Comparing Arraylist and String

Plz can anyone help me to find that this what will be the behaviour of this code.I have an Enumeration and and ArrayList.I want to comapre each object of Enumeration with each object of ArrayList.The code is
private boolean checkDeviceType(HttpServletRequest request){
          Enumeration e = request.getHeaderNames();
          String tmp = null;
          //String[] strKeys = null;
          ArrayList al = getValues("test");
          while(e.hasMoreElements()){
               tmp = (String)e.nextElement();
               for(int i = 0; i < al.size(); i++){
                    if(tmp.equalsIgnoreCase(al.toString()))// Ye line theek se check kar ki chalegi ya nahin
               return true;
          return false;
     }

Plz can anyone help me to find that this what will be
the behaviour of this code.I have an Enumeration and
and ArrayList.I want to comapre each object of
Enumeration with each object of ArrayList.The code
is
> private boolean checkDeviceType(HttpServletRequest
request){
          Enumeration e = request.getHeaderNames();
          String tmp = null;
          //String[] strKeys = null;
          ArrayList al = getValues("test");
          while(e.hasMoreElements()){
               tmp = (String)e.nextElement();
               for(int i = 0; i < al.size(); i++){
if(tmp.equalsIgnoreCase(al.get(i).toString()))// Ye line line theek se check kar ki chalegi ya nahin
               return true;
          return false;
     }You didn't extract the object from the ArrayList--so, your toString converts the whole ArrayList to a String, not just a single element. I fixed the line with your comment--added "get(i)."
Please use code tags (button above posting box) when posting code.

Similar Messages

Arraylist and string split help

i want to add items from a textfile into an array list here is the txt file
Title,Artist
tester,test
rest,test
red, blue
here is the code i am using
try{
FileReader fr = new FileReader(fileName);
BufferedReader br = new BufferedReader(fr);
String s;
int c = 0;
while((s = br.readLine()) != null) {
c=c+1;
CD c3 = new CD("");
String tokens[] = s.split(",");
        for(String token : tokens) {
      System.out.println(c);
       System.out.println(tokens.toString());
          if ( c == 2){
            c3.setTitle(token);
                System.out.println(c);
                 System.out.println(token);
         c = c+1;
              if ( c == 3 ){
                c3.setArtist(token);
                discsArray.add(c3);
                  System.out.println(token);
                c = 1;
          System.out.println(token); }}
fr.close();
}catch (Exception e){
      System.out.println("exception occurrred");
}here is the output of the array
title: tester artist: tester title: rest artist: tester title: red artist: red
as you can see it misses the last line of the textfile and also doesnt display all of the separated string;
thanks any help is appreciated

thanks for ur help but that wasnt the problem
i have fixed it however when its read all the lines
an exception is always thrown
everything works just crashes at the end
any ideas
try{
FileReader fr = new FileReader(fileName);
BufferedReader br = new BufferedReader(fr);
String s;
int c = 0;
while((s = br.readLine()) != null) {
c=c+1;
CD c3 = new CD("");
String tokens[] = s.split(",");
        for(String token : tokens) {
          if ( c == 2){
            c3.setTitle(token);
                  c = c+1;
          if ( c == 3 ){
                c3.setArtist(token);
       if ( c == 3 ){
                discsArray.add(c3);
                c = 1;
fr.close();
br.close();
}catch (Exception e){
      System.out.println("exception occurrred");
}

Compare string and string from db

I successfully queried a field from mysql into a jcombobox.
What I can't figure out is why:
String fromDB = comboBox.getSelectedItem().trim();
AND
String newString = "sameStringFromMySQL";are not equal. I already trimmed the text from the combo box but they are still not considered equal.
WHY???

just like how i described above.
(fromDB.equals(newString)) returns false.
Then they are not equal.
Most likely reasons:
-fromDB: This is starting with the text you think.
-fromDB: You aren't getting it from the right place.
-fromDB: You are modifying it before it gets to the comparison.
-NewString: Doesn't have the value you think.
-The comparison above isn't really the problem.
You can always print the bytes in any string by using the getBytes() method on String and printing out both strings just before the above comparison (not elsewhere.)

Need help sorting an ArrayList of strings by an in common substring

I'm trying to sort a .csv file, which I read into an ArrayList as strings. I would like to sort by the IP address within the string. Can someone please help me figure out the best way to sort these strings by a common substring each has, which is an IP address.
I'm pretty sure that I need to use Collections some how, but I don't know where to begin with them besides trying to look online for help. I had no luck finding any good examples, so I came here as a last resort.
Thanks for any help provided.

You need to write your own Comparator class. In the compare() method you substring out the two IP addresses, compare them and return appropriate value. Then you call Collections.sort() and pass your list and comparator.

Regular expressions and string matching

Hi everyone,
Here is my problem, I have a partially decrypted piece string which would appear something like.
Partially deycrpted:     the?anage??esideshe?e
Plain text:          themanagerresideshere
So you can see that there are a few letter missing from the decryped text. What I am trying to do it insert spaces into the string so that I get:
                    The ?anage? ?esides he?e
I have a method which splits up the string in substrings of varying lengths and then compares the substring with a word from a dictionary (implemented as an arraylist) and then inserts a space.
The problem is that my function does not find the words in the dictionary because my string is only partially decryped.
     Eg:     ?anage? is not stored in the dictionary, but the word �manager� is.
So my question is, is there a way to build a regular expression which would match the partially decrypted text with a word from a dictionary (ie - ?anage? is recognised and �manager� from the dictionary).

I wrote the following method in order to test the matching using . in my regular expression.
public void getWords(int y)
int x = 0;
for(y=y; y < buff.length(); y++){
String strToCompare = buff.substring(x,y); //where buff holds the partially decrypted text
x++;
Pattern p = Pattern.compile(strToCompare);
for(int z = 0; z < dict.size(); z++){
String str = (String) dict.get(z); //where dict hold all the words in the dictionary
Matcher m = p.matcher(str);
if(m.matches()){
System.out.println(str);
System.out.println(strToCompare);
// System.out.println(buff);
If I run the method where my parameter = 12, I am given the following output.
aestheticism
aestheti.is.
demographics
de.o.ra.....
Which suggests that the method is working correctly.
However, after running for a short time, the method cuts and gives me the error:
PatternSyntaxException:
Null(in java.util.regex.Pattern).
Does anyone know why this would occur?

How to Sort JTable data using Multiple fields (Date, time and string)

I have to fill the JTable data with some date, time and string values. for example my table data looks like this:
"1998/12/14","15:14:38","Unicorn1","row1"
"1998/12/14","15:14:39","Unicorn2","row2"
"1998/12/14","15:14:40","Unicorn4","row3"
"1998/12/17","12:14:12","Unicorn4","row6"
Now the Sorted Table should be in the following way:
"1998/12/17","12:14:12","Unicorn4","row6"
"1998/12/14","15:14:40","Unicorn4","row3"
"1998/12/14","15:14:39","Unicorn2","row2"
"1998/12/14","15:14:38","Unicorn1","row1"
ie First Date field should be sorted, if 2 date fields are same then sort based on time. if date and time fields are same then need to be sorted on String field.
So if any one worked on this please throw some light on how to proceed. I know how to sort based on single column.
But now i need to sort on multiple columns.So what is code change in the Comparater class.
Thanks in advance.. This is urgent....

I think your Schedule objects should implement Comparable. Then you can sort your linked list using the Collections.sort() method without passing in a Comparator.class Schedule(Date date, String class) implements Comparable
public void compareTo(Object obj)
Schedule other = (Schedule)obj;
return date.getTime() - other.getDate().getTime();
}

What to do when readString() fails and String[] out of bounds ?

Dear Java People,
I have a runtime error message that says:
stan_ch13_page523.InvalidUserInputException: readString() failed. Input data is not a string
java.lang.StringIndexOutOfBoundsException: String index out of range: 0
below is the program
thank you in advance
Norman
import java.io.*;
import java.util.*;
public class FormattedInput
    // Method to read an int value
    public int readInt()
      for(int i = 0; i < 2; i ++)
      if(readToken() == tokenizer.TT_NUMBER)
        return (int)tokenizer.nval;   // value is numeric so return as int
      else
        System.out.println("Incorrect input: " + tokenizer.sval +
           " Re-enter as integer");
        continue;         //retry the read operation
      } // end of for loop
      System.out.println("Five failures reading an int value" + " - program terminated");
      System.exit(1); // end the program
      return 0;
     public double readDouble() throws InvalidUserInputException
       if(readToken() != tokenizer.TT_NUMBER)
          throw new InvalidUserInputException(" readDouble() failed. " + " Input data not numeric");
       return tokenizer.nval;
     public String readString() throws InvalidUserInputException
       if(readToken() == tokenizer.TT_WORD || ttype == '\"' || ttype == '\'')
        return tokenizer.sval;
       else
         throw new InvalidUserInputException(" readString() failed. " + " Input data is not a string");
       //helper method to read the next token
       private int readToken()
         try
           ttype = tokenizer.nextToken();
           return ttype;
         catch(IOException e)
           e.printStackTrace(System.err);
           System.exit(1);
          return 0;
       //object to tokenize input from the standard input stream
       private StreamTokenizer tokenizer = new StreamTokenizer(
                                            new BufferedReader(
                                             new InputStreamReader(System.in)));
       private int ttype;                  //stores the token type code
import java.io.*;
import java.util.*;
public class TryVectorAndSort
     public static void main(String[] args)
    Person aPerson;           // a Person object
    Crowd filmCast = new Crowd();
    //populate the crowd
    for( ; ;)
      aPerson = readPerson();
      if(aPerson == null)
        break;   // if null is obtained we break out of the for loop
      filmCast.add(aPerson);
    int count = filmCast.size();
    System.out.println("You added " + count + (count == 1 ? " person": " people ") + "to the cast.\n");
    //Show who is in the cast using an iterator
     Iterator myIter = filmCast.iterator();
    //output all elements
    while(myIter.hasNext() )
      System.out.println(myIter.next());
    }//end of main
      //read a person from the keyboard
      static public Person readPerson()
     FormattedInput in = new FormattedInput();
        //read in the first name and remove blanks front and back
        System.out.println("\nEnter first name or ! to end:");
        String firstName = "";
        try
        firstName = in.readString().trim(); //read and trim a string
        catch(InvalidUserInputException e)
        e.printStackTrace(System.err);
        //check for a ! entered. If so we are done
        if(firstName.charAt(0) == '!')
          return null;
        //read the last name also trimming the blanks
        System.out.println("Enter last name:");
        String lastName= "";
        try
          lastName = in.readString().trim(); //read and trim a string
        catch(InvalidUserInputException e)
         e.printStackTrace(System.err);
        return new Person(firstName, lastName);
//when I ran the program the output I received was:
import java.io.StreamTokenizer;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.BufferedReader;
public class InvalidUserInputException extends Exception
   public InvalidUserInputException() { }
      public InvalidUserInputException(String message)
          super(message);
import java.util.*;
class Crowd
public Crowd()
    //Create default Vector object to hold people
     people = new Vector();
public Crowd(int numPersons)
    //create Vector object to hold people with given capacity
     people = new Vector(numPersons);
    //add a person to the crowd
    public boolean add(Person someone)
      return people.add(someone);
     //get the person at the given index
      Person get(int index)
      return (Person)people.get(index);
     //get the numbers of persons in the crowd
      public int size()
        return people.size();
      //get people store capacity
      public int capacity()
        return people.capacity();
      //get a listIterator for the crowd
      public Iterator iterator()
        return people.iterator();
        //A Vector implements the List interface (that has the static sort() method
        public void sort()
          Collections.sort(people);
      //Person store - only accessible through methods of this class
      private Vector people;
public class Person implements Comparable
public Person(String firstName, String lastName)
    this.firstName = firstName;
    this.lastName = lastName;
public String toString()
    return firstName + " " + lastName;
   //Compare Person objects
    public int compareTo(Object person)
       int result = lastName.compareTo(((Person)person).lastName);
       return result == 0 ? firstName.compareTo(((Person)person).firstName):result;
private String firstName;
private String lastName;

Dear Nasch,
ttype is declared in the last line of the FormattedInput class
see below
Norman
import java.io.*;
import java.util.*;
public class FormattedInput
    // Method to read an int value
    public int readInt()
      for(int i = 0; i < 2; i ++)
      if(readToken() == tokenizer.TT_NUMBER)
        return (int)tokenizer.nval;   // value is numeric so return as int
      else
        System.out.println("Incorrect input: " + tokenizer.sval +
           " Re-enter as integer");
        continue;         //retry the read operation
      } // end of for loop
      System.out.println("Five failures reading an int value" + " - program terminated");
      System.exit(1); // end the program
      return 0;
     public double readDouble() throws InvalidUserInputException
       if(readToken() != tokenizer.TT_NUMBER)
          throw new InvalidUserInputException(" readDouble() failed. " + " Input data not numeric");
       return tokenizer.nval;
     public String readString() throws InvalidUserInputException
       if(readToken() == tokenizer.TT_WORD || ttype == '\"' || ttype == '\'')
         System.out.println(tokenizer.sval);
        return tokenizer.sval;
       else
         throw new InvalidUserInputException(" readString() failed. " + " Input data is not a string");
       //helper method to read the next token
       private int readToken()
         try
           ttype = tokenizer.nextToken();
           return ttype;
         catch(IOException e)
           e.printStackTrace(System.err);
           System.exit(1);
          return 0;
       //object to tokenize input from the standard input stream
       private StreamTokenizer tokenizer = new StreamTokenizer(
                                            new BufferedReader(
                                             new InputStreamReader(System.in)));
       private int ttype;                  //stores the token type code
     }

Linked List and String Resources

Linked Lists can be very slow when removing dynamic Strings.
If you add and remove Strings in the
following way, the performance is very poor:
int n = 10000;
long time = System.currentTimeMillis ();
List list = new LinkedList();
for (int i = 0 ; i < n ; i++)
list.add ("" + n);
for (int i = n-1 ; i >= 0 ; i--)
list.remove(i/2);
- If you add and remove the not dynamic String: "" + 10000 instead,
- or do not remove the String (but add it in the middle),
- or use a ArrayList
the performance is much better.
I suppose it depends on handling the String resources.
If you run the following class, you will see what I mean:
public class SlowLinkedList
public static void main (String[] args)
// Be carefull when accessing/removing Strings in a Linked List.
testLinkedList ();
testLinkedListHardCodedString();
testLinkedListNoRemove();
testArrayList();
testArrayListNoParam();
private static void testLinkedList ()
int n = 10000;
long time = System.currentTimeMillis ();
List list = new LinkedList();
for (int i = 0 ; i < n ; i++)
list.add ("" + n);
for (int i = n-1 ; i >= 0 ; i--)
list.remove(i/2);
time = System.currentTimeMillis () - time;
System.out.println ("time dynamic String remove " + time);
private static void testLinkedListHardCodedString ()
int n = 10000;
long time = System.currentTimeMillis ();
List list = new LinkedList();
for (int i = 0 ; i < n ; i++)
list.add ("" + 10000);
for (int i = n-1 ; i >= 0 ; i--)
list.remove(i/2);
time = System.currentTimeMillis () - time;
System.out.println ("time same String remove " + time);
private static void testLinkedListNoRemove ()
int n = 10000;
long time = System.currentTimeMillis ();
List list = new LinkedList();
for (int i = 0 ; i < n ; i++)
list.add (i/2, "" + n);
time = System.currentTimeMillis () - time;
System.out.println ("time add dynamic String " + time);
private static void testArrayList ()
int n = 10000;
long time = System.currentTimeMillis ();
List list = new ArrayList();
for (int i = 0 ; i < n ; i++)
list.add ("" + n);
for (int i = n-1 ; i >= 0 ; i--)
list.remove(i/2);
time = System.currentTimeMillis () - time;
System.out.println ("time ArrayList " + time);
private static void testArrayListNoParam ()
int n = 10000;
long time = System.currentTimeMillis ();
List list = new ArrayList ();
for (int i = 0 ; i < n ; i++)
list.add ("" + 10000);
for (int i = n-1 ; i >= 0 ; i--)
list.remove(i/2);
time = System.currentTimeMillis () - time;
System.out.println ("time ArrayList same String " + time);
A typic output of the Performance is:
time dynamic String remove 1938
time same String remove 312
time add dynamic String 31
time ArrayList 63
time ArrayList same String 31

begin long winded reply
It doesn't matter if they are Strings or any other Object. LinkedList, in the way you are executing
remove, is not effecient. The LinkList remove will look at the index, if it is less than the median
it will start iterating from 0, if it is greater, it will start iterating in reverse from the end. Since you
are removing from the median, it will always take the longest (either forward or backward) to
get to the middle. Whereas, ArrayList simply uses the arraycopy to drop the element from the
array. The "NoRemove" test doesn't make sense to me in relation to the others.
Also, the VM is performing optimizations when you hardcode the 'n' value to 10000, it seems
that the VM won't optimize when using 'n'. Tusing Integer.toString(n), instead of "" + n,
in the first test case, it will yield better results.
My profs in college drove collections into my head and removing from a linked list without
an iterator is going to be inefficient. Iterators are a beautiful thing, use them.
Try this code instead, it simulates your remove in the middle with an iterator and, on my
machine, is faster than the ArrayList.
private static void testLinkedList() {
    int n = 10000;
    long time = System.currentTimeMillis ();
    List list = new LinkedList();
    for (int i = 0 ; i < n ; i++) {
        list.add (Integer.toString(n));
    boolean forward = false;
    for (ListIterator li = list.listIterator(n >> 1); li.hasNext() || li.hasPrevious();) {
        if (forward) {
            li.next();
            forward = false;
        } else {
            li.previous();
            forward = true;
        li.remove();
    time = System.currentTimeMillis () - time;
    System.out.println ("time dynamic String remove " + time);
}One other thing, run the tests more than once in a single VM and take the average. You could
apply some statistical analysis to figure out which is better within a certain confidence percentage,
but that is probably overkill. :)
Check the collection tutorial for more info: http://java.sun.com/docs/books/tutorial/collections/implementations/general.html
end long winded reply
Matt

How to change elements in ArrayList into String

Greetings,
i like to change elements in arrayList into string.
This is how i declare an ArrayList in a Java file
ArrayList listing = new ArrayList();below is just a simple example of how i insert the string into the arraylist
String concat = "';
concat = concat + "apple";
//Transfer the concat string into arraylist
listing.add(concat);
return listing;
{code}
On my Jsp page, it will receive the ArrayList from the java file. Lets say the Arrayist is pass into my JSP arraylist
This is my JSP arraylist
{code}ArrayList optLists = new ArrayList();{code}
Inside the arraylist element, it holds data eg: *308577;;RS | [CAT 2] Level: Arena, Section: A02* with a pipe between RS and CAT 2.
Now i looping the arraylist
{code}int a = 0;
     for ( a=0; a < optLists.size(); a++)
          String tempString = "";
          String splitTemp = "";
                 String tempString = (String)optLists.get(a);
          splitTemp = tempString.split("|");
          System.out.println("Split String Results: "+ splitTemp);
     {code}}
Heres the error:
*SeatAvailable_jsp.java:560: incompatible types*
    *[javac] found   : java.lang.String[]*
    *[javac] required: java.lang.String*
    *[javac]             splitTemp = tempString.split("|");*
    *[javac]*
What can i do to solve the problem?
Edited by: leeChaolan on May 2, 2008 4:45 AM
Edited by: leeChaolan on May 2, 2008 4:48 AM

paternostro is right, you are returning an array into a string which is wrong
but try this, i haven't tested it though..
nt a = 0;
     for ( a=0; a < optLists.size(); a++)
          String tempString = "";
          String splitTemp = "";
                 String tempString = (String)optLists.get(a);
          String[] splitTemp = tempString.split("|");
          for(String xyz : splitTemp)
               System.out.println("Split String Results: "+ xyz);
     }Edited by: linker on May 2, 2008 1:17 PM
Edited by: linker on May 2, 2008 1:18 PM

Macro to compare CSV and Excel file

Team,
Do we have any macro to compare CSV and Excel file.
1) In Excel we should have two text boxes asking the user to select the files from the path where they have Stored
2) First Text is for CSV file
3) Second Text box is for Excel file
4) We Should have Compare button that should run the Macro and Show the Differences.
Thanks!
Kiran

Hi
Based on my understanding, we need to convert the 2 files into the same format before comparing two different formats files.
Here are the options:
1. Convert the CSV file and Excel file into 2-dim Arrays, then compare them, about how to load a CSV file into VBA array, you can search it from
internet or ask a solution in VBA forum.
VBA forum:
http://social.msdn.microsoft.com/Forums/en-US/home?forum=isvvba
2. Also you can import CSV file to Excel sheet, and then compare them.
Here is the sample code for your reference:
‘import csv file
Sub InputCSV()
Dim Wb As Workbook
Dim Arr
Set Wb = GetObject(Application.GetOpenFilename("csv file,*.csv", , "please choose a csv file", , False))
Arr = Wb.ActiveSheet.Range("A1").CurrentRegion
Wb.Close False
Range("A1").Resize(UBound(Arr), UBound(Arr, 2)) = Arr
End Sub
‘compare sheet
Sub CompareTable()
Dim tem, tem1 As String
Dim text1, text2 As String
Dim i As Integer, hang1 As Long, hang2 As Long, lie As Long, maxhang As Long, maxlie As Long
Sheets("Sheet1").Select
Columns("A:A").Select
With Selection.Interior
.Pattern = xlNone
.TintAndShade = 0
.PatternTintAndShade = 0
End With
Range("A1").Select
Sheets("Sheet2").Select
Rows("1:4").Select
With Selection.Interior
.Pattern = xlNone
.TintAndShade = 0
.PatternTintAndShade = 0
End With
Range("A1").Select
MaxRow = 250
MaxColumn = 40
For hang1 = 2 To maxhang
Dim a As Integer
a = 0
tem = Sheets(1).Cells(hang1, 1)
For hang2 = 1 To maxhang
tem1 = Sheets(2).Cells(hang2, 1)
If tem1 = tem Then
a = 1
Sheets(2).Cells(hang2, 1).Interior.ColorIndex = 6
For lie = 1 To maxlie
text1 = Sheets(1).Cells(hang1, lie)
text2 = Sheets(2).Cells(hang2, lie)
If text1 <> text2 Then
Sheets(2).Cells(hang2, lie).Interior.ColorIndex = 8
End If
Next
End If
Next
If a = 0 Then
Sheets(1).Cells(hang1, 1).Interior.ColorIndex = 5
End If
Next
Hope this will help.
Best Regards
Lan
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How do we compare a complex string?

Hi guys,
how do i compare the following strings
input_Variable: User-agent : *
if i want to ensure that the input_variable has "User-agent" and the character '*'.
There are 3 possiblities for input_variable:
1) User-agent: *
2) disallow: http:///xxxxxxxxxxxx
3) User-agent:Somename
The white space between the words could be uneven and same goes with the character case.
thanks,
Derik

Hi.. Derik
How about this one..
String input_Variable = "[from your input method]";
if ( input_Variable.indexOf("User-agent") != -1
&& input_Variable.indexOf("*") != -1 )
System.out.println("yeah.. authorized..");
indexOf(String str) method returns -1 when it can't find out a specific string from the source string..

Converting ArrayList to String

Hi ,
I have ArrayList of String of size three. I want to make one string out of these three and also want to skip coma. I appreciate if any one can guide me.
Thanks
Panna

So you have a list with "abc" "def" and "ghi" in it?
And you want to get a single String "abcdefghi"?
Then iterate over the list, append()ing each element to a StringBuffer.

Arraylists and arrays

i'm trying to put the numbers in an arraylist into an int[] array. could anyone tell me how this could be done? i tried the below but i get an error pointing to return divisors.toArray();
import java.util.ArrayList;
import java.util.List;
class FactorsDemo {
    public static void main(String[] args) {
     //for(int i = 10; i < 30; i+=5) {
         int[] divisors = getDivisors(10);
    static int[] getDivisors(int n) {
     List<Integer> divisors = new ArrayList<Integer>();
     for(int d = 1; d <= n/2; d++) {
         if(n%d == 0) divisors.add(new Integer(d));
     return divisors.toArray();
}

i'm trying to get this code to compile without using generics, just to see how it is done. it gets the divisors of a number, puts them into an arraylist, and then returns an array with those same divisors.
i tried to cast the arraylist object to an int, but it's not working.
can anyone show me what i need to do?
import java.util.ArrayList;
import java.util.List;
class FactorsDemo2 {
    public static void main(String[] args) {
     for(int i = 10; i < 50; i+=5) {
         System.out.print("Factors of "+i+": ");
         int[] divisors = getDivisors(i);
         display(divisors);
    static int[] getDivisors(int n) {
     List divisors = new ArrayList();
     for(int d = 1; d <= n/2; d++) {
         if(n%d == 0) divisors.add(new Integer(d));
     int[] myInts = new int[divisors.size()];
        for(int i = 0; i < divisors.size(); i++) {
               myInts[i] = (int) divisors.get(i);
        return myInts;
    static void display(int[] x) {
     for(int i = 0; i < x.length; i++) {
         System.out.print(x[i]+" ");
     System.out.println();
}FactorsDemo2.java:21: inconvertible types
found : java.lang.Object
required: int
myInts[i] = (int) divisors.get(i);
^
Note: FactorsDemo2.java uses unchecked or unsafe operations.
Note: Recompile with -Xlint:unchecked for details.
1 error

Problem with Column types and String

Hi
I have some problem while comparing against empty string.
My column is of type it_Linked_Button. Actually it seems that column type doesn't matter.
If cell that belongs to this column is empty and based on other columns' values I put some value into this cell.
It works fine.
But when I clear that cell and try to put some value again nothing happens.
In my if statement I'm checking against empty string and it fails second time.
Before I put anything in that cell (in debugger) that value is "" so it is empty and it works.
(OK, I see that after I posted this message it was slightly reformated)
But after I put something and clear that cell and try to put something again (in debugger) I get "(here is some long space) " which fails String.IsNullOrEmpty(var) test.
What is going on? Has it something to do with Column type?
How to clear it so I can put something in it again?
One more thing - to put values and clear it I use DbDataSource SetValue method. And String.Empty or ""(doesn't matter)
Thanks
Kamil
NOTE
I made some workaround that gives me the behaviour I want but still I would like to know what is going on?
Edited by: Kamil Wydrzycki on Sep 24, 2009 12:57 PM

DrLaszloJamf wrote:
warnerja wrote:
DrLaszloJamf wrote:
1. Could you define an Enum? Then you could switch on enum values.
2. Wait for Java 7 which is supposed to extend switch to strings?3. Put the target strings in a collection, write a loop to find the match in the collection and use the matching index in the switch statement. At least that will get rid of the hashcode kludge, where it won't mistakenly 'match' a string which isn't the actual target.3b: Map<String, Command>Yep.
I also wanted to point this out to the OP:
For example, let's say the 7 character string "BugABoo" happens to have the same hashcode as "EDI_DOC". And let's say your input just happens to have the string "BugABoo" in it, where you're extracting the 7 character substring. See the problem? You're getting "BugABoo" but treating it as if it really were "EDI_DOC", by virtue of comparing hashcodes instead of actual strings.
OOPS!

Compare substrings in strings

Not sure if this bit of code is what I'm suppose to be doing - hopefully someone can point me int he direction of the thing to think about
** Returns the number of times a given substring appears within the strings of a list of strings*
** @param listOfStrings the ArrayList that contains the strings to check*
** @param keyword the substring to find in each of the strings*
** @return the number of times keyword appear in the strings listed in listOfStrings*
public int keywordCount(ArrayList listOfStrings, String keyword) {
     int counter;
     for(int i = 0; i < listofStrings.size(); i ++){
          if (listofStrings.get[i] == keyword){
               counter += 1;
          return System.out.println("keyword appears " + counter " " times.");
}{code}

return System.out.println("keyword appears " + counter " " times.");
{code}
You either return something or print something to the console. Don't do both. Also, see how the end bracket and semicolon are red. That means you have made an error with your formatting.
I'd say you would need nested loops. Outer loop to iterate over your list of Strings. Inner loop to iterate over each string to see how many times the substring exists in that String.

Comparing Arraylist and String

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