Adding 3 horizontal lines to a  2D Line flash chart

Hi
I have a nice 2D Line flash chart. I would like to add three horizontal lines (they are constant values) on the graph. These lines are thresholds for the values displayed on the graph.
I tried to add trhe series to the graph, it worlks well but the problem is that it slow down too much the process of computing of the chart
Here is my request, you see with the 3 series added :
DECLARE
X VARCHAR2 (4000);
BEGIN
x := 'SELECT NULL, TRUNC(DATE1, ''HH''), AVG(VALEUR) "Hauteur",
     (SELECT SEUIL_BAS FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Seuil bas",
     (SELECT SEUIL_ALERTE FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Alerte",
(SELECT SEUIL_ALARME FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Alarme"
FROM SIVOA.EVV_'
|| UPPER (:p184_ename) ||
' WHERE CLEF_VAR = (SELECT CLEF_VAR FROM SIVOA.SITE_ECHELLE WHERE SITE = '''
|| UPPER (:p184_ename) ||
''') AND DATE1 BETWEEN TO_DATE ('''
||:P8_DATE_DEBUT||'000000'', ''DD/MM/YYYYHH24MISS'') AND TO_DATE ('''
||:P8_DATE_FIN  ||'235959'', ''DD/MM/YYYYHH24MISS'')
GROUP BY TRUNC(DATE1, ''HH'')
ORDER BY TRUNC(DATE1, ''HH'')';
RETURN (X);
END;Is there a way to add 3 lines without using a query ?
Thank you for your kindness !
Christian

Hi,
I have not solved but found an improvement, I select a constant from a table. This constant is displayed along the horizontal axis.
Example of constant :
(SELECT SEUIL_BAS FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Seuil bas",
DECLARE
X VARCHAR2 (4000);
BEGIN
x := 'SELECT NULL, TRUNC(DATE1, ''HH''), AVG(VALEUR) "Hauteur",
(SELECT SEUIL_BAS FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Seuil bas",
(SELECT SEUIL_ALERTE FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Alerte",
(SELECT SEUIL_ALARME FROM SIVOA.SITE_ECHELLE WHERE SITE = '''|| UPPER (:p184_ename) ||''') "Alarme"
FROM SIVOA.EVV_'
|| UPPER (:p184_ename) ||
' WHERE CLEF_VAR = (SELECT CLEF_VAR FROM SIVOA.SITE_ECHELLE WHERE SITE = '''
|| UPPER (:p184_ename) ||
''') AND DATE1 BETWEEN TO_DATE ('''
||:P8_DATE_DEBUT||'000000'', ''DD/MM/YYYYHH24MISS'') AND TO_DATE ('''
||:P8_DATE_FIN ||'235959'', ''DD/MM/YYYYHH24MISS'')
GROUP BY TRUNC(DATE1, ''HH'')
ORDER BY TRUNC(DATE1, ''HH'')';
RETURN (X);
END;
Perhaps a way is to customize the XML code generated.

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    </div>
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    _#-->
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    </div>
    <!--#_
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    <div id="DepartmentField">
    <!--#_
    var encodedDept = $htmlEncode(ctx.CurrentItem.Department);
    var displayDept = Srch.U.getSingleHHXMLNodeValue(hhProps, "department");
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    </div>
    <!--#_
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    if(has_org == true) {
    _#-->
    <div id="Organization">
    <!--#_
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    var displayorg = Srch.U.getSingleHHXMLNodeValue(hhProps, "Organization");
    if ($isEmptyString(displayorg)) { displayorg = encodedorg }
    _#-->
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    </div>
    <!--#_
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    <!--#_
    if(has_olocator == true) {
    _#-->
    <div id="OfficeLocator">
    <!--#_
    var encodedolocator = $htmlEncode(ctx.CurrentItem.OfficeLocator);
    var displayolocator = Srch.U.getSingleHHXMLNodeValue(hhProps, "OfficeLocator");
    if ($isEmptyString(displayolocator)) { displayolocator = encodedolocator }
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    </div>
    <!--#_
    _#-->
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    <div id="OfficeBaseLocation">
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    var encodedbolocation = $htmlEncode(ctx.CurrentItem.BaseOfficeLocation);
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    <!--#_
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    <!--#_
    } else if(has_ski == true) {
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    _#= encodedVal =#_
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    <!--#_
    _#-->
    <!--#_
    } else if(has_pp == true) {
    var encodedVal = Srch.U.getMultipleHHXMLNodeValues(hhProps, "pastprojects", 3, delimiter);
    if (Srch.U.e(encodedVal)) { encodedVal = $htmlEncode(Srch.U.getUnEncodedMultiValuedResults(ctx.CurrentItem.PastProjects, 3, delimiter))}
    if (!Srch.U.e(encodedVal)) {
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    <div id="PastProjectsValue" class="ms-srch-ellipsis">
    <span id="FieldTitle" class="ms-soften"> _#= $htmlEncode(Srch.Res.item_People_PastProjects) =#_ </span>
    _#= encodedVal =#_
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    <!--#_
    _#-->
    <!--#_
    } else if(has_int == true) {
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    Thanks,
    Linda Li                
    Forum Support
    Please remember to mark the replies as answers if they help and unmark them if they provide no help. If you have feedback for TechNet Subscriber Support, contact
    [email protected]
    Linda Li
    TechNet Community Support

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