Basic ThisDemo flow of Control Understanding

Question

Ok ive got two classes, the first being television.java;
public class Television
public int channel;
public int volume;
public Television()
this(4,10);
System.out.println("Inside no-arg constructor");
public Television(int c)
this(c, 10);
System.out.println("Inside one-arg constructor");
public Television(int c, int v)
System.out.println("Inside two-arg constructor");
channel = c;
volume = v;
the second is ThisDemo.java;
public class ThisDemo
public static void main(String [] args)
System.out.println("Instantiating first television");
Television t1 = new Television();
System.out.println(t1.volume + " " + t1.channel);
int channel = 206;
System.out.println("Instantiating second television");
Television t2 = new Television(channel);
System.out.println(t2.volume + " " + t2.channel);
int volume = 7;
System.out.println("Instantiating third television");
Television t3 = new Television(channel, volume);
System.out.println(t3.volume + " " + t3.channel);
can someone explain to me why the first three lines of output are:
Instantiating first television
Inside two-arg constructor
Inside no-arg constructor
10 4
is it because withing the Television() constructor it says, this(4,10) so it jumps from the print out for the two arg constructor then back to the no-arg constructor. I would really like to get my head around this. Thanks. Richard

Answer 1

is it because withing the Television() constructor it says, this(4,10) so it jumps
from the print out for the two arg constructor then back to the no-arg
constructor.Yes.
Remember you call this(4, 10) before you print the fact that you are in the
no argument constructor. (And, of course, you have to do this.)