Conditional GROUP BY clause

Hi,
I have four columns in group by clause. I want to add conditional group by clause.
Case 1 : If one of the  column's value is null, I don't want to include it in group by clause. Means, Now GROUP BY clause will have only 3 columns.
Case 2 : If not null, then GROUP BY clause with all four columns.
Please help me out on this.
Thanks in advance.  

Hi
I think it won't matter, all group functions by default ignore NULLs so your result won't differ.
select  dept, loc, sum(sal)
from (
select 'A' emp , 1 dept , 'P' loc , 100 sal from dual union all
select'B',1,'P',200 from dual union all
select'C',2,'P',300 from dual union all
select'D',2,'P',400 from dual union all
select'E',3, 'P',500 from dual union all
select'F',3, 'P',600 from dual union all
select'G',4, 'Q',700 from dual union all
select'H', null,'Q' , 1000 from dual union all
select'I',null ,'Q', 2000 from dual union all
select 'J' ,null, 'Q',300 from dual)
group by dept,loc;
Output
DEPT      LOC      SUM(SAL)
1                P      300
2                P      700
3                P      1100
                Q      3300
4                Q      700
Now by doing grouping only for NOT NULL values,
select dept,loc, sum(sal)
from (
select 'A' emp , 1 dept , 'P' loc , 100 sal from dual union all
select'B',1,'P',200 from dual union all
select'C',2,'P',300 from dual union all
select'D',2,'P',400 from dual union all
select'E',3, 'P',500 from dual union all
select'F',3, 'P',600 from dual union all
select'G',4, 'Q',700 from dual union all
select'H', null,'Q' , 1000 from dual union all
select'I',null ,'Q', 2000 from dual union all
select 'J' ,null, 'Q',300 from dual)
where dept is not null          --------------NOT NULL Condition
group by dept, loc;
Output
DEPT     LOC      SUM(SAL)
1           P           300
2           P           700
3           P           1100
4           Q           700
Now by doing grouping only for NULL values,
select dept,loc, sum(sal)
from (
select 'A' emp , 1 dept , 'P' loc , 100 sal from dual union all
select'B',1,'P',200 from dual union all
select'C',2,'P',300 from dual union all
select'D',2,'P',400 from dual union all
select'E',3, 'P',500 from dual union all
select'F',3, 'P',600 from dual union all
select'G',4, 'Q',700 from dual union all
select'H', null,'Q' , 1000 from dual union all
select'I',null ,'Q', 2000 from dual union all
select 'J' ,null, 'Q',300 from dual)
where dept is null               --------------NULL Condition
group by dept, loc;
Output
DEPT      LOC         SUM(SAL)
                Q           3300
The output is same for both the conditions.

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               0          1
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               2          2
               3          2
               4          1
               5          1
               6          1
    Selezionate 7 righe.
    SQL> Bye Alessandro

  • How can I pass multiple condition in where clause with the join table?

    Hi:
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    Thanks in advance for any help.
    Regards,
    TD

    If you are using SQL-Plus or Reports you can use lexical parameters like:
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    SELECT &columns FROM &tables &condition;
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    Best of luck!

  • How to use order by within Group by clause

    Hi All,
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    Thanks .

    order by clause should be used at the last in any query.......but in group by clause u can't use use that becoz u group according to column then no ordering is needed there......if u want to filter something then u can use having clause and later if u need to arrange then u can use order by clause.........
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  • Problem in case of or condition in  where clause in case of leftouter joi.

    hi
    i am encountering a wierd problem.
    in a select query if i have a left outer join and a or condition in where clause the order of condition in or matters and if i use a to_char problem is solved.
    see query below
    select * from custsupp left outer join Salesperson s on custsupp.sales_rep = s.id ,state a where (CS_FLAG='C' or CS_flag ='B') and custsupp.state = a.id
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    also if i remove left outer join and keep order of condition as it is i get result i.e
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    also if i add a to_char to co,umns CS_FLAG i get the result.
    select * from custsupp left outer join Salesperson s on custsupp.sales_rep = s.id ,state a where (to_char(CS_FLAG)='C' or to_char(CS_flag ='B')) and custsupp.state = a.id
    why it is so?
    CS_flag is of type nchar
    Shreyas
    Edited by: shreyasd on Jun 9, 2010 11:07 PM

    First if you don't want to take credit of the free sample then follow the below procedure:
    1. Do the GRN for all the three item and for the free item in the excise tab at the item level select the material as non cenvatable. Just remember to add base value of the item
    2.  If you want to capture the Part1 entry then just do the normal transaction and while posting the excise with J1IEX just remove the excise duties for the free item.
    3. For paying the vendor the excise amount, just do subsequent debit in the MIRO and in the details tab add in the unplanned delivery cost the amount that you want to pay for the excise duties
    Second case if you want to take credit of the duties:
    1. Do the Normal GRN process, add the base value and excise values for the free item.
    2. Post the Excise duites with J1iEX.
    3. The with the account entry you can settle the excise payment
    Hope this will help you
    Enjoyyyyyyyyyyy
    Akshit

  • Creation of view with clob column in select and group by clause.

    Hi,
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                 ON users_ec_1.USER_ID = Backup_Latest.USER_ID
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    CONTENT_ID     NUMBER(10,0)
    TITLE          VARCHAR2(50)
    KEYWORDS     VARCHAR2(100)
    CONTENT          CLOB
    ISPOPUP          NUMBER(1,0)
    CREATED          TIMESTAMP(6)
    SEARCHSTARTDATE     TIMESTAMP(6)
    SEARCHENDDATE     TIMESTAMP(6)
    HITS          NUMBER
    TYPE          VARCHAR2(50)
    CREATEDBY     VARCHAR2(20)
    UPDATED          TIMESTAMP(6)
    ISDISPLAYED     NUMBER(1,0)
    UPDATEDBY     VARCHAR2(20)
    AVERAGERATING     NUMBER
    VOTES          NUMBERAny help realyy appreciated.
    Thanks in advance
    Edited by: user512743 on Dec 10, 2008 10:46 PM

    Hello,
    Specifically, this should be asked in the
    ASP.Net MVC forum on forums.asp.net.
    Karl
    When you see answers and helpful posts, please click Vote As Helpful, Propose As Answer, and/or Mark As Answer.
    My Blog: Unlock PowerShell
    My Book: Windows PowerShell 2.0 Bible
    My E-mail: -join ('6F6C646B61726C40686F746D61696C2E636F6D'-split'(?<=\G.{2})'|%{if($_){[char][int]"0x$_"}})

  • -- SQL -- GROUP BY clause: non-aggregate fields mandate

    Hello,
    I was studying Databases, (particularly the retrieval of the data), and found something interesting.
    While using an Aggregate Function in the SELECT clause, it is mandatory to have all the non-aggregate fields in the SELECT clause to be there in the GROUP BY clause.
    For example,
    SELECT dept_no, SUM(salary)
    FROM employee
    GROUP BY dept_no;
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    But, what if the user misses the dept_no in the GROUP BY clause or he/she misses the GROUP BY clause itself?
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    SQL2:_
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    I am unable to understand why is this not handled?

    Hi,
    998478 wrote:
    ... If we mix aggregate and non-aggregate values then there must be a GROUP BY clause containing all the non-aggregate values. Why is this not handled by the database/compiler itself? It IS handled by the compiler itself. The compiler handles it by raising an error. The compiler has no way of knowing whether you want to remove something from the SELECT clause, or to add something to the GROUP BY clause, or not to use aggregate functions, or to use more aggregate functions, or some combination of the above. If the compiler re-wrote your code, and did any of these things automatically, it would be wrong more often than it was right, and you would (rightly) be complaining about its behavior.
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    ,       job
    ,       SUM (sal)
    FROM       scott.emp
    GROUP BY  deptno
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    <h3>1. Remove something from the SELECT clause</h3>
    SELECT    deptno
    ,       SUM (sal)
    FROM       scott.emp
    GROUP BY  deptno
    ;<h3>2. Add something to the GROUP BY clause</h3>
    SELECT    deptno
    ,       job
    ,       SUM (sal)
    FROM       scott.emp
    GROUP BY  deptno
    ,         job
    ;<h3>3. Not use aggregate functions</h3>
    SELECT    deptno
    ,       job
    ,       sal
    FROM       scott.emp
    ;<h3>4. Use more aggregate functions</h3>
    SELECT    deptno
    ,       MIN (job)
    ,       SUM (sal)
    FROM       scott.emp
    GROUP BY  deptno
    ;These aren't all the options, either. For example, the correct fix might be to use analytic functions instead of aggregate functions.
    How can anybody say which of these is right? All of them are the right answer for some problem.
    By the way, saying that everying in the SELECT clause must be an aggregate or in the GROUP BY clause is a bit over-simplified.
    More completely, here are the ABC's of GROUP BY:
    When you use a GROUP BY clause and/or an aggregate function, then everything in the SELECT clause must be:
    (A) an <b>A</b>ggregate function,
    (B) one of the "group <b>B</b>y" expressions,
    (C) a <b>C</b>onstant, or
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    Edited by: Frank Kulash on Apr 13, 2013 1:44 PM
    Added code examples.

  • Problem with the query in group by clause

    hi, i have problem with group by clause, can some one please help me.
    select
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    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(1, 1,'NL','AP',100,20);
    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(1, 2,'PO','AP',20,20);
    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(1, 3,'NL','AP',70,20);
    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(2, 1,'NL','PA',100,20);
    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(2, 2,'NL','PA',100,20);
    insert into temp_tab(header_id, line_num,country, source, dr,cr) values(3, 1,'KR','PO',100,20);
    commit;
    Appreciate your help.
    Thanks,

    select header_id,
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             where a1.country=a.country
             and a1.source='AP'
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    ,countryIt's kinda hard to follow what your query does... maybe because I'm only at my second coffee..
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