Conflict of class-names in two projects

Hello,
I have one workspace with two projects. On project is "used" by second project (via add libraries).
Problem: both projects have a package with the same name (system) and class with the same name (system.Session).
How to reference from project P1 to (P1)system.Session and (P2)system.Session together? >import system.Session< is insufficient... How to extend >import< for P1/P2?
Thanks for any hint.
Jara

Hi,
As the previous poster noted the easiest option would be to rename one of the classes, otherwise you can deal with by using a different class loader. Take a look at the javadoc in URLClassLoader for how to set up on. This will allow you to load the classes into a different namespace.
This interestingly enough allow you to have more than one instance of a Singleton in a java vm.
Thanks,
Gerard Davison

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Conflicting class names

I've been seeing an error a lot recently:
The name of this class, 'MyClassName', conflicts with the
name of another class that was loaded, 'MyClassName'.
I'm not sure why I keep getting this error, especially with
projects that only have one custom class. The only way I have been
able to get around it is to continually rename the class.

I've been seeing an error a lot recently:
The name of this class, 'MyClassName', conflicts with the
name of another class that was loaded, 'MyClassName'.
I'm not sure why I keep getting this error, especially with
projects that only have one custom class. The only way I have been
able to get around it is to continually rename the class.

Open my project and everythings blank? I changed class name.. But everythings gone? Heres a link to my project.

I broke my project! I made a lil christmas tree with labled presents under it for my friends to click on and it will take them to a link where they can get a gift card code i got for them.
Anwyas.. I swear.. everything was fine.. All i remember doing last was changing the composition class name and the changing the untittled bit at the top to the same. Also, I did accidently open it in an older version of edge since i have 2 copies on my machine but i do that all the time and never broke a project before.. so i donno..
I zipped up my files. I am kinda desperate to get this fixed.. Its christmas! Iv been working on this forever.. It needs to be done today.. It was perfect.. I just want my files back? Is there anyway?
Heres my project if anyone wants to take a look... Everything i did is just gone/blank.. D: http://portalpacific.net/AussieChristmasParty.rar
Any help REALLY appreciated!!!
Happy Holidays!

Hey Redesign. You still online? I managed to re-create the page I lost.. Took a few hours.. I am having a slight problem though. I centered the composition using the stage preferences to the left, I also added a preloader. These worked fine. I must of done something to break both the centering and the preloader. Its not even letting me edit it. Do you see anything abnormal? (It says it should be centered in the settings in the html file too but its not also same issue with http://portalpacific.net/AussieChristmasParty2.rar

The name of this class conflicts with the name of another class

I had a problem when compiling my flash movie. I had made an
instance from a class, but the output kept saying:
"The name of this class, XXX, conflicts with the name of
another class that was loaded XXX."
I read a lot of developers have the same problems, when i
looked it up:
Google
link on : "conflicts with the name of antother class that was
loaded"
Apparently it is some kind of bug caused by different times,
between local/network machines and servers.
Also when there is a time difference involved between 2
computers, then this problem also occurs.
Can't macromedia fix this bug? .....Because as a developer i
don't want to adjust my time, everytime i want to test my flash
movies or have to compile my movie 2 times. The other developers
are getting tired of it also.
We need to get this bug trough to macromedia or adobe!
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What does $ sign in a class name signifies

I have downloaded a project as a jar file(zip), when I unzipped it it gave me two files
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SchoolQadBase$RecordType.java(this has a Record type defined it).
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Can I just include the RecordType in my SchoolQadBase.java and delete the other file?
If I rebuilt the project does that affect any of my functionality.
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package org.atcc.erpproxy.model;
import java.io.Serializable;
import java.util.Date;
public class ErpQADBase extends AbstractErpObject
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private String department2 = "";
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public RecordType getRecordType() {
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public void setRecordType(RecordType recordType) {
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}

What does the $ sign in the class name signifies?It signifies that it is an inner class
Can I just include the RecordType in my SchoolQadBase.java and delete the other file?Definitely not
Edited by: tjacobs01 on Nov 17, 2008 7:46 PM

How to get the class name and field name dynamically

Hi
I have a class (ex: Contract) the fields (ex : a,b,c) .i need to get the class name and field name dynamically
ex
if( validation file for the field Contract.a){
return contract.a;
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Please help me .............
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Edited by: 849614 on Aug 11, 2011 6:49 AM

YoungWinston wrote:
maheshguruswamy wrote:
Agreed, but IMO, i still feel its best if there is no tie in between consumer class level details and the database it talks to. A service layer is needed in between them.Sounds like you've done a bit of this before. Me, I've either been a modeller/DBA, doling out data, or a nuts and bolts programmer (and actually more toolmaker than apps, but did a bit of that too).
Do you know of a good book about the "middle ground" (ie, these service layers)? I understand it empirically, but haven't had a lot of exposure to it.
Winston
Edited by: YoungWinston on Aug 11, 2011 10:34 PM
PS: Apologies. Edited my previous post, presumably while you were composing your reply, when I finally realized what '.filed' meant.Most of my work is in web development, never been a DBA :) . The biggest 'concern' in my shop is 'separation of concerns'. The UI group reports up to a different IT head, the DB group reports up to a different IT head and so on. The looser the coupling between these systems, the lesser the project costs (Integration, QA etc) are. Martin Fowler's books contain good information about separation of concerns in an enterprise environment. The two books which i recommend are
[url http://www.amazon.com/Patterns-Enterprise-Application-Architecture-Martin/dp/0321127420]Enterprise Application Architecture and
[url http://www.amazon.com/Enterprise-Integration-Patterns-Designing-Deploying/dp/0321200683/ref=pd_sim_b_1]Enterprise Integration Patterns

[svn:fx-trunk] 5604: Ensuring qualified class names are used in type selector cache keys for Flex 4 applications .

Revision: 5604
Author: [email protected]
Date: 2009-03-26 14:00:26 -0700 (Thu, 26 Mar 2009)
Log Message:
Ensuring qualified class names are used in type selector cache keys for Flex 4 applications.
QE: Yes, this should address style issues for test cases that contain two different components with the same local name.
Dev: No
Doc: No
Checkintests: Pass
Modified Paths:
flex/sdk/trunk/frameworks/projects/framework/src/mx/styles/StyleProtoChain.as

Remember that Arch Arm is a different distribution, but we try to bend the rules and provide limited support for them. This may or may not be unique to Arch Arm, so you might try asking on their forums as well.

Conflit in class name and package name

I have a small doubt. If the class name and the package name are the same in a folder, is there will be any conflict between these while using it. That means suppose a folder named 'animator' contain a package 'a' and a class name 'a'. I got any error in the 'Eclipse' tool that "a collides with a package". Is this can be solved my any change of setting in Eclipse? If then where can i change.? Can anybody help me to solve this issue??

This works fine: just add an import to Test.java.
import PackageName.MyClass;
public class Test
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        MyClass a = new MyClass();
public class PackageName {}
package PackageName;
public class MyClass {}It's a pretty wacky, useless example, but it works.
Plus I thought inner classes would have a dollar sign in their .class file names. When I compile this:
public class OuterClass
    public static void main(String [] args)
        OuterClass outer = new OuterClass();
        System.out.println(outer);
    public String toString() { return "I'm an OuterClass"; }
    class InnerClass
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}I see two .class files: OuterClass.class and OuterClass$InnerClass.class
Why make up examples like this? It's hard enough writing code, and it's easy to disambiguate for the compiler.

See error (Class Name: com.sun.data.provider.impl.CachedRowSetDataProvider

hi maseter
sir i try to user user given user password check form database
i have two text box and one button
i select partytable from verver side and drop in form
then use partytabledataprovider see in sessionbeen1
i use this code not reeor in build time but when i run project then give me error
=================
RowKey userRowKey = partytableDataProvider.findFirst
(new String[] { "partytable.partyid", "partytable.title" },
new Object[] { username.getText(), password.getText() });
if (userRowKey == null) {
ty.setValue("userid not right");
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ty.setValue("welcom in page");
===============
////(((((// String stid = (String) partytableDataProvider.getValue("PARTYTABLE.PARTYID");
// ty.setValue(stid);*/
see my error
Exception Details: java.lang.IllegalArgumentException
partytable.partyid
Possible Source of Error:
Class Name: com.sun.data.provider.impl.CachedRowSetDataProvider
File Name: CachedRowSetDataProvider.java
Method Name: getFieldKeyInternal
Line Number: 481
Source not available. Information regarding the location of the exception can be identified using the exception stack trace below.
Stack Trace:
com.sun.data.provider.impl.CachedRowSetDataProvider.getFieldKeyInternal(CachedRowSetDataProvider.java:481)
com.sun.data.provider.impl.CachedRowSetDataProvider.getFieldKey(CachedRowSetDataProvider.java:439)
com.sun.data.provider.impl.AbstractTableDataProvider.findFirst(AbstractTableDataProvider.java:143)
logintestform.Page1.button2_action(Page1.java:442)
sun.reflect.NativeMethodAccessorImpl.invoke0(NativeMethodAccessorImpl.java:-2)
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
sun
please give me idea how i check user give username and password form table
thank's
aamir

Hi ,
Wondering if you were able to get past this issue. If not , I would suggest checking the prefix's on the metadata of the column name.
Radhika

Class name of stub for EJBHome Impl

Hi,
I am doing a context.lookup to find the EJBHome stub and I print the class name
of the object that is looked up, every time a diffrent name comes up.
Object obj = ic.lookup("ejb/test");
System.out.println(hh.getClass().getName());
I get $Proxy1
and when I add the two more lines
Object obj1 = ic.lookup("javax/jms/QueueConnectionFactory");
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Object obj = ic.lookup("ejb/test");
System.out.println(obj.getClass().getName());
and re-run only my client I get:
weblogic.jms.client.JMSConnectionFactory
$Proxy2
I understand that weblogic generates the stub dynamically, but how come (class name
of) a object bound to JNDI tree keeps changing?
and why does that happen for the connection factory(is that not a RMI stub too)?
viswa

viswa <[email protected]> wrote:
Hi,
I am doing a context.lookup to find the EJBHome stub and I print the class name
of the object that is looked up, every time a diffrent name comes up.
Object obj = ic.lookup("ejb/test");
System.out.println(hh.getClass().getName());
I get $Proxy1
and when I add the two more lines
Object obj1 = ic.lookup("javax/jms/QueueConnectionFactory");
System.out.println(obj1.getClass().getName());
Object obj = ic.lookup("ejb/test");
System.out.println(obj.getClass().getName());
and re-run only my client I get:
weblogic.jms.client.JMSConnectionFactory
$Proxy2
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of) a object bound to JNDI tree keeps changing?You can look at java/lang/reflect/Proxy.java to see how proxy class names are generated.
BTW, it looks like WebLogic 7.0 doesn't use JDK dynamic proxies anymore and generates
stub/skeleton bytecode by itself, so Stub class names are no longer $Proxy123 but xxx_WLStub.
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viswa--
Dimitri

Class name and file name

if i have putiple classes in a single file then if a clas declared as public then the file name shoud me same as class name.... why?
if i declare two public class in a same source fiel what will happen????????
plz help................
thanks in advance

And i bet a million dollars that even you don't
search the forum before posting anything . So stop
suggesting that .Too bad that I wasn't included in the bet. You won't be coz you are a veteran and it's from you and the other veterans(I will include my peers as well) that i learnt a lot including good googling.
It happens
that I search the forum before I post an answer.
Searching the forum using google is actually very
effective.Yes and thats the very reason i didn't mention googling in that reply because i know that google gives the results from the threads in the forum as i myself have read a lot of posts at this forum using google and obtained solutions.But it's a different case when a person has to manually search the forum(without google) to see if a topic matches his needs and as i just mentioned off lately most of the posts come out with crappy headers like "Please Help Me" ; "Error" ; "Can't compile" ; "Help Needed" ; "What's wrong in this".How much sense does these headers make with respect to the what the post is really about.One can't expect a person to verify each such post with such crappy headers and read each's contentns.Just imagine how frustrating it is.Even the posters lose their cool when someone posts with such titles.Then just imagine what will be the condition of the person who is asked to check the forum before posting.But i totally endorse googling.There is no pardon or any sort of respite for a person who has posted without googling which would have fetched him top notch answers.
Oh God!That looks really long!

Class name and package name clashing

When i have a class and a package with the same name, I cannot access classes in the package. For example I have 3 classes and 1 package as below
- Test.java
- PackageName.java
+ PackageName // this is a directory
- MyClass.java
Below are the codes of .java files
Test.java
=======
public class Test { PackageName.MyClass a = new PackageName.MyClass ();}
PackageName.java
===============
public class PackageName{ }
MyClass.java
==========
package PackageName; public class MyClass { }
I can compile PackageName.java and MyClass.java but not Test.java. It says
cannot resolve symbol
symbol : class MyClass
location: class PackageName
PackageName.MyClass a = new PackageName.MyClass ();
But if I remove the PackageName.java, I can compile Test.java perfectly. I think when I use PackageName.MyClass, java thinks that I try to access an inner class MyClass of PackageName class, and that does not exists. Is there any way to solve this ambiguation, other than making the package name and class name different? Thank you very much.

This works fine: just add an import to Test.java.
import PackageName.MyClass;
public class Test
    public static void main(String [] args)
        MyClass a = new MyClass();
public class PackageName {}
package PackageName;
public class MyClass {}It's a pretty wacky, useless example, but it works.
Plus I thought inner classes would have a dollar sign in their .class file names. When I compile this:
public class OuterClass
    public static void main(String [] args)
        OuterClass outer = new OuterClass();
        System.out.println(outer);
    public String toString() { return "I'm an OuterClass"; }
    class InnerClass
        public String toString() { return "I'm an InnerClass"; }
}I see two .class files: OuterClass.class and OuterClass$InnerClass.class
Why make up examples like this? It's hard enough writing code, and it's easy to disambiguate for the compiler.

How to convert a String variable as class name and method name?

i have two classes
class Student
public String insertStudent(String sname)
{ return("Student has been inserted "); }
class Teacher
public String execute(String methodName, String className)
{ //return statement of the method 'insertStudent' in the class 'Student'; }
}Now, i have a class with the main method. Here, i would like to call the method *'insertStudent'* of class *'Student'*
using the method *'execute'* of class *'Teacher',* passing the method-name and the class-name (viz. insertStudent, Student) as the
String parameter.
Can anyone please help me out. Thanks
regards,
chinglai

You should have just added that as a comment on your [initial posting|http://forums.sun.com/thread.jspa?threadID=5334953] instead of starting a new thread.
Now, i have a class with the main method. Here, i would like to call the method 'insertStudent' of class 'Student'using the method 'execute' of class 'Teacher', passing the method-name and the class-name (viz. insertStudent, Student) as the
String parameter.
Why oh why? What do you want to achieve?
Let me tell you: there is a way to do what you try to do, but it's not recommended and should be used only very sparingly. Especially not in anything like your code, that resembles normal business logic (as opposed to an application framework such as Spring, for example).
Can you explain what exactly you want to do with that? Why should a Teacher be able to call any random method ony any other class. And what good would that do?

How to programmatically get the source for a class provided the class name?

Hello,
As a quick background, I am providing some tools to potential users of an in-house framework. One is the ability to generate quick prototypes from our existing demo applications. Assume a user downloads our jars and uses them in their project (we are using Eclipse, but that detail should not greatly affect my question). Included in the jars is a demos package that contains ready-to-run classes that serve to exhibit certain functionality. Since many users may just need quick extensions of these demos, I am trying to provide a way for them to be able to create a new project that starts with a copy of the demo class.
So, the user is provided a list of the existing demos (each one uses a single class). When the user makes their selection, with the knowledge of our framework, I can translate that into what demo class they need (returned as a string of format package.subpack1.subpackn.DemoClassName). What I now want to do is to use that complete class name to get the source (look up the file) for the corresponding class, and copy it into to a new file in their project (the copying into the project can be done easily in Eclipse, so what I need help with is the bolded part). Is there a simple way to get the source given a class path for a class as described above? You may assume the source files are included in the jars for the framework.
Thanks in advance.

If there's a file named "package.subpack1.subpackn.DemoClassName.java" in a "demos" directory in the jar, then yes. You'd just use
InputStream code = getResourceAsStream("/demos.package.subpack1.subpackn.DemoClassName.java");Or if those dots in the name actually separate directory names, i.e. you have a "package" directory under "demos" and a "subpack1" director under that and so on, then:
InputStream code = getResourceAsStream("/demos/package/subpack1/subpackn/DemoClassName.java");

Can you determine a dragged objects Class Name when it is dropped?

Is there a way to determine the class name for a dragged object.
I have set up two objects. One is a JList that acts as a data source for the second object which is a JTable. Both objects serve as both drag source and drop targets. I need to be able to react to the following events:
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3. Drag value from JTable to JList (deletes item from JTable).
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Any help would be appreciated.
Thanks

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Conflict of class-names in two projects

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