Bug report about create new footprint with Rounded rectangle in 3D info Bottom

I create new footprint with rounded rectangle in 3D info Bottom,the rounded rectangle must be in bottom,but In fact,the rounded rectangle
created in top layer.i think it's wrong.
I used ultiboard 10.1.357.

Hi,
Thank you for reporting this. This has been a long standing issue with Ultiboard and we are looking into resolving this.
There is a work around although a very inconvenient one. You can set the height to what you require and use a negative offset to move the shape to the other side of the board. The 3D shape will appear on the other side, but in reality is just shifted, not mirrored.
Hope that helps. We apologize for the inconvenience.
Yi
Software Developer
National Instruments - Electronics Workbench Group

Similar Messages

Create New user with ...

Hi all
I need to create new user with the following privileges :
1- access any table data (read only)
2- access the tables structure (read only)
3- access the tables relations (read only)
thanx in advance

Hi,
giggs11 wrote:
I did the following :
create user youruser identified by yourpassword;
grant connect to youruser;
grant SELECT_CATALOG_ROLE to username;
but I cann't see my tables
there is no erroExample :-
Step 1:-
sql> Conn system/manager@orcl;
connected.
step 2:-
SQL> create user trial identified by trial;
User created.
Step 3:-
SQL> grant connect to trial;
Grant succeeded.
SQL>grant SELECT_CATALOG_ROLE to trial;
Grant succeeded.
SQL> grant select any table to trial;
Grant succeeded.
Step 4:
SQL> conn trial/trial@orcl;
Connected.
SQL> select * from tab;
no rows selected
Step 5:
SQL> select * from scott.dept;
DEPTNO DNAME LOC
10 ACCOUNTING NEW YORK
20 RESEARCH DALLAS
30 SALES CHICAGO
40 OPERATIONS BOSTON
Step 6:
SQL> desc scott.dept;
Name Null? Type
DEPTNO NOT NULL NUMBER(2)
DNAME VARCHAR2(14)
LOC VARCHAR2(13)
you must read about privileges..
http://download.oracle.com/docs/cd/B10501_01/server.920/a96521/privs.htm
Regards
S.Azar
DBA
"Question is Unquestionable"
Edited by: azarmohds on Aug 15, 2009 6:28 AM
Edited by: azarmohds on Aug 15, 2009 6:32 AM

I didn't find any log in the event viewer about creating new VM.

Dears ,
I'd like to find a log in the event logs about creating new Virtual machine , please check with us.

Hi Ramy,
Sorry for the mistake , I'm using 2012R2 and I have the event ID 13002 .
Now I realize you are using 2012 not R2 , so I found a 2012 host to verify that ... you are right .
Best Regards
Elton Ji
We
are trying to better understand customer views on social support experience, so your participation in this
interview project would be greatly appreciated if you have time.
Thanks for helping make community forums a great place.

HT204088 Dear sirs, Could you please help me on my problem with my apple ID I create new account with security questions, and when I try to purchase paid application,it ask me for answers the questions but it's not working, My account have 50$ and stil

Dear sirs,
Could you please help me on my problem with my apple ID
I create new account with security questions, and when I try to purchase paid application,it ask me for answers the questions but it's not working,
My account have 50$ and still didn't buy anything

You need to ask Apple to reset your security questions; ways of contacting them include clicking here and picking a method for your country, phoning AppleCare and asking for the Account Security team, and filling out and submitting this form.
(100546)

Error while trying to create new assignment with supervisor through API

Hi Experts,
I'am trying to create new assignment with supervisor for employee, but i'am facing this error:
=============================================================
ORA-20008: Error While Create new assignment..-20001
ORA-20001: The supervisor assignment that you have entered is invalid.
Please check that you have entered the supervisor,
that the supervisor assignment belongs to this supervisor and that the assignment is effective.
ORA-06512: at line 198
=============================================================
This is my script, (Oracle EBS 12.1.1)(DB 11):
DECLARE
v_user_id NUMBER;
v_res_id NUMBER;
v_res_appl_id NUMBER;
v_org_now_no_manager_warning BOOLEAN;
v_spp_delete_warning BOOLEAN;
v_other_manager_warning BOOLEAN;
v_tax_district_changed_warning BOOLEAN;
v_entries_changed_warning VARCHAR(4000);
v_person_id per_all_assignments_f.person_id %TYPE;
v_business_group_id hr_all_organization_units_tl.organization_id %TYPE;
v_people_group_id per_all_assignments_f.people_group_id %TYPE;
v_object_version_number per_all_assignments_f.object_version_number %TYPE;
v_special_ceiling_step_id per_all_assignments_f.special_ceiling_step_id %TYPE;
v_group_name pay_people_groups.group_name %TYPE;
v_ass_effective_start_date per_all_assignments_f.effective_start_date %TYPE;
v_effective_start_date per_all_assignments_f.effective_start_date %TYPE;
v_effective_end_date per_all_assignments_f.effective_end_date %TYPE;
v_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_sup_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_supervisor_assignment_id per_all_assignments_f.assignment_id %TYPE;
v_job_id per_jobs.job_id %TYPE;
v_grade_id per_grades.grade_id %TYPE;
v_location_id hr_locations_all.location_id %TYPE;
v_payroll_id pay_all_payrolls_f.payroll_id %TYPE;
v_pay_basis_id per_pay_bases.pay_basis_id %TYPE;
BEGIN
v_user_id := FND_GLOBAL.user_id ;
v_res_id := FND_GLOBAL.resp_id ;
v_res_appl_id:= FND_GLOBAL.resp_appl_id;
FND_GLOBAL.apps_initialize(v_user_id, v_res_id, v_res_appl_id);
BEGIN
SELECT organization_id
INTO v_business_group_id
FROM hr_all_organization_units_tl
WHERE name = 'Vision University'
AND language = 'US';
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20000,'Error While Retrieving (Business Group ID) Info...'||SQLCODE||' '||SQLERRM);
END;
FOR R IN (SELECT * FROM xx_assignment) LOOP
BEGIN
SELECT assignment_id , ass_f.object_version_number
INTO v_assignment_id , v_object_version_number
FROM per_all_assignments_f ass_f, per_all_people_f p_f
WHERE ass_f.person_id = p_f.person_id
AND ass_f.business_group_id = p_f.business_group_id
AND ass_f.business_group_id = v_business_group_id
AND p_f.employee_number = R.employee_number
AND TRUNC(p_f.effective_start_date)= TRUNC(ass_f.effective_start_date)
AND TRUNC(p_f.effective_end_date) = TRUNC(ass_f.effective_end_date);
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20001,'Error While Retrieving (Assignmet_ID) for employee..'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT job_id
INTO v_job_id
FROM per_jobs
WHERE trim(lower(name)) = trim(lower(r.employee_job))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20002,'Error While Retrieving (Job_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT grade_id
INTO v_grade_id
FROM per_grades
WHERE trim(lower(name)) = trim(lower(r.employee_grade))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20003,'Error While Retrieving (Grade_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT location_id
INTO v_location_id
FROM hr_locations_all
WHERE trim(lower(description))= trim(lower(r.employee_location))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20004,'Error While Retrieving (Location_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT payroll_id
INTO v_payroll_id
FROM pay_all_payrolls_f
WHERE trim(lower(payroll_name)) = trim(lower(r.payroll_name))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20005,'Error While Retrieving (Payroll_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT pay_basis_id
INTO v_pay_basis_id
FROM per_pay_bases
WHERE trim(lower(pay_basis)) = trim(lower(r.pay_basis))
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20006,'Error While Retrieving (Pay_Basis_ID) Info...'||SQLCODE||' '||SQLERRM);
END;
BEGIN
SELECT person_id
INTO v_person_id
FROM per_all_people_f
WHERE employee_number = r.supervisor_number
AND business_group_id= v_business_group_id;
SELECT assignment_id
INTO v_sup_assignment_id
FROM per_all_assignments_f
WHERE person_id = v_person_id
AND business_group_id = v_business_group_id;
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20007,'Error While Retrieving (Assignmet_ID) for supervisor..'||SQLCODE||' '||SQLERRM);
end;
BEGIN
hr_assignment_api.update_emp_asg_criteria(p_effective_date => TRUNC(SYSDATE),
p_datetrack_update_mode => 'CORRECTION',
p_assignment_id => v_assignment_id,
p_validate => FALSE,
p_called_from_mass_update => NULL,
p_grade_id => v_grade_id,
p_position_id => NULL,
p_job_id => v_job_id,
p_payroll_id => null,--v_payroll_id,
p_location_id => v_location_id,
p_organization_id => v_business_group_id,
p_pay_basis_id => v_pay_basis_id,
p_segment1 => NULL,
p_segment2 => NULL,
p_segment3 => NULL,
p_segment4 => NULL,
p_segment5 => NULL,
p_segment6 => NULL,
p_segment7 => NULL,
p_segment8 => NULL,
p_segment9 => NULL,
p_segment10 => NULL,
p_segment11 => NULL,
p_segment12 => NULL,
p_segment13 => NULL,
p_segment14 => NULL,
p_segment15 => NULL,
p_segment16 => NULL,
p_segment17 => NULL,
p_segment18 => NULL,
p_segment19 => NULL,
p_segment20 => NULL,
p_segment21 => NULL,
p_segment22 => NULL,
p_segment23 => NULL,
p_segment24 => NULL,
p_segment25 => NULL,
p_segment26 => NULL,
p_segment27 => NULL,
p_segment28 => NULL,
p_segment29 => NULL,
p_segment30 => NULL,
p_employment_category => NULL,
p_concat_segments => NULL,
p_grade_ladder_pgm_id => NULL,
p_supervisor_assignment_id => v_sup_assignment_id,
p_people_group_id => v_people_group_id,
p_object_version_number => v_object_version_number,
p_special_ceiling_step_id => v_special_ceiling_step_id,
p_group_name => v_group_name,
p_effective_start_date => v_ass_effective_start_date,
p_effective_end_date => v_effective_end_date,
p_org_now_no_manager_warning => v_org_now_no_manager_warning ,
p_spp_delete_warning => v_spp_delete_warning,
p_entries_changed_warning => v_entries_changed_warning,
p_tax_district_changed_warning => v_tax_district_changed_warning,
p_other_manager_warning => v_other_manager_warning);
EXCEPTION
WHEN OTHERS THEN
RAISE_APPLICATION_ERROR(-20008,'Error While Create new assignment..'||SQLCODE||' '||SQLERRM);
END;
END LOOP;
COMMIT;
END;
Thank you & Best Regards

I think this is essentially saying that the Supervisor Assignment is wrong or no longer effective. Looking at your SQL to fetch the Supervisor Assignment there are a number of potential issues. This is what you've currently got:
SELECT person_id
INTO v_person_id
FROM per_all_people_f
WHERE employee_number = r.supervisor_number
AND business_group_id= v_business_group_id;
SELECT assignment_id
INTO v_sup_assignment_id
FROM per_all_assignments_f
WHERE person_id = v_person_id
AND business_group_id = v_business_group_id;
Potential Problems/Clarifications
1. What is r.supervisor_number, what does it contain and how is it derived? I can't see that anywhere else in the block...
2. Is there a chance that r.supervisor_number is referencing an employee who has left, ie, now an ex-employee?
3. The SELECT statement that fetches the assignment_id does not perform any date-effective restrictions, which means you might be lucky enough to fetch the person's current assignment. But you might also fetch an old or future-dated assignment.
4. The SELECT statement that fetches the assignment_id does not restrict the type of assignment, so if this manager has applied for a job (ie, they have an applicant assignment) or some other type of non-employee assignment you might be picking that up.
This would work better for you:
SELECT paaf.assignment_id
INTO v_sup_assignment_id
FROM per_all_people_f papf
,per_all_assignments_f paaf
WHERE papf.employee_number = r.supervisor_number
AND papf.business_group_id = v_business_group_id
AND nvl(papf.current_employee_flag, 'N') = 'Y'
AND trunc(sysdate) BETWEEN
papf.effective_start_date AND papf.effective_end_date
AND papf.person_id = paaf.person_id
AND paaf.assignment_type = 'E'
AND paaf.primary_flag = 'Y'
AND trunc(sysdate) BETWEEN
paaf.effective_start_date AND paaf.effective_end_date;
If it doesn't return a row it means that the supervisor (or whatever employee is returned by r.supervisor_number) is not active as at sysdate and cannot be used. Note that this SQL only applies for employees. If you can have Contingent Workers as supervisors in your implementation then this needs tweaking.
Does that help?

How to create new docs with custom swatch palette?

Looking to create new documents with a corporate color palette already available instead of having to load the .ase files. Fat chance?

Thanks Bob - I was trying that on a test MAC and it just was not sticking. A shutdown instead or a restart seemed to put things back in order and now all is good.

How to create new user with more than one default folder

hi
A new user created in OCS has only one default folder(Inbox).
I want to create new user with customized default folder.
for example:
a new user has more than one default folder(Inbox,Outbox,Draft,Dustbin...)
And also I want to automaticly enable the functions:
When sending messages, place a copy in Outbox
Keep message drafts in Draft
Move deleted messages to Dustbin
who know that?
thanks

The same reason that Apple and 3rd Party vendors put multi-size templates in one file I expect. I am trying to construct an in-house standard template for use in our company, and it is easier to manage if there is only one file to send to people rather than many - both initially and for subsequent edits / updates to the template.
Of course it would be possible to create several templates (one for each size). But since it is clear that templates can be combined, it appears sensible to do this - unless the doing of it is horridly complicated

Create new application with same ID as a previous application

10gR2, webtogo client. We are in a situation where due to what looks like some corruption issue/inability to publish correctly, we may need to drop our existing application and re-create. So the application will have a new applications.id. applications.dsn and applications.publication value. This will most certainly force all our offline users to do a re-install which we want to avoid. (correct? - I'm assuming the offline databases like a1121.odb are keyed to the 1121 applications.id)
Wondering if there is any way to re-create a new application but with the old application ID. One way we think we could do this is that after dropping the application, reset the mobileadmin APPIDS sequence so that it will pick up the ID of the old app when we create the new one. And so have the same applications.id. applications.dsn and applications.publication value.
However, wondering if we do this, we'd cause some other issue. Anyone have any ideas? (we have ticket open for the publication problem, but not much progress yet on that end.)

You may create new mode with the same transaction.
I'm not sure, that you may just "copy-paste" the content from one mode into another.
To create new mode with the same transaction, you may use the following code:
data: l_current_tcode like sy-tcode.
move sy-tcode to l_current_tcode.
    CALL FUNCTION 'TH_CREATE_MODE'
      EXPORTING
        transaktion    = l_current_tcode
        del_on_eot     = 1
*        PARAMETERS     = l_pars
        process_dark   = 'X'
      IMPORTING
*        mode           =
      EXCEPTIONS
        max_sessions   = 1
        internal_error = 2
        no_authority   = 3
        OTHERS         = 4.
    IF sy-subrc <> 0.
      MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
              WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
    ENDIF.
What transaction do you need to display?
Message was edited by: Cyrill Smirnov

Creating new database with old database datafile

is it possible to create new database with old datafile
i lost my database ,i have no back up, just i have datafiles,
i want to create new database and want to create tablespaces with old datafiles
pls suggest me right one
tahnk you

SQL> recover database using backup controlfile until cancel;
ORA-00279: change 339559282 generated at 03/09/2008 12:23:01 needed for thread 1
ORA-00289: suggestion : F:\ORA9IAS\RDBMS\ARC01901.001
ORA-00280: change 339559282 for thread 1 is in sequence #1901
Specify log: {<RET>=suggested | filename | AUTO | CANCEL}
ORA-00308: cannot open archived log 'F:\ORA9IAS\RDBMS\ARC01901.001'
ORA-27041: unable to open file
OSD-04002: unable to open file
O/S-Error: (OS 2) The system cannot find the file specified.
ORA-01547: warning: RECOVER succeeded but OPEN RESETLOGS would get error below
ORA-01194: file 1 needs more recovery to be consistent
ORA-01110: data file 1: 'F:\ORA9IAS\ORADATA\IASDB\SYSTEM01.DBF'

Create new folder with name of file?

I am generating about 20 files from a 3d model. I open the model let's say the name is "delorean" then I want to create a new folder with all the generated files. I'm using a watch me Do to generate the files. The watch me do will save them in whatever folder I specify ahead of time. Should I just specify new folder each time, then rename it with the file name afterwards? If so how do I get the original file name so that I can use it to rename the file. Is there an example of doing something like this somewhere?
Thanks.
This forum is great.
Dan

I am going to guess that you start off with a single file - what are you doing to generate these files? My *Get Names of Finder Items* action can get a name to use in the *New Folder* action - items passed to the New Folder action will get copied to it, so a little more detail may help in creating the workflow.
The *Dispense Items Incrementally* action can also be used to dole out the items one at a time - knowing what the workflow is doing would help with the use of this action as well.

Creating New db(with new name) with the old db backup sql server 2008

Friends..
version: Sql Server 2008
I have a database in a name college1 (more than 200 tables and view etc...)
i want to create a new db with all the structures including the data of the above db college1 with a new name college2
so...i finished the step 1 successfully.. what are the other steps i have to do...like validating the invalid objects. etc....
Step 1:
RESTORE DATABASE college2 FROM DISK = 'D:\DailyDBbackup\college1.bak'
WITH replace,
move 'college2 ' TO 'D:\Program Files\Microsoft SQL Server\MSSQL10.MSSQLSERVER\MSSQL\DATA\college2 .mdf',
move 'college2 _log' TO 'D:\Program Files\Microsoft SQL Server\MSSQL10.MSSQLSERVER\MSSQL\DATA\college2 _log.ldf';
step 2: ?
Step 3: ?
thanks...

but...when i type
use college1
select * from (it will display all tables under the above db)
but when i do..
use college2
select * from (only system tables are displaying..)
Did restore completed successfully ? If yes Expand database , can you see tables in the new database you restored ?. Sometimes when you type incorrect word which does not matches anything you wont get help from intellicense you should not be worried about this
if tables are there in new database college 2
Please mark this reply as answer if it solved your issue or vote as helpful if it helped so that other forum members can benefit from it
My Technet Wiki Article
MVP

SharePoint 2013 unable to create new column with existing column name

Hi Support,
I'm currently having a problem in creating my first custom list in my SharePoint site. When I tried to create a new columns with existing name, e. g "date reported" = Date/Time , "Due Date" =
Date/Time
It's prompt the error like this " The page at sharepoint.itechdomain.com says: The Column name that you entered is already in use or reserved. Choose another name." I've read some forum, someone say's they need javascript command
to fixs the problem. If these the solution for my problem, I'm not familiar on how to used javascript in my sharepoint.
Kindly help me how to fixs my problem as soon as possible.
Your comment or any suggestion would be greatly appreciated.
Thank you
Best Regards,
Bishelp

I already tried this procedure, but it doesn't work. Still the prompt says " The
Column name that you entered is already in use or reserved. Choose another name". Is there any solution for this kind of problem?
Let me know,
Thank you

Creating new page with new parent tab

Does this happen to anyone else? When I try to create a new page that will have a new parent tab and standard tab in a 2-level tab setup, it never seems to work right. I end up having to dele the new parent tab and standard tab I created while creating the new page. Then once the page is created, I go into Shared Components -> Tabs, and create a new Parent Tab and assign it to this new page. Seems like a crazy way to have to do it.
I know this sounds crazy and it is hard to explain the issue, but anyone who has had this problem with creating a new page with new 2-level tabs will understand what I am talking about.
Can anyone point me to an explanation on how this should be done? I know I must be missing something.
Thanks,
John

I've recently had to muck around with the 2 level tabs aswell. There are some things making this rather difficult indeed.
What i'd do when creating a new page you want to have under a new tab, but also with a new parent tab, is to create it with only a new STANDARD tab. Don't create a new parent tabset. All parent tabs are in the same tabset, and if you create a new tabset you'll effectively see only this new parent tab + tab on the page you created.
So unless you want the page to be on an absolutely new set of tabs, you'll probably just want the page to be on a new top-level tab with under that a new standard tab. Like so:
<NEW PARENT> | parent 1 | parent 3 | parent 4
<NEW TAB> |
To achiece this, you'll need a new standard tab set. You can create this when creating the page. The standard tab set is the set used for you lower level tabs, so obviously we do need a new one.
As for the parent set which you can choose upon page creation, choose the already existing parent tab set. This set contains all your already existing parent tabs, and you wish to add one for display.
When you finish creating the page and run it, you'll see that the standard (lower level) tab is there, and is set to active, but your parent tab is not there.
Go to Shared Components > Tabs. Select the "Manage Tabs" tab there. You can notice your new set there, but notice the striped outline of it. This tab has no parent tab for it! And this is the problem with tab creation in 2-level tabs: you can make a new STANDARD tab and tabset, and define a parent tab set OR create a NEW tab set with tab. Both options fail us: what we want is a NEW parent tab in an existing parent tab set!
So to fix our problem, from the manage tabs tab click on "Manage Parent Tabs", found on the right hand side of the screen in the region "Parent Tab Tasks".
This'll bring you to a magical new tab within the tab components. It's a mystery to me why it has to be hidden like this, and makes it a real pain to use. On this page you can manage your parent tabs (the only place to do so actually...). Here you'll see there is no parent tab for your page (again), but here you can create a new parent tab from the right hand menu "Parent Tab Tasks" > "Create New Parent Tab". Enter a label, and choose your existing parent tab set as parent tab set. Don't create a new set. As for target, refer to your new page again.
However, we are not done yet. You are returned to the "Parent Tab Management" page. You new parent tab will be shown there, but when you run your page, the parent tab will not be set active yet.
To fix that, go back to the "Parent Tab Management". Select your parent tab so you go to it's details. Firstly, give it a new sequence number, otherwise it'll be shared with one (the parent tabs are created with sequence nr 10, so most probably on a shared position with your first parent tab).
Then turn your eyes on the "Current on Standard TabSet" list item. It'll have an option selected, but take a good look: it'll be the same name as your parent tab. From the options, select your new Standard tab set (the lower level set) which holds your new page. Then apply your changes and run your page: both your parent and standard tab will be there and highlighted. Yay!

Set up new iPhone 5 with iCloud restore, then iTunes created new library with only content already on phone. How do I find and sync everything in original library?

My daughter got a new iPhone 5 and we set it up using the option to restore her iPhone 4 backup from iCloud. This worked great and everything on the old phone showed up on the new phone. Because we were traveling, we weren't able to sync the iPhone 5 with iTunes at that time.
She purchased new apps and music on the iPhone 5. When we returned home she synced with iTunes, and it seems to have created a new library, with only the content currently on the phone. I don't know if it prompted her to do this on the first sync or not - she doesn't remember.
So in iTunes, the library now only shows the music on the phone. A sync isn't doing much now because when choosing the phone in iTunes and selecting each content type across the top (Apps, Music, Movies, TV Shows) the box is unchecked to sync that content. When I check the box to "Sync Music", iTunes gives a warning:
Are you sure you want to sync music? all existing songs and playlists on the iPhone Becca's iPhone will be replaced with songs and playlists from your iTunes library.
Same goes for apps, except that warning also mentions that the apps and their data will be erased and replaced.
At some point she was also getting a message that this iPhone was associated with another library, but I'm not sure how she had triggered that. She says she canceled out of that. I can see all of the music
How do we get iTunes to see the "old" library of songs, videos and apps without losing the ones she's purchased already on the iPhone? The music files themselves are still on the computer, and include music both purchased from iTunes as well as music ripped from CDs. Thanks for any advice!

See Recover your iTunes library from your iPod or iOS device.
tt2

HR_MAINTAIN_MASTERDATA create new employee with specific PERNR

I have a list of new employee to import into SAP in automation
And this employee have a I have a list of new employee to import into SAP in automation
And this employees have a their id
How can i create new employees into SAP with a their id ?
thanks

Is your system set up to assign a new employee number when the hire process is initiated? Why are you giving people an employee number before they are hired into the HR system?
If you use PA40 I think (not sure) you can assign an employee number on the screen.
SL

Bug report about create new footprint with Rounded rectangle in 3D info Bottom

Similar Messages

Maybe you are looking for