AES SecretKeyFactory not available

Question

Hi,
I found that there is a bug in using SecretKeyFactory keyFactory with reference to http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=7022467
I tried implementing with KeySpec too,but found one or the other error.
I'm posting here my code.Please help me out to decrypt.
import javax.crypto.Cipher;
import javax.crypto.SecretKey;
import javax.crypto.SecretKeyFactory;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Hex;
public class DecryptTest {
     public static void main(String[] args) throws Exception {
          String keyStr = "6a6b663472346c38736873346569727538346234333534376635333962353666";
          String eid = "bf940165bcc3bca12321a5cc4c753220129337b48ad129d880f718d147a2cd1bfa79de92239ef1bc06c2f05886b0cd5d";
          String rid = "00028e7353d9c4eca480a57a1ca9ba9b";
          int keysize = 256;
          // decode the key string into bytes (using Apache Commons)
          byte[] keyBytes = Hex.decodeHex(keyStr.toCharArray());
          // create a representation of the key
          SecretKeySpec spec = new SecretKeySpec(keyBytes, "AES");
          // turn the key spec into a usable key
          SecretKeyFactory keyFactory = SecretKeyFactory.getInstance("AES");
          SecretKey key = keyFactory.generateSecret(spec);
          // use a cipher to decrypt the eid
          Cipher cipher = Cipher.getInstance("AES");
          cipher.init(Cipher.DECRYPT_MODE, key);
          byte[] plainText = cipher.doFinal(Hex.decodeHex(eid.toCharArray())); // decode from Hex again
          String Eid = new String(plainText, "ASCII");
          System.out.println(Eid);
}

Answer 1

964782 wrote:
well I'm new to this encryption...and the work around again gave the same error..
import java.security.spec.KeySpec;
import javax.crypto.Cipher;
import javax.crypto.SecretKey;
import javax.crypto.SecretKeyFactory;
import javax.crypto.spec.SecretKeySpec;
import org.apache.commons.codec.binary.Hex;
public class DecryptTest {
     public static void main(String[] args) throws Exception {
          String keyStr = "6a6b663472346c38736873346569727538346234333534376635333962353666";
          String eid = "bf940165bcc3bca12321a5cc4c753220129337b48ad129d880f718d147a2cd1bfa79de92239ef1bc06c2f05886b0cd5d";
          String rid = "00028e7353d9c4eca480a57a1ca9ba9b";
          int keysize = 256;
          // decode the key string into bytes (using Apache Commons)
          byte[] keyBytes = Hex.decodeHex(keyStr.toCharArray());
          // create a representation of the key
          SecretKey spec = new SecretKeySpec(keyBytes, "AES");
          // turn the key spec into a usable key
          SecretKeyFactory keyFactory = SecretKeyFactory.getInstance("AES");
          SecretKey key = keyFactory.generateSecret((KeySpec) spec);
          // use a cipher to decrypt the eid
          Cipher cipher = Cipher.getInstance("AES/ECB/PKCS5Padding");
          cipher.init(Cipher.DECRYPT_MODE, key);
          byte[] plainText = cipher.doFinal(Hex.decodeHex(eid.toCharArray())); // decode from Hex again
          String Eid = new String(plainText, "ASCII");
          System.out.println(Eid);
I obviously did not make is clear enough. You don't actually need a SecretKeyFactory; you just generate the key using
SecretKey key = new SecretKeySpec(keyBytes, "AES");This way you don't need to use a SecretKeyFactory. Just use the above key to init() the Cipher.
and also I didn't get you on " The ciphertext in your code was not generated using the key in your code."
Thanks for your help!!If I apply the change I suggest I get
javax.crypto.BadPaddingException: Given final block not properly paddedwhich implies either the key is wrong or the ciphertext was not generated using the key or the block mode was different or the padding was different. For any given key bytes I can use AES in the JCE to decrypt ciphertext generated using both the BouncyCastle lightweight API and the OpenSSl library so I'm pretty sure the decryption process is correct so I think that your encryption process did not use that key or a different block mode was used or a different padding was used. Since I don't know how you generated that ciphertext I can't be more specific.