Append strings to file
Hi,
How do i modify "write characters to file.vi" such that every time i append a new string to the same file, it will start at a new line?
There is this parameter in the vi that is called "convert eol"? Read the help file but could not figure out what is a end of line marker. Please help.
Thanks.
Hi,
the easiest way is to concatenate EOL symbol with your string and then write this new string to the file.
So you will write something like
EOL"your string". (or "/nyour string" in codes)
EOL symbol and "Concatenate strings.vi" you can find in "Functions/String/..."
Good luck.
Oleg Chutko.
Similar Messages
-
How to read appended objects from file with ObjectInputStream?
Hi to everyone. I'm new to Java so my question may look really stupid to most of you but I couldn't fined a solution by myself... I wanted to make an application, something like address book that is storing information about different people. So I decided to make a class that will hold the information for each person (for example: nickname, name, e-mail, web address and so on), then using the ObjectOutputStream the information will be save to a file. If I want to add a new record for a new person I'll simply append it to the already existing file. So far so good but soon I discovered that I can not read the appended objects using ObjectInputStream.
What I mean is that if I create new file and then in one session save several objects to it using ObjectOutputStream they all will be read with no problem by ObjectInputStream. But after that if in a new session I append new objects they won't be read. The ObjectInputStream will read the objects from the first session after that IOException will be generated and the reading will stop just before the appended objects from the second session.
The following is just a simple test it's not actual code from the program I was talking about. Instead of objects containing different kind of information I'm using only strings here. To use the program use as arguments in the console "w" to create new file followed by the file name and the strings you want save to the file (as objects). Example: "+w TestFile.obj Thats Just A Test+". Then to read it use "r" (for reading), followed by the file name. Example "+r TestFile.obj+". As a result you'll see that all the strings that are saved in the file can be successfully read back. Then do the same: "+w TestFile.obj Thats Second Test+" and then read again "+r TestFile.obj+". What will happen is that the strings only from the first sessions will be read and the ones from the second session will not.
I am sorry for making this that long but I couldn't explain it more simple. If someone can give me a solution I'll be happy to hear it! ^.^ I'll also be glad if someone propose different approach of the problem! Here is the code:
import java.io.*;
class Fio
public static void main(String[] args)
try
if (args[0].equals("w"))
FileOutputStream fos = new FileOutputStream(args[1], true);
ObjectOutputStream oos = new ObjectOutputStream(fos);
for (int i = 2; i < args.length ; i++)
oos.writeObject(args);
fos.close();
else if (args[0].equals("r"))
FileInputStream fis = new FileInputStream(args[1]);
ObjectInputStream ois = new ObjectInputStream(fis);
for (int i = 0; i < fis.available(); i++)
System.out.println((String)ois.readObject());
fis.close();
else
System.out.println("Wrong args!");
catch (IndexOutOfBoundsException exc)
System.out.println("You must use \"w\" or \"r\" followed by the file name as args!");
catch (IOException exc)
System.out.println("I/O exception appeard!");
catch (ClassNotFoundException exc)
System.out.println("Can not find the needed class");How to read appended objects from file with ObjectInputStream? The short answer is you can't.
The long answer is you can if you put some work into it. The general outline would be to create a file with a format that will allow the storage of multiple streams within it. If you use a RandomAccessFile, you can create a header containing the length. If you use streams, you'll have to use a block protocol. The reason for this is that I don't think ObjectInputStream is guaranteed to read the same number of bytes ObjectOutputStream writes to it (e.g., it could skip ending padding or such).
Next, you'll need to create an object that can return more InputStream objects, one per stream written to the file.
Not trivial, but that's how you'd do it. -
i'm trying to append some string to a file but it gives me error while compiling.
here's my code:
import java.io.FileOutputStream;
import java.io.File;
import java.io.IOException;
import java.util.Calendar;
import java.util.Date;
import java.awt.*;
import java.text.SimpleDateFormat;
public class testWrite
public static void main(String args[])
File outputFile=new File("file.txt");
try
Calendar myCalendar = Calendar.getInstance();
FileWriter oStream=new FileWriter(outputFile,true);
FileOutputStream oStream=new FileOutputStream(outputFile,true);
SimpleDateFormat datfmt = new SimpleDateFormat( "dd.MM.yyyy HH:mm:ss" );
Date date=new Date();
String strDate=datfmt.format(date);
oStream.write(strDate.getBytes());
oStream.close();
catch(IOException e)
can someone tell me what's wrong with it.here is the corrected programme
import java.io.*;
import java.io.FileOutputStream;
import java.io.File;
import java.io.IOException;
import java.util.Calendar;
import java.util.Date;
import java.awt.*;
import java.text.SimpleDateFormat;
public class testWrite
public static void main(String args[])
//File outputFile=new File("file.txt");
try
Calendar myCalendar = Calendar.getInstance();
//FileWriter oFileWriter=new FileWriter("file.txt",true);
FileOutputStream oStream=new FileOutputStream("file.txt",true);
SimpleDateFormat datfmt = new SimpleDateFormat( "dd.MM.yyyy HH:mm:ss" );
Date date=new Date();
String strDate=datfmt.format(date);
oStream.write(strDate.getBytes());
oStream.close();
catch(IOException e)
U had used file object in the constructor of the fileOutputStream object which is not the argument the constructor expects,the constructor expects a String with the fileName in it. -
Hi everyone,
I have created a zip file (test.zip), but i cant figure out how to append a text file to it.
Can anybody help?http://java.sun.com/j2se/1.5.0/docs/api/java/util/zip/ZipInputStream.html#createZipEntry(java.lang.String)
-
How to append two CSV files using ftp
Hi
Please let me know the FTP command to append the two .CSV files into one .CSV file.
e.g.
Let me explain:
one CSV file has the fields F1 , F2, F3 , F4 and has 5 records
another CSV file has the same sequence of fields F1, F2, F3, F4 and has 10 records
after appending both the files , I must get 15 records.
Thanks
AlokOk I will try out.
I am illustrating my requirement as follow
File#1 (type .CSV)
F1 F2 F3 F4
100 566 89 86
235 256 56 12
File#2 (type .CSV)
F1 F2 F3 F4
56 56 98 102
12 23 36 523
23 56 56 89
Now we want to Append File#1 to File#2 as follow:
F1 F2 F3 F4
100 566 89 86
235 256 56 12
56 56 98 102
12 23 36 523
23 56 56 89
Please suggest now that which command would be appropiate.
Alok -
Problem with Append mode in File Receiver
Hello,
I am facing some problem with Append Mode in File Receiver.
In channel config, i have given :
Construction Mode : Append
File Type : Text
Message Protocol : File Content Conversion
The size of the file which i am trying to send is about 9.5MB.
I got this error,
"Recovering from loss of connection to database; message
loaded into queue by recover job: System Job (Failover Recovery)".
So, it would seem that there was a loss of connnection to the database
while the file was being written.
Note - XI successfully recovered from the connection loss and
successfully wrote the file, however since the communication channel
was set to append, it appended to the partial file that was written
before the database connection loss. This is not correct. The file
should have been overwritten after the recovery even though the communication
channel was configured to append.
Can anyone help me on this regard.
Thanks,
Soorya.Hi Venkat,
I would suggest u to split the file in to chunks if u face any problem in processing at a time in append mode and also
Memory Requirements are must 4 processing huge files:
Q: Which memory requirements does the File Adapter have? Is there a restriction on the maximum file size it can process?
A: The maximum file size that can be processed by the File Adapter depends on a number of factors:
o The most important one is the size of the Java heap, which is shared among all messages processed at a certain point in time. In order to be able to process larger messages without an out of memory error (OOM), it is recommended to increase the size of the available Java heap and/or to reduce the concurrency in the system so that fewer messages are processed in parallel.
o Another factor negatively influencing the maximum message size in releases up to and including XI 3.0 SP 13 is an enabled charcter set (encoding) conversion if the message type is set to "Text".
o Using the transport protocol "File Transfer Protocol (FTP)" also uses more memory for processing than the transport protocol "File System (NFS)" (up to and including XI 3.0 SP 13).
o If the Message Protocol "File Content Conversion" is used in a File Sender channel, consider that not only the size of the input file affects the File Adapter's memory usage, but even more the size of the XML resulting from the conversion, which is usually a few factors larger than the original plain text file.
To reduce the memory consumption in this scenario, consider configuring the setting "Maximum Recordsets per Message" for the sender channel. This will cause the input file to be split into multiple smaller mesages.
Plz do refer the following links:
U may plan the availability of ur communication channel using "Planning Availability Times" feature
http://help.sap.com/saphelp_nw04/helpdata/en/45/06bd029da31122e10000000a11466f/frameset.htm
/people/sravya.talanki2/blog/2005/11/29/night-mare-processing-huge-files-in-sap-xi
hi check the below links for reference
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/10748ef7-b2f0-2910-7cb8-c81e7f284af5
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/7086f109-aaa7-2a10-0cb5-f69bd2affd2b
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/2498bf90-0201-0010-4884-83568752a857
https://www.sdn.sap.com/irj/sdn/go/portal/prtroot/docs/library/uuid/cc1ec146-0a01-0010-90a9-b1df1d2f346f
Regards,
Vinod. -
Get specific Strings from File
Good morning to every one.
I 've got a text file which contains a customer number and an order number, coded as we see in the picture below:
I am trying to develop a tool in Visual Studio, which it reads the file line-by-line and fills a listbox, with the order_number and the customer number. From the file above, I know that the order number are the digits on the first 'column' after the leading-zeros,
until '/', and the customer number are the digits without zeros in the 'third' column before 'CUSTOMER_NUMBER'. My form looks like:
The problem is, that the number of before the fields in file, are not equal in every line.
So, my question is how I can retrieve the 'order number' and 'customer number' from the text file and copy the results to list box, after clicking on 'Get Strings' button, like:
359962656 2238914
359562804 2238914
etc...
I attach my code here:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO;
namespace ReadStringFileApp
public partial class frmMain : Form
public frmMain()
InitializeComponent();
OpenFileDialog openfile = new OpenFileDialog();
//openfiledialog to pickup filename
private void btnFindFile_Click(object sender, EventArgs e)
openfile.Filter = "Text|*.txt";
if (openfile.ShowDialog() == DialogResult.OK)
lbxResults.Items.Clear();
txtFilepath.Text = openfile.FileName.ToString();
//get strings from file
private void btnGetStrings_Click(object sender, EventArgs e)
//check if there is a file path on textbox
if (txtFilepath.Text == "")
MessageBox.Show("No File Select. Please select a file", "Error File Name", MessageBoxButtons.OK, MessageBoxIcon.Error);
btnFindFile.Focus();
return;
//create list for all lines inside file
List<string> lines = new List<string>();
string line;
using (StreamReader r = new StreamReader(@txtFilepath.Text))
while ((line = r.ReadLine()) != null)
string ordernum;//string for order number
string customer;//string for customer number
//line = ordernum + "\t" + customer; //concatenate results to fill the list box
lbxResults.Items.Add(line);
r.Close(); //close file
private void btnExportToFIle_Click(object sender, EventArgs e)
//check if listbox is empty
if (lbxResults.Items.Count == 0)
MessageBox.Show("Result List is empty! Choose a file to proceed.", "Error Result List", MessageBoxButtons.OK, MessageBoxIcon.Error);
btnGetStrings.Focus();
return;
//read listbox contents and parse to a list object
List<string> list = new List<string>();
foreach (String i in lbxResults.Items)
list.Add(i);
//Create a file in c: with results
File.WriteAllLines(@"C:\export-test.txt", list, Encoding.Default);
MessageBox.Show("File export completed!", "File Export", MessageBoxButtons.OK, MessageBoxIcon.Information);
Thank you in advanced@ Joel Engineer
and@
Val10
I combined your responses and I get my results correctly. I attached the code I rewrite for further use:
private void btnGetStrings_Click(object sender, EventArgs e)
//check if there is a file path on textbox
if (txtFilepath.Text == "")
MessageBox.Show("No File Select. Please select a file", "Error File Name", MessageBoxButtons.OK, MessageBoxIcon.Error);
btnFindFile.Focus();
return;
//create list for all lines inside file
List<string> lines = new List<string>();
string line;
using (StreamReader r = new StreamReader(@txtFilepath.Text))
while ((line = r.ReadLine()) != null)
string order_customer;
Regex reg = new Regex("0*");
//set an string array, to split the file in columns positions, defining the characters
string[] daneio = line.Split(new char[] { ' ', '\t' }, StringSplitOptions.RemoveEmptyEntries);
//get order number from the first column
var ordernum_zeros = reg.Match(daneio[0]).Value;
daneio[0] = daneio[0].Replace(ordernum_zeros, String.Empty);
daneio[0] = daneio[0].Substring(0, daneio[0].IndexOf("/"));
//get customer column, without zeros
var customer_zeros = reg.Match(daneio[5]).Value;
daneio[2] = daneio[2].Replace(customer_zeros, String.Empty);
daneio[2] = daneio[2].Substring(0, daneio[5].IndexOf("CUSTOMER_NUMBER"));
//combine the result in listbox
order_customer = daneio[0] + "\t" + daneio[2];
lbxResults.Items.Add(order_customer);
r.Close(); //close file
Thank you for your help! -
External Table which can handle appending multiple csv files dynamic
I need an external table which can handle appending multiple csv files' values.
But the problem I am having is : the number of csv files are not fixed.
I can have between 2 to 6-7 files with the suffix as current_date. Lets say it will be like my_file1_aug_08_1.csv, my_file1_aug_08_2.csv, my_file1_aug_08_3.csv etc. and so on.
I can do it by following as hardcoding if I know the number of files, but unfortunately the number is not fixed and need to something dynamically to inject with a wildcard search of file pattern.
CREATE TABLE my_et_tbl
my_field1 varchar2(4000),
my_field2 varchar2(4000)
ORGANIZATION EXTERNAL
( TYPE ORACLE_LOADER
DEFAULT DIRECTORY my_et_dir
ACCESS PARAMETERS
( RECORDS DELIMITED BY NEWLINE
FIELDS TERMINATED BY ','
MISSING FIELD VALUES ARE NULL )
LOCATION (UTL_DIR:'my_file2_5_aug_08.csv','my_file2_5_aug_08.csv')
REJECT LIMIT UNLIMITED
NOPARALLEL
NOMONITORING;Please advice me with your ideas. thanks.
Joshua..Well, you could do it dynamically by constructing location value:
SQL> CREATE TABLE emp_load
2 (
3 employee_number CHAR(5),
4 employee_dob CHAR(20),
5 employee_last_name CHAR(20),
6 employee_first_name CHAR(15),
7 employee_middle_name CHAR(15),
8 employee_hire_date DATE
9 )
10 ORGANIZATION EXTERNAL
11 (
12 TYPE ORACLE_LOADER
13 DEFAULT DIRECTORY tmp
14 ACCESS PARAMETERS
15 (
16 RECORDS DELIMITED BY NEWLINE
17 FIELDS (
18 employee_number CHAR(2),
19 employee_dob CHAR(20),
20 employee_last_name CHAR(18),
21 employee_first_name CHAR(11),
22 employee_middle_name CHAR(11),
23 employee_hire_date CHAR(10) date_format DATE mask "mm/dd/yyyy"
24 )
25 )
26 LOCATION ('info*.dat')
27 )
28 /
Table created.
SQL> select * from emp_load;
select * from emp_load
ERROR at line 1:
ORA-29913: error in executing ODCIEXTTABLEOPEN callout
SQL> set serveroutput on
SQL> declare
2 v_exists boolean;
3 v_file_length number;
4 v_blocksize number;
5 v_stmt varchar2(1000) := 'alter table emp_load location(';
6 i number := 1;
7 begin
8 loop
9 utl_file.fgetattr(
10 'TMP',
11 'info' || i || '.dat',
12 v_exists,
13 v_file_length,
14 v_blocksize
15 );
16 exit when not v_exists;
17 v_stmt := v_stmt || '''info' || i || '.dat'',';
18 i := i + 1;
19 end loop;
20 v_stmt := rtrim(v_stmt,',') || ')';
21 dbms_output.put_line(v_stmt);
22 execute immediate v_stmt;
23 end;
24 /
alter table emp_load location('info1.dat','info2.dat')
PL/SQL procedure successfully completed.
SQL> select * from emp_load;
EMPLO EMPLOYEE_DOB EMPLOYEE_LAST_NAME EMPLOYEE_FIRST_ EMPLOYEE_MIDDLE
EMPLOYEE_
56 november, 15, 1980 baker mary alice 0
01-SEP-04
87 december, 20, 1970 roper lisa marie 0
01-JAN-99
SQL> SY.
P.S. Keep in mind that changing location will affect all sessions referencing external table. -
Appending multiple *.csv files while retaining the original file name in the first column
Hi guys it's been awhile.
I'm trying to append multiple *.csv files while retaining the original file name in the first column, the actual data set is about 40 files.
file a.csv contains:
1, line one in a.csv
2, line two in a.csv
file b.csv contains:
1, line one in b.csv
2, line two in b.csv
output.csv result is this:
I would like this:
a.csv, 1, line one in a.csv
a.csv, 2, line two in a.csv
b.csv, 1, line one in b.csv
b.csv, 2, line two in b.csv
Any suggestions to speed up my hobbling attempts would be aprieciated
Thanks,
-SS
Solved!
Go to Solution.What you could do is given in the attachment.
Started with 2 files :
a.csv
copy of a.csv
Both with data :
1;1.123
2;2.234
3;3.345
Output :
a.csv;1;1.123
a.csv;2;2.234
a.csv;3;3.345
Copy of a.csv;1;1.123
Copy of a.csv;2;2.234
Copy of a.csv;3;3.345
If you have more questions, just shoot
Kind regards,
- Bjorn -
Have fun using LabVIEW... and if you like my answer, please pay me back in Kudo's
LabVIEW 5.1 - LabVIEW 2012
Attachments:
AppendingCSV.JPG 73 KB -
Appending a .sql file to a pdf
Is it possible to append a .sql file to a PDF as an Appendix. I am using Acrobat Pro 9.
Hi randha m,
What actually you mean by append. Do you mean attach. Try to elaborate little more your query.
Regards,
Ajlan Huda. -
I want to search for a string in file. I can do it reading the file in line by line and search each line but that would be more expensive. Is there are any api/freeware library, which can help me to search for a string in file?
- RYou can eliminate the overhead of creting strings, and also of translating bytes to chars, but that's all you can do. Do not forget:
Premature optimization is the root of all evil.
Using ByteBuffer and java.nio could be the best. I do not believe there's a library doing exactly what you need - I suppose nobody really needs it and it's easy to do. -
Hello everyone
I am working on a galil motor controller for a stepper motor. I have a fully functioning code for the stepper motor but I am now trying to create a data file to log the motors activity. I have created two attempts at appending to a file everytime the motor changes position. One of my attempts was a shift register using a while loop, it works the only problem with it is that it is constantly running. This makes the motor run constantly so if I set an angle itll try to keep setting it as long as the while loop is running.
Attached is my VI I have worked very hard at this. Please let me know how i could fix it
Thanks
Attachments:
galil mc USER rotationTESTING 5-13.vi 251 KB
galil mc USER rotation 5-12-14.vi 237 KBYou write to the file before setting the pointer to the end. Here, I made a very simple edit that should get you going.
There are only two ways to tell somebody thanks: Kudos and Marked Solutions
Unofficial Forum Rules and Guidelines
Attachments:
Append to File.PNG 50 KB -
Append string to stringbuffer in same line
I have stringbuffer in which i append string thiesestring is of variable lengt
has different value .I want that when i append string to stringbuffer it append
to same line .I use append method of stringbuffer.But the whole value is not
in same line it breaks into many line all lines are not of same size.
ThanksTry making the textarea larger and see if it still
shows on a new line...Textarea width is very large .There are many line break sometimes all lines
are of different length so there is no issue of word wrap .I check the output
sometimes it gives newline when it encounter space but not always .there are also spaces in single line .Sometimes it gives new line when it encounter >
and sometimes it continue in same line after enconter > .
Thanks -
Hello world,
I'm stuck in a predicament: The storage guys have asked me to reduce the frequency of backups on three of our instances to save bandwidth on the WAN when the backup files are copied across to another datacenter. The application owners do not want to backup
any less frequently.
We do daily full backups and Tr-log backups every 15 minutes throughout the day.
Storage have advised that the SAN only copies changes (ie new files or the changes to existing ones)
Is it possible/ would it be of any benefit, to backup and append an existing file? Can I do this with the logs as with the databases?
Thanks in advanceStorage have advised that the SAN only copies changes (ie new files or the changes to existing ones)
I am not very sure that it will pick changes from existing ones, I think if it sees the file is changed it will start coping as 1 big file and will not solve your purpose. You might get it reconfirm with storage on this. Also even if it does like you said
I wonder if next backup runs and file is still getting copied over then backup will start failing saying "file is in use".
If application owner is saying 15 min log backup then we cant reduce the frequency, but if you have some other drive/disk where you can divert tlog backup say for 2 hours then you can run differential backup every 2 hour which goes to SAN. You will be safe
even if something happen you have tlog on 1 drive and
differential get copied to other datacenter. (But point in time recovery will be issue as you will not have any tlog backups for restore)
I cant think of anything else to reduce frequency, but for bandwidth see if you can use compress(enterprise edition) or zip backup file to save bandwidth. -
[SOLVED] sed; string with file
Hi,
Is it possible the to replace a string with file contents, for example; i have the following XML file:
<?xml version="1.0" encoding="UTF-8"?>
<modification>
<id>Testing</id>
<version>0.0.1</version>
<vqmver required="true">2.5.0</vqmver>
<author><![CDATA[Dragon707]]></author>
<file name="template/a.tpl">
<operation error="log">
<search position="before"><![CDATA[
whooo
]]></search>
<add><![CDATA[
@include[src/script_whooo.js]
]]></add>
</operation>
</file>
<file name="template/b.tpl">
<operation error="log">
<search position="before"><![CDATA[
wheee
]]></search>
<add><![CDATA[
@include[src/script_wheee.js]
]]></add>
</operation>
</file>
</modification>
And the file src/script_whooo.js contains:
alert(1);
And the file src/script_wheee.js contains:
alert(2);
What i want is that the string "@include[src/script_whooo.js]" replaces the content with src/script_whooo.js. The expected output is then:
<?xml version="1.0" encoding="UTF-8"?>
<modification>
<id>Testing</id>
<version>0.0.1</version>
<vqmver required="true">2.5.0</vqmver>
<author><![CDATA[Dragon707]]></author>
<file name="template/a.tpl">
<operation error="log">
<search position="before"><![CDATA[
whooo
]]></search>
<add><![CDATA[
alert(1);
]]></add>
</operation>
</file>
<file name="template/b.tpl">
<operation error="log">
<search position="before"><![CDATA[
wheee
]]></search>
<add><![CDATA[
alert(2);
]]></add>
</operation>
</file>
</modification>
Last edited by Dragon707 (2014-11-14 12:06:22)Procyon wrote:
I don't think you can get the filename from the file into the 'r' command of sed without naming the filenames explicitly.
Try this in bash:
while read; do
[[ "$REPLY" =~ ^(.*)@include\[([^\]]*)\](.*)$ ]] &&
REPLY=${BASH_REMATCH[1]}$(cat "${BASH_REMATCH[2]}")${BASH_REMATCH[3]}
echo "$REPLY"
done < script.xml
It only does one @include[] per line though.
Thanks for your answer, i got it to work however, i still miss the tabs in the output.xml file. Is there a way to keep the tabs in the output.xml?
#!/bin/bash
INPUT="input.xml"
OUTPUT="output.xml"
echo "" > $OUTPUT
while read; do
[[ "$REPLY" =~ ^(.*)@include\[([^\]]*)\](.*)$ ]] &&
REPLY=${BASH_REMATCH[1]}$(cat "${BASH_REMATCH[2]}")${BASH_REMATCH[3]}
echo $REPLY >> $OUTPUT
done < $INPUT
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