Comparing the 1/2 character

hi there,
I'm reading an input stream which contains a character that represents the fraction 1/2.
Using the 1.3 jdk I was able to do a string comparison with the 1/2 character, and what was read in through the input stream.
However, using the 1.4 jdk, what is read in through the input stream is what looks like a capital S. I cannot compare the 1/2 character nor a capital S successfully with this character.
Can someone tell me what sort of character encoding I need to do in order for it to work?
thanks
Daniel

The encoding (it is default) is ISO-8859-15
ISO-8859-15 does not have the "one half" character. You need to change the encoding you use for reading to ISO-8859-1 which probably is the encoding the page is in.
(Indeed, if I go to that page using iso-8859-15 as the encoding (which I've configured as the default) I see the ligature oe, but when I change the encoding the browser uses to iso-8859-1 the character changes to "one half". Wonder how you got a thing that looks like S, "oe" doesn't look like S to me...)
You can change the encoding by passing its name as a parameter to the InputStreamReader constructor:InputStreamReader isr = null;
try {
isr = new InputStreamReader(connxn.openStream(), "iso-8859-1");
} catch (UnsupportedCharacterEncodingException ignore) {
// as if it could ever be thrown with iso-8859-1...
BufferedReader in = new BufferedReader(isr);Web pages are a mess since the introduction of euro and iso-latin-15, now some western sites are in iso-latin-1, some in iso-latin-15 and some in cp1252 and it gets quite awkward when they use characters that are not in the same code points, such as smart quotes or the euro character... Or, in this case, the one over two character.

Similar Messages

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My doubt here is how can we compare the character fields.?
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DATA : a TYPE char10 VALUE 'DBCD',
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Compare the current value with the previous value in the same column

Hi all,
I have to include a statement in a query which allows to compare the current value of column A with the previous value of column A (same column). from there, I need to add a condition in order to have the expected result.
Let's take an example to illustrate what I want to achieve:
I have the following columns in table called 'Charges':
Ship_id batch_nr Order_nr Price
SID1111 9997 MD5551 50
SID1111 9998 MD5552 50
SID1111 9999 MD5553 50
SID2222 8887 MD6661 80
SID2222 8887 MD6662 80
SID2222 8887 MD6662 80
SID3333 6666 MD7771 90
I want to check if the ship_id of row 2,3 (and more if available) is equal to the ship_id of row 1.
If it is the case, then value 'together with the first batch_nr' in row 2 and 3 under Price column. If not, then keep the original value of Price column
PLease see below the expected result:
Ship_id batch_nr Order_nr Price
SID1111 9997 MD5551 50
SID1111 9998 MD5552 together with 9997
SID1111 9999 MD5553 together with 9997
SID2222 8887 MD6661 80
SID2222 8887 MD6662 together with 8887
SID2222 8887 MD6663 together with 8887
SID3333 6666 MD7771 90
Thanks in advance for your help, it is really urgent.
Imco20030

Hi,
user11961002 wrote:
Hi,
Here is the query that I use:
[ select
sl.ship_id,
o.ordnum,
o.reffld_5 "BatchNR",
sum(tc1.chrg_amt) "FreightPRC",
sum(tc2.chrg_amt) "FuelPRC",
sum (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt) "Total Price"
from ord_line ol
join ord o on (ol.ordnum = o.ordnum and ol.client_id = o.client_id)
join shipment_line sl on (ol.ordnum = sl.ordnum and ol.client_id = sl.client_id and ol.ordlin = sl.ordlin)
join adrmst a2 on (o.rt_adr_id = a2.adr_id)
left join tm_chrg tc1 on (tc1.chargetype = 'FREIGHT' and tc1.chrg_role = 'PRICE' and tc1.ship_id = sl.ship_id)
left join tm_chrg tc2 on (tc2.chargetype = 'FUELSURCHARGE'and tc2.chrg_role = 'PRICE' and tc2.ship_id = sl.ship_id)
where sl.ship_id = 'SID0132408'
group by o.client_id, o.ordnum, o.reffld_2, sl.ship_id, a2.adrnam, a2.adrln1, a2.adrpsz, a2.adrcty, a2.ctry_name,
o.reffld_5, ol.early_shpdte
order by ship_id
]That looks like the query you were using before you started this thread.
Modify it, using the analytic fucntions FIRST_VALUE and LAG, like I showed you.
I see that you did simplify the problem quite a bit, and it's good that you did that.
It doesn't matter that your real problem involves joins or GROUP BY. Analytic functions are calculated on the results after all joins and GROUPS BYs are done. Just substitute your real expressions for the simplified ones.
For example, in your simplified problem, there was a column called order_nr, but I see now that's it's really called o.ordnum. Where the solution I posted earlier says "ORDER BY order_nr", you should say "ORDER BY o.ordnum".
Here's a less obvious example: in your simplifed problem, there was a column called price, but I see now that it's really SUM (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt). Where the solution I posted earlier says "TO_CHAR (price)", you should say "TO_CHAR (SUM (tc1.chrg_amt + tc2.chrg_amt + tc3.chrg_amt))". (You can't use an alias, like "Total Price", in the same SELECT clasue where it is defined.)
I removed some columns from the select as they are not relevant for the wanted action like 'adress details or other references'.
Now here is the result:
Shipment ID     Order Number     WMS Batch     Freight      Fuel Price Order Total Price
SID0132408     MDK-000014-05602649     04641401     110     10 120
SID0132408     MDK-000014-05602651     04641402     110     10 120
SID0132408     MDK-000014-05602652     04641363     110     10 120
as you can see, the 3 orders have the same shipment ID.
The expected result should be shown under column 'Total Price' as follows:
Shipment ID     Order Number     WMS Batch     Freight      Fuel Price Order Total Price
SID0132408     MDK-000014-05602649     04641401     110     10 120
SID0132408     MDK-000014-05602651     04641402     110     10 tog with 04641401
SID0132408     MDK-000014-05602652     04641363     110     10 tog with 04641401Okay, so those are the correct results that I asked for, plus the incorrect results you're getting now. Thanks; extra information doesn't hurt.
But where is the raw data that you're starting with?
It looks like you tried to format the code (but not the results) by typing this 1 character:
before the formatted section and this different character
after the formatted section. To post formatted text on this site, type these 6 characters
before the formatted section, and the exact same 6 characters again after the formatted section.

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Hi All
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Create a new column in a table that compares the value of one column with its previous value

The DDL:
DECLARE
@T TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
DECLARE
@K TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
INSERT
INTO @T
VALUES(22,'C_V_Harris','2014-01-02 10:23:49.0000000',
23.335,
23.347)
INSERT
INTO @T
VALUES(21,'C_V_Harris','2014-01-02 10:05:13.0000000',
23.357,
23.369)
INSERT
INTO @T
VALUES(20,'C_V_Harris','2014-01-02 09:56:15.0000000',
23.364,
23.377)
INSERT
INTO @T
VALUES(19,'C_V_Harris','2014-01-02 09:45:26.0000000',
23.351,
23.367)
INSERT
INTO @T
VALUES(18,'C_V_Harris','2014-01-02 09:43:20.0000000',
23.380,
23.396)
INSERT
INTO @T
VALUES(17,'C_V_Harris','2014-01-02 09:34:28.0000000',
23.455,
23.468)
INSERT
INTO @T
VALUES(16,'C_V_Harris','2014-01-02 09:30:37.0000000',
23.474,
23.486)
INSERT
INTO @T
VALUES(15,'C_V_Harris','2014-01-02 09:18:12.0000000',
23.419,
23.431)
INSERT
INTO @T
VALUES(14,'C_V_Harris','2014-01-02 09:16:06.0000000',
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INSERT
INTO @K
SELECT
ROW_NUMBER()
OVER (ORDER
by IDNO)
AS RN,*
FROM
@T
SELECT
* FROM
@K
--not working:
SELECT
a.RN,a.Price2
FROM
@K a
INNER
JOIN @K
b
ON
a.RN=b.RN-1
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name
Date
Price1
Price2
Comp
22
C_V_Harris
1/2/2014 10:23:49
23.335
23.347
0
21
C_V_Harris
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23.369
1
20
C_V_Harris
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23.364
23.377
1
19
C_V_Harris
1/2/2014 9:45:26
23.351
23.367
-1
18
C_V_Harris
1/2/2014 9:43:20
23.38
23.396
1
17
C_V_Harris
1/2/2014 9:34:28
23.455
23.468
1
16
C_V_Harris
1/2/2014 9:30:37
23.474
23.486
1
15
C_V_Harris
1/2/2014 9:18:12
23.419
23.431
-1
14
C_V_Harris
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-1
How can I structure the statement to get (the most recent - order by date ) result for Comp?

Satheesh Variath, I just had to make some corrections from your script to get the correct answer:
CREATE
VIEW vw_Comp
AS
SELECT
TOP 1 t.IDNO,t.name,t.[Date],t.Price1,t.Price2,
CASE
WHEN t.Price2
> LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNO)
THEN 1
WHEN t.Price2
< LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNo)
THEN -1
ELSE 0
END
AS Comp
FROM
@T t
ORDER
BY DATE
DESC
The adjustments: the selection of the most recent comparison (Top 1) and the use of the function LAG (instead of LEAD) to get the previous value of the column.

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Hi Keith,
As I understand you are trying to add compare the values.
I am trying to look into it but as of now I have this workaround for you. You can try to create a new column having if formula that returns 1 if the cell values are equal and 0 if they are not.
At the total row we compare the sum of value of the column with if formula that we created and the sum 1128 in this case with the help of if formula again.
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Paid
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Rock City
220
220
1
Orlando
517
516
0
Boston
391
392
0
Total
1128
1128
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Here it co
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I have enclosed a VI that contains what I've achieved until now, which is nothing
I appreciate your time and help.
Best regards,
JAVIER VIDAL
Attachments:
Other_Main_Menu.vi ‏103 KB

Javier,
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