Converting a single entry within an array into 16 entries within a new array. Building an array without knowing the exact amount of array entries.

Question

I'm developing a VI that reads a text file and does a manipulation on the data it reads. The VI does the following: First, it reads all the ASCII characters from a text file, converts them to 8-bit words, until EOF occurs. Then I do some simple conversion to each byte. The result is that each bit entry of the byte now gives 2 3-bit entries, making a total of 16 3-bit values returned for each byte within the original array. For example, when I read element #0 of the byte array, I get the byte value of 1011000. My VI then converts this to 16 seperate 3-bit values. I can do the conversion just fine. My pro
blem is figuring out how to put these 16 elements into an array to be written out of my 6534 card. I know how to do the DIO write part, but the problem is how do I combine the 16 elements into an array for thousands of bytes read from the text file? Also, the size of the file that I read is unknown until it is read, so I may have to output many sucessive outputs as described above. The first element read would give 16 3-bit elements for the new array, the second byte read would give another 16 3-bit elements and so on upto N values in the original array. Any ideas ?

Answer 1

Place a for loop, wire N with your readed string lenght, pass the string inside and wire it to string subset, with the lenght entry wired to 1 and the offset entry to the loop counter (i). Then, you can play with every character inside the loop, and have an output array composed with the result of every character.
Hope this helps