Compare two arrays

I have two arrays such as these
Array 1                          Array 2
a      1
a      5                                 a
b      2                                 b
c      3                                 f
d      4                                 g
e      5                                 h
f       6
g      7
g      10
h      8
h      9/
with what i have now i can create an array that lists the matching elements
Results:
a          1
b          2
f           6
g          7
h          8
However, it does not record both sets of a,g, and h, only the first instance. Anyone know how to fix this problem?
Any help is appreciated
Solved!
Go to Solution.
Attachments:
Compare Arrays.vi ‏14 KB

rmarks12 wrote:
im pretty new to labview.
That's okay we were all new at some point. If you have an question about a function in particular you can open the context help (CTRL + H) and over over a function to learn more. Also here is some free training if you are interested.
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Similar Messages

Compare Two Array

Hi,
can you plz help me.
How i can compare two array. following my code..
var my_array:Array=Array(5,10,15,20,25,30)
var new_array:Array=Array(7,8,9,10,11,12,13)
for(var i:Number=0;i<my_array.length;i++){
    if(my_array[i]==new_array[i]){
        trace(my_array[i])
Thanks in Advance,
JaxNa

hey dear can you tell me one thing..
when my_array length is 3
and new_array length is 5
that time how i can compare two array actually i have this problem..
var my_array:Array = Array(5, 10, 15, 20);
var new_array:Array = Array(7, 8, 9, 10, 11, 12);
for (var i:Number = 0; i<my_array.length; i++) {
     if (my_array[i] == new_array[i]) {
        trace("'My Array' "+i+"("+my_array[i]+") 'new_array' "+i+"("+new_array[i]+") = Matching");
     } else {
        trace("'My Array' "+i+"("+my_array[i]+") 'new_array' "+i+"("+new_array[i]+") = Not Matching");
Thanks

How to (logical) compare two arrays

Hello,
i have two boolean arrays.
A[0,1,1,1,0,1,0,0,1,0,0,0,0]
B[0,1,1,1,0,1,0,0,1,0,1,1,0]
They have same size. The only difference are the last two 1,1 in array B.
What do i have to do to get an array that contains only the differences?
C[0,0,0,0,0,0,0,0,0,0,1,1,0]
Thx

... And if you want less obscure code, simply use a "not equal" from the comparison palette, same result.
"Not equal" is much easier to understand for a new programmer than the geeky " xor". It is also more universal and works for arrays of any datatype. For example xor will do bitwise for integers and won't work for DBL, != will always give you a boolean array showing which elements differ.
LabVIEW Champion . Do more with less code and in less time .

Compare two arrays (greater-equal) has wrong result. Bug?

Hallo,
in my attached example (LX 8.2) i have three arrays which are displayed in the graph.
As you can see the "Trace-plot" is below the "LowerLimit-plot".
In the code i do a "Trace >= LowerLimit" which should have the result = FALSE because its not always >=.
But the result is TRUE!!
Why??
All three arrays have 201 points
Thanks for your help
Attachments:
TraceTest.vi ‏19 KB

It is only recording the last point saved from the comparison. Try This:
Message Edited by Tom Haggerty on 12-04-2007 08:50 AM
Message Edited by Tom Haggerty on 12-04-2007 08:51 AM
Sorry about the hidden wires! I just added the FOR loop very quickly and didn't clean it up.
Tom
Message Edited by Tom Haggerty on 12-04-2007 08:52 AM
Attachments:
fix.PNG ‏11 KB

Failed to compare two elements in the array

very often, I have the error "Failed to compare two elements in the array" in Exchange 2013 ECP. We are not running DAG. I google a bit but don't get a lot of result on this.
I was trying to track mail from a user who send to DL group. Since I can't do in in ECP , how can I do it in EMS?

I too have this issue. I'm not sure how wide spread. I know of one user who sends emails regularly to a DL named "All Users" which is a Security Group which we then add real users to and not just every mailbox. When he sends the emails,
from his perspective, everything is fine, meaning he gets to NDR or anything. Also, when he adds the Dl in Outlook To field and expands it, all the correct users are there. In fact, it tells him there are 203 addresses here. However, only
184 are actually getting the message. When I try the EAC to view the tracking report, it will show the message, but if I click on the edit button, I get "Failed to compare two elements in the array". If I try from EMC with search-messagetrackingreport
-identity "recipient address" -sender "sender address" -bypassdelegatechecking and the recipient address is the group, it says it could not be found. If I try with simply putting an email address of someone who is a member of that group, it says Warning:
An unexpected error has occured and a Watson dump is being generated. Failed to compare two elements in the array. I don't know what else to try. Anybody??

I am looping and through an array comparing two bigdecimals:

I am looping and through an array comparing two bigdecimals:
I get the max for valueB only if I have multiple items. not when I have one item why would that be:
val=0;
if (array.compareTo(valueB) > 0) {

Hi. You were wise to trace the value of n. Your problem seems
to be that the tests succeed (almost always) in the very first
iteration because they truly don't match (where n = 0) and
execution breaks out. You need to adjust the logic. As one
approach, while sticking with your code and not changing it too
much (such as using more efficient int vs Number):
at the very top, define a counter var ct:int = 0;
before the testing loop, define a flag, such as var
flag:boolean = false;
you could then invert the logic in the loop and test for ==
rather than for !=
if you find a match, do--> flag = true;
and break
at the end of testing, use the flag to decide whether to
store the new value
if (!flag) {
// add to array
ct++;
also, use a while loop for controlling the whole thing-->
while(ct < max) { }
to know when you're done
You can also check out the Array functions indexOf() and
some(), to make things more efficient and faster/easier
when you're all done, you can also look into using if (a != b
&& c != d)
for efficiency, instead of nesting them separately
good luck :)

Two array objects compareTo:

Have two arrays: ttt and ppp. I have to have a method to compare them.
public int compareTo(object ob)
both of the arrays are int type and both have super long numbers in them.
Thanks

Actually, the reflection api is pretty fast since
JDK1.4.0...No. Reflection could not be fast. In J2SDK1.4 it seems to be faster then in previous releases. But improvments do not include array operations. So here are some results of simple benchmark:
bash-2.05a$ /usr/java/jdk1.3.1_04/bin/java TestArray
Result for reflect copiing (3 elements, 1000000 times): 4915ms
Result for system copiing (3 elements, 1000000 times): 460ms
Result for pure java copiing (3 elements, 1000000 times): 137ms
bash-2.05a$
bash-2.05a$ /usr/java/j2sdk1.4.0_01/bin/java TestArray
Result for reflect copiing (3 elements, 1000000 times): 6082ms
Result for system copiing (3 elements, 1000000 times): 491ms
Result for pure java copiing (3 elements, 1000000 times): 115ms
bash-2.05a$
bash-2.05a$ /usr/java/j2sdk1.4.1/bin/java TestArray
Result for reflect copiing (3 elements, 1000000 times): 5738ms
Result for system copiing (3 elements, 1000000 times): 497ms
Result for pure java copiing (3 elements, 1000000 times): 157ms
bash-2.05a$
As you can see, in new Java reflect operations on arrays are even slower then in jdk1.3.1. System copiing is good alternative for pure java (element by element) copiing, espetially for big arrays. And here is the code of this benchmark, test it on your PC also:
import java.lang.reflect.*;
public class TestArray {
    static void doNothing(){}
    static int field;
    public static void main(String[] args) throws Exception {
        final int COUNT = 3, TIMES = 1000*1000;
        final String[] arr1 = new String[COUNT];
        final String[] arr2 = new String[COUNT];
            long time = -System.currentTimeMillis();
            for(int i=TIMES; i-->0;)
                copyReflect(arr1, arr2, COUNT);
            time += System.currentTimeMillis();
            System.out.println("Result for reflect copiing ("+COUNT+" elements, "+TIMES+" times): "+time+"ms");
            long time = -System.currentTimeMillis();
            for(int i=TIMES; i-->0;)
                copySystem(arr1, arr2, COUNT);
            time += System.currentTimeMillis();
            System.out.println("Result for system copiing ("+COUNT+" elements, "+TIMES+" times): "+time+"ms");
            long time = -System.currentTimeMillis();
            for(int i=TIMES; i-->0;)
                copyPureJava(arr1, arr2, COUNT);
            time += System.currentTimeMillis();
            System.out.println("Result for pure java copiing ("+COUNT+" elements, "+TIMES+" times): "+time+"ms");
    private static void copyReflect(Object src, Object dst, int count) {
        for(int i=count; i-->0; ) Array.set(dst, i, Array.get(src, i));
    private static void copySystem(Object src, Object dst, int count) {
        System.arraycopy(src, 0, dst, 0, count);
    private static void copyPureJava(String[] src, String[] dst, int count) {
        for(int i=count; i-->0; ) dst[i] = src;

How to compare two rows in PL/SQL?

Hi All,
How to compare two rows in PL/SQL? Is there any method that I can use instead of comparing them column by column?
Any feedback would be highly appreciated.

PhoenixBai wrote:
Hi All,
How to compare two rows in PL/SQL? Is there any method that I can use instead of comparing them column by column?What "rows" are you referring to?
If you're talking of rows within a PL/SQL associative array there are techniques as described in the documentation... e.g.
SQL> ed
Wrote file afiedt.buf
1 declare
2    type v1 is table of number;
3    r1 v1 := v1(1,2,4);
4    r2 v1 := v1(1,2,3);
5 begin
6    if r1 MULTISET EXCEPT DISTINCT r2 = v1() then
7      dbms_output.put_line('Same');
8    else
9      dbms_output.put_line('Different');
10    end if;
11* end;
SQL> /
Different
PL/SQL procedure successfully completed.
SQL> ed
Wrote file afiedt.buf
1 declare
2    type v1 is table of number;
3    r1 v1 := v1(1,2,3);
4    r2 v1 := v1(1,2,3);
5 begin
6    if r1 MULTISET EXCEPT DISTINCT r2 = v1() then
7      dbms_output.put_line('Same');
8    else
9      dbms_output.put_line('Different');
10    end if;
11* end;
SQL> /
Same
PL/SQL procedure successfully completed.
SQL>If you're talking about rows on a table then you can use the MINUS set operator to find the rows that differ between two sets of data...
SQL> select * from emp;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17-DEC-1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20-FEB-1981 00:00:00       1600        300         30
      7521 WARD       SALESMAN        7698 22-FEB-1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-1981 00:00:00       2975                    20
      7654 MARTIN     SALESMAN        7698 28-SEP-1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-1981 00:00:00       2850                    30
      7782 CLARK      MANAGER         7839 09-JUN-1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19-APR-1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17-NOV-1981 00:00:00       5000                    10
      7844 TURNER     SALESMAN        7698 08-SEP-1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-1987 00:00:00       1100                    20
      7900 JAMES      CLERK           7698 03-DEC-1981 00:00:00        950                    30
      7902 FORD       ANALYST         7566 03-DEC-1981 00:00:00       3000                    20
      7934 MILLER     CLERK           7782 23-JAN-1982 00:00:00       1300                    10
14 rows selected.
SQL> select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7521 WARD       SALESMAN        7698 22-FEB-1981 00:00:00       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-1981 00:00:00       2975                    20
      7782 CLARK      MANAGER         7839 09-JUN-1981 00:00:00       2450                    10
      7788 SCOTT      ANALYST         7566 19-APR-1987 00:00:00       3000                    20
      7839 KING       PRESIDENT            17-NOV-1981 00:00:00       5000                    10
      7900 JAMES      CLERK           7698 03-DEC-1981 00:00:00        950                    30
      7934 MILLER     CLERK           7782 23-JAN-1982 00:00:00       1300                    10
7 rows selected.
SQL> select * from emp
2 minus
3 select * from emp2;
     EMPNO ENAME      JOB              MGR HIREDATE                    SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17-DEC-1980 00:00:00        800                    20
      7499 ALLEN      SALESMAN        7698 20-FEB-1981 00:00:00       1600        300         30
      7654 MARTIN     SALESMAN        7698 28-SEP-1981 00:00:00       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-1981 00:00:00       2850                    30
      7844 TURNER     SALESMAN        7698 08-SEP-1981 00:00:00       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-1987 00:00:00       1100                    20
      7902 FORD       ANALYST         7566 03-DEC-1981 00:00:00       3000                    20
7 rows selected.If you actually need to know what columns data is different on "non-matching" rows (based on your primary key) then you'll have to compare column by column.

Add and remove items by comparing 2 arrays

I have two arrays of objects. Each object has a unique name property besides few others. One of the array is a local copy and the other one is sent from server after regular intervals. The local copy of arrays is then used to add a movieclips into a container.
Now, I want that when I receive an array from the server, I compare it with the one which is already with me locally such that the items which were not in the received array but were there in the local array, get removed from the container and the newly added ones only get added. The items which were present in both local and remote array remain as it is. how can i do this?

I may be missing something, but it doesn't sound like you need to compare anything, you just need to replace the local array with the newly received one.
local array = 1,2,3,4,5
new array 3,4,5,6,7
Based on what you described you would get rid of 1 and 2 and use 3,4,5. I am assuming you would use the new ones that came from the server, so you essentially end up using 3,4,5,6,7
So you should just need to go thru the new array and if something in the container is not in the new array then remove it.

Compare two text files for matching data

HI
I want to compare data in two separate spreadsheet files and store the matching data in another spreadsheet file.
like
1)reading data from two spread sheets
2)compare the data of fist one with second
3)writing the matched data to third one.
I am find difficulty in combining them to sort string bu string
pls help me in this
thanks
jyohti

hi
i am implementing the following logic
1) textfile1--------->string to array
2)textfile 2--------->string to array
3) compare the elements (substring) of one array to other using for loop
4)append the match to an array every time you find a match betwwen two arrays
5)wriitng the result in new file
i am strugulling in with 3) i have finshed 1,2,4and 5 th part
problelms are with indexing and loop conditions for me...
anyways i am trying and feeling like i will finish and post that soon....

Compare 2 arrays,if same value add the value.If different value show 0

hello to all! i am new to labview and i'am trying to solve a labview exercise
''compare 2 arrays 1d 1x10 (the values of them are lucky numbers from 1 to 10) .compare them and create a new array [1,10] that saves the same values in the corresponding places ,while in the remainder places where the elements of 2 tables are different show 0''
One Example
In this time of project i have stuck at the comparison of values of two array.and how i would achive creating the Array3! I have search the forum about founding any answer.Any ideas?
Message Edited by sdadfsdfds on 06-05-2008 12:08 PM
Message Edited by sdadfsdfds on 06-05-2008 12:09 PM

I am guessing that since this is a labview exercise it is meant as a learning experience. There are several ways to solve this problem, I have shown one way below. I suggest that you try and come up with other ways on your own. Feel free to ask any questions.
Cheers
Message Edited by jmcbee on 06-05-2008 11:25 AM
CLA, CLED, CTD,CPI, LabVIEW Champion
Platinum Alliance Partner
Senior Engineer
Using LV 2013, 2012
Don't forget Kudos for Good Answers, and Mark a solution if your problem is solved.
Attachments:
Compare Arrays.PNG ‏3 KB

Compare two strings for partial or full match

I have been trying to figure out away of comparing two strings.
I can get the full string matching to successfully work but am struggling on how to get partial eg wildcard search working.
say I had names like paul Duncan, George Morrison.
I have split them up so its now paul , duncan i then use the users entered string to compare it against the name name to see if it matches anything in the first name or the last name if it does i added it to an arraylist.
however i have tried t use a indexof as i believe this looks for similarity (Substring matches?) but it always returns -1.
Could anyone possibly direct me to a method that will allow me to use partial text string to match it against stored user names.
eg user enters pa
I would return anything that would contain pa
thanks for any help

thank you for the reply
Sorry I forgot to put in the code.
This is a reduced down version including the read in from a text file as well as the index of if statement and the adding of it to an array list.
public class FindContact {
String res;
/** Creates a new instance of FindContact */
public FindContact() {
public Object[] FindAUser(String passSearch) {
System.out.println("getting here");
ArrayList found = new ArrayList();
String patternStr = ",";
int j, i = 0;
try {
BufferedReader in = new BufferedReader(new FileReader("H:\\out.txt"));
String str;
while ((str = in.readLine()) != null) {
String[] fields = str.split(patternStr);
//for(j=0;j < fields.length;j++) {
if (fields.length != 0) {
if (passSearch.indexOf(fields[0])!=-1 || passSearch.indexOf(fields[1])!=-1) {
found.add(str);
System.out.println("ENDDDDDDDD value ");
in.close();
} catch (IOException e) {
System.out.println(e.toString());
Object[] foundResult = new Object[found.size()];
foundResult = found.toArray();
if (foundResult.length >= 0) {
System.out.println(foundResult.length);
return foundResult;
Hope that helps as it has confused me and am not sure why it is not returning a value.
Should I maybe use the contain method instead to search for the user inputted string?

Can;t find what is wrong. Trying to add elements in two arrays

Hello everyone
I'm trying to take as input two numbers, convert them to arrays and add all the element of the array one by one. I want the result to be the sum of every element of the array. Let's say array1={1,2,3,4} and array2={2,6,4,3} I want the final result to be 3877.
If the sum of one element of the array is greater than nine, then I would put zero and add 1 to the element on the left.
Here is the code:
import javax.swing.JOptionPane;
public class Main {
    public static void main(String[] args) {
        String numberOne = JOptionPane.showInputDialog
                                ("Enter the first number: ");
     String numberTwo = JOptionPane.showInputDialog
                                ("Enter the second number: ");
        //compare string length and make them equal length
        int[]n1 = toArray(numberOne); // my first array
     int[]n2 = toArray(numberTwo); // my second array
     //call the method that ads both strings
     int[]finalArray = arrSum(n1,n2);
       JOptionPane.showMessageDialog(null, "The sum of the two numbers is: "
               + finalArray);
    }//end of main
    //method to create an array from a string
    public static int[] toArray(String str)
            int[]arr = new int[str.length()];
            arr[0]=0;
            for (int i=1; i<str.length(); i++)
          arr= Character.digit(str.charAt(i),10);
return arr;
}//end of toArray
//method to add arrays by elements
public static int[]arrSum (int[]arr1, int[]arr2){
for (int i = arr1.length-1; i >=1; i--)
int sum = arr1[i] + arr2[i];
if (sum > 9)
          { sum -= 10;
          arr1[i-1]++;
return arr1;
}//end of arrSum method
}Edited by: designbc01 on Feb 16, 2010 1:15 AM

The best advice I can give you is to break your problem up into smaller pieces. First, focus on a method that converts an input String into an array. When you have that working perfectly, then focus on creating a method that "adds" two arrays with the logic you described. When you have that working perfectly, then combine the two different pieces.
Why does your for loop in toArray( ) start with 1? The first index of a String, array, or pretty much anything else, is zero.

How to compare two files using MD5?

Hi,all:
How to compare two files to know if they're the same without any difference?I want to use MD5, but I just konw how get a message digest of a string. How to get a message digest of a file? Or there is other method to compare two files?
Thanks advance!

This is starting to sound rather a lot like a homework problem.
An MD5 message digest is simply a 16 byte array. To compare two message digests...
byte[] md5incoming = ...
byte[] md5comparison = ...
if( md5incoming.equals(md5comparison) ) {
System.out.println("MD5 Checksums match");
}To find out how to generate an MD5 checksum, please look up MessageDigest in the API documentation, and do a google search for "MD5 java"
In a networked scenario, there are two issues - firstly the performance in sending copies of files all over the place (imagine if it's a 10Gb file to be compared over a 14.4K modem link, this would take a while). Secondly, the network link itself might insert an error in the file and you'd get a false miss.
By only sending MD5 digests over the link, you simultaneously reduce the error (shorter files are less likely to be corrupted) and reduce the transmission time (16 bytes takes practically no time to transmit over damp string, let alone any sort of sensible device).
D.

Compare two images

Hai Java Guys,
How to compare two images using java.If any thing different at any place ,we have to give details of that pixel.It is GIS project.If anybody know solution for this plz let me know.Thank you in asdvance.
Basha

If the two images are represented as java.awt.Images and have the same scale you can use the java.awt.image.PixelGrabber to obtain an array of the pixel values for each image. Compare the values of these two arrays, and you know where in the images you have differing pixels.

Compare two arrays

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