Application vs. Servlet

I have an application that parses an XML file whose URL is received as a parameter.
I have created a servlet that calls this application. I changed the main methods to callable "public void MethodName()". The servlet needs to call one class and then another. It will call the first class, but throws this error when attempting to call the second:
[Servlet Error]-[com/ibm/etools/xmlschema/beans/BaseType]: java.lang.NoClassDefFoundError: com/ibm/etools/xmlschema/beans/BaseType
Why would this class work in an application and not in a servlet??
Application code:
BeFreeRequestSAXParser.java
- this runs and then calls XMLDataParser.java
- XMLDataParser dp = new XMLDataParser();
dp.loadExistingInstance( uri.toString()); (Works great)
Serlvet code:
CustomersAlsoPurchased.java
- this calls BeFreeRequestSAXParser (works fine)
- BeFreeRequestSAXParser tries to call XMLDataParser but does not
work.
Any suggestions?

[Servlet
Error]-[com/ibm/etools/xmlschema/beans/BaseType]:
java.lang.NoClassDefFoundError:
com/ibm/etools/xmlschema/beans/BaseTypeIn general servlet containers use a modified class loader hierachy, you should consult the documentation of your servlet container. This matters, because you have to make sure any extra classes are made available when they are not part of the jdk or the container itself.
With tomcat you either have to place them in the folder shared by all contexts or in the WEB-INF/lib, or figure out another way.
http://jakarta.apache.org/tomcat/tomcat-4.1-doc/class-loader-howto.html

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How application call servlet via https

Hi guys
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I meant to give a code example in the last one, sorry.
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It will be very helpful to me if any one found me the solution for the following.
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How can i terminate web application from servletWhat do you mean by this?
also i want to close the browser window immediately
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Urgent:Please Help. Need to deploy web application with servlet:(

Tomcat 4.0 is already installed.
Trying to deploy a web application and invoke a servlet through it.
Here is the command I am using for deploying the application:
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The simplest solution would be to put the war file inside the webapps directory and restart the server. You should be able to access the app using the http://servername/app

Calling java application from servlet using servletexec servlets

We are using servletexec 3.0,IIS 5.0, sun Java SDK 1.3.1_12.
I have a servlet which works fine. This servlet is being called from the submit of the form in a html file.
It works fine.
But now i have to use a third party credit card application from my servlet.How can i do that.
I have added the third party jar files in the classpath of servletexec.
How can i use their methods.
Please let me know.

Something like this ?
import thirdparty.*;
import javax.servlet.http.*;
public class MyServlet extends HttpServlet {
public void doGet(HttpServletRequest request, HttpServletResponse response) {
ThirdPartyClass t = new ThirdPartyClass();
t.someMethod();
}

Calling Java application from servlet

Hi !
I'm trying to run a Java application from within a servlet with Tomcat 4. I'm using the Runtime.getRuntime ().exec () method. So the application is run in a different JVM as a subprocess of the servlet. I use ObjectInputStream and ObjectOutputStream and a serializable object to enable communication between the servlet and the application.
I tested the application and the serializable object with another Java application that works as the caller and it works fine. However, replacing the caller application with the servlet I get a StreamCorruptedException. The structure of the caller application and the servlet is the same.
My questions are:
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- Should I use an environment with the call to Runtime.getRuntime ().exec () ? How do I use it ?
- Is the called application forced to run in my servlet's context ?
- Is there a better way to do this ?
Thanks to all

Here's my code:
1. The serializable object:
// Object Obj
import java.io.*;
public class Obj implements Serializable
public int n;
public Obj ()
n = 0;
public Obj (int n)
this.n = n;
public String toString ()
return getClass ().getName () + " -> (n = " + n + ")";
2. The application Sub (subprogram)
// Application Sub
import java.io.*;
public class Sub
private static File f;
private static FileWriter fw;
public static void main (String [] args)
throws IOException, InterruptedException, ClassNotFoundException
ObjectInputStream ois;
ObjectOutputStream oos;
Obj obj;
ois = new ObjectInputStream (System.in);
obj = (Obj) ois.readObject ();
f = new File ("Sub.txt");
fw = new FileWriter (f);
fw.write (obj.toString ());
fw.close ();
oos = new ObjectOutputStream (System.out);
oos.writeObject (obj);
ois.close ();
oos.close ();
3. The application AMain (caller application)
// Application AMain
import java.io.*;
class AMain
private static File f;
private static FileWriter fw;
public static void main (String [] args)
throws IOException, ClassNotFoundException
Runtime r;
Process p;
ObjectInputStream ois;
ObjectOutputStream oos;
Obj obj, obj2;
r = Runtime.getRuntime ();
p = r.exec ("java Sub");
oos = new ObjectOutputStream (p.getOutputStream ());
obj = new Obj (5);
oos.writeObject (obj);
oos.flush ();
B.comunica (obj);
System.out.println ("AMain sends to Sub: " + obj.toString ());
try
p.waitFor ();
catch (InterruptedException e)
System.out.println ("Subprogram was interrupted");
System.out.println (e.toString ());
ois = new ObjectInputStream (p.getInputStream ());
System.out.print ("Sub sends to AMain: ");
obj2 = (Obj) ois.readObject ();
System.out.println (" " + obj2.toString ());
oos.close ();
ois.close ();
p.destroy ();
4. The servlet SMain (the calling servlet)
// Servlet SMain
import javax.servlet.*;
import javax.servlet.http.*;
import java.sql.*;
import java.io.*;
import java.util.*;
public class SMain extends HttpServlet
public void doPost (HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException
Runtime r;
Process p;
ObjectInputStream ois;
ObjectOutputStream oos;
Obj obj, obj2;
int state, i;
res.setContentType ("text/html");
ServletOutputStream out = res.getOutputStream ();
out.println ("<html>");
out.println ("<head><title>Sub</title></head>");
out.println ("<body>");
out.println ("Invoking subprogram...");
out.println (" ");
try
r = Runtime.getRuntime();
p = r.exec ("java -cp .;c:\\Programs\\Apache~1.0\\webapps\\SMain\\WEB-INF\\classes Sub");
out.println ("...invoked ");
oos = new ObjectOutputStream (p.getOutputStream ());
obj = new Obj (5);
oos.writeObject (obj);
oos.flush ();
out.println (" SMain sends to Sub: " + obj.toString () + " ");
try
p.waitFor ();
catch (InterruptedException e)
out.println (" Subprogram was interrupted ");
out.println (" " + e.toString () + " ");
state = p.exitValue ();
out.println (" Subprogram state: " + state + " ");
ois = new ObjectInputStream (p.getInputStream ());
out.print (" Sub sends to SMain: ");
obj2 = (Obj) ois.readObject ();
p.destroy ();
catch (SecurityException e)
out.println (" SecurityException ");
out.println (" " + e.toString () + " ");
catch (IOException e)
out.println (" IOException ");
out.println (" " + e.toString () + " ");
catch (Exception e)
out.println (" Exception ");
out.println (" " + e.toString () + " ");
out.println ("</body>");
out.println ("</html>");
So, as you can see, both application AMain and servlet SMain invoke application Sub and pass it the serializable object Obj. Oddly enough, application AMain works fine whereas servlet SMain throws a StreamCorruptedException exception.
johnpoole said:
�It's hard to guess what would cause the exception without seeing code, but the interaction between the processes would differ from that between two applications, because the servlet process is started with a different class loader. I'm not sure which one the jvm started by the call would use.�
How can I enforce that a System classloader be used in the call to Runtime.getRuntime ().exec () ? (I mean by System classloader a classloader equals to the one applications are launched from console).
johnpoole said
�Is there a reason why you aren't starting the second process manually and then connecting to it on a port?�
The idea is providing a Web interface for an application running in the server. The servlet is used to restrict access to this application but once access is granted (passing the servlet) the application should not be constrained.

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You don't program such things. You could use a tool like ANT to do the deployment for you and at the same time you can configure a cleanup task.

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Hi there
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I installed Survey application which demonstrate the servlet
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Hi
JDeveloper online help system has examples of configuring JavaWeb
server.
Goto Help system.
In the "tutorials" book you will find a subtopic "Servlet
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The other place is in the "Sample Applications" book you will
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regards
Chris tournier (guest) wrote:
: I installed Survey application which demonstrate the servlet
: architecture.
: The application works well with Jdevelopper 2.0
: The connection with the database server works.
: I installed the Sun Java Web Server 1.1.3 on my PC.
: The Java Web administrator works fine. I registered the 2
: servlets on the administrator but the JDBC connection failed.
: I obtained this resulting error page when try to use the
: SDSessionServlet
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: The servlet named "oracle.jdbc.driver.OracleDriver", at the
: requested URL
: http://gvawsgcf:8080/servlet/SDSessionServlet
: reported this exception:
: oracle.jdbc.driver.OracleDriver
: The administrator of this web server should resolve this
problem.
: What shall I do?
: Thanks in advance
null

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I will be very greatfull if you send me some URL's related to this.
Thanks,
babloo.

Hello,
Is every one busy or no one intrested to help me?
This is my Code:
import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
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Hi,
Thanx for ur help..
My application is a JSP one..
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Manipulating JDBC Datasources from a java application or servlet

How can i manipulate - add, delete, update - JDBC Datasources from a java applcation or servlet?

Maybe we can help, if you explain a little more.
What do you mean with:
How can i manipulate - add, delete, update - JDBC
Datasources from a java applcation or servlet?Do you want to
* create databases
* change a database's properties
* create or change tables
* create or change the rows in tables
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Thats all I can guess from what you told us. Tell more!

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I want to create a servlet in PAR application. This servlet should be capable of accessing the functions of other java files included in PAR Application. Servlet should be capable of accessing the functions say doContent(req, resp) of any class of PAR application.
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Please help and replies will be appreciated.

Hi,
Depending upon your usecase there are different ways to implement this logic.
Check this for example (Read my answer in this post):
https://forums.sdn.sap.com/thread.jspa?threadID=349151
Also check these senarios:
http://help.sap.com/saphelp_nw70/helpdata/en/42/9ddf20bb211d72e10000000a1553f6/frameset.htm
http://help.sap.com/saphelp_nw70/helpdata/en/42/9ddcc9bb211d72e10000000a1553f6/frameset.htm
Also the delegation may be interesting for you:
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Greetings,
Praveen Gudapati

Connecting to Remote EJB from Servlet in same application

Please help!
I was able to connect to SessionBeans and EJB from my sample java client in OCJ4 but when I try to do same thing from my web application using servlets, I get the below NullPointerException error.
The JNDI lookup works fine using java client but difficult from a servlet.
I am sure there is something I am missing.
Thanks
This is what I do in the servlet:
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// Standalone OC4J connection details
env.put(Context.INITIAL_CONTEXT_FACTORY, "com.evermind.server.rmi.RMIInitialContextFactory");
env.put(Context.SECURITY_PRINCIPAL, "admin");
env.put(Context.SECURITY_CREDENTIALS, "admin");
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And when I call the following procedure, it blow up at the line sessionEJB.getLineItem(new Long(1304));
sessionEJB is a class variable.
void processCatalogPage(HttpServletRequest request,
HttpServletResponse response,
ActionMapping mapping,
HttpSession session
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try {
ActionForward actFor = null;
String itemId = request.getParameter("id");
if ( itemId != null ) {
String[] itemIds = new String[1];
itemIds[0] = itemId;
sessionEJB.getLineItem(new Long(1304));
actFor = mapping.findForward("catalog");
return (mapping.findForward("success"));
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rvlet.java:507)
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va:740)
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oke(ServletRequestDispatcher.java:765)
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quest(HttpRequestHandler.java:790)
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Dec 11, 2004 11:45:24 PM org.apache.struts.action.RequestProcessor processExcept
ion
WARNING: Unhandled Exception thrown: class javax.ejb.EJBException

Avi,
Thanks for your response. I am actually returning a new InitialContext in a function call in the servlet. What I have noticed though is that JDeveloper creates two ear files for the application. One for the ejbs called ejb1.ear and another for the web files webapp1.ear. These are located in the applications subdirectory in OC4J directory.
I know I have two projects in the application, model and viewController. I am just trying to follow the MVC pattern.
In short, I don't think the web and the ejbs are in same ear file. I made the web project depend on the ejbs though. There is an option to set such. I don't know how to tell JDeveloper to put them all in one ear file.
I will appreciate any suggestion.
Thanks
Matilda

Application vs. Servlet

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