Configuring the PATH for jdk1.3.1_01 in WindowsXP

I need help in configuring the autoexec.bat file for jdk1.3.1_01 . I am running on WindowsXP. (I used to have win 98 on my old pc that crashed and had jdk1.2.1 and working just fine) Now I have a new pc and have tried the following:
windir=C:\WINDOWS
SET winbootdir=C:\WINDOWS
SET COMSPEC=C:\WINDOWS\COMMAND.COM
SET PATH=C:\WINDOWS;C:\WINDOWS\COMMAND;C:\jdk1.3.1_01\bin
SET PROMPT=$p$g
SET TEMP=C:\WINDOWS\TEMP
SET TMP=C:\WINDOWS\TEMP
When I type in C:\path ...it does not show the path I entered. I have no clue what I am doing and the instructions I printed out from sun just do not help me out at all. I really need to get this working so I can continue learning. If anyone can please straighten me out on this I would really appreciate it. Feel free to email me at [email protected]
Thanks Reba

Your PATH appears to be correct. However, to verify your PATH you should be able to type the following:
c:\>echo %PATH%
This will display your PATH setting on the console. In addition, you can verify that your PATH setting is correct by typing:
c:\>java -version
If your path is set correctly, you should see something like:
java version "1.3.0"
Java(TM) 2 Runtime Environment, Standard Edition (build 1.3.0-C)
Java HotSpot(TM) Client VM (build 1.3.0-C, mixed mode)
If, instead, you get something like:
"Bad command or file name"
Then your PATH is not configured correctly.
Hope this helps.

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Short Text
Frontend Services
Functionality
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