-each>
</BookList>
</xsl:template>
Now we are able to use this stylesheet in BPEL. In general BPEL create the following code:
<assign name="Transform">
<bpelx:annotation>
<bpelx:pattern>transformation</bpelx:pattern>
</bpelx:annotation>
<copy>
<from expression="ora:processXSLT('RemoveNode.xsl'
, bpws:getVariableData('Variable_BookList','payload')" />
<to variable="Variable_BookListTemp" part="payload"/>
</copy>
</assign>
But this code does not pass parameters to the stylesheet. The ora:processXSLT() can do this it has an additional parameter in this function:
<assign name="Transform">
<bpelx:annotation>
<bpelx:pattern>transformation</bpelx:pattern>
</bpelx:annotation>
<copy>
<from expression="ora:processXSLT('RemoveNode.xsl'
, bpws:getVariableData('Variable_BookList','payload')" />
, bpws:getVariableData('BPELxslparameters'))"/>
<to variable="Variable_BookListTemp" part="payload"/>
</copy>
</assign>
Now only you have to create the BPELxslparameters variable and assign it with the correct name/value pairs. The structure of the this variable is as follows:
<?xml version="1.0" encoding="windows-1252" ?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"
xmlns="http://schemas.oracle.com/service/bpel/common"
targetNamespace="http://schemas.oracle.com/service/bpel/common"
elementFormDefault="qualified">
<xsd:element name="parameters">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="item" minOccurs="1" maxOccurs="unbounded">
<xsd:complexType>
<xsd:sequence>
<xsd:element name="name" type="xsd:string"/>
<xsd:element name="value" type="xsd:string"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
</xsd:schema>
Create in BPEL the variable BPELxslparameters and let it point to this strucure:
<process ....
xmlns:common="http://schemas.oracle.com/service/bpel/common"
.../>
<variable name="BPELparameters" element="common:parameters"/>
Now we can in BPEL create an empty XML message, based on this strcuture and assign the values to these parameters and then call the processXSLT function.
<bpelx:assign name="Assign_GenerateEmptyParameterSet">
<copy>
<from>
<parameters xmlns="http://schemas.oracle.com/service/bpel/common">
<item>
<name>pTitle</name>
<value/>
</item>
<item>
<name>pAutor</name>
<value/>
</item>
</parameters>
</from>
<to variable="BPELparameters" query="/common:parameters"/>
</copy>
</bpelx:assign>
<assign name="Assign_setXSLTParameters">
<copy>
<from expression="'Harry Potter'"/>
<to variable="BPELparameters" query="/common:parameters/common:item[1]/common:value"/>
</copy>
<copy>
<from expression="'J.R.R. Tolkien'"/>
<to variable="BPELparameters" query="/common:parameters/common:item[1]/common:value"/>
</copy>
</assign>
Posted by Marc Kelderman SOA Blog at 1/16/2008 09:20:00 PM

Parent nodes have themselves as childs, in contrast to BW hierarchy

Hello Gurus,
I have a problem concerning hierarchies and grouping in CR2008.
Inserting the hierarchy works fine, but here's the problem:
Every parent node has itself as child node, i.e. the hierarchy shown is:
1
1.1
1.2
1.2.2
1.2.3
instead of the correct:
1
1.2
1.2.3
That even occurs when I just include the Node ID, without any grouping and hierarchy settings.
Such behaviour is undesirable for my purpose, so how can I make Crystal Reports behave like I expect/want? I am completely confused where these additional nodes are originating, as they are definitely not defined in the BW hierarchy. Therefore I suspect the problem somewhere in Crystal, although I have no actual evidence supporting this...
Has anyone an idea how to solve that problem? I have crawled through SDN and unfortunately wasn't able to find a solution...
Thanks!

Hi Ingo,
first I'd like to apologize for the late reply, I was very busy with another project during the last weeks.
It seems to be the bookable nodes setting in the query, at least only such parent nodes are affected that have data posted to themselves. Obviously, the actual parent node as shown in Crystal is the one with data aggregated by Crystal and the child node is the one with the data that was posted to the node.
I'll try to find some free time during the remainder of the week for further investigation and provide additional feedback.
Thanks for your help so far!

Parent node showing in schema when child nodes not present

I had several folks answer my questions on mapping from a flat file to an EDI 835 schema and I am down to just a couple of issues before I finish up. I have a conditional mapping issue that I have to solve before I can map the rest of the document. I am
mapping three fields in a single non-repeating line in the flat file to a repeating segment in the 835. Basically I need to create a separate AMT_ClaimSupplementalInformation segment for each field in the flat file line. As you can see in the picture
below I want to create a AMT_ClaimSupplementalInformation segment for CDISCOUNT, CINELIGIBLE and CALLOWED.
You can see I have quite a bit of conditional logic attached to the three fields, but I have all three connected via a loop to the AMT_ClaimSupplementalInformation parent. I cannot attach the loop to the parent of the three fields because it only appears
once in the file. And if I leave the loop out the AMT segments get stacked funny, like this:
<AMT_ClaimSupplementalInformation>
AMT1
AMT1
AMT2
AMT2
</AMT_ClaimSupplementalInformation>
You can see how they should be stacked in the next pic.
In some cases however, one of those fields may be blank so I will not need to create a AMT_ClaimSupplementalInformation segment for it. I was able to use some conditional mapping ideas you guys gave me using the Not-Equal and Value Mapping functoids, and
that works great to keep blank child nodes from being created. However, Since I have a loop attached to the AMT_ClaimSupplementalInformation parent node it still creates an empty parent node even when the child nodes are not created. See the empty parent
node in the pic below.
Since looping functoids can only be attached to links I don't know how to make the parent node conditional.
Any suggestions?
Thanks.

Boatseller, thanks for the tip. I did end up going the XSLT direction. It's a bit of a hack, but I'm using the following XSLT to eliminate empty nodes :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="@*|node()">
<xsl:if test=". != ''">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
I created a new map with the 835 schema on each side. I then created an XSLT file and pointed to it in the Custom XSLT Path property. It seems to work well. I call this map right after my FlatFile_To_835 map.
I was hoping to use the scripting functoid with inline XSLT in the map so that I didn't have to worry about deploying the XSLT file(just another thing to keep up with in the future), but when I compile it I get the following error:
The "Scripting" functoid has 1 input parameter(s), but 2 parameter(s) are expected.
I'm wondering if I'm connecting the schemas incorrectly in the map:
In any case, I'm past the empty nodes issue for now, which was a big roadblock. Now I have to deal with the CAS segments which are, as you said, a real pain.
Thanks for all of your input.

ADF Tree setting focus back to parent node after deletion of child node

Hi,
Is there a way to get the focus back to the parent node (or rather any particular node) in a tree?
I have a use case where we need to get the focus back to the parent node after a child node is deleted.
Currently the focus is shifted to the next node in the tree, but the need is to get the focus shifted back to the parent node. Also the parent node should be re-invoked to populate to get the latest status after deletion of the child node.
Any help/pointers?
Thanks

Thanks for the reply Frank.
I saw the link http://sreevardhanadf.blogspot.in/2012/07/showing-next-row-as-current-row-after.html
However the issue is since I am using custom created tree using POJO tree item (composite object).
calling myTree.getWrappedData() doesn't gives me a handle to JUCtrlHierBinding and subsequent access to JUCtrlHierNodeBinding.
my program gives me data like -
List<MyTreeItem> treeData = (List<MyTreeItem>)treeModel.getWrappedData();
because my tree model is build using -
treeModel = new ChildPropertyTreeModel(items, "children");
where items is List of <MyTreeItem>
Hence I am unable to get a handle using -
List nodeParentList = nodeParent .getKeyPath();
I am programmatically able to invoke the parent node to get the fresh data, only issue is the focus/selection of that node is not happening
Is there a way around?
Thanks
Sachin

Treeview Add Child to Parent Node Without Creating a New Parent

I have a treeview setup with a HierarchicalDataTemplate in my XAML as follows:
<TreeView Grid.Column="1" Grid.Row="0" ItemsSource="{Binding treeViewObsCollection}">
<TreeView.ItemTemplate>
<HierarchicalDataTemplate ItemsSource="{Binding mainNodes}">
<TextBlock Text="{Binding topNodeName}"/>
<HierarchicalDataTemplate.ItemTemplate>
<DataTemplate>
<TextBlock Text="{Binding subItemName}"></TextBlock>
</DataTemplate>
</HierarchicalDataTemplate.ItemTemplate>
</HierarchicalDataTemplate>
</TreeView.ItemTemplate>
</TreeView>
Here is the ViewModel which is set as the Data Context for the XAML File.
class AdvancedErrorCalculationViewModel : ViewModelBase
static ObservableCollection<TreeViewClass> _treeViewObsCollection = new ObservableCollection<TreeViewClass>();
public static ObservableCollection<TreeViewClass> treeViewObsCollection { get { return _treeViewObsCollection; } }
public class TreeViewClass : ViewModelBase
public TreeViewClass(string passedTopNodeName)
topNodeName = passedTopNodeName;
mainNodes = new ObservableCollection<TreeViewSubItems>();
public string topNodeName
get { return this.GetValue<string>(); }
set { this.SetValue(value); }
public ObservableCollection<TreeViewSubItems> mainNodes { get; private set; }
public class TreeViewSubItems : ViewModelBase
public TreeViewSubItems(string passedSubItemName, string passedSubItemJobStatus)
subItemName = passedSubItemName;
subItemJobStatus = passedSubItemJobStatus;
public string subItemName
get { return this.GetValue<string>(); }
set { this.SetValue(value); }
public string subItemJobStatus
get { return this.GetValue<string>(); }
set { this.SetValue(value); }
public static void AddTreeViewItems(string passedTopNodeName, string passedChildItemName, string passedChildItemJobStatus)
treeViewObsCollection.Add(new TreeViewClass(passedTopNodeName)
mainNodes =
new TreeViewSubItems(passedChildItemName, passedChildItemJobStatus)
The problem lies with the AddTreeViewItems method
seen above. Currently, if I call the method by let's say:
AdvancedErrorCalculationViewModel.AddTreeViewItems("Parent","Child 1", "Completed");
it creates the parent and child nodes just fine. No issues there.
However, if I call the method again with the same Parent name but a different Child; for example:
AdvancedErrorCalculationViewModel.AddTreeViewItems("Parent","Child 2", "Completed");
It creates a new Parent node with a child node Child 2 instead. Thus, I have something like this:
- Parent
- Child 1
- Parent
- Child 2
I would like to modify this function so that if the parent name is the same, the child node should belong under the previous Parent instead
of under a new Parent node. Something like this:
- Parent
- Child 1
- Child 2
Could anyone help me modify my code to detect if the Parent node exists in the observablecollection already and if so, place the child node under the existing parent? The main problem I am facing is trying to add items to a previously created observable collection
with an existing hierarchy because I don't know how to access the previous observable collection anymore. Help me with this please.
Thanks in advance. :)

You need to try and find an existing entry and if it's there add the child to that instead.
I notice you're a student and I guess this is probably an assignment.
By the way.
I suggest you work on the name of your collections and classes there.
EG A class should be singular but way more meaningfull than treeviewsubitem.
Anyhow, finding the top node could be done using linq. Since you can get none, SingleOrDefault is the method to use.
Thus something like:
TreeViewClass tvc = treeViewObsCollection.Where
(x=>x.Title == passedTopNodeName).SingleOrDefault();
Will give you tvc null or the qualifying entry.
If it's null, do what you have now.
If it's not then add the child item to tvc.
tvc is a reference to the TreeViewClass you have in that collection.
Please don't forget to upvote posts which you like and mark those which answer your question.
My latest Technet article - Dynamic XAML

Accessing Parent Node of an XML through XSLT

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