Bookmarks in several columns
Is there a way to display bookmarks in several columns instead a one long ?
Firefox 14.01 Win 7
Have a look at this:
*Multicolumn Bookmarks: https://addons.mozilla.org/firefox/addon/multicolumn-bookmarks/
If it is your bookmark toolbar and you want multiple rows, look at this:
*Multirow Bookmarks Toolbar Plus: https://addons.mozilla.org/firefox/addon/multirow-bookmarks-toolbarplus/
'''If this reply solves your problem, please click "Solved It" next to this reply when <u>signed-in</u> to the forum.'''
Not related to your question, but...
You may need to update some plug-ins. Check your plug-ins and update as necessary:
*Plug-in check --> http://www.mozilla.org/en-US/plugincheck/
*Adobe Shockwave for Director Netscape plug-in: [https://support.mozilla.org/en-US/kb/Using%20the%20Shockwave%20plugin%20with%20Firefox#w_installing-shockwave Installing ('''''or Updating''''') the Shockwave plugin with Firefox]
*'''''Adobe PDF Plug-In For Firefox and Netscape''''': [https://support.mozilla.org/en-US/kb/Using%20the%20Adobe%20Reader%20plugin%20with%20Firefox#w_installing-and-updating-adobe-reader Installing/Updating Adobe Reader in Firefox]
*Shockwave Flash (Adobe Flash or Flash): [https://support.mozilla.org/en-US/kb/Managing%20the%20Flash%20plugin#w_updating-flash Updating Flash in Firefox]
*Next Generation Java Plug-in for Mozilla browsers: [https://support.mozilla.org/en-US/kb/Using%20the%20Java%20plugin%20with%20Firefox#w_installing-or-updating-java Installing or Updating Java in Firefox]
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Using distinct on several columns
Dear all;
I am have a query of the following form
select distinct id, zoneid, close_date from table_one
which gave a different result
from the same query with a different form
select distinct close_date, id, zoneid from table_one
Hence, I would like to understand why and how the phrase distinct is being used when utilizied in several columns.
THank youBy all means, feel free to post a testcase that we can reproduce, along with your database version ( the result of: select * from v$version; ).
My gut feeling is that this has to do with your unknown data and unknown datatypes...or 'very maybe' your database version.
SQL> create table table_one as
2 select 1 id, 1 zoneid, to_date('01-01-2010 22:22:22', 'dd-mm-yyyy hh24:mi:ss') close_date from
dual union
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4 select 1, 1 zoneid, to_date('01-01-2010 22:22:23', 'dd-mm-yyyy hh24:mi:ss') from dual;
Table created.
SQL> select distinct id, zoneid, close_date from table_one;
ID ZONEID CLOSE_DATE
1 1 01-01-2010 22:22:23
1 1 01-01-2010 22:22:22
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I cannot find the way how to show report representing records as icons organized in several columns - similary as applications are shown if "Icons" view is selected in HTMLDB 2.0 development environnment homepage. No available report template did the job.
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Thanks a lot :-)))Hi Vikas
Thanks for the tip. It was interesting insight into HTMLDB internals....
I'we found the way how to do the same job with a standard report template by building the SELECT in the following way:
select col1,col2,col3,col4,col5
from(
select
opportunity_name col1,
lead(opportunity_name,1,'') OVER (ORDER BY opportunity_name) col2,
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lead(opportunity_name,3,'') OVER (ORDER BY opportunity_name) col4,
lead(opportunity_name,4,'') OVER (ORDER BY opportunity_name) col5,
case when mod(rank () OVER (ORDER BY opportunity_id) -1,5)=0 then 1 else 0 end endofline
from opportunities
order by opportunity_name)
where endofline=1
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============================
What about to add the classical Windows File Explorer Viewer with "Small Icons/Large Icons/List Detail" display options as one of standard report templated??? -
Getting the count of DISTINCT of several columns
How can i get the count of DISTINCT of several columns?
SQL> select count(distinct ename) from emp;
COUNT(DISTINCTENAME)
14
SQL> select count(distinct ename, job) from emp;
select count(distinct ename, job) from emp
ERROR at line 1:
ORA-00909: invalid number of argumentsHello,
You should separate them out like this
select count(distinct ename), count(distinct job) from emp;Regards -
I cannot figure out how to hide the bookmark/reading list column
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I want to see all my bookmarks in a column when I click the "Bookmarks" icon. icon.
When I click the "Bookmarks" icon, my list no longer appears. They are still there but hidden. How do I get the column listing to appear again?
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Open the '''Bookmarks Manager.'''
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Where is the bookmark 'auto-click' column?
Can anyone tell me how to make the auto-click column appear in the bookmark window of Safari?
Thanks.Yes, the column is "Auto-Click" not Auto-Tab". I bet you only see it available for folders on your Bookmarks Bar with a check-box appearing only besides the folders on the Bookmarks Bar.
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With FFox open and Sync enabled, moving a bookmark, either in the Bookmark sidebar or in 'Show All Bookmarks' window, to another location - for example: dragging a bookmark from "Unsorted" to another location in Bookmarks - causes a delay during which time the Bookmark list seems to freeze and bookmarks can't be moved, selected, etc. The delay lasts for several seconds, and is longer on slower/older machines. If I attempt to move a bookmark (or folder) during the delay, it will move in unexpected ways once Bookmarks unfreezes as locations within the Bookmark list have changed.
With Sync disabled, bookmarks can be moved/selected/etc. without any delay.
Systems Tested: [Note: All systems had the most current version of FFox available for them.]
MacBook Pro 26 (2014) w/OSX 10.9
IBM ThinkPad T41x (2010) w/XPpro
Macbook Pro 266 (2009) w/OSX 10.6
IBM ThinkPad T61x (2008) w/XPpro
Mac Mini (2008) w/OSX 10.6
Mac Mini (2007) w/OSX 10.5
Macbook Pro 233 (2007) w/Ubuntu v14
ASUS P1AH (2006) w/Ubuntu 12
My main computer is the Macbook Pro 266, and I noticed this behavior: FFox v36 bookmark delay with Sync enabled is about the same as v35, v35 was worse (longer delay) than v34, v34 was better (less delay) than v33, v33 was better than v32, V32 was much worse than v31, v31 was much worse (Sync unusueable) than v30, v30 was much worse (Sync unusueable) than v29, v29 delay made Sync unusueable.Currently 664 [exported from FFox Bookmarks to URL Manager for the count] abut never more than 4000: beyond 4000 bookmarks and FFoxs' Bookmarks respond slowly even without Sync active. I currently have 5 computer with FFox set up to use Sync. While I don't expect FFox to manage a huge collection of URLs, I would be nice to be able to access a Bookmark collection of 6000 to 8000 without noticeable delay. It's a simple text file after all, and as I'm only effecting one URL, why so long to update?
fyi: URL Manager tells me that I've amassed about 300,000 bookmarks, some from the late 90's which I still use for research. -
Can you make several columns in pages
I am considering buying Pages for iPad. Wanted to know if you can make three or more columns in a document?
Thanks
GteaThanks, that helped me to decide.
Thanks again
Gtea -
Hopefully someone can help. I created a new form from an Excel spreadsheet, but the form field recognition didn't "take" well and very little of the spreadsheet translated into form fields. I need to create new fields (31) for each column (about 10) and I want the fields in each column to have a keyword from the parent column and the fields numbered consecutively. I'm really hoping I don't have to do this manually!
Next, is there a way to total the values in a column of fields (the same as the SUM function in Excel?) or does the form user have to dig out a calculator and add everything?
Can I create an email (submit) button and direct how (ie email) and by what method the form is sent?
Once the form is completed, is there a way for the user to lock it before sending it - ie a button they could press to make it no longer fillable? Or can I set the document to be a regular .pdf once it leaves the host machine?
I think that's it! Hopefully someone can help soon - this is a work project that could be potentially very time consuming if I have to create each form field manually. Thank you for any assistance!
Cheers,
LostintheNorthLostintheNorth wrote:
Rats! Thank you for your link - I may take you up on that... however for the purposes of this form I'm more than halfway done, so I might as well keep plugging away. A workaround I found was to creat 32 of something I only need 31 of, then delete the parent. Somehow even playing with spacing on the "create multiple fields" option as the fields are being created only gets the vertical alignment close - no matter what I do I still end up manually aligning (vertically) 31 little boxes for each column so they fit visually. Grrrr.
Yes, this can be very tricky. If you don't get the exact right offset between each field, the difference will accumulate and after a while it will be completely off.
You just have to play around with it, until you get it right. Or almost right, and then adjust it manually.
Another thing I've noticed, is that when you select one field and right click for properties, you get an expanded version, as opposed to select/shift/enter for a bunch of cells only yields an abbreviated properties box - what's up with that? Is there a way to change this? For instance, I had set the properties for a column of 31 cells to be number, 1 decimal place. Halfway through my project, the lady I am doing the favor for tells me she would like 2 decimal places, requiring me to manually change each box for 62 cells! Apparently cell formatting is not an option in the abreviated properties dialogue! Is there a fix for that?
No, there isn't. Some propeties you have to set manually (or get right the first time, before copying and pasting...). There is a way to do it with a script, but it's a bit complex and requires using an undocumented method.
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Yeah, it's possible, but requires quite a bit of scripting knowledge. If you wish, contact me personally (by PM or email at try6767 at gmail dot com) and I could possibly create this for you.
If you want to do it yourself, you would have to learn a lot about both the Date object in JS and about the various date printing and scanning methods in Acrobat JS. -
Finding the lowest number from several columns
Hi all,
I'm analysing data from students' two years course where they had 4 units. What I'd like to be able to do is see at a glance which of the 4 units for each student was their lowest - therefore allowing me to see if one unit in particular was letting them down. see pic and the 4 highlighted columns.
I have got the info as a graph, but you have to look individual at each one.
Can anyone help with a formula that could present the results for each student by the column header. E.g. In column A is the student names and in column B is the name of the column they got the lowest mark (in this case MS1, MS2, MS3 or MS4). I would love to be able make this as will really help next year's cohort!
Best,
GregHi Greg,
Have a look at the SMALL function. It allows you to see the smallest, second smallest... value in a list.
The SMALL function returns the nth-smallest value within a set of numeric values. The smallest value is ranked number 1.
SMALL(value-set, ranking)
value-set: A collection of number values, date/time values, or duration values. All values must be of the samevalue type.
ranking: A number value representing the size ranking of the value you want to retrieve. ranking must be in the range of 1 to the number of values in the collection.
Type = in a cell to bring up the Functions Panel. Type small in the search box.
Regards,
Ian. -
How to divide values to several columns
Hi
I have a table including values that I want to display in 5 columns.
Table structure is:
Use_id number (primary key)
target id number
code number
Values in a table are:
1 234 22
2 345 23
3 564 24
4 634 25
5 345 24
6 545 22
7 234 23
8 634 23
I want to select (display) the values like:
target_id code22 code23 code24 code 25
234 22 23
345 23 24
564 24
634 23 25
545 22
Is it possible to create a view for that purpose?
Message was edited by:
user545002If you know the different possible codes in advance, you can try something else like below :
SQL> create table mytable (Use_id number primary key,
2 target_id number,
3 code number);
Table created.
SQL>
SQL> insert into mytable
2 select 1, 234, 22 from dual union all
3 select 2, 345, 23 from dual union all
4 select 3, 564, 24 from dual union all
5 select 4, 634, 25 from dual union all
6 select 5, 345, 24 from dual union all
7 select 6, 545, 22 from dual union all
8 select 7, 234, 23 from dual union all
9 select 8, 634, 23 from dual ;
8 rows created.
SQL>
SQL> create or replace view myview
2 as select target_id,
3 max(decode(code,22,code)) code22,
4 max(decode(code,23,code)) code23,
5 max(decode(code,24,code)) code24,
6 max(decode(code,25,code)) code25
7 from mytable
8 group by target_id;
View created.
SQL>
SQL> select * from myview;
TARGET_ID CODE22 CODE23 CODE24 CODE25
234 22 23
345 23 24
545 22
564 24
634 23 25
SQL> Nicolas. -
Is it possible to force a value in at least one of several columns?
Is it possible to define a constraint that says at least one of a set of columns must have a value?
I have a table of securities. There are three types of security identifiers that I am recording: CUSIP, SEDOL, ISIN. So I have a column for each type of identifier. Is it possible to set a constraint to make sure that at least one of those
columns has a value?
Thanks.
J
http://digitalcamel.blogspot.com/Hi J,
Try like this,
CREATE TABLE T1
CUSIP int ,
SEDOL int,
ISIN int,
CHECK (CUSIP IS NOT NULL OR SEDOL IS NOT NULL OR ISIN IS NOT NULL)
INSERT T1 SELECT 1,NULL,NULL
INSERT T1 SELECT NULL,2,NULL
INSERT T1 SELECT NULL,NULL,3
INSERT T1 SELECT NULL,NULL,NULL
SELECT * FROM T1
sathya - www.allaboutmssql.com ** Mark as answered if my post solved your problem and Vote as helpful if my post was useful **. -
Can I only combine several columns?
Dear expert,
Have one quick question on BEX report, here is detail,
Situation: Except build-in dimension, one infocube includes 1 additonal dimension, company code, the key figure are, sales amount, sales qty. The table content for this infocube are the following:
Company code, Calendar Day, Sales Amount, Sales Qty
ZB00 20080101 20 10
ZB01 20080102 20 10
ZB02 20080103 30 10
ZB03 20080104 10 1
Requirement: When we search the sales amounts and qty by company code, in the result, ZB00 always is combined with ZB01 like the following:
ZB00+ZB01, ZB02, ZB03
Sales amt: 40 30 10
Sales qty: 20 10 1
In order to achieve it, I am thinking, there could be one way, that is, I can add one navigation attribute (infoobject: consolidation_group) into infoobject company_code, it specifies which company codes are in the same group, then in the query, I put infoobject consolidation_group as column, in the infoobject company code, I put the same group for ZB00 and ZB01, then it can achieve this. But my question is, is there any another way to achieve this, for example, don't need to change infoobject and just make some enhancement on query?
Hope some experts can contribute more great ideas on this?
Thanks in advanced.
best regards
PatrickNo issue with Apple according to my view.
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