Concat substring and string question

Hello,
So I am trying to add together a string \\fafs10\home and the concat of a substring of the first initial of a GivenName and LastName. I keep getting a NaN error.
Here's what I have:
=string("\\fafs10\home\") + concat(substring(GivenName,0,1), LastName)
I want to return this as a default value to my list.
Any help would be greatly appreciated. Thank you.
Matthew

Hi
are you doing this in a calculated column or within a rule on an InfoPath form or another way?
you should probably just go with
concat("\\fafs10\home\",substring(GivenName,0,1),LastName)
Regards
Sergio Giusti Sergio Blogs
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Concat Date and String!

Hello,
My requirement is that I need to concat a string with a date. I tried to convert the date to char but I am not getting the date format and then want to contact with the string.
here is the requirement:
Contact Date: 12/08/2011.
In order to do this, I tried to convert the date into string but having difficulty in getting the date format.
any help is appreciated.
Thanks -

manyam16 wrote:
Hello,
My requirement is that I need to concat a string with a date. I tried to convert the date to char but I am not getting the date format and then want to contact with the string.
here is the requirement:
Contact Date: 12/08/2011.
In order to do this, I tried to convert the date into string but having difficulty in getting the date format.
any help is appreciated.
Thanks -The "tricky" part to what you are asking for is that when you cast a date column as char, the format may change. For example, when I look at my system date as is (it is a date field), the format is as follows:
1/26/2012 5:53:11 AM
When I cast it as CHAR, it appears as follows:
2012/01/26 05:53:11
Why am I saying this? Because the details of the next step will be determined by where the characters are in the string. For this exercise, I will assume that after casting to CHAR, the format is as you say. Then the stringing should look something like this:
Contact Date: 12/08/2011. SUBSTRING(CAST("your date column" AS CHAR) FROM 1 FOR 2) ...to give you the 12
SUBSTRING(CAST("your date column" AS CHAR) FROM 4 FOR 2) ...to give you the 08
SUBSTRING(CAST("your date column" AS CHAR) FROM 7 FOR 4) ...to give you the 2011
So concatenating them, you get:
SUBSTRING(CAST("your date column" AS CHAR) FROM 1FOR 2)||'/'||SUBSTRING(CAST("your date column" AS CHAR) FROM 4 FOR 2)||'/'||SUBSTRING(CAST("your date column" AS CHAR) FROM 7 FOR 4)
Now you can concatenate your text to the above string...

How to Split the string using Substr and instr using loop condition

Hi every body,
I have below requirement.
I need to split the string and append with single quotes('') followed by , (comma) and reassign entire values into another variable. so that i can use it where clause of update statement
for example I am reciveing value as follows
ALN varchar2(2000):=(12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434);
Note: In the above variable i see 8 transactions, where as in real scenario i donot how many transaction i may recive.
after modification i need above transactions should in below format
ALTR Varchar2(2000):=('12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434');
kindly help how to use substr and instr in normal loop or for loop or while loop while modifying the above transactions.
Please help me to sort out this issue.
Many Thanks.
Edited by: user627525 on Dec 15, 2011 11:49 AM

Try this - may not be the best way but...:
create or replace type myTableType as table of varchar2(255)
declare
v_array mytabletype;
v_new_str varchar2(4000);
function str2tbl
         (p_str   in varchar2,
          p_delim in varchar2 default '.')
         return      myTableType
    as
        l_str        long default p_str || p_delim;
         l_n        number;
         l_data     myTableType := myTabletype();
    begin
        loop
            l_n := instr( l_str, p_delim );
            exit when (nvl(l_n,0) = 0);
            l_data.extend;
            l_data( l_data.count ) := ltrim(rtrim(substr(l_str,1,l_n-1)));
            l_str := substr( l_str, l_n+length(p_delim) );
        end loop;
        return l_data;
   end;
begin
v_array := str2tbl ('12ERE-3MT-4Y,4IT-5O-SD,OP-K5-456,P04-SFS9-098,90P-SSF-334,3434-KJ4-O28,AS3-SFS0-J33,989-3KL-3434', ',');
      FOR i IN 1 .. v_array.COUNT LOOP
         v_new_str := v_new_str || ''''||v_array(i)||'''' || ',';
      END LOOP;
   dbms_output.put_line(RTRIM(v_new_str, ','));
end;
OUTPUT:
=======
'12ERE-3MT-4Y','4IT-5O-SD','OP-K5-456','P04-SFS9-098','90P-SSF-334','3434-KJ4-O28','AS3-SFS0-J33','989-3KL-3434'HTH
Edited by: user130038 on Dec 15, 2011 12:11 PM

Using the Concat & Substring

Hello all,
Pretty simple question, just running into syntax errors.
I want to take the first letter of fields 1 and 2, and the 6, 9, and 3rd number of fields three. I can do this with a substring one at a time, but I need to this so it puts all of the values from the substr together, ex. 051097HT. This is Date of birth, and initials. How would I usr the Concat for this. My last attempt.
TextField1.rawValue = Concat(Substr (txtDOB.rawValue, 6,2),(Substr(txtDOB.rawValue,9,2)
This is not the complete solution, just 2 parts. Not sure how to write it to put it together.
TIA!!!
Rudy

Jim,
These string operations are part of Core JavaScript, not Acrobat. To learn about using string in the JavaScript language you should take a look at a JavaScript Language Reference. The O'Reilly book is the best but there are plenty of online resources as well.
>>TextField1.rawValue = str1.substr, (6,2)+ str2.substr, (9,2)
This line has a syntax problem, it should be
TextField1.rawValue = str1.substr(6,2)+ str2.substr(9,2);
To keep it from adding the numbers you can force the this expression into a string context like this
TextField1.rawValue = String(str1.substr(6,2))+ String(str2.substr(9,2));
OR
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Thom Parker
WindJack Solutions
www.windjack.com

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I have a non-validating sax-parser, which appears to work fine. Except in some instances it hiccups and loses characters. "How are you" will come out as "are you".
I found the problem occurs in the method that reads chars and creates a substring.
When start reaches 8192, it resets itself to 1 and starts a new line, thereby chopping the text.
How can I reset start?
Jim
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Probably your characters() method is being called twice by the parser, once for the "How " part and again for the "are you" part, and probably the parser decides to do this because of its 8192-character internal buffers. Unfortunately this is legitimate behaviour for a SAX parser, and you'll have to fix your program to allow for it.

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Hello,
I have a string (column is normal range) like 70 - 110 mg/dl.
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2 as
3 (
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6 select '70-110mg/dL   ' str from dual union all
7 select '70 -110mg/dL ' str from dual union all
8 select '70- 110mg/dL ' str from dual union all
9 select '70-110 mg/dL ' str from dual
10 )
11 select trim(substr(str, 1, instr(str, '-') - 1)) num1,
12         trim(substr(str, instr(str, '-') + 1, instr(str, 'mg') - instr(str, '-') - 1 )) num2
13    from t;
NUM1            NUM2
0.3             1.0
70              110
70              110
70              110
70              110
70              110
6 rows selected.
SQL>Asif Momen
http://momendba.blogspot.com

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Edited by: Kamil Wydrzycki on Sep 24, 2009 12:57 PM

DrLaszloJamf wrote:
warnerja wrote:
DrLaszloJamf wrote:
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How to Plot number and string in one row (data logger counter) ?

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i have problem about plot the number & string in one row, as shown on the picture below :
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Attachments:
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Difference between String=""; and String =null

I want to know the difference especially the ADVANTAGE between the following-
1. String s="";
String s="ABC"
and
String s;
String s="ABC";
or String s=null;
String s="ABC";
2. Object anyObject;
anyObject-new Object();
and
Object anyObject=null;
anyObject=new Object();

Tanvir007 wrote:
I want to know the difference especially the ADVANTAGE between the following-
1. String s="";s points to the empty string--the String object containing no characters.
String s="ABC"s points to the String object containing the characters "ABC"
String s; Declares String reference varialbe s. Doesn't not assign it any value. If it's a local variable, it won't have a value until you explicitly assign it. If it's a member variable, it will be given the value null when the enclosing object is created.
String s="ABC";Already covered above.
or String s=null;s does not point to any object.
String s="ABC";???
You've already asked this twice.
Are you talking about doing
String s = null;
String s = "ABC";right after each other?
You can't do that. You can only declare a variable once.
If you mean
String s = null;
s = "ABC";It just does what I described above, one after the other.
2. Object anyObject;
anyObject-new Object();
and
Object anyObject=null;
anyObject=new Object();As above: In the first case, its value is undefined until the new Object line if it's a local, or it's null if it's a member.
As for which is better, it depends what you're doing.

Concat substring and string question

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