Case Statement and Group By issues

Question

Hi this is my initial query which works perfectly:
select ff.cla_case_no, Cost_before_Decision, Cost_Of_Claim, decline, Decline_Description from
fraud_nov_14_final ff
,(select cla_case_no, (sum(total_cost_adj_old) + sum(decline_estimate)) Cost_before_Decision
from reporting.ci_final@test
group by cla_case_no) z
where ff.cla_case_no = z.cla_case_noI now want to add in a condition based on a column called decline:
select ff.cla_case_no, Cost_before_Decision, Cost_Of_Claim, ff.decline, Decline_Description from
fraud_nov_14_final ff
,(select cla_case_no, (case when decline = 1 or decline = 2  THEN (sum(total_cost_adj_old) + sum(decline_estimate)) ELSE Total_Cost END) Cost_before_Decision
from reporting.ci_final@test
group by cla_case_no) z
where ff.cla_case_no = z.cla_case_noThe error message I receive is :
ORA-00979: not a GROUP BY expression
00979. 00000 - "not a GROUP BY expression"
Thanks in advance for your help!!
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Answer 1

You would need DECLINE in the group by clause of your inner query.
Additionally you would need to change TOTAL_COST to SUM(TOTAL_COST) in where case statement.
But then you would retrieve one row for each value of DECLINE in this query.
You also could use this:
(I don't know if it will meet your requirements)
SELECT ff.cla_case_no,
                 cost_before_decision,
                 cost_of_claim,
                 ff.decline,
                 decline_description
  FROM fraud_nov_14_final ff,
                 (SELECT   cla_case_no,
                           SUM (decode(decline,1,total_cost_adj_old+decline_estimate,
                                               2,total_cost_adj_old+decline_estimate,
                                               total_cost))  cost_before_decision
                                FROM reporting.ci_final@test
                  GROUP BY cla_case_no) z
WHERE ff.cla_case_no = z.cla_case_no;(untested code, because I don't have your tables)
Edited by: hm on 23.11.2011 06:52