Clarification on Multiplication Table

Question

Hi! I have written the following program on multiplication table but the output is slightly different from expected and I do not know where has went wrong. Pls help!l
The question is, if x=5 and y=6, the output shld be
1*6=6
2*6=12
3*6=18
4*6=24
5*6=30
If x=3 and y=4, the output shld be
1*3=3
2*3=6
3*3=9
4*3=12
import java.util.*;
public class multiplicationTable
static Scanner console = new Scanner(System.in);
public static void main(String args[])
  //variable declaration
  int x;
  int y;
  int result;
  System.out.print("Enter the value X: ");
     x = console.nextInt();
  System.out.print("Enter value Y: ");
     y = console.nextInt();
  for (int i=1; i<=x; i++) {
    result = i * y;  
    System.out.print( result );
    System.out.println( i + " * " + y + " = " + result + "\n");
Output
--------------------Configuration: MultiplicationTable - JDK version 1.5.0_19 <Default> - <Default>--------------------
Enter the value X: 3
Enter value Y: 4
41*4 = 4
82*4 = 8
123*4 = 12
Process completed.

Answer 1

Solution found....
import java.util.*;
public class multiplicationTable
static Scanner console = new Scanner(System.in);
public static void main(String args[])
  //variable declaration
  int x;
  int y;
  int result;
  System.out.print("Enter the value X: ");
     x = console.nextInt();
  System.out.print("Enter value Y: ");
     y = console.nextInt();
  for (int i=1; i<=x; i++) {
    result = i * y;  
    System.out.println( i + " * " + y + " = " + result + "\n");
}