Assign any type payload(XML stream) a schema?

Is any posibility to do it in BPEL?
It can be done like this to write that payload into a file, and read it by assigning a schema to it. but I really don't won't do it in this way.
Any can help me out and thanks.
Regards,
Kerr

Hello Kerr,
I do not know, if this applies to your problem as I never used any type til now, but I read about assigning a type using the rename operation of an Assign activity. Perhaps this could be usefull:
http://download.oracle.com/docs/cd/B31017_01/integrate.1013/b28981/manipdoc.htm#sthref873
Regards,
Marco

Similar Messages

Is it possible to use List Type in XML schema within the SOA Rule author?

Is it possible to use List Type in XML schema within the SOA Suite Rule author? The reason is that with the following XSD, Rule author generates XML facts of type "List" for the element "ResultSet". Basically I want to check the Input facts (Input1, Input2, Input3) for some conditions and then assign action to the element Resultset of type List (array). The output Resultset can contain multiple values based on the input facts. My problem is that I am unable to see the ResultSet in the "Assign" action type of the action block. Is it possible to use the Resultset of type List with the Rule author or is there any limitation on the rule author and any workaround for this?
<schema xmlns="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.oracle.com/ns/TestMultipleOutputs"
elementFormDefault="qualified">
<element name="TestMultipleOutputs">
<complexType>
<sequence minOccurs="0">
<element name="Input1" type="string" minOccurs="0"/>
<element name="Input2" type="string" minOccurs="0"/>
<element name="Input3" type="string" minOccurs="0"/>
<element name="ResultSet" type="string" minOccurs="0"
maxOccurs="unbounded"/>
</sequence>
</complexType>
</element>
</schema>
--Thanks a lot

Hi Richard,
I have slightly modified the xml schema you suggested and was able to import into the rule author. the following is the modified XSD. Rule Author created a List type for the "ResultSet" . I still don't see "Resultset" in the assign action, so I tried creating RL function in order to assign the output to the "Resultset", but was unsuccessful so far. can you please let me know how to populate the resultset with the output values? Thanks a lot.
<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema attributeFormDefault="unqualified"
xmlns:ns1="http://www.oracle.com/ns/TestComplexOutputs"
xmlns:xsd="http://www.w3.org/2001/XMLSchema"
targetNamespace="http://www.oracle.com/ns/TestComplexOutputs"
xmlns:tns="http://www.oracle.com/ns/TestComplexOutputs"
elementFormDefault="qualified">
<xsd:element name="TestComplexOutputs">
<xsd:complexType>
<xsd:sequence minOccurs="0">
<xsd:element name="Input1" type="xsd:string" minOccurs="0"/>
<xsd:element name="Input2" type="xsd:string" minOccurs="0"/>
<xsd:element name="Input3" type="xsd:string" minOccurs="0"/>
<xsd:element name="ResultSet" type="tns:ResultSetType" minOccurs="0"
maxOccurs="unbounded"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:complexType name="ResultSetType">
<xsd:sequence>
<xsd:element name="ResultSet" type="tns:ResultSetStructure" minOccurs="1"
maxOccurs="unbounded"/>
</xsd:sequence>
</xsd:complexType>
<xsd:complexType name="ResultSetStructure">
<xsd:sequence>
<xsd:element name="ErrorReason">
<xsd:simpleType>
<xsd:restriction base="xsd:string"/>
</xsd:simpleType>
</xsd:element>
</xsd:sequence>
</xsd:complexType>
</xsd:schema>

XPath query error - xml extension in schema

Hi,
I am getting following error when i try to assign values to input xml payload before
invoke process.
"{http://schemas.xmlsoap.org/ws/2003/03/business-process/}selectionFailure" has been thrown.
<selectionFailure>
<part name="summary" >
<summary>XPath query string returns multiple nodes. According to BPEL4WS spec 1.1 section 14.3, The assign activity part and query /child::parameter/child::param1 should not return multipe nodes. Please check the BPEL source at line number "40" and verify the part and xpath query /child::parameter/child::param1. </summary>
</part>
</selectionFailure>
The generated XPath resolves to a single node only (tested using XMLSpy). The only reason i can think of is that the xml schema in wsdl is extending a base xml type to a new type.
It works fine if the extending xml type is merged with it's base type, and used as one single complex type.
------------------WSDL START
<?xml version="1.0" encoding="UTF-8"?>
<definitions xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:http="http://schemas.xmlsoap.org/wsdl/http/" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/" xmlns:mime="http://schemas.xmlsoap.org/wsdl/mime/" xmlns:tns="http://justdoit.ws.sunflower2.pageone.com" targetNamespace="http://justdoit.ws.sunflower2.pageone.com">
     <types>
          <xs:schema targetNamespace="http://justdoit.ws.sunflower2.pageone.com">
               <xs:complexType abstract="true" name="BaseObject">
                    <xs:sequence>
                         <xs:element name="param1" nillable="true" type="xs:string"/>
                         <xs:element name="param2" nillable="true" type="xs:string"/>
                    </xs:sequence>
               </xs:complexType>
               <xs:complexType name="FooBar">
                    <xs:complexContent>
                         <xs:extension base="tns:BaseObject">
                              <xs:sequence>
                                   <xs:element name="param3" nillable="true" type="xs:string"/>
                                   <xs:element name="param4" nillable="true" type="xs:string"/>
                                   <xs:element name="param5" nillable="true" type="xs:string"/>
                                   <xs:element name="param6" nillable="true" type="xs:string"/>
                              </xs:sequence>
                         </xs:extension>
                    </xs:complexContent>
               </xs:complexType>
          </xs:schema>
     </types>
     <message name="justDoItRequest">
          <part name="parameter" type="tns:FooBar"/>
     </message>
     <message name="justDoItResponse">
          <part name="parameter" type="tns:FooBar"/>
     </message>
     <portType name="justDoItPort">
          <operation name="justDoIt">
               <input message="tns:justDoItRequest"/>
               <output message="tns:justDoItResponse"/>
          </operation>
     </portType>
     <binding name="justDoItBinding" type="tns:justDoItPort">
          <soap:binding style="rpc" transport="http://schemas.xmlsoap.org/soap/http"/>
          <operation name="justDoIt">
               <soap:operation soapAction="tns:justDoIt"/>
               <input>
                    <soap:body use="literal"/>
               </input>
               <output>
                    <soap:body use="literal"/>
               </output>
          </operation>
     </binding>
     <service name="justDoItService">
          <port name="NewPort" binding="tns:justDoItBinding">
               <soap:address location="http://127.0.0.1:8080/axis/services/justDoIt"/>
          </port>
     </service>
</definitions>
------------------WSDL END
------------------BPEL START
          <assign name="assign-1">
               <copy>
                    <from variable="input" part="payload" query="/tns:justDoItRequest/tns:input1"></from>
                    <to variable="req" part="parameter" query="/parameter/param1"/>
               </copy>
          </assign>
          <invoke name="invoke-1" partnerLink="justDoIt" portType="tns:justDoItPort" operation="justDoIt" inputVariable="req" outputVariable="res"/>
------------------BPEL END
reg,
Amitoj.

I am also having the xml extension issue and since we are dealing with large WSDL files (exceed 40,000 lines) it would be ridiculous to move all extension classes to the base type (parent class). Has this bugged been looked at and when can it be resolved since it seems to be a major issue in JDeveloper.
Chris

Error consuming Web service - content type text/xml;charset=utf-8 of the response message does not match the content type of the binding

Hi all,
We are trying to interact with Documentum server through DFS exposed WCF which communicates through port 9443 and we are provided with documentum issued Public Key certificates. We have successfully imported the certificates in client machine and configured
the bindings as below in our .Net web application config file.
<system.serviceModel>
<bindings>
<wsHttpBinding>
<binding
name="ObjectServicePortBinding1">
<security
mode="Transport">
<transport
clientCredentialType="None"
proxyCredentialType="None"
realm=""
/>
<message
clientCredentialType="Certificate"
algorithmSuite="Default"
/>
</security>
</binding>
<binding
name="QueryServicePortBinding">
<security
mode="Transport">
<transport
clientCredentialType="None"
proxyCredentialType="None"
realm=""
/>
<message
clientCredentialType="Certificate"
algorithmSuite="Default"
/>
</security>
</binding>
</wsHttpBinding>
</bindings>
Also, we set the message encoding as MTOM and the wcf client object initialization code snippet is as below,
ObjectServicePortClient
serviceClient = new
ObjectServicePortClient(new
WSHttpBinding("ObjectServicePortBinding1"),
new
EndpointAddress(UriUtil.ObjectServiceUri));
if (serviceClient.Endpoint.Binding
is
WSHttpBinding)
   WSHttpBinding
wsBinding = serviceClient.Endpoint.Binding as
WSHttpBinding;
wsBinding.MessageEncoding =
"MTOM".Equals(transferMode) ?
WSMessageEncoding.Mtom :
WSMessageEncoding.Text;
serviceClient.Endpoint.Behaviors.Add(new
ServiceContextBehavior(Config.RepositoryName,
Config.DocumentumUserName,
Config.DocumentumPassword));
When we execute the above code, we are getting error message as below,
Exception: The content type text/xml;charset=utf-8 of the response message does not match the content type of the binding (multipart/related; type="application/xop+xml"). If using a custom encoder, be sure that the IsContentTypeSupported
method is implemented properly. The first 407 bytes of the response were: '<?xml version="1.0" ?><S:Envelope xmlns:S="http://schemas.xmlsoap.org/soap/envelope/"><S:Body><S:Fault xmlns:ns4="http://www.w3.org/2003/05/soap-envelope"><faultcode>S:VersionMismatch</faultcode><faultstring>Couldn't
create SOAP message. Expecting Envelope in namespace http://schemas.xmlsoap.org/soap/envelope/, but got http://www.w3.org/2003/05/soap-envelope </faultstring></S:Fault></S:Body></S:Envelope>'
Then, we changed the bindings as below
<system.serviceModel>
<bindings>
<wsHttpBinding>
<binding
name="ObjectServicePortBinding1">
<security
mode="Transport">
<transport
clientCredentialType="Certificate"
proxyCredentialType="None"
realm=""
/>
<message
clientCredentialType="Certificate"
algorithmSuite="Default"
/>
</security>
</binding>
<binding
name="QueryServicePortBinding">
<security
mode="Transport">
<transport
clientCredentialType="
Certificate"
proxyCredentialType="None"
realm=""
/>
<message
clientCredentialType="Certificate"
algorithmSuite="Default"
/>
</security>
</binding>
</wsHttpBinding>
</bindings>
We are getting another error message,
Exception: The client certificate is not provided. Specify a client certificate in ClientCredentials.
Any pointers on resolving this issue would be highly helpful.
Thanks

Hi Dhanasegaran,
As per your case, the corresponding details which may guide you to resolve this issue:
1. First of all, you can try to call the wcf service directly from the browser & check where it will point out the correct location.
2. In config file ,Set IncludeExceptionDetailInFaults to true to enable exception information to flow to clients for debugging purposes .
Set this to true only during development to troubleshoot a service like below :
<serviceBehaviors>
<behavior name="metadataAndDebugEnabled">
    <serviceDebug
      includeExceptionDetailInFaults="true"
/>
    <serviceMetadata
      httpGetEnabled="true"
      httpGetUrl=""
/>
</behavior>
</serviceBehaviors>
3. I suggest you to change that <security mode ="TransportWithMessageCredential"> instead of <security mode ="Transport">
for more information, refer the following link :
https://msdn.microsoft.com/en-us/library/aa354508(v=vs.110).aspx

Mapping Java Types to XML Types

Hi, I have a small doubt in web services,
1) how a java data type can match with xml data type in wsdl,
2) how and where the java program can find the matching java
    data type to xml data type and vice versa
3) whether any mechanism is available for this data conversion?
4) where can i find that one?
Please advice me
Regards
Marimuthu.N

Hi Marimuthu.N,
My answers for your question, Kindly let me know if you need some more inputs.
+1) how a java data type can match with xml data type in wsdl,+
In SOAP 1.1 you have the following data types which is in XSD(XML Schema Definition), the same data type is also available in Java. For example (string, normalizedstring in xml is available as java.lang.String)
The complete list can be found in the table below.
XSD to Java Mapping.
XSD Type--------------------------------Java Type
base64Binary----------------------------byte[]
hexBinary---------------------------------byte[]
boolean------------------------------------Boolean
byte-----------------------------------------Byte
dateTime----------------------------------java.util.Calendar
date-----------------------------------------java.util.Calendar
time-----------------------------------------java.util.Calendar
decimal------------------------------------java.math.BigDecimal
double-------------------------------------Double
float-----------------------------------------Float
hexBinary---------------------------------byte[]
int--------------------------------------------Int
unsignedShort---------------------------Int
integer--------------------------------------java.math.BigInteger
long------------------------------------------Long
unsignedInt-------------------------------Long
QName-------------------------------------javax.xml.namespace.QName
short----------------------------------------Short
unsignedByte---------------------------Short
string---------------------------------------java.lang.String
anySimpleType-------------------------java.lang.String
+2) how and where the java program can find the matching java+
data type to xml data type and vice versa
Here is my WSDL which has a method getHello --> Pass Input as String --> Get Response as String.
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions targetNamespace="http://zackria.googlepages.com" xmlns:apachesoap="http://xml.apache.org/xml-soap" xmlns:impl="http://zackria.googlepages.com" xmlns:intf="http://zackria.googlepages.com" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsdlsoap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">

<wsdl:types>
<schema elementFormDefault="qualified" targetNamespace="http://zackria.googlepages.com" xmlns="http://www.w3.org/2001/XMLSchema">
   <element name="getHello">
    <complexType>
     <sequence>
      <element name="s" type="xsd:string"/>
     </sequence>
    </complexType>
   </element>
   <element name="getHelloResponse">
    <complexType>
     <sequence>
      <element name="getHelloReturn" type="xsd:string"/>
     </sequence>
    </complexType>
   </element>
</schema>
</wsdl:types>
   <wsdl:message name="getHelloResponse">
      <wsdl:part element="impl:getHelloResponse" name="parameters"/>
   </wsdl:message>
   <wsdl:message name="getHelloRequest">
      <wsdl:part element="impl:getHello" name="parameters"/>
   </wsdl:message>
   <wsdl:portType name="Test">
      <wsdl:operation name="getHello">
         <wsdl:input message="impl:getHelloRequest" name="getHelloRequest"/>
         <wsdl:output message="impl:getHelloResponse" name="getHelloResponse"/>
      </wsdl:operation>
   </wsdl:portType>
   <wsdl:binding name="TestSoapBinding" type="impl:Test">
      <wsdlsoap:binding style="document" transport="http://schemas.xmlsoap.org/soap/http"/>
      <wsdl:operation name="getHello">
         <wsdlsoap:operation soapAction=""/>
         <wsdl:input name="getHelloRequest">
            <wsdlsoap:body use="literal"/>
         </wsdl:input>
         <wsdl:output name="getHelloResponse">
            <wsdlsoap:body use="literal"/>
         </wsdl:output>
      </wsdl:operation>
   </wsdl:binding>
   <wsdl:service name="TestService">
      <wsdl:port binding="impl:TestSoapBinding" name="Test">
         <wsdlsoap:address location="http://localhost:8080/TestWebService/services/Test"/>
      </wsdl:port>
   </wsdl:service>
</wsdl:definitions>I use apache axis for the client side code. I also suggest to start using this to get quickly into SOA(Service Oriented Architecture)
package com.googlepages.zackria;
import org.apache.axis.client.Call;
import org.apache.axis.client.Service;
import javax.xml.namespace.QName;
* TestClient for Webservice
* @author $author$Mohammed Zackria
* @version $Revision$1.00
public class TestClient {
     * main method
     * @param args pass nothing as far now
    public static void main(String[] args) {
        try {
            String endpoint = "http://localhost:8080/TestWebService/services/Test";
            Service service = new Service();
            Call call = (Call) service.createCall();
            call.setTargetEndpointAddress(new java.net.URL(endpoint));
            call.setOperationName(new QName("http://zackria.googlepages.com", "getHello"));
            //String Conversion
            String ret = (String) call.invoke(new Object[] { "Zack" });
            System.out.println("Sent 'Zack', got '" + ret + "'");
        } catch (Exception e) {
            System.err.println(e.toString());
}+3) whether any mechanism is available for this data conversion?+
Check the above code which has the following portion
//String Conversion
String ret = (String) call.invoke(new Object[] { "Zack" });
By default APACHE Axis returns Object Array which can be Casted to your WSDL defined data type.
+4) where can i find that one?+
[Eclipse Webservice|http://www.eclipse.org/webtools/jst/components/ws/1.5/tutorials/BottomUpWebService/BottomUpWebService.html]
Hope this helps out, Kindly Let me know if you need some more or if i have not answered your question.
Regards,
Zack
Edited by: zack on Nov 22, 2008 1:47 PM
Edited by: zack on Nov 22, 2008 1:49 PM

Webservice Consume Proxy error : XML stream: 'document not wellformed'.

Dear All ,
I facing problem when i try to test my service consumer .
Its end with error message :
Error when processing Web service call
Error when calling SOAP Runtime functions: CX_SXML_PARSE_ERROR:An exception with the type CX_SXML_PARSE_ERROR occurred, but was
An exception with the type CX_SXML_PARSE_ERROR occurred, but was neither handled locally, nor declared in a RAISING clause
Error while parsing an XML stream: 'document not wellformed'.
Need your help guys.
Thanks,
Ikrar
Edited by: ikrarSAP on Jun 17, 2011 2:34 PM

Hi,
Actually i dont have any idea on BOBJ. But this kind error usually occurs in the following cases:
The parameters you called from web service do not match with parameters using by tables at R/3. So, it can not parse.
A Web service's WSDL file is not well-formed because of an element specifying two attributes with the same name, the client application produces this error.
Either there is indeed an issue with how the XML is being encoded and then decoded on other end or there's a step that is being missed somewhere.
Thanks & Regards,
Sai Kiran Rao.

JAXB: How to unmarshal from xml contains two schemas?

Hi, all.
My question is in subject.
Ex.)
schema1.xsd:
(snip)...
<xsd:element name="xxx">
<xsd:complexType>
<xsd:sequence>
<xsd:any namespace="##other" minOccurs="0" maxOccurs="unbounded" processContents="lax"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
...(snip)
schema2.xsd:
(snip)...
<xsd:element name="yyy">
<xsd:complexType>
<xsd:sequence>
<xsd:element ref="zzz" minOccurs="1" maxOccurs="1"/>
</xsd:sequence>
</xsd:complexType>
</xsd:element>
<xsd:element name="zzz" type="xsd:string"/>
if I have a xml like the following, xml validation is correct:
sample.xml:
(snip)...
<ns1:xxx xmlns:ns1="...(schema1.xsd)...">
<ns2:yyy xmlns:ns2="...(schema2.xsd)...">
<ns2:zzz>SAMPLE</ns2:zzz>
</ns2:yyy>
</ns1:xxx>
I want to unmarshal from this xml using JAXB, but actually ths xxx didn't have any tag in List class given getAny() method, because xxx doesn't know about yyy, I think.
These schemas cannot change as requirements of customer.
How to unmarshal from xml contains two schemas using JAXB?
tx.

I solved it myself.
JAXBContext can be specified many context path at same time.
Ex.)
context = JAXBContext.newInstance("package1:package2:package3...");
So, unmarshaller can know how to choose what be instanced.
tx.

The system could not find a javax.ws.rs.ext.MessageBodyWriter or a DataSourceProvider class for the com.rest.assignment.EmpBean type and application/json mediaType. Ensure that a javax.ws.rs.ext.MessageBodyWriter exists in the JAX-RS application for the

Hi,
Im trying to create a Rest WS with a @GET method that will return me an Emp object. I need the output as a JSON string.
I have created a dynamic web project and added javax RS jars:
When im trying to run this, i'm getting the below mentioned error:
FlushResultHa E org.apache.wink.server.internal.handlers.FlushResultHandler handleResponse The system could not find a javax.ws.rs.ext.MessageBodyWriter or a DataSourceProvider class for the com.rest.assignment.EmpBean type and application/json mediaType. Ensure that a javax.ws.rs.ext.MessageBodyWriter exists in the JAX-RS application for the type and media type specified.
RequestProces I org.apache.wink.server.internal.RequestProcessor logException The following error occurred during the invocation of the handlers chain: WebApplicationException (500 - Internal Server Error)
Please help as im stuck with this from long.
Thanks in advance.
Below is the code for my service class:
package com.rest.assignment;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Enumeration;
import java.util.HashSet;
import java.util.Properties;
import java.util.Set;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.Application;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
@Path("/restService")
public class RestService extends Application {
    @GET
    @Path("/getEmpDetails")
    @Produces(MediaType.APPLICATION_JSON)
    public Response getStringResponse()
        EmpBean empBean = new EmpBean();
        String filePath = "C:/Program Files/IBM/workspace/HelloWorld/src/com/rest/resources/EmpData.properties";
        Properties properties = new Properties();
        try {
            properties.load(new FileInputStream(filePath));
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
         Enumeration e = properties.propertyNames();
         String result="";
        String[] empDetailsArr;
        while (e.hasMoreElements()) {
          String key = (String) e.nextElement();
          String empDetails = properties.getProperty(key);
          empDetailsArr=empDetails.split(",");
          empBean.setFirstName(empDetailsArr[0]);
          empBean.setLastName(empDetailsArr[1]);
          empBean.setEmpId(empDetailsArr[2]);
          empBean.setDesignation(empDetailsArr[3]);
          empBean.setSkillSet(empDetailsArr[4]);
          result = empDetailsArr[1];
        //return empBean;
        return Response.ok(empBean).type(MediaType.APPLICATION_JSON_TYPE).build();
    @Override
    public Set<Class<?>> getClasses() {
        Set<Class<?>> classes = new HashSet<Class<?>>();
        classes.add(RestService.class);
        classes.add(EmpBean.class);
        return classes;
and my empBean goes like this:
package com.rest.assignment;
public class EmpBean {
    private String firstName;
    private String lastName;
    private String empId;
    private String designation;
    private String skillSet;
    public String getFirstName() {
        return firstName;
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    public String getLastName() {
        return lastName;
    public void setLastName(String lastName) {
        this.lastName = lastName;
    public String getEmpId() {
        return empId;
    public void setEmpId(String empId) {
        this.empId = empId;
    public String getDesignation() {
        return designation;
    public void setDesignation(String designation) {
        this.designation = designation;
    public String getSkillSet() {
        return skillSet;
    public void setSkillSet(String skillSet) {
        this.skillSet = skillSet;
Web.xml goes like this:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>restWS</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>REST</servlet-name>
<servlet-class>com.ibm.websphere.jaxrs.server.IBMRestServlet</servlet-class>
<init-param>
   <param-name>javax.ws.rs.Application</param-name>
   <param-value>com.rest.assignment.RestService</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>REST</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
When i try to return a string from my get method, it gives me a proper response. i get this exception when im trying to return a JSON response.

Hi,
Im trying to create a Rest WS with a @GET method that will return me an Emp object. I need the output as a JSON string.
I have created a dynamic web project and added javax RS jars:
When im trying to run this, i'm getting the below mentioned error:
FlushResultHa E org.apache.wink.server.internal.handlers.FlushResultHandler handleResponse The system could not find a javax.ws.rs.ext.MessageBodyWriter or a DataSourceProvider class for the com.rest.assignment.EmpBean type and application/json mediaType. Ensure that a javax.ws.rs.ext.MessageBodyWriter exists in the JAX-RS application for the type and media type specified.
RequestProces I org.apache.wink.server.internal.RequestProcessor logException The following error occurred during the invocation of the handlers chain: WebApplicationException (500 - Internal Server Error)
Please help as im stuck with this from long.
Thanks in advance.
Below is the code for my service class:
package com.rest.assignment;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.util.Enumeration;
import java.util.HashSet;
import java.util.Properties;
import java.util.Set;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.Application;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
@Path("/restService")
public class RestService extends Application {
    @GET
    @Path("/getEmpDetails")
    @Produces(MediaType.APPLICATION_JSON)
    public Response getStringResponse()
        EmpBean empBean = new EmpBean();
        String filePath = "C:/Program Files/IBM/workspace/HelloWorld/src/com/rest/resources/EmpData.properties";
        Properties properties = new Properties();
        try {
            properties.load(new FileInputStream(filePath));
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
         Enumeration e = properties.propertyNames();
         String result="";
        String[] empDetailsArr;
        while (e.hasMoreElements()) {
          String key = (String) e.nextElement();
          String empDetails = properties.getProperty(key);
          empDetailsArr=empDetails.split(",");
          empBean.setFirstName(empDetailsArr[0]);
          empBean.setLastName(empDetailsArr[1]);
          empBean.setEmpId(empDetailsArr[2]);
          empBean.setDesignation(empDetailsArr[3]);
          empBean.setSkillSet(empDetailsArr[4]);
          result = empDetailsArr[1];
        //return empBean;
        return Response.ok(empBean).type(MediaType.APPLICATION_JSON_TYPE).build();
    @Override
    public Set<Class<?>> getClasses() {
        Set<Class<?>> classes = new HashSet<Class<?>>();
        classes.add(RestService.class);
        classes.add(EmpBean.class);
        return classes;
and my empBean goes like this:
package com.rest.assignment;
public class EmpBean {
    private String firstName;
    private String lastName;
    private String empId;
    private String designation;
    private String skillSet;
    public String getFirstName() {
        return firstName;
    public void setFirstName(String firstName) {
        this.firstName = firstName;
    public String getLastName() {
        return lastName;
    public void setLastName(String lastName) {
        this.lastName = lastName;
    public String getEmpId() {
        return empId;
    public void setEmpId(String empId) {
        this.empId = empId;
    public String getDesignation() {
        return designation;
    public void setDesignation(String designation) {
        this.designation = designation;
    public String getSkillSet() {
        return skillSet;
    public void setSkillSet(String skillSet) {
        this.skillSet = skillSet;
Web.xml goes like this:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<display-name>restWS</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>REST</servlet-name>
<servlet-class>com.ibm.websphere.jaxrs.server.IBMRestServlet</servlet-class>
<init-param>
   <param-name>javax.ws.rs.Application</param-name>
   <param-value>com.rest.assignment.RestService</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>REST</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
</web-app>
When i try to return a string from my get method, it gives me a proper response. i get this exception when im trying to return a JSON response.

XML stream utf-8 encoding

Hi folks,
I'm trying to establish a CSTRING XML stream with utf-8 encoding. I've only managed to do this in XSTRING so far.
If i use this coding, i get a binary output.
DATA: gt_result TYPE TABLE OF string,
         l_result type string.
constants: encoding type string value 'UTF-8'.
data: g_ixml type ref to if_ixml.
data: g_stream_factory type ref to IF_IXML_STREAM_FACTORY.
data: g_encoding type ref to if_ixml_encoding.
g_ixml = cl_ixml=>create( ).
g_stream_factory = g_ixml->CREATE_STREAM_FACTORY( ).
g_encoding = g_ixml->create_encoding( character_set = 'utf-8'
                                        byte_order = 0 ).
data: resstream type ref to if_ixml_ostream.
resstream = g_stream_factory->create_ostream_cstring( l_result ).
call method resstream->set_encoding
    EXPORTING
      encoding = g_encoding.
* XML Transformieren
CALL TRANSFORMATION id_indent
    SOURCE     itab = it_Itab
    RESULT XML resstream.
* Temporär, XML File erzeugen
refresh gt_result.
APPEND l_result TO gt_result.
CALL METHOD cl_gui_frontend_services=>gui_download
    EXPORTING
      filename         = 'c:test.xml'
    CHANGING
      data_tab         = gt_result
    EXCEPTIONS
      file_write_error = 1.
Without this expression :
g_encoding = g_ixml->create_encoding(
             character_set = 'utf-8' byte_order = 0 ).
I get a cstring stream, but in utf-16.
My question now is, how do I manage to get a utf-8 encoded stream in cstring?
Thanks for your help.
Cheers
Daniel

This is the solution:
METHOD TRANSFORM_XML.
TYPE-POOLS TRUXS.
*********************** XML ***********************************
DATA: GT_RESULT TYPE TABLE OF STRING,
         L_RESULT TYPE ETXML_LINE_STR.
CONSTANTS: ENCODING     TYPE STRING VALUE 'UTF-8'.
DATA: G_IXML TYPE REF TO IF_IXML.
DATA: G_STREAM_FACTORY TYPE REF TO IF_IXML_STREAM_FACTORY.
DATA: G_ENCODING TYPE REF TO IF_IXML_ENCODING.
G_IXML = CL_IXML=>CREATE( ).
G_STREAM_FACTORY = G_IXML->CREATE_STREAM_FACTORY( ).
G_ENCODING = G_IXML->CREATE_ENCODING( CHARACTER_SET = ENCODING
                                        BYTE_ORDER = 0 ).
DATA: RESSTREAM TYPE REF TO IF_IXML_OSTREAM.
RESSTREAM = G_STREAM_FACTORY->CREATE_OSTREAM_XSTRING( L_RESULT ).
CALL METHOD RESSTREAM->SET_ENCODING
    EXPORTING
      ENCODING = G_ENCODING.
* XML Transformieren
CALL TRANSFORMATION ID_INDENT
    SOURCE     ITAB = IT_ITAB
    RESULT XML RESSTREAM.
* XString to String
CALL FUNCTION 'ECATT_CONV_XSTRING_TO_STRING'
    EXPORTING
      IM_XSTRING = L_RESULT
      IM_ENCODING = 'UTF-8'
    IMPORTING
      EX_STRING   = E_XML.
* Temporär, XML File erzeugen
refresh gt_result.
APPEND e_xml TO gt_result.
CALL METHOD cl_gui_frontend_services=>gui_download
    EXPORTING
      filename         = 'c:test.xml'
    CHANGING
      data_tab         = gt_result
    EXCEPTIONS
      file_write_error = 1.
ENDMETHOD.
How can I give the 10 points to myself?
Cheers
Daniel

Do I need to have any type of anti-virus or malware, spyware protection for my Macbook Pro?

My Macbook is a year old. When I bought it, I was told by several people that I would not need any type of anti-virus software or anything to protect my computer because Mac did not get infected that often. However, I have had people today tell me that I do need protection for my computer. My Mac runs about as good as the day I got it, but I really don't want anything to happen to it. If I need to get an anti-virus, or malware/spyware software, what programs would y'all recomend? I am just looking for information. Thanks!

1. This comment applies to malicious software ("malware") that's installed unwittingly by the victim of a network attack. It does not apply to software, such as keystroke loggers, that may be installed deliberately by an intruder who has hands-on access to the victim's computer. That threat is in a different category, and there's no easy way to defend against it. If you have reason to suspect that you're the target of such an attack, you need expert help.
If you find this comment too long or too technical, read only sections 5, 6, and 10.
OS X now implements three layers of built-in protection specifically against malware, not counting runtime protections such as execute disable, sandboxing, system library randomization, and address space layout randomization that may also guard against other kinds of exploits.
2. All versions of OS X since 10.6.7 have been able to detect known Mac malware in downloaded files, and to block insecure web plugins. This feature is transparent to the user, but internally Apple calls it "XProtect." The malware recognition database is automatically checked for updates once a day; however, you shouldn't rely on it, because the attackers are always at least a day ahead of the defenders.
The following caveats apply to XProtect:
It can be bypassed by some third-party networking software, such as BitTorrent clients and Java applets.
It only applies to software downloaded from the network. Software installed from a CD or other media is not checked.
3. Starting with OS X 10.7.5, there has been a second layer of built-in malware protection, designated "Gatekeeper" by Apple. By default, applications and Installer packages downloaded from the network will only run if they're digitally signed by a developer with a certificate issued by Apple. Software certified in this way hasn't necessarily been tested by Apple, but you can be reasonably sure that it hasn't been modified by anyone other than the developer. His identity is known to Apple, so he could be held legally responsible if he distributed malware. That may not mean much if the developer lives in a country with a weak legal system (see below.)
Gatekeeper doesn't depend on a database of known malware. It has, however, the same limitations as XProtect, and in addition the following:
It can easily be disabled or overridden by the user.
A malware attacker could get control of a code-signing certificate under false pretenses, or could simply ignore the consequences of distributing codesigned malware.
An App Store developer could find a way to bypass Apple's oversight, or the oversight could fail due to human error.
For the reasons given above, App Store products, and other applications recognized by Gatekeeper as signed, are safer than others, but they can't be considered absolutely safe. "Sandboxed" applications may prompt for access to private data, such as your contacts, or for access to the network. Think before granting that access. OS X security is based on user input. Never click through any request for authorization without thinking.
4. Starting with OS X 10.8.3, a third layer of protection has been added: a "Malware Removal Tool" (MRT). MRT runs automatically in the background when you update the OS. It checks for, and removes, malware that may have evaded the other protections via a Java exploit (see below.) MRT also runs when you install or update the Apple-supplied Java runtime (but not the Oracle runtime.) Like XProtect, MRT is presumably effective against known attacks, but maybe not against unknown attacks. It notifies you if it finds malware, but otherwise there's no user interface to MRT.
5. XProtect, Gatekeeper, and MRT reduce the risk of malware attack, but they're not absolute protection. The first and best line of defense is always your own intelligence. With the possible exception of Java exploits, all known malware circulating on the Internet that affects a fully-updated installation of OS X 10.6 or later takes the form of so-called "trojan horses," which can only have an effect if the victim is duped into running them. The threat therefore amounts to a battle of wits between you and the malware attacker. If you're smarter than he thinks you are, you'll win.
That means, in practice, that you never use software that comes from an untrustworthy source, or that does something inherently untrustworthy. How do you know what is trustworthy?
Any website that prompts you to install a “codec,” “plug-in,” "player," "extractor," or “certificate” that comes from that same site, or an unknown one, is untrustworthy.
A web operator who tells you that you have a “virus,” or that anything else is wrong with your computer, or that you have won a prize in a contest you never entered, is trying to commit a crime with you as the victim. (Some reputable websites did legitimately warn visitors who were infected with the "DNSChanger" malware. That exception to this rule no longer applies.)
Pirated copies or "cracks" of commercial software, no matter where they come from, are unsafe.
Software of any kind downloaded from a BitTorrent or from a Usenet binary newsgroup is unsafe.
Software that purports to help you do something that's illegal or that infringes copyright, such as saving streamed audio or video for reuse without permission, is unsafe. All YouTube "downloaders" are in this category, though not all are necessarily harmful.
Software with a corporate brand, such as Adobe Flash Player, must be downloaded directly from the developer’s website. If it comes from any other source, it's unsafe.
Even signed applications, no matter what the source, should not be trusted if they do something unexpected, such as asking for permission to access your contacts, your location, or the Internet for no obvious reason.
6. Java on the Web (not to be confused with JavaScript, to which it's not related, despite the similarity of the names) is a weak point in the security of any system. Java is, among other things, a platform for running complex applications in a web page, on the client. That was always a bad idea, and Java's developers have proven themselves incapable of implementing it without also creating a portal for malware to enter. Past Java exploits are the closest thing there has ever been to a Windows-style virus affecting OS X. Merely loading a page with malicious Java content could be harmful.
Fortunately, client-side Java on the Web is obsolete and mostly extinct. Only a few outmoded sites still use it. Try to hasten the process of extinction by avoiding those sites, if you have a choice. Forget about playing games or other non-essential uses of Java.
Java is not included in OS X 10.7 and later. Discrete Java installers are distributed by Apple and by Oracle (the developer of Java.) Don't use either one unless you need it. Most people don't. If Java is installed, disable it — not JavaScript — in your browsers.
Regardless of version, experience has shown that Java on the Web can't be trusted. If you must use a Java applet for a task on a specific site, enable Java only for that site in Safari. Never enable Java for a public website that carries third-party advertising. Use it only on well-known, login-protected, secure websites without ads. In Safari 6 or later, you'll see a lock icon in the address bar with the abbreviation "https" when visiting a secure site.
Follow the above guidelines, and you’ll be as safe from malware as you can practically be. The rest of this comment concerns what you should not do to protect yourself from malware.
7. Never install any commercial "anti-virus" or "Internet security" products for the Mac, as they all do more harm than good, if they do any good at all. Any database of known threats is always going to be out of date. Most of the danger is from unknown threats. If you need to be able to detect Windows malware in your files, use the free software ClamXav— nothing else.
Why shouldn't you use commercial "anti-virus" products?
Their design is predicated on the nonexistent threat that malware may be injected at any time, anywhere in the file system. Malware is downloaded from the network; it doesn't materialize from nowhere.
In order to meet that nonexistent threat, the software modifies or duplicates low-level functions of the operating system, which is a waste of resources and a common cause of instability, bugs, and poor performance.
By modifying the operating system, the software itself may create weaknesses that could be exploited by malware attackers.
8. ClamXav doesn't have these drawbacks. That doesn't mean it's entirely safe. It may report email messages that have "phishing" links in the body, or Windows malware in attachments, as infected files, and offer to delete or move them. Doing so will corrupt the Mail database. The messages should be deleted from within the Mail application.
ClamXav is not needed, and should not be relied upon, for protection against OS X malware. It's useful only for detecting Windows malware. Windows malware can't harm you directly (unless, of course, you use Windows.) Just don't pass it on to anyone else.
A Windows malware attachment in email is usually easy to recognize. The file name will often be targeted at people who aren't very bright; for example:
♥♥♥♥♥♥♥♥♥♥♥♥♥♥!!!!!!!H0TBABEZ4U!!!!!!!.AVI♥♥♥♥♥♥♥♥♥♥♥♥♥♥.exe
ClamXav may be able to tell you which particular virus or trojan it is, but do you care? In practice, there's seldom a reason to use ClamXav unless a network administrator requires you to run an anti-virus application.
9. It seems to be a common belief that the built-in Application Firewall acts as a barrier to infection, or prevents malware from functioning. It does neither. It blocks inbound connections to certain network services you're running, such as file sharing. It's disabled by default and you should leave it that way if you're behind a router on a private home or office network. Activate it only when you're on an untrusted network, for instance a public Wi-Fi hotspot, where you don't want to provide services. Disable any services you don't use in the Sharing preference pane. All are disabled by default.
10. As a Mac user you don't have to live in fear that your computer is going to be infected every time you install an application, read email, or visit a web page. But neither should you have the false idea that you will always be safe, no matter what you do. The greatest harm done by security software is precisely its selling point: it makes people feel safe. They may then feel safe enough to take risks from which the software doesn't protect them. Nothing can lessen the need for safe computing practices.

How to change the HTTP Response as XML (Content Type "text\xml") When Post

Hi Friends ,
I have created one RFC Destination TYPE H . When i am trying to post some XML Message to that particular HTTP Service using POST method . It succesfully accepted the XML File but , it is returning the String as " OK" . In the connection test trace i have seen the Content Type as "text/html" but * I need to get as XML format no Srting ( Type "text\xml" . ) *
I need to get response back as XML not plain text .
1 Any Configuration setting do we need to do on Service (SICF ) ?
2. Or any other place we need to modify to get the HTTP Response as XML not plain text
Can you please help to solve the problem . Any clue ?
Thanks & Regards.,
V.Rangarajan

Dear users,
we have requirement sending SMS to the customers mobiles. I am successfully sending the messages to the customers mobiles by using the above method. Facing issues with response message. The response messages is in plain text fromat in single line like...Sent
Using HTTP_AAE Receiver adapter.
The response message was failed while excution of the message mapping with the error
Mapping failed in runtimeRuntime Exception when executing application mapping program com/sap/xi/tf/_MM_SMS_CUST_RES_; Details: com.sap.aii.utilxi.misc.api.BaseRuntimeException; Content is not allowed in prolog.
please share the comments how to pass the Status of the message to SAP ECC from SAP HTTP adapter
Regards,
Sudir.

XML validation against schema in XSD format

I have a requirement for validation of XML file against XML schema(XSD format). Using IXML liabrary I know how to validate XML file against schema in DTD format. But i am not getting how to do it against XSD. Is it possible using IXML liabrary? Also i wanted to know how to attach one XML or CSV file into another XML file using SAP ABAP.
Please provide solution!!

Hi Madhura,
see here my comparison of the web version against the local file version on my Windows box (which is itself not the fastest): It makes a factor 16 in difference!
C:\Temp\xsdvalidator>java XsdValidator madhu.xsd madhu.xml
cvc-pattern-valid: Value 'provamail.it' is not facet-valid with respect to patte
rn '[^@]+@[^.]+[.].+' for type 'EmailType'.
NOK - Validation error
Elapsed time: 16353 ms
C:\Temp\xsdvalidator>java XsdValidator madhu_local.xsd madhu.xml
cvc-pattern-valid: Value 'provamail.it' is not facet-valid with respect to patte
rn '[^@]+@[^.]+[.].+' for type 'EmailType'.
NOK - Validation error
Elapsed time: 994 ms
Obviously, the w3c.org domain that you specified as ressource location is very slow - and, as the FAQ shows, this delay is intentional!
The W3C servers are slow to return DTDs. Is the delay intentional?
Yes. Due to various software systems downloading DTDs from our site millions of times a day (despite the caching directives of our servers), we have started to serve DTDs and schema (DTD, XSD, ENT, MOD, etc.) from our site with an artificial delay. Our goals in doing so are to bring more attention to our ongoing issues with excessive DTD traffic, and to protect the stability and response time of the rest of our site. We recommend HTTP caching or catalog files to improve performance.
--> They don't want to have requests to their site from productive servers all around the world.
Regards,
Rüdiger

Urgent help for processing XML stream read from a JAR file

Hi, everyone,
Urgently need your help!
I am reading an XML config file from a jar file. It can print out the result well when I use the following code:
===============================================
InputStream is = getClass().getResourceAsStream("conf/config.xml");
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line;
while ((line = br.readLine()) != null) {
System.out.println(line); // It works fine here, which means that the inputstream is correct
// process the XML stream I read from above
NodeIterator ni = processXPath("//grid/gridinfo", is);
Below is the processXPath() function I have written:
public static NodeIterator processXPath(String xpath, InputStream byteStream) throws Exception {
// Set up a DOM tree to query.
InputSource in = new InputSource(byteStream);
DocumentBuilderFactory dfactory = DocumentBuilderFactory.newInstance();
dfactory.setNamespaceAware(true);
Document doc = dfactory.newDocumentBuilder().parse(in);
// Use the simple XPath API to select a nodeIterator.
System.out.println("Querying DOM using " + xpath);
NodeIterator ni = XPathAPI.selectNodeIterator(doc, xpath);
return ni;
It gives me so much errors:
org.xml.sax.SAXParseException: The root element is required in a well-formed doc
ument.
at org.apache.xerces.framework.XMLParser.reportError(XMLParser.java:1213
at org.apache.xerces.framework.XMLDocumentScanner.reportFatalXMLError(XM
LDocumentScanner.java:570)
at org.apache.xerces.framework.XMLDocumentScanner$XMLDeclDispatcher.endO
fInput(XMLDocumentScanner.java:790)
at org.apache.xerces.framework.XMLDocumentScanner.endOfInput(XMLDocument
Scanner.java:418)
at org.apache.xerces.validators.common.XMLValidator.sendEndOfInputNotifi
cations(XMLValidator.java:712)
at org.apache.xerces.readers.DefaultEntityHandler.changeReaders(DefaultE
ntityHandler.java:1031)
at org.apache.xerces.readers.XMLEntityReader.changeReaders(XMLEntityRead
er.java:168)
at org.apache.xerces.readers.UTF8Reader.changeReaders(UTF8Reader.java:18
2)
at org.apache.xerces.readers.UTF8Reader.lookingAtChar(UTF8Reader.java:19
7)
at org.apache.xerces.framework.XMLDocumentScanner$XMLDeclDispatcher.disp
atch(XMLDocumentScanner.java:686)
at org.apache.xerces.framework.XMLDocumentScanner.parseSome(XMLDocumentS
canner.java:381)
at org.apache.xerces.framework.XMLParser.parse(XMLParser.java:1098)
at org.apache.xerces.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.
java:195)
at processXPath(Unknown Source)
Thank you very much!
Sincerely Yours
David

org.xml.sax.SAXParseException: The root element is required in a well-formed document.This often means that the parser can't find the document. You think it should be able to find the document because your test code could. However if your test code was not in the same package as your real (failing) code, your test is no good because getResourceAsStream("conf/config.xml") is looking for that file name relative to the package of the class that contains that line of code.
If your test code wasn't in any package, put a slash before the filename and see if that works.

Error in XML Parsing through Schema doc.MalformedURLException

Hi,
I need to validate xml file before parsing it through XML schema validation. My XML file and schema files are in the same directory and I need am validation it using below code.
Java Code_
String rbBasePath = ConfigurationFactory.getInstance().getConfigurations("ConfigParam").get("config.rb.properties", DEFAULT_RB_PATH);
InputSource xmlInputSource = new InputSource (rbBasePath + ConfigConstants.XML_FILE_NAME);
File schemaFileObj = new File (rbBasePath + ConfigConstants.XML_SCHEMA_FILE_NAME);
SAXSource source = new SAXSource (xmlInputSource);
SchemaFactory sf = SchemaFactory.newInstance (XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = sf.newSchema (schemaFileObj);
Validator validator = schema.newValidator ();
validator.setErrorHandler (new ParserErrorHandler());
validator.validate (source);
But, I am getting following error.
java.net.MalformedURLException: unknown protocol: c_
After some google, I found there may be some bug which does not read the file if file path contains some space in between. But in my case schema path does not contain any space in between.
Please help to figure out this issue.
Edited by: Jaykishan on Jul 20, 2011 12:17 PM
Edited by: Jaykishan on Jul 20, 2011 12:18 PM

Error occurs at below line of code.
validator.validate (source);
Error message: MalformedURLException. java.net.MalformedURLException: unknown protocol: c
My xml and xsd file is located at: C:\config\resources\AlertData.xml, C:\config\resources\AlertDataSchema.xsd.

Validate xml againt registerd schema, ignoring xsi:noNamespaceSchemaLocatio

hi,
i would like to validate received xml against registered schema, ignoring the one defined in xml. I use XMLisValid(xml_data ,schema_url) but it works only if there is no xsi:noNamespaceSchemaLocation attrubute.
This is sample xml.
<?xml version="1.0" encoding="UTF-8"?>

<ROOT xmlns:xdb="http://xmlns.oracle.com/xdb" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="http://localhost/public/xsd/myapp.xsd">
     <ID>0</ID>
     <INFO>
          <INFO_ID>0</INFO_ID>
          <INFO_CONTENT>Text</INFO_CONTENT>
     </INFO>
</ROOT>
Anybody knows if it is possible?
Thanks in advance..

Hi,
It should work according to the documentation, but obviously it doesn't.
So I guess you'll have to consider one of these options :
- Changing the xsi:noNamespaceSchemaLocation at the source to use the URL of your registered schema instead
- The other way around : register your schema at the URL defined in the document
- Removing the xsi:noNamespaceSchemaLocation attribute prior to validation
Here's an example for the third option :
BEGIN
dbms_xmlschema.registerSchema(
    schemaURL => 'myapp2.xsd'
, schemaDoc =>
'<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:element name="ROOT">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="ID" type="xs:integer"/>
        <xs:element name="INFO">
          <xs:complexType>
            <xs:sequence>
              <xs:element name="INFO_ID" type="xs:integer"/>
              <xs:element name="INFO_CONTENT" type="xs:string"/>
            </xs:sequence>
          </xs:complexType>
        </xs:element>
      </xs:sequence>
    </xs:complexType>
</xs:element>
</xs:schema>'
, local => true
, genTypes => false
, genTables => false
END;
SQL> declare
2
3    doc xmltype := xmltype('<?xml version="1.0" encoding="UTF-8"?>
4 <ROOT xmlns:xdb="http://xmlns.oracle.com/xdb"
5        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
6        xsi:noNamespaceSchemaLocation="http://localhost/public/xsd/myapp.xsd">
7 <ID>0</ID>
8 <INFO>
9 <INFO_ID>0</INFO_ID>
10 <INFO_CONTENT>Text</INFO_CONTENT>
11 </INFO>
12 </ROOT>');
13
14    isValid integer;
15
16 begin
17
18    doc := doc.deleteXML('/ROOT/@xsi:noNamespaceSchemaLocation','xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"');
19
20    select xmlisvalid(doc, 'myapp2.xsd') into isValid from dual;
21
22    dbms_output.put_line('isValid = '||to_char(isValid));
23
24 end;
25 /
isValid = 1
PL/SQL procedure successfully completed

Assign any type payload(XML stream) a schema?

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