Can't figure out block quote line after quote issue
Hi - I'm building a block quote in DW for my site and can't figure out 2 things:
1. How to move up the text after the first line so it's the same throughout
2. How to move the quote author over to the right margin
Below is the CSS and HTML for what I have so far as below that is a snap shot of what I'm seeing:
blockquote {
background: #F0F7FF;
border-left: 10px solid #9D9D9D;
margin: 1.5em 10px;
padding: 0.5em 10px;
quotes: "\201C""\201D""\2018""\2019";
blockquote:before {
color: #9D9D9D;
content: open-quote;
font-size: 8em;
line-height: 0.9em;
margin-right: 0.25em;
vertical-align: -0.4em;
blockquote p {
display: inline;
font-family: Times New Roman;
font-size: 1.8em;
line-height: 1.8em;
</style>
</head>
<body>
<blockquote><p><em>Pellentesque habitant morbi tristique senectus et netus et malesuada fames ac turpis egestas. Vestibulum tortor quam, feugiat vitae, ultricies eget, tempor sit amet, ante. Donec eu libero sit amet quam egestas semper. Aenean ultricies mi vitae est. Mauris placerat eleifend leo."</em></p>
<br><br>
<p>— Albert Einstein</p></blockquote>
Probably need to get a bit creative to include the large quote:
<!DOCTYPE HTML>
<html>
<head>
<meta charset="UTF-8">
<title>Untitled Document</title>
<style>
body {
font-family: times;
blockquote {
background: #F0F7FF;
border-left: 10px solid #9D9D9D;
margin: 1.5em 10px;
padding: 0.5em 10px;
quotes: "\201C""\201D""\2018""\2019";
.quote {
position: absolute;
top: 45px;
color: #9D9D9D;
padding: 0 0 0 2%;
font-size: 8em;
letter-spacing: -10px;
blockquote p {
text-indent: 60px;
position: relative;
font-family: Times New Roman;
padding: 0 0 0 3%;
font-size: 1.8em;
line-height: 1.8em;
blockquote .author {
text-align: right;
padding: 0 3% 0 0;
margin: 0;
</style>
</head>
<body>
<blockquote><span class="quote">‘‘</span><p><em>Pellentesque habitant morbi tristique senectus et netus et malesuada fames ac turpis egestas. Vestibulum tortor quam, feugiat vitae, ultricies eget, tempor sit amet, ante. Donec eu libero sit amet quam egestas semper. Aenean ultricies mi vitae est. Mauris placerat eleifend leo."</em></p>
<p class="author">— Albert Einstein</p>
</blockquote>
</body>
</html>
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I will attach the code I have below. It is almost entirely done but i am getting a NullPointerException that is driving me nuts, and I can't figure out were it is coming from.
Help is greatly appreciated.
First code:
import java.util.Scanner;
import java.io.*;
import java.util.Random;
import java.util.Collection;
public class DistributionPlagiarist
public static void main(String[] args) throws IOException
Scanner keyboard = new Scanner(System.in);
int keyLength=0, phraseLength=0, numberOfPhrases=0;
String inputFileName="", keepReadingFromFile="", theFile="";
FrequencyLibrary text = new DenseFrequencyLibrary();
if(args.length != 4)
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phraseLength = Integer.parseInt(args[1]);
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inputFileName = args[3];
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text.add(name, singleCharacter);
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stop++;
count++;
int countNumberOfPhrases=0;
while(numberOfPhrases > 0)
countNumberOfPhrases++;
String phrase = randomphrase(text, phraseLength, keyLength);
System.out.println("Phrase " + countNumberOfPhrases + ":\n" + phrase);
numberOfPhrases--;
private static String randomphrase(FrequencyLibrary textLibrary, int phraseLengthToMake, int startLength)
String startString="";
char characterToAdd=' ';
startLength++;
Random generator = new Random();
int sizeOfLibrary=textLibrary.size()/2, randomInt = generator.nextInt(sizeOfLibrary+1), value=0;
Collection<String> stringNames = textLibrary.makeStringCollection();
for(String stringFromCollection : stringNames)
if(randomInt == value)
startString = stringFromCollection;
value++;
String thePhrase = new String(startString);
System.out.println("INITIAL START:" + startString + "TTTT");
int substringStart=1;
while(startLength < phraseLengthToMake)
characterToAdd = textLibrary.randomUniformChoose(startString);
thePhrase = thePhrase + characterToAdd;
System.out.println("CHARACTER:" + characterToAdd + "TTTT");
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startString = thePhrase.substring(substringStart, thePhrase.length());
boolean answer = textLibrary.contains(startString);
System.out.println(answer);
System.out.println("NEW STRING:" + startString + "TTTT");
startLength++;
substringStart++;
return thePhrase;
}Second code:
import java.util.Collection;
import java.util.HashMap;
public class DenseFrequencyLibrary implements FrequencyLibrary
private HashMap<String, MultiSetOfChar> bookTitleAndCharacterAndIntegerHashMap = new HashMap<String, MultiSetOfChar>();
private MultiSetOfChar keyAndValuePairs = new DenseMultiSetOfChar();
* Creates a new DenseFrequencyLibrary with all the essential things clear;
DenseFrequencyLibrary()
bookTitleAndCharacterAndIntegerHashMap.clear();
* Input the value from the creation of the DensneMultiSetOfChar into a HashMap. If the key
* already exists then the value associated with it is updated by one.
* @param character a char to be used in forming the HashMap
* @return characterMap
private HashMap<String, MultiSetOfChar> inputIntoMap(String name, char character)
if(!bookTitleAndCharacterAndIntegerHashMap.containsKey(name))
keyAndValuePairs = new DenseMultiSetOfChar(character);
else
keyAndValuePairs.add(character);
this.bookTitleAndCharacterAndIntegerHashMap.put(name, keyAndValuePairs); //input character and value
return bookTitleAndCharacterAndIntegerHashMap; //return the new HashMap
* Returns the number of books in the library.
* @return |b|, ie the number of books in b
public int size()
int numberOfBooks=bookTitleAndCharacterAndIntegerHashMap.size();
return numberOfBooks;
* Searches the library for an occurrence of a given book
* @param target the name of a book to be searched for in the library
* @return true if and only if the argument is already a book title in the library.
public boolean contains(String target)
boolean bookIsInLibrary=false;
if(bookTitleAndCharacterAndIntegerHashMap.containsKey(target))
bookIsInLibrary = true;
return bookIsInLibrary;
* Returns the MultiSetOfChar that represents the occurrences of the individual characters
* in the text of the book indicated by the argument.
* @param target
* @return MultiSetOfChar
public MultiSetOfChar getFrequencies(String target)
MultiSetOfChar frequencyMultiSetOfChar = bookTitleAndCharacterAndIntegerHashMap.get(target);
return frequencyMultiSetOfChar;
* Modifies the character occurrences associated with name to include one more occurrence of element.
* @param name string of the name of the book
* @param element character to add to the specified book
public void add(String name, char element)
bookTitleAndCharacterAndIntegerHashMap = inputIntoMap(name, element);
* Modifies the character occurrences associated with name to include one less occurrence of element.
* @param name string of the name of the book
* @param element character to be removed from the specified book
* @return true if and only if the book is modified.
public boolean remove(String name, char element)
boolean characterWasRemovedFromBook=false;
//if the target character is in the map then remove it
if(bookTitleAndCharacterAndIntegerHashMap.containsKey(name))
MultiSetOfChar keyAndValuePairs = bookTitleAndCharacterAndIntegerHashMap.get(name);
keyAndValuePairs.remove(element);
characterWasRemovedFromBook = true; //set answer to true because the HashMap was changed
else //target does not exist in the HashMap
characterWasRemovedFromBook = false; //set answer to false because the HashMap was not changed
return characterWasRemovedFromBook;
* Returns a random character, chosen from the same distribution as the characters appear in the book.
* For example, if 5% of the characters in "Alice in Wonderland" are an 'A', then this method should
* return an 'A' about 5% of the time.
* @param name string of the name of the book to search through and remove a character
* @return true if and only if the argument is already a book title in the library.
public char randomUniformChoose(String name)
MultiSetOfChar keyAndValuePairs = bookTitleAndCharacterAndIntegerHashMap.get(name);
char randomCharacter = keyAndValuePairs.randomUniformChoose();
return randomCharacter; //return the random character pulled out
public Collection<String> makeStringCollection()
Collection<String> stringCollection = bookTitleAndCharacterAndIntegerHashMap.keySet();
return stringCollection;
}Third code:
import java.util.HashMap;
import java.util.Set;
import java.util.Collection;
import java.util.Random;
* DenseMultiSetOfChar implements MultiSetOfChar.
* @mathmodel b is a finite multiset
* @mathdef
* |b| is the cardinality of b
* ||c,b|| is the number of occurrences of element c in b
* @author Kyle Hiltner
public class DenseMultiSetOfChar implements MultiSetOfChar
private char characterInput=' ';
private HashMap<Character, Integer> characterMap = new HashMap<Character, Integer>();
* Create a new DenseMultiSetOfChar with zero argument
DenseMultiSetOfChar()
characterMap.clear(); //clear static HashMap
* Create a new DenseMultiSetOfChar with the passed in value.
* @param newChar character input to be added to the HashMap
DenseMultiSetOfChar(char newChar)
this.characterInput = newChar; //set characterInput to the value passed in
characterMap = inputIntoMap(this.characterInput); //call private procedure to add characterInput to HashMap
* Input the value from the creation of the DensneMultiSetOfChar into a HashMap. If the key
* already exists then the value associated with it is updated by one.
* @param character a char to be used in forming the HashMap
* @return characterMap
private HashMap<Character, Integer> inputIntoMap(char character)
//if the character is not in the HashMap then add it with the starting value of 1
if(!characterMap.containsKey(character))
characterMap.put(character, 1); //input character and value
else //character does exist
int value = characterMap.get(character); //get the value for the specified key
value++; //increase the value so as to show that another character was added
characterMap.put(character, value); //place the character and new value in the HashMap
return characterMap; //return the new HashMap
* Returns the number of elements in this multiset (ie its cardinality).
* Note that since multisets can include duplicates, the cardinality may be
* larger than the number of distinct elements. Also, the total number of
* items in the multiset is bounded above by Integer.MAX_VALUE.
* @return |b|, ie the cardinality of b
public int getCardinality()
int totalElementsInMap=0;
Collection<Integer> integerCollection = characterMap.values(); //create a collection for easy iteration
//iterate through each value in the HashMap and compute the total number of elements in the HashMap
for(Integer valueFromCollection : integerCollection)
totalElementsInMap = totalElementsInMap + valueFromCollection; //compute new value of total values
return totalElementsInMap; //return the final total value
* Returns the number of occurrences of a given element in the multiset. A
* simple identity relating getElementCount and getCardinality is that the
* sum of getElementCount for each char is equal to the cardinality of the
* set.
* @param target
* char to be counted in the multiset
* @return ||target,b||, ie the number of occurrences of target in b
public int getElementCount(char target)
int numberOfGivenCharacters=0; //set initial value
//if the HashMap contains the target character then numberOfGivenCharacters is set to the value
if(characterMap.containsKey(target))
numberOfGivenCharacters = characterMap.get(target); //set numberOfGivenCharacters to the value assigned to the target character
return numberOfGivenCharacters; //return the value for the target character
* Returns a set such that every element in the multiset is in the set (but
* no duplicates). The cardinality of the returned set must be less than or
* equal to |b|. The cardinality of the two are equal if and only if b
* contains no duplicate elements.
* @return a set of Character, s, such that: <br />
* (for all (Character)i in s : (char)i in b) and <br />
* (for all (char)i in b : (Character)i in s)
public Set<Character> getElementSet()
Set<Character> characterSet = characterMap.keySet(); //create a Set from the keys of characters in the HashMap
return characterSet; //return the character Set
* Adds a single element to the multiset. This operation always increases
* the cardinality of the multiset by 1, assuming that the maximum capacity
* of Integer.MAX_VALUE has not been reached.
* @param item
* the char to be added to b
* @requires |b| < Integer.MAX_VALUE
* @alters b
* @ensures b = #b union {item}
public void add(char item)
characterMap = inputIntoMap(item); //call the private method to add new character (item) to the HashMap
* Removes the target, if it is present in the multiset. The method returns
* true if and only if it changes the multiset.
* @param target
* the char to be removed
* @alters b
* @ensures (target not in #b) ==> (b = #b) <br />
* (target in #b) ==> (b union {target} = #b)
* @return target in #b
public boolean remove(char target)
boolean answer=false; //set initial value to false
//if the target character is in the map then remove it
if(characterMap.containsKey(target))
int value = characterMap.get(target); //find the value associated with the target character
//if the value is 1 call remove from the HashMap and remove key and value
if(value == 1)
characterMap.remove(target); //remove key and value from the HashMap
else //value is greater than 1
value--; //decrease value to show removal
characterMap.put(target, value); //replace target character with new value back into the HashMap
answer = true; //set answer to true because the HashMap was changed
else //target does not exist in the HashMap
answer = false; //set answer to false because the HashMap was not changed
return answer; //return answer
* Returns a char chosen randomly based on the contents of the multiset.
* This operation does not remove the char from the multiset or change the
* multiset in any way. In particular, the cardinality of the multiset is
* the same before and after this method.
* <p>
* Characters should be returned with a random distribution equal to the
* distribution of characters in the multiset. That is, for a character that
* appears N times in a multiset of cardinality M, the probability of that
* character being returned is N / M. For example, a multiset that contains
* only the character 'a', possibly many times, would always result in an
* 'a' being generated. On the other hand, a multiset with an equal number
* of 'a' and 'b' elements would return an 'a' approximately half the time
* and a 'b' the other half.
* @requires |b| >= 1
* @return char c with probability p, where: <br />
* p = ||c,b|| / |b|
public char randomUniformChoose()
char randomCharacter=' ';
Random generator = new Random();
int totalElementsInMap=0;
Collection<Integer> integerCollection = characterMap.values(); //create a collection for easy iteration
//iterate through each value in the HashMap and compute the total number of elements in the HashMap.
//Do this in case a remove call was made
for(Integer valueFromCollection : integerCollection)
totalElementsInMap = totalElementsInMap + valueFromCollection; //compute new value of total values
int randomInt = generator.nextInt(totalElementsInMap+1), lowerValue=0, upperValue=0;
Collection<Character> keyCollection = characterMap.keySet();
//iterate through each value in the HashMap and compute the total number of elements in the HashMap
for(Character keyFromCollection : keyCollection)
upperValue = upperValue + characterMap.get(keyFromCollection);
if(randomInt == upperValue)
randomCharacter = keyFromCollection;
if(randomInt >= lowerValue && randomInt <= upperValue)
randomCharacter = keyFromCollection;
lowerValue = upperValue + 1;
return randomCharacter; //return the random character pulled out
}The Error:
Exception in thread "main" java.lang.NullPointerException
at DenseFrequencyLibrary.randomUniformChoose(DenseFrequencyLibrary.java:137)
at DistributionPlagiarist.randomphrase(DistributionPlagiarist.java:146)
at DistributionPlagiarist.main(DistributionPlagiarist.java:112)I will attempt to explain what this does in as few words as possible. For a breakdown of the lab go urlhttp://www.cse.ohio-state.edu/~paolo/teaching/494MJ/labs/lab8.shtml{url}. If you don't feel like reading that: THe program reads in some command line arguments. From there it reads from the file provided in the command line and creates "keys" from the specified length. From there I need to create a phrase of the specified length. If i am supposed to create more then one then i do. That is pretty much it. I can't figure out where (really why) the NullPointerException error is coming from.
Help is appreciated!!Post the actual error text (copy and paste, don't "interpret" it) here.
It should include a stack trace which references a line number of the program -
unless you suppressed the trace, in which case change your error handling
so that the trace is produced.
Identify which program line in your post the error is pointing to so that we can match
the error with your program, since your post doesn't have line numbers..
Edited by: ChuckBing on Nov 16, 2007 7:19 PM
Also - posting large amounts of code (as you did) will reduce the chance of anyone helping -
Can't figure out what is wrong with recovery DVDs
Last year, right after turning my laptop ON, I've created 4 DVDs as such: http://i56.tinypic.com/6i79rn.jpg
Recovery DVD Disk 1
Recovery DVD Disk 2
Recovery DVD Disk 3
Windows Recovery Environment 64-bit
My Laptop is Qosmio F60-14R, with Windows 7 Home Premium.
Now all I want to do is format my laptop and re-install windows 7 Home premium using those 4 DVDs. However I can't figure out why I cannot re-install or get the laptop back to the factory state.
This have wasted 8 hours straight of my time and frustrated me by great deal. Can you kindly tell me what I have to do? I am lost!Here is what I have done so far:
I inserted 'Windows Recovery Environment (64-bit)' DVD and booted the laptop from it.
First thing that loads up is a window with two options:
- Toshiba Recovery Wizard
- System Recovery Options
Taking Toshiba Recovery Wizard as choice, clicking Next.
It asks me: "Please set 1st Recovery Media and press Next to Continue.
So, I insert Recovery DVD 1 and then click Next. However it ejects the disc drive (seems Recovery DVD 1 is not the correct Disk!).
So I repeat the same process with Recovery DVD 2 and Recovery DVD 3 and again the Disk Drive ejects the Disks.... As a desperation attempt I even put the Windows Recovery Environment Disk inside but that as well get ejected.
Okay, so the Toshiba Recovery Wizard is not the right choice 'it seems'.
So, I restart the laptop and inserted 'Windows Recovery Environment (64-bit)' DVD and booted the laptop from it.
First thing that loads up is a window with two options: (First choice failed, now trying second choice)
- --Toshiba Recovery Wizard--
- System Recovery Options
So, choosing System Recovery Options this time and clicking Next. I Choose US as Keyboard, then click Next. A small window appears which gives me two further options:
- Use Recovery tools that can help fix problems starting Windows. Select an Operating System to repair.
- Restore your computer using a system image that you created earlier.
So, I already tried the first choice and it takes me to another window with several recovery tools. One of the tools is System Image Recovery but when I click it, it gives a Warning messagebox that says:
Windows cannot find a system image on this computer. etc.
But when I insert every disk, still the warning messagebox shows up as if all the four recovery DVDs are irrelevant.
So, it seems the first choice doesn't lead me anywhere. So, remains the second choice:
- Restore your computer using a system image that you created earlier.
Turns out it is exactly the same 'System Image Recovery' from first option mentioned few lines earlier. So, there you have it, checkmate.
Please guide. -
Can't figure out how to create an update form in a cfwindow tag
I finally was able to figure out how to do an add form inside
of a cfwindow tag yesterday. But I want this form to be
multipurpose, and allow edits as well. But for the life of me, I
can't figure out how to pass a row of data to the form inside a
cfwindow. Normally, I'd pass the primary key via the URL but if I
try to do that here, it basically reloads the page and closes out
the cfwindow since I have the window set to not show by default.
My page has a list of departments. My page is called
departments.cfm. For each row in the department list, there is a
link called edit. When the user clicks this link, I want the
cfwindow to open with the cfform populated with the data from the
department list for the row selected. Sounds simple enough, except
how do I pass the department_id to the form? If my link is <a
href="departments.cfm?id=#department_id#>Edit</a>, the
cfwindow tag displays and I can see the data in it, but then closes
right away. I finally figured out that it was calling the page
again and the cfwindow is closing because I have it set to not
display by default. I'm about ready to drop this cfwindow and just
do real popup windows via javascript. And I'm normally not in favor
of doing popup windows, but the application I'm working on doesn't
have enough real estate on the screen to do a hidden form, so a
separate window containing the form is my best solution.
Anyone have any suggestions?Well, this is kind of a tough one for me, but it sounds like
the best way will be to launch a JavaScript function everytime the
user clicks the link, like this:
<cfoutput query="getDepartments">
<a href="javascript:showWin(#yourID#)">show
window</a>
<br>
</cfoutput>
the showWin function will both create the window and launch
it, passing in the user chosen var:
function showWin(id) {
var URL = 'editDeptPage.cfm?dept_id=' + id;
var winName = 'deptWin' + id;
ColdFusion.Window.create(winName, 'Edit the Department',
URL,
{x:100,y:100,height:300,width:400,modal:false,closable:true,
draggable:true,resizable:true,center:true,initshow:true,
minheight:200,minwidth:200 })
The following line of code is supposedly to make sure that
the window refreshes each time it is launched, by naming it
something new each time:
var winName = 'deptWin' + id;
However, if it doesn't work, I think there's a Window refresh
function in the Ext library but I'm not sure.
Also, in the showWin function, after the Window is created,
you might need this but I'm not sure:
ColdFusion.Window.show(winName)
Talk to you later,
Peter -
Master page size conflict? Can't figure out what's wrong...
Hi community,
I posted this ticket earlier, but I think I should post it in English, for a larger audience...
So here's the story :
I got a really odd issue while moving (or adding) pages...
Here's a very basic layout :
Now, lets place page 2 after page 3. Here's the result :
As you can see, pages don't seem to relate properly to master pages.
I can't figure out why...
If I apply masters onto my pages, InDesign says there's a size conflict.
Assuming I would apply again my master, ID will replace elements at the right place for now, but doesn't solve the problem at all.
Any idea ??
Here's a download link for this document :
http://dl.free.fr/lPfXwwajm
Please note, I'm working with InDesign CS6 (8.0.2 version)
Thanks a lot for your help!
VincentHi Willy.
I didn't use the page tool (I never do), but it's a collaborative project, so I can't be sure nobody did.
As you might have guessed, the attached Indd file is not the real file: I did remove all styles, variants, blocks,... everything from the original project to reduce it to a very basic template...
If I create a document from scratch, obviously there is no problem. If I don't find the solution, I will recreate the document from scratch, but you'll understand I'd like to avoid spending my time that way...
So...
I tried changing the orientation from document setup and crtl-z... didn't do the trick!
Now, here are more information for a better understanding:
The original project was landscape orientated (A4).
I had to adapt it to a portrait orientation version (still A4). Please note I didn't use the page tool. Obviously, something got wrong there and did create the problem...
Now, if I right-click my page panel and set its view "by variant", the name of the (unique) variant is the same than the original project, even though it has a different orientation.
The strange thing is that the name is a personalized one (it should have been "A4 H"). Why is that? I dunno... Why (anf who did?) change the name of the "variant" is a mystery... But I guess this could be a clue...
Well... still stuck on this puzzler...
Thanks all for your help anyway...
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