Context Menu to Execute a powershell script within selected directory.

Question

Hi,
I'm trying to run a powershell script from a context menu, I've been able to create a context menu, however, when I attempt to run the script it will only run at the default location. What I'd like to do is right-click a folder then click "Do Script"
and have it run the script with the location set to the directory I right clicked.
So for clarities sake, if I right click C:\example then when the script runs it should recognize .\ as C:\example
This is what I currently have in my registry entry. However it's shouting about how there is no parameter for Set-Location that matches -File, I can see that it's taking the Set-Location command, then it's trying to see if -File will is a perameter for it,
but I' trying to use -File for the powershell command. Anyone have any ideas for that?
PowerShell -Command "Set-Location -LiteralPath '%V'" -File C:\script\Test.ps1
Any ideas? I'm wondering if there is something in Powershell like how Bash has something like this to do commands inline
$ > Command -parameter <arg> && Command -parameter <arg>

Answer 1

To setup a script to launch in a men from within a context menu you must create a the following.
Create the following keys:
HKEY_CLASSES_ROOT\Directory\Shell\<Script Name>
HKEY_CLASSES_ROOT\Directory\Shell\<Script Name>\command
Within <Script Name> change the (Default) value to the words you want to have as a context menu example, "Launch Script Here".
Within the command Key change the (Default) value to
PowerShell.exe -File "C:\Script_location\script_name.ps1" "%v"
PowerShell.exe is executed with the -File flag followed by the scripts exact location and "%v " is a variable pointing to the location that was selected.