Applet Impersonating a browser for file upload

Has anyone ever tried to make an applet talk to a servlet and upload a file (multipart encoded) to an appropriate servlet, if so, then I would like to learn how.
Thanks.

In Java Servlet Programming by Jason Hunter, published by O'Reilly, in Chapter 10 is a very good discussion and example of applet to servlet communication.
ps: I am referencing the first edition of this book. I think there is a second edition available now.

Similar Messages

Applet that will browse for files!

I have used applications in the past where you want to open a file in that application, such as a word document in a word processor. Is there that sort of facility available to Java. Say that I write an applet that excepts text in a box and the text could be found on a text file on the user's hard drive. Is there code that would open a dialog box where the user could navigate to the appropriate text file? Any code, web resource or suggestions very gratefuly received. Thanks, Dave.

Addendum ;)
You can actually sign applets with you own certficate. This will let your applet get the autorization to access the file sistem. People using that applet will just have to trust that selfmade certificate, since it won't be officially trusted. It's kind of a workaround so to speak, but it lets you provide an applet with no restrictions. And for free, no fee.
There's a thread on this forum explaing step by step how to proceed to sign an applet using a self-signed certificate.
Applet vs Application: Deployment and version control are very easy and require little effort while redeploying a java appliation to a lot of people is a serious issue, unless you provide the required "update" functionality by yourself (code it ;(
Another option would be using Java Webstart, but there again you would probably have to sign the application to get the necessary functionality (Security Managager again.)
Patrick

BI IP --- Planning function for File Upload

Hai All,
In BI IP , When I am trying to load the data (text file) by using Planning function for File Upload. I am getting an error message When I am clicking on Update .
Error Message : Inconsistent input parameter (parameter: <unknown>, value <unknown>).
In Text file I am using Tab Separation for each value
Anyone help me out.
Thanks,
Bhima

Hi Bhima
Try one of these; it should work:
1. If you are on SP 14 you would need to upgrade to SP 15. It would work fine
2. If not, then -
a] apply note 1070655 - Termination msg CL_RSPLFR_CONTROLLER =>GET_READ_WRITE_PROVIDS
b] Apply Correction Instruction 566059 [i.e: in Object - CL_RSPLFR_CONTROLLER GET_READ_WRITE_PROVIDS,
delete the block: l_r_alvl = cl_rspls_alvl=>factory( i_aggrlevel = p_infoprov ).
and insert block - l_r_alvl = cl_rspls_alvl=>factory( i_aggrlevel = i_infoprov ).
Goodluck
Srikanth

URGENT! File Upload Utility or a Custom UI for File Upload is needed!

Hi all,
I'm trying to find or develop a file upload utility or custom user interface rather than editing and adding file type item to a page. There is a free portlet for file upload in Knowledge Exchange resources, but it is for 3.0.9 release. I'm using portal 9.0.2.
I could not any sample about the new release. Also API such as wwsbr_api that is used to add item to content areas is out dated.
I create a page with a region for "items". When "edit" page and try to add an "file" type item the generated url is sth like this;
"http://host:7779/pls/portal/PORTAL.wwv_additem.selectitemtype****"
After selecting item type as a simple file autogenerated url is sth. like ;
"http://host:7779/pls/portal/PORTAL.wwv_add_wizard.edititem"
I made search about these API but could not find anything (in PDK PL/SQL API help, too).
I need this very urgent for a proof of consept study for a customer.
Thanks in advance,
Kind Regards,
Yeliz Ucer
Oracle Sales Consultant

Answered your post on the General forum.
Regards,
Jerry
PortalPM

'Browse For File' icon not working in Dreamweaver CS4

Hello All.
Ever since upgrading my copy of Dreamweaver from version 8 to CS4, I seem to have accounted an annoying bug (?)
If, for example, I want to change an image on a webpage, I would click the image in question on the screen and by using the Properties panel would select a new image by clicking the 'Browse For File' icon in the 'Source File Of Image' section of the panel.
Then I would select the new image, hit 'OK' and the image would be changed.
Now when I do this nothing happens - the original image remains and cannot be altered.
I now have to manually type the link of the new image into the 'Source File Of Image' field, which is a pain.
I have even disabled my firewall and anti-virus just in case these were somehow conflicting but still no change.
Any ideas anyone please?
Thanks,
Jon
Using Dreamweaver CS4 on Windows Vista Home Premium SP2

If Dreamweaver is behaving in an odd way, it frequently means that there is a corrupt personal configuration folder.
Close Dreamweaver, locate the personal configuration folder, and rename it.
When you restart Dreamweaver, it should create a new configuration folder with all the program defaults.
For details of how to find the configuration folder, see this page in the Dreamweaver FAQ.
Hope this solves your issue.

ALBPM 6.0 : The maximum size for file uploads has been exceeded.

Hi,
I use AquaLogic BPM Entreprise server to deploy my Process. When I try to publish a process on my server I get the following error:
An unexpected error ocurred.
The error's technical description is:
"javax.servlet.jsp.JspException: null"
Possible causes are:
The maximum size for file uploads has been exceeded.
If you are trying to publish an exported project you should publish it using the remote project option.
If you are trying to upload the participant's photo you should choose a smaller one.
An internal error has ocurred, please contact support attaching this page's source code.
Has someone resolve it?
Thank's.

Hi,
Sure you've figured this out by now, but when you get the "Maximum size for file uploads" error during publish consider:
1. if your export project file is over 10mb, use "Remote Project" (instead of "Exported Project") as the publication source. That way when you select the remote project, you will point to ".fpr" directory of the project you are trying to publish.
Most times your project is not on a network drive that the server has access to. If this is the case, upload the .exp file to the machine where the Process Administrator is running, then expand it in any directory (just unzip the file). Then, from the Process Administrator, use the option to publish a Remote Project by entering the path to the .fpr directory you just created when unzipping the project.
2. Check to see if you have cataloged any jars and marked them as non-versionable. Most of the times the project size is big just because of the external jar files. So as a best practice, when you do a project export select the option "include only-versionable jars", that will get reduce the project size considerably (usually to Kb's). Of course you have to manually copy the Jar files to your Ext folder.
hth,
Dan

Browse for file/img not working - Win 7

Browse for file/img not working still - Win 7
I have tried "run as Admin" and in "XP Compatibility mode" but still no luck fixing this issue in Win 7. Anyone have a potential fix so I can stop wasting time double checking every link/img on new work?
Thanks!

Are you referring to this issue?
Problem selecting local root folder in Vista & Windows 7
http://forums.adobe.com/thread/478327
If so, there's no fix yet and not likely to be one.

Snow Leopard Browse for file dialog bug in current Flash Player?

We have noticed a possible bug in the Flash Player within Mac's latest OS version Snow Leopard.
When a Browse for file dialog is initiated, upon returning to the browser. It's as if there is a layer above the flash app which stops interaction with the mouse. MouseOver events no longer take place and a click is require to remove this layer. If you move your mouse at all after the click this invisible layer returns limiting interaction.
We have tested this with 2 macs running snow leopard and the latest Flash Player. And also verified it is not an issue on Mac OSX previous to Snow Leopard.
It seems to effect only FF and Safari. Opera functions correctly.. Here is a video we created documenting the problem: http://www.conceptshare.com/flash_issue.mov
We have not had any customers complain about this yet. But if it's infact a bug, it's just a matter of time.
Any feedback would be appreciated.
Thanks,
Chris

Hi Scott,
Any workaround on this? I've tried numerous hacks to no avail. The only thing that works is to switch to another application and then switch back. When you say it fixed itself in safari would that be because of an update to safari or an update to the flash player? Also, have you tried the flash player beta on adobe labs? i think it is fixed in there but i don't believe users will update to a beta to fix this issue.

Session tracking for File Upload Servlet

Hey Friends,
I am developing a File Upload servlet and I need your help in certain matters .I have taken the servlet code from java-edge.com and am modifying it to give custom behaviour.I have a main page for upload (form upload)(lets call it form 1).If the file to be uploaded already exists on the server then a page is generated by the server saying that file already exists.(form 2)Now it is here(in form 2) that I want to provide an extra button which when submitted would recall the same servlet /or maybe another one and would provide the user for overriding the existing file.
Now as per the code I would set the Override flag to be false in the second form and false in the main form .
Given the case that it is a form based uploading servlet how do I maintain the user session when going to the next form or how do i pass the variables of the first form into second form .
I am also facing another problem that is how do i manage multiple file uploads at a time .This basic system allows only one file per upload .
P.S If someone could also throw some light on how to use the com.oreilly servlet (the latest version) it would be lovely but for now I want to focus on developing the current one

Hi Jocelyn,
I want to apologize firstly for the delay in my response.
I was seriously bogged down due to certain circumstances and so couldnt reply.Thanks a million for your prompt reply.I'll post the Html content here and you will find the servlet code as is at the following U.R.L
http://www.java-edge.com/Viewcode.asp?Value=serv012
Form1:
<HTML>
<HEAD>
<TITLE> Upload </TITLE>
</HEAD>
<BODY >
<h2>Upload Your File!</h2>
<form ENCTYPE="multipart/form-data" action="http://localhost:8080/servlet/Upload" method=post>
click <b> browse </b>to select the file <br>
<b> File:</b>
<input type="FILE" name="Filename" value="" MAXLENGTH=255 size=50><br>
Click here to upload!<input type=submit value=Upload>
<input type=hidden name=Directory value="G:/Workspace/Upload/">
<input type=hidden name=SuccessPage value="G:/Workspace/successpage.html">
<input type=hidden name="OverWrite" value="false">
<input type=hidden name="OverWritePage" value="">
</form>
</BODY>
</HTML>
Form 2
<HTML>
<HEAD>
<TITLE> Upload </TITLE>
</HEAD>
<BODY >
<h2>Upload Your File!</h2>
<form ENCTYPE="multipart/form-data" action="http://localhost:8080/servlet/Upload" method=post>
click <b> browse </b>to select the file <br>
<b> File:</b>
<input type="FILE" name="Filename" value="" MAXLENGTH=255 size=50><br>
Click here to upload!<input type=submit value=Upload>
<input type=hidden name=Directory value="G:/Workspace/Upload/">
<input type=hidden name=SuccessPage value="G:/Workspace/successpage.html">
<input type=hidden name="OverWrite" value="true">
<input type=hidden name="OverWritePage" value="G:/Workspace/overwritepage.html">
</form>
</BODY>
</HTML>
Now in Form 2 I would add another button which when clicked would prompt the user if he wishes to overwrite the page.
I am also posting the servlet code although I am sure u would prefer reading the one on the site
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class Upload extends HttpServlet
static final int Max = 102400;// max. size of the file can be 100K
String path;// stores path
String msg;// store message of success
//init method is called when servlet is first loaded
public void init(ServletConfig config)throws ServletException
super.init(config);
if(path == null)
path = "G:/Workspace/Upload/";
if(msg == null)
msg = "File successfully uploaded. Check out!";
public void doPost(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException
ServletOutputStream sos = null;
DataInputStream dis = null;
FileOutputStream fos = null;
try
resp.setContentType("text/plain");// return type of response is being set as plain
sos = resp.getOutputStream();// gets handle to the output stream
catch(IOException e)
System.out.println(e);
return;
try
String contentType = req.getContentType();// gets client's content type that should be multipart/form-data
if(contentType!=null && contentType.indexOf("multipart/form-data")!= -1)
     // gets handle to the input stream to get the file to be uploaded from client
     dis = new DataInputStream(req.getInputStream());
     // gets length of the content data
     int Length = req.getContentLength();
     if(Length>Max)// length of the content data is compared with max size set
     sos.println("sorry! file too large");
     sos.flush();
     return;
     //to store the contents of file in byte array
     byte arr[] = new byte[Length];
     int dataRead = 0;
     int totalData = 0;
     while(totalData <Length)
     dataRead = dis.read(arr,totalData,Length);
     totalData += dataRead;
     String data = new String(arr);//byte array converted to String
     arr = null;
     // gets boundary value
     int lastIndex = contentType.lastIndexOf("=");
     String boundary = contentType.substring(lastIndex+1,contentType.length());
     String dir = "";
     if(data.indexOf("name=Directory")>0)// the type ""Directory"" is searched in the web page
     dir = data.substring(data.indexOf("name=Directory"));
     //gets directory
     // the directory higher in the directory tree cannot be selected
     if(dir.indexOf("..")>0)
     sos.println("Error- the directory higher in the directory tree cannot be selected");
     return;
     String successPage="";
     if(data.indexOf("name=\"SuccessPage\"")>0)// the type ""SuccessPage"" is searched in the web page
     successPage =data.substring(data.indexOf("name=\"SuccessPage\""));
     // gets successpage
     String overWrite="";
     if(data.indexOf("name=\"OverWrite\"")>0)// the type ""Overwrite"" is searched in the web page
     overWrite =data.substring(data.indexOf("name=\"OverWrite\""));
     overWrite = overWrite.substring(overWrite.indexOf("\n")+1);
     overWrite = overWrite.substring(overWrite.indexOf("\n")+1);
     overWrite = overWrite.substring(0,overWrite.indexOf("\n")-1);//gets overwrite flag
     else
     //overWrite = "false";
     String overWritePage ="";
     if(data.indexOf("name=\"OverWritePage\"")>0)// the type ""OverwritePage"" is searched in the web page
     // ensures same file is not uploaded twice
     overWritePage =data.substring(data.indexOf("name=\"OverWritePage\""));
     overWritePage = overWritePage.substring(overWritePage.indexOf("\n")+1);
     overWritePage = overWritePage.substring(overWritePage.indexOf("\n")+1);
     overWritePage = overWritePage.substring(0,overWritePage.indexOf("\n")-1);// // gets overwritepage
     //gets upload file name
     String file =data.substring(data.indexOf("filename=\"")+10);
     file = file.substring(0,file.indexOf("\n"));
     file = file.substring(file.lastIndexOf("\\")+1,file.indexOf("\""));
     int position;//upload file's position
     position =data.indexOf("filename=\"");//find position of upload file section of request
     position =data.indexOf("\n",position)+1;//find position of content-disposition line
     position =data.indexOf("\n",position)+1;//find position of content-type line
     position =data.indexOf("\n",position)+1;//find position of blank line
     int location =data.indexOf(boundary,position)-4;//find position of next boundary marker
     data =data.substring(position,location);// uploaded file lies between position and location
     String fileName = new String(path + dir + file);// the complete path of uploadad file
     File check = new File(fileName);
/*************************CASE OVERRIDE ************************************/
     //String overwrite=req.getParameter("OverWrite");
     if(check.exists())// checks for existence of file
          if(overWrite.equals("false"))
                    if(overWritePage.equals(""))
                    sos.println("Sorry ,file already exists");
                    //return;
                    else
                    //overWritePage="G:/Workspace/overwritepage.html";
                    fos = new FileOutputStream(fileName);
                    fos.write(data.getBytes(),0,data.length());
                    //resp.sendRedirect(overWritePage);
                    sos.println("File Overridden");
          //return;
     File checkDir = new File(path + dir);
     if(!checkDir.exists())//checks for existence of directory
     checkDir.mkdirs();
fos = new FileOutputStream(fileName);
fos.write(data.getBytes(),0,data.length());
sos.println("File successfully uploaded");
if(check.exists())
          if(overWrite.equals("true"))
               fos = new FileOutputStream(fileName);
               fos.write(data.getBytes(),0,data.length());
               if(successPage.equals(""))
               sos.println(msg);
               sos.println("File successfully uploaded");// if success HTML page URL not received
               else
               successPage="G:/Workspace/successpage.html";
               resp.sendRedirect(successPage);
     else// incase request is not multipart
     sos.println("Not multipart");
}//END OF TRY BLOCK
catch(Exception e)
          try
          System.out.println(e);
          sos.println("unexpected error");
          catch(Exception f)
          System.out.println(f);
finally
          try
          fos.close();// file output stream closed
          catch(Exception f)
          System.out.println(f);
          try
          dis.close();// input stream to client closed
          catch(Exception f)
          System.out.println(f);
          try
          sos.close();// output stream to client closed
          catch(Exception f)
          System.out.println(f);
}//END OF DOPOST METHOD
} //END OF CLASS
Jocelyn the above code may have tid bit errors which u could understand.But I hope u get the overall idea of whats going on

Creating Progress Bar for File Upload

Hi, I'm trying to implement a progress bar indicator for a file upload in WebDynpro, without very good results.
I'm using a fileupload UI element, a TimerTrigger and a ProgressIndicator UI elements for this purpose.
It seems that using the fileupload UI element the iview is locked during the file upload, and therefore it prevents for the timer triggered action to be performed (this action updates the progress bar).
Additionally I havent been able to capture the transfered bytes from the upload. Maybe I'm using the wrong elements?
How could I achieve this. Has anyone done it?
I would really appreciate all the help I could get.
Homer Vargas

Hi,
Can anyone please tell me the way to upload file from client system to server.
The code i have is as follows:-
Jsp:-
function saveImage(){
     //projectname.javafilename
     var strStatus = "save";
     document.saveImageForm.action="/irj/servlet/prt/portal/prtroot/TestXML.TextImageLink?frmstatus="+ strStatus;
     document.saveImageForm.method="post";
     document.saveImageForm.submit();
<form name="saveImageForm" encrypt="multipart/form-data">
<table width="388" cellpadding="1" cellspacing="1" bgcolor="#F0F0F0" border='0'>
     <tr>
             <td><font color="blue" face="verdana" size="2">IMAGE:</font></td><td><input id="image" type="file" name="image" value=""/></td>
     </tr>
<tr>
     <td><input type="submit" name="submit" value="Submit" onclick="saveImage();"/></td>
     </tr>
</table>
</form>
now i am not getting what to write in java file
using IPortalComponentRequest.
Using the jsp file upload in tomcat is working but here it is not working
please help meee
Thanks in Advance
Regards
Sirisha

Error handling for file upload

HI Experts,
I have a question on file upload process in sap MDG-S.
Scenario : Upload the content from a CSV file using the file upload prcoess.
Query : For example if there are 5 records in the file and if there is an error in 3rd record what happens to the rest of the records i.e. 1,2 and 3,4.
a) Will record 1 and record 2 get posted and record 3,4 will be failed?
b) All 4 records will not be posted as there is one errored record.
Regards,
Charita.

Hi charitha,
As per your request if there is a error in any of the record in a particular file it does'nt loads any of the fields to the target, it will be terminated with an error.
As i checked with an example of Space delimited file in which 4th field has no spaces, and i used this file as source and run the job it does'nt return any values but terminated with an error.
let me know if i am right..
Regards,
Amjad

Emulating HTTP POST for file upload with J2ME

I have search through a lot of site and couldn't find the actual code. I try to emulate below html with J2ME.
<form method="POST" enctype="multipart/form-data" action="Insert.asp">
<td>File :</td><td>
<input type="file" name="file" size="40"></td></tr>
<td> </td><td>
<input type="submit" value="Submit"></td></tr>
</form>
here is my code :
HttpConnection c = null;
InputStream is = null;
OutputStream os = null;
byte[] filecontent = file byte content ...
try {
c = (HttpConnection)Connector.open("http://xx.com/insert.asp");
c.setRequestMethod(HttpConnection.POST);
c.setRequestProperty("Content-Length", String.valueOf(cmg.length + 15));
c.setRequestProperty("Content-type","multipart/form-data");
os = c.openOutputStream();
os.write("file=c:\\abc.png".getBytes());
os.write(filecontent);
os.flush();
I can emulate form with text field and it work, but when it come to file upload, above code not working, I don't know what to put for the outputstream, filename ? content ? or both ? since the html only has one field that is the "file" field. The file is actually store in rms with filename abc.png, and I just put in the c:\ for the server as a dump path.

File upload is more complicated then that... you need multi-part MIME formatting.... But I have just the code...
http://forum.java.sun.com/thread.jspa?forumID=256&threadID=451245

Validator for file upload component is not working !!

This validator method for a file upload component is throwing a java.lang.NullPointerException.
public void fileUpload1_validate(FacesContext context, UIComponent component, Object value) {
long size= fileUpload1.getUploadedFile().getSize();
if (size>65535){
throw new ValidatorException(new FacesMessage("Your image is too big!"));
Any help to solve this problem is very much appreciated.
Thanks.

Hi i have a fileUpload in a pop-up and the methods are :
public void fileUpload1_validate(FacesContext context, UIComponent component, Object value) {
try {
com.sun.rave.web.ui.model.UploadedFile uploadedFile = ((Upload)component).getUploadedFile();
long l_filesize = uploadedFile.getSize();
if ( l_filesize > 1000000)
throw new ValidatorException(new FacesMessage("File Size should be less than 1000000 bytes! It is" + l_filesize));
else {
String tipo = uploadedFile.getContentType();
if ( tipo.compareTo("application/word") == -1 )
if ( tipo.compareTo("application/rtf") == -1 )
if ( tipo.compareTo("application/pdf") == -1 )
throw new ValidatorException(new FacesMessage("Error : los tipos de archivo aceptados son PDF, WORD y RTF"));
} catch (Exception ex) {
this.mauvaisFichier = true;
error(ex.getMessage());
public String botonValidar_action() {
if ( !this.mauvaisFichier )
if ( this.fileUpload1.getUploadedFile() != null )
if ( this.fileUpload1.getUploadedFile().getSize() > 0 )
try {
this.getSessionBean1().getComunicacion().setArchivo( new javax.sql.rowset.serial.SerialBlob(this.fileUpload1.getUploadedFile().getBytes() ) );
this.getSessionBean1().getComunicacion().setTipoArchivo( this.fileUpload1.getUploadedFile().getOriginalName().substring(this.fileUpload1.getUploadedFile().getOriginalName().length() - 3 ) );
} catch(Exception e){
e.getMessage();
return null;
I have to put a boolean value because the first time, validation code doesn't function ( the method botonValidar_action() is called ) correctly. The error message appears but empty.
If I try next time then it's ok.
Thx for any issue.

Size limit for files uploaded to htmldb_application_files

Hi,
Is there any size limit for files which are to be uploaded to htmldb_application_files (and then stored as BLOB in db)?
Regards,
Tom

Hi Tom,
the only limitation is that the BLOB data type is 4GB
large.
So you can store max. 4 GB data in BLOB.Did you mean BFILE? Depending on the version, size limit is between 8TB and 128TB, as in the 10g2 documentation:
PL/SQL LOB Types
C.

Need help for file upload - reposted for Steve Muench

Hi Steve,
I have been involved developing a web application that requires a file upload operation. I have studied your example on Upload Text File and Image Example in the Not Yet Documented ADF Sample Applications section. I got the file upload part worked but could not get the original file name to populate the name field..i.e. if I upload myFile.txt to the database, the name field will be myFile.txt (not the name enter by user). Is there a way to capture the filename info? or is it possible to do so within ADF framework? I am using ADF/Struts/JSP with ORDDoc data type. Thanks very much.
Bill

Hello Nani,
You need to change any settings in 'FILE' transaction. This transaction is used to set up Logical file paths. ( In general it will be set already for your system).
You can use the following code.
DATA: LC_LOGICAL_FILENAME_EXPSRC LIKE RCGIEDIAL-IEFILE
                                                VALUE 'EHS_IMP_SOURCES'.
DATA:      L_EMERGENCY_FLAG            TYPE C.
DATA:      L_FILE_FORMAT               LIKE FILENAME-FILEFORMAT.
data : X_RCGIEDIAL LIKE RCGIEDIAL occurs 0 with HEADER LINE.
read the default pathname on application server
    CALL FUNCTION 'FILE_GET_NAME'
         EXPORTING
            CLIENT                  = SY-MANDT
              LOGICAL_FILENAME        = LC_LOGICAL_FILENAME_EXPSRC
              OPERATING_SYSTEM        = SY-OPSYS
            parameter_1             = ' '
            PARAMETER_2             = ' '
            USE_PRESENTATION_SERVER = ' '
            WITH_FILE_EXTENSION     = ' '
            USE_BUFFER              = ' '
         IMPORTING
              EMERGENCY_FLAG          = L_EMERGENCY_FLAG
              FILE_FORMAT             = L_FILE_FORMAT
              FILE_NAME               = X_RCGIEDIAL-IEFILE
         EXCEPTIONS
              FILE_NOT_FOUND          = 1
              OTHERS                  = 2.
    write :/ 'file format', L_FILE_FORMAT,
           / 'file name', X_RCGIEDIAL-IEFILE.
Thanks,
Jyothi

Applet Impersonating a browser for file upload

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