Calculate previous Sunday from the current day

Hi Gurus,
Can anybody tell what is the name of the function module which caluclates the previous Sunday from the Current system date. or any other idea how to calculate previous sunday from the current system date in Query.
Thanks
Liza

Hello,
See my previous thread to you for a similar Re: Find out previous Monday based on 0CALDAY
Thanks
Chandran

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2nd Previous Period from the current period

Hi MM Gurus,
Is it possible in MM to open a 2nd previous from the current period?
Please advise,
Thanks,
Themba

hi,
> Check the OSS NOTE 487381
You can only open the last period via using the MMPI..using indicator allow back posting...
Other than this you can open pervious periods for sandbox techniques. as well ....but SAP don't recommend it...
check few posted threads on SDN...
Regards
Priyanka.P
Edited by: Priyanka Paltanwale on Jun 2, 2009 9:52 AM

CALCULATE 6 MINS FROM THE CURRENT SYSTEM TIME....................?

Hi
I want to subtract few mins (say 5 min , 10 min ,15 mins , max to 55 mins) from the current system time,
ex-current time 00:40:00
Subtract 5 mins(means 5 mins backward)
Final time 00:35:00
ex-current time 01:20:00
Subtract 30 mins(means 30 mins backward)
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Pls help me with this with a appropriate logic or FM..
Thanks a lot in advance
Basic Date and Time questions are not allowed. They have been answered umpteen times. Please search for them.
Edited by: kishan P on Sep 1, 2010 12:05 PM
Edited by: Matt on Sep 1, 2010 9:01 AM - And please do not post in ALL CAPITALS

May be you can do something like this!
data: l_time like sy-uzeit.
data: l_time1 like sy-uzeit value '06'. "6 hrs to be deducted from system time
move sy-uzeit to l_time. "this is system time
"write l_time.
"write:/ l_time1.
SUBTRACT l_time1 from l_time.
write:/ l_time. "This is 6 hrs behind system time
Rajasekhar

CALCULATE 6 HOURS FROM THE CURRENT SYSTEM TIME....................?

hi
good
i want to subtract 6 hours from the current system time,
ex-current time 17.07
Subtract 6 hours(means 6 hours backward)
Final time 11.07
Pls help me with this with a appropriate logic.
Thanks a lot in advance
mrutyun^

May be you can do something like this!
data: l_time like sy-uzeit.
data: l_time1 like sy-uzeit value '06'. "6 hrs to be deducted from system time
move sy-uzeit to l_time. "this is system time
"write l_time.
"write:/ l_time1.
SUBTRACT l_time1 from l_time.
write:/ l_time. "This is 6 hrs behind system time
Rajasekhar

Previous quarter from the current date using Date functions

hi all,
how can i get the value of the previous quarter and previous month using using NOW() function in the formula.
regards,
Rk
Edited by: Rk on Feb 13, 2009 9:28 AM

Hi Pk,
This "DSTR(DADD(NOW(),-1,'Q'),'YYYYQ')" will give you just an year 2008 (if you run this today).
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How to return the week number starting from Sunday as the first day

Hi Friends,
My application needs to have a report for the weekly totals and must have the Sunday as the first day for the week. For example, January of 2005 should be in the report for having six weeks, Jan 1 is Saturday, this is week 1, Week 2 is from 2 to 8, and the last week , week 6 has 30 and 31. Days need not be displayed, only the week number as follows:
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=========== =========
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Week 2 8,168
Week 3
Week 4
Week 5
Week 6
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Try this
---------------------------------------------actual formula---------------
select ceil(
( to_number(to_char(to_date('1-'||to_char(sysdate,'MON-YYYY'),'DD-MON-YYYY'),'D')) -1
+ to_number(to_char(sysdate,'DD'))
) / 7
week_number
from dual
e.g try different dates below by replacing 31-Jan-2005
select ceil(
( to_number(to_char(to_date('1-'||to_char(to_date('31-JAN-2005'),'MON-YYYY'),'DD-MON-YYYY'),'D') ) -1
+ to_number(to_char(to_date('31-JAN-2005'),'DD'))
) / 7
week_number
from dual
How does it work
week number is calculated by dividing the current day number by number of days
so in your case if the week starts at a different day , you just add the offset and divide by 7
In the first part, i am finding the week day number for the 1st day of the current month and this is used as offset.
Hope this helps
-nj
http://www.infocaptor.com

Regarding subtraction of 10 days from the current date

Need to know how I can get 10 days subtracted from the current date before the report is excuted. This needs to appear in the selection screen before the report is excuted.
The select option contains two fields the first field is the date which is 10 days subtracted from the current date and the next field is the current date.
Please suggest.
Thanks.

Hi Dolly
I had a same req before check that code:
AT SELECTION-SCREEN OUTPUT.
IF pa_older = 'X'.
CALL FUNCTION 'RP_CALC_DATE_IN_INTERVAL'
EXPORTING
date = pa_end "<<<<< date or in ur case sy-datum
days = '10'
months = '00'
signum = '-'
years = '00'
IMPORTING
calc_date = pa_end1. " <<< subtracted date
ENDIF.

Urgent ---calculate version from the current week number

hi,
i have an requrenment to modify the charasteric routines
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pls advice me which FM i have to call or provide me with some sample codeing.
points wil be rewarded
ravi

There is a FM "WEEKNR_GET".
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You will need a ABAP person to do this.
Ravi Thothadri

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When I display the e-mail with the subject line "abc", the contents are from the e-mail with the subject line "def" in the in-basket.
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How can i stay logged in on iPhone Skype after i delete the app from the 'current' apps?

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format until Outlook programmers add this Technology Age feature in newer versions.
See, this month kind of messed me up because I have so many projects for November that start tomorrow and next week, but I haven't seen them until this week. I would have been better quipped--at least expecting them--had I been able to see all of those projects
since last week or the week prior.
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Changing the calendar settings: Sunday as the first day of the week

Dear Masters of SAP universe,
In ECC6.0, I am using a LIS info-structure with the period split set to week.
I would like to know how can I change the calendar settings in order to consider Sunday as the first day of the week, instead of Monday.
For example:
A sales order created on Dec 12th creates the record 201049 in the info structure S900 - SPWOC.
I would like to have it as 201050, where 50 is the currently week in the system.
I already checked OSS notes and the transaction SCAL for customizing. But I did not find a solution this issue.
Your help is highly appreciated!

hi,
this seems to be a calendar issue.
please check for OSS also - 1158474.
balajia

Does anyone know how to remove sundays from the datepicker in BC?

I have a client that is closed on Sundays and occasionally gets an irate customer that books late saturday and is upset that no one is there on Sundays. So I would really like to remove the option of Sundays from the date picker.

Hi guys,
I had the same problem as jbyrom and found a work-around using a bit of jQuery. Before I begin...
Downsides
It's a bit of a pain if you have tons of date fields, as you'll need to add a class to each datepicker field
Because you need to add a class to each datepicker field, you'll need to add the Web Form as HTML (ie make sure "insert as module instead" is unchecked when adding the form to a page)
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Users could still put in "restricted" dates by manually typing the date instead of clicking the date in the datepicker
How-To
Add a class to each datepicker field you want to restrict days on (I'm using "datepickerhack").
Add the script below the form (ie at least after the closing </form> tag). This is so jQuery and BC's Java_Datepick.js are loaded before the script.
Add some CSS to your stylesheet to make it obvious to them they can't click certain dates.
Script
<script type="text/javascript">
$(document).ready(function(){
     $(".datepickerhack").focus(function(){
          // Grab the ID of the relevant date field and use it to call the built-in BC displayDatePicker function
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</script>
CSS
Last step is something simple for usability, so users know they can't click the unclickable days. I just used:
.date tr td:first-child{background-color:#CCC;}
.date tr:last-child td{background-color:#FFF;}
The second line is needed as the last row contains the "Today"/"Clear"/"Close" buttons (as opposed to dates)
Edit: fixed formatting, added last "Downside"

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Hi Everyone,
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Here is a pseudo - code sample -
SELECT T1.DocEntry, T1.DocNum, T1.DocDate
FROM AU.dbo.OINV T1
WHERE "CURRENT FINANCIAL YEAR"
Notice above that I would like to replace "CURRENT FINANCIAL YEAR" with an SQL code snippet that selects all dates from the beginning of the financial year (1/07/xx) to the current date.
Any help here will be greatly appreciated.
Kind Regards,
David

Hi Everyone,
Here is a code snippet that permits returning only values from the current financial year -
DECLARE @day nvarchar(2) = DAY(GETDATE())
DECLARE @currentMonthAndDay INT = CAST(CAST(MONTH(GETDATE()) as nvarchar(2)) + (REPLICATE('0', 2 - LEN(@day)) + @day) as int)
DECLARE @StartOfFinancialYear DATETIME
SET @StartOfFinancialYear = CAST(YEAR(GETDATE()) - CASE WHEN @currentMonthAndDay<701 then 1 else 0 end as nvarchar(max)) + '0701'
SELECT *
FROM AU.dbo.OINV T0
WHERE T0.DocDate >= @StartOfFinancialYear
AND T0.DocDate < DATEADD(yy, 1, @StartOfFinancialYear)
Many thanks to Faheem for providing the answer to returning only results from the current financial year, in this thread: http://social.msdn.microsoft.com/Forums/sqlserver/en-US/2edbe630-faca-4f94-a014-04f5a832f81d/returning-results-that-fall-within-the-current-financial-year?forum=transactsql
Kind Regards,
David

Get three previous records of the current record

Hi,
I need to get three previous records of the current record in an Oracle Form
Sorry for the lengthy explanation:
I have a table name: ARCHIVE_DATA with column name: coll_time and its data type DATE.
SQL> SELECT COLL_TIME FROM ARCHIVE_DATA;
COLL_TIME
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
12-AUG-05
10 rows selected.
SQL> select to_char(coll_time,'dd-mon-yyyy:HH:MI:SS') from ARCHIVE_DATA;
TO_CHAR(COLL_TIME)
12-aug-2005:02:42:00
12-aug-2005:02:43:00
12-aug-2005:02:44:00
12-aug-2005:02:45:00
12-aug-2005:02:46:00
12-aug-2005:02:47:00
12-aug-2005:02:48:00
12-aug-2005:02:49:00
12-aug-2005:02:50:00
12-aug-2005:02:51:00
10 rows selected.
This is the Requirement:
In a Form's Block(BLK1), for example: the current_record is the fifth record from the top
(i.e. 12-aug-2005:02:46:00)
When the fifth record is the current_record and When I click a button, three previous records of the
current_record should be populated on the screen.
See what I did:
I created another table same as the first table(ARCHIVE_DATA) and its name is: THREE_RECS.
I am inserting three records from the first table(ARCHIVE_DATA) into the second table: THREE_RECS
which are less than the current record and ORDER BY DESC.
CANVAS:
Two blocks (BLK1, BLK2) based on ARCHIVE_DATA and THREE_RECS are on the same CANVAS.
But the first block (BLK1) which is based on the first table:ARCHIVE_DATA is populated with one record and the
second block (BLK2) is empty.
So when I click a particular button (ex: prev_recs), the second block(BLK2) should be populated with
three previous records of the current record( :BLK1.COLL_TIME)
(off course :BLK2 populates with one record and use arrows or scrollbar to get the other two records)
This is the code I wrote in the trigger and followed by the error:
1 BEGIN
2 DECLARE
3 cursor c1 IS
4           SELECT MONITOR_ID,
5               SAMPLE_ID,
6               COLL_TIME,
7               DEW_POINT
8          FROM ARCHIVE_DATA;
9 cursor c2(passing_date IN date) IS
10           SELECT MONITOR_ID,
11               SAMPLE_ID,
12               COLL_TIME,
13               DEW_POINT
14          FROM (SELECT MONITOR_ID,
15               SAMPLE_ID,
16               COLL_TIME,
17               DEW_POINT
18          FROM ARCHIVE_DATA
19          ORDER BY COLL_TIME desc)
20      WHERE COLL_TIME < passing_date;
21     BEGIN
22     FOR cur_rec in c1
23     LOOP
24          IF (cur_rec.COLL_TIME = to_date(:BLK.COLL_TIME,'dd-mon-yyyy:HH24:mi:ss')) then
25     FOR second_cur_rec in c2(second_cur_rec.COLL_TIME)
26          LOOP
27      IF c2%rowcount < 4 then
28               BEGIN
29               INSERT INTO THREE_RECS
30                    values(second_cur_rec.MONITOR_ID,
31                         second_cur_rec.SAMPLE_ID,
32                         second_cur_rec.COLL_TIME,
33                         second_cur_rec.DEW_POINT);
34               COMMIT;
35               END IF;
36 END LOOP;
37 END IF;
38 END LOOP;
39 END;
40 END;
This is the error I am getting:
Error 103 at line 14
Encountered the symbol "(" when expecting one of the following
a PL/SQL variable or double quoted string
an expanded name
an expanded name link
a table reference __expression
a key word
Resuming parse at line 126, column 46
Thanks in advance

Why not just a simple select that doesn't involve a second table and PL/SQL?
sql>select * from t1 order by dt;
DT
08/12/2005 02:42:00am
08/12/2005 02:43:00am
08/12/2005 02:44:00am
08/12/2005 02:45:00am
08/12/2005 02:46:00am
08/12/2005 02:47:00am
08/12/2005 02:48:00am
08/12/2005 02:49:00am
08/12/2005 02:50:00am
08/12/2005 02:51:00am
10 rows selected.
sql>select dt
2    from (select dt, row_number() over (order by dt desc) rn
3            from t1
4           where dt < to_date('12-aug-2005:02:46:00', 'dd-mon-yyyy:hh:mi:ss'))
5   where rn <= 3
6   order by dt;
DT
08/12/2005 02:43:00am
08/12/2005 02:44:00am
08/12/2005 02:45:00am
3 rows selected.If the use of an analytical function (row_number()) is a problem with Forms, then the query can also be done as:
sql>select dt
2    from (select dt
3            from (select dt
4                    from t1
5                   where dt < to_date('12-aug-2005:02:46:00', 'dd-mon-yyyy:hh:mi:ss')
6                   order by dt desc)
7           where rownum <= 3)
8   order by dt;
DT
08/12/2005 02:43:00am
08/12/2005 02:44:00am
08/12/2005 02:45:00am
3 rows selected.

Calculate previous Sunday from the current day

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