Adding the same Vector object into a JTable acts weird

Question

I'm using a JTable with a DefaultTableModel as the model. When I try to add rows in a loop using the same Vector object (clearing it out beforehand), the result is that every row in the table is identical to the last one. Is that because the DefaultTableModel stores a reference to my Vector object for each row? And by clearing and changing the vector this effectively changes very row in the table? That's the only rationale I can come up with...
Here's the loop...
Iterator itr = directorySet.iterator();
Vector rowVector = new Vector(getColumnCount());
while (itr.hasNext()) {
File file = (File) itr.next();
rowVector.clear()
rowVector.add(file.getName());
rowVector.add("<Directory>");
rowVector.add("");
addRow(rowVector);
Any comments appreciated. Thanks,
-nick

Answer 1

By having a single vector object and making your all your rows refer to that would only populate all the rows with the latest data the vector has. This is the right behaviour, since all you rows effectively have a reference to your single vector object. To avoid this, do something like this....
Iterator itr = directorySet.iterator();
Vector rowVector = new Vector(getColumnCount());
while (itr.hasNext()) {
File file = (File) itr.next();
//Instead of clearing your rowVector here, allocate a new vector object to your rowVector reference.
//This would solve your problem effectively.
rowVector = new Vector(getColumnCount());
//rowVector.clear()
rowVector.add(file.getName());
rowVector.add("<Directory>");
rowVector.add("");
addRow(rowVector);
}