AES/ECB/NoPadding

Question

Dear ALL,
I am having a problem AES algorithm
I'm using AES/ECB/NoPadding
import java.security.NoSuchAlgorithmException;
import java.security.Provider;
import java.security.Security;
import javax.crypto.Cipher;
import javax.crypto.KeyGenerator;
import javax.crypto.SecretKey;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
import org.jpos.iso.ISOUtil;
public class AesTest {
     static Provider p = new org.bouncycastle.jce.provider.BouncyCastleProvider();
     public static void main(String[] args) {
          Security.addProvider(p);
          try {
               byte aesKeyByte[] =  ISOUtil.hex2byte("EE5C261E5B0FF0E78CFF3D6D65DDB220");
               byte clearValue[] =  ISOUtil.hex2byte("7C096716F12BAE6B");
               SecretKey AESKey = new SecretKeySpec(aesKeyByte,"AES");
               byte enout[] = encrypt(AESKey, clearValue, p, "ECB", null);
               System.out.println("ENCR DATA : "+ISOUtil.hexString(enout));
               byte deout[] = decrypt(AESKey, enout, p, "ECB", null);
               System.out.println("DER DATA : "+ISOUtil.hexString(deout));
          } catch (Exception e) {
               e.printStackTrace();
     public static byte[] encrypt(SecretKey secretKey, byte[] clearBytes, Provider p,
               String mode, byte[] IV) throws Exception {
          if ("CBC".equals(mode)) {
               Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding", p
                         .getName());
               cipher
                         .init(Cipher.ENCRYPT_MODE, secretKey, new IvParameterSpec(
                                   IV));
               return cipher.doFinal(clearBytes);
          } else {
               Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding", p
                         .getName());
               cipher.init(Cipher.ENCRYPT_MODE, secretKey);
               return cipher.doFinal(clearBytes);
     public static byte[] decrypt(SecretKey secretKey, byte[] ciperBytes, Provider p,
               String mode, byte[] IV) throws Exception {
          if ("CBC".equals(mode)) {
               Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding", p
                         .getName());
               cipher
                         .init(Cipher.DECRYPT_MODE, secretKey, new IvParameterSpec(
                                   IV));
               return cipher.doFinal(ciperBytes);
          } else {
               Cipher cipher = Cipher.getInstance("AES/ECB/NoPadding", p
                         .getName());
               cipher.init(Cipher.DECRYPT_MODE, secretKey);
               return cipher.doFinal(ciperBytes);
}Error
javax.crypto.IllegalBlockSizeException: data not block size aligned
     at org.bouncycastle.jce.provider.JCEBlockCipher.engineDoFinal(Unknown Source)
     at javax.crypto.Cipher.doFinal(DashoA13*..)
     at AesTest.encrypt(AesTest.java:72)
     at AesTest.main(AesTest.java:41)
Regards
Edited by: EJP on 21/07/2011 15:45

Answer 1

But I'm using ECB mode. So my clear data has 8 byte block
When I use clear data = 7C096716F12BAE6B7C096716F12BAE6B (16 bytes, two 8 blocks), there is no any exception
But clear data = 7C096716F12BAE6B7C096716F12BAE6B7C096716F12BAE6B (3 8 blocks ) again getting same error
Note : I'm not facing this issue with DES algorithm.
Actually, I don't know length of my clear text, what I'm doing I will make 8 bytes blocks of clear text and used to encrypt it.
Example
Clear text = 1111 2 makes 1111 2000 0000 0005
Can you tell me how to encrypt this kind of data using AES with ECB mode ?
Regards