Converting int[] to Integer[]

How to convert an int array to Integer[] without iterating the int[]?
we can traverse the int[] and add to Integer[]. But the traversing takes too much time. Is there any method to do the above conversion?

If you are using 1.5, you can use the individual elements of the int[] as if they were an Integer, so why do you need to convert it? If it is to pass the array as an argument, then sorry, you are going to have to traverse the arrays and set the elements. And, at most, this will take a second or two of time (even if you have an array of nearly max size), so in what way is this "taking too much time"?
Edit: And any API method to do this with a single line of code, would still, inside the method, need to traverse the arrays, so now time would be saved. If it is to save programming time, then take a few minutes to write a method for it now, and then every time you need it in the future, just use that method.

Similar Messages

Can't convert int to java.lang.Object

When I deploy my customer Bean, the following error occures, I think the main problem is Can't convert int to java.lang.Object, does anyone facing the same problem with me?
<pre>C:\j2sdkee1.3\repository\home\gnrtrTMP\CustomerApp\CustomerBean_RemoteHomeImpl.j
ava:27: Incompatible type for declaration. Can't convert int to java.lang.Object
java.lang.Object primaryKey = ejb.ejbCreate(param0, param1, para
m2);
^
C:\j2sdkee1.3\repository\home\gnrtrTMP\CustomerApp\CustomerBean_RemoteHomeImpl.j
ava:57: Incompatible type for =. Can't convert int to java.lang.Object.
primaryKeys = ejb.ejbFindByPrimaryKey( param0);
^</pre>
I really need your help!!!

you can only convert one object type to another. Integer is an object int isnt. You might want to convert int to Integer and then go ahead.
see if it works.

Can't convert int to java.lang.Integer.

Hi everyone.
I'm working on an auction site at the moment and have problems gaining a bidID number. This is part of my code and my error.
AuctionFacade aHse = (AuctionFacade) application.getAttribute("AuctionFacade");
String strTraderName = (String)session.getAttribute("traderName");
String strPassword = (String)session.getAttribute("password");
String strIDNum = request.getParameter("auctionID");
Integer intID = Integer.valueOf(strIDNum);
Integer [] bids = aHse.getAllBids(intID);
float fltYourBid = aHse.getBidPrice(bids.length);
^
Can't convert int to java.lang.Integer.
can anyone help please?

So, does "aHse.getBidPrice" expect an int or an Integer as its parameter? And does it return an int, or an Integer, or what? The answer to those questions may lead to your solution -- look at what you are actually using as the parameter, for example.

Int to Integer

how to convert int value to Integer value?
Thanks.

running the risk of sounding stupid
what's the difference?Sir,
An int is a primitive. An Integer is an object. Specifically a wrapper object for the primitive type int.
Java has both objects and primitives.
Sincerely,
Slappy

How to convert Date to Integer

Hi all,
please send the code How to convert the Date to Integer
I want like this
example: Date= 04.11.2002 after conversion the integer is: 4112002
like this I want if anyone knows this please send it as soon as possible
byee
thanks

Assuming ... String ASimpleDateFormat;
// do this first
ASimpleDateFormat = ASimpleDateFormat.replace(".","");
// then parse
int DateAsInt = Integer.parseInt(ASimpleDateFormat);

Convert float to integer

how to convert float to integer?
and convert it back from integer to float?

You can cast a float to an integer using the following syntax:
float f = 1.245;
int i = (int)f;
To convert an int to a float you use a similar syntax:
int i = 3;
float f = (float)i;
You'll also find some interesting methods for the Float and Integer object s in the Java API documentation.

Can't convert int to int[] URGENT!

HI list!
Here is the code part I have:
/** Holds the permutated groups which are arrays of integers. */
Vector v;
if(arg.length<3) System.exit (0); //Need at least 3 arguments
elements=new int[arg.length-1]; //Create array to hold elements
/* Copy the arguments into the element array. */
for(i=0;i<arg.length-1;i++) elements=Integer.parseInt(arg[i+1]);
groupsize=Integer.parseInt(arg[0]); //Get the number in each group.
calc(groupsize,elements.length); //Find out how many permutations there are.
v=permutate(groupsize,elements); //Do the permutation
for(i=0;i<v.size();i++) { //Print out the result
elements=(int[]) v.get(i);
System.out.println("");
for(j=0;j<elements.length;j++) System.out.print(elements
[j]+" ");
System.out.println("\nTotal permutations = "+v.size());
and the error I get is:
Permutate.java:26: Incompatible type for =. Can't convert int to int[]. for(i=0;i<arg.length-1;i++) elements=Integer.parseInt(arg[i+1]);

elements=(int[]) v.get(i);
The above statement is illegal. Its not possible to
use an array type in casting at all.
Basically you are trying to do a kind of multiple
casting, which is not possible.
You might want to store vectors in vector v instead of
arrays in vector v. Its better to do this.There's nothing wrong with the line
elements = (int[]) v.get(i);
assuming the returned object from the vector is in fact an array of int. Even then, it is a runtime exception condition not a compile-time error.
Using arrays is perfectly valid where you know the size of the array at creation and do not need to resize it during use... The arrays are fast and compact. This is however not a comment on the approach taken in this case but merely an observation that arrays are not always an inferior choice to one of the collection classes.
Now put up your dukes... ;)

Convert Date to Integer

I want to take this years number and convert it to an int.
I have tried the following and i get errors saying it cannot resolve symbol: parseInt.
Date thisyear = new Date();
int thisyearint = Integer.parseInt(thisyear.getYear());
Can anbody tell me how to di this simple conversion?
Mossybreen

It would help a great deal if you'd read the javadocs. If you had, you'd notice that the getYear() method in java.util.Date is deprecated. You shouldn't be using it.
I think the proper way to do this is to use java.util.Calendar:
Calendar calendar = new GregorianCalendar();
int yearAsInt = calendar.get(Calendar.YEAR);See if that's better.
MOD

Logic of converting strings to integer

Hi all,
I know that , I can convert a string into a number using API , Ineger.parseInt() . But i want to know the reall algoritham behind that
.Can anybody explane that ?
Basically I am interested in
String s = "123";
int i = Integer.parseInt(s);
But i want to know what is the logic running behind this ?. Can anybody please help me. ...?
Thanks in advance....

The decompiled version parseInt() from Integer class
     * Parses the string argument as a signed decimal integer. The
     * characters in the string must all be decimal digits, except that
     * the first character may be an ASCII minus sign <code>'-'</code>
     * (<code>'\u002D'</code>) to indicate a negative value. The resulting
     * integer value is returned, exactly as if the argument and the radix
     * 10 were given as arguments to the
     * {@link #parseInt(java.lang.String, int)} method.
     * @param s        a <code>String</code> containing the <code>int</code>
     *             representation to be parsed
     * @return     the integer value represented by the argument in decimal.
     * @exception NumberFormatException if the string does not contain a
     *               parsable integer.
    public static int parseInt(String s) throws NumberFormatException {
     return parseInt(s,10);
     * Parses the string argument as a signed integer in the radix
     * specified by the second argument. The characters in the string
     * must all be digits of the specified radix (as determined by
     * whether {@link java.lang.Character#digit(char, int)} returns a
     * nonnegative value), except that the first character may be an
     * ASCII minus sign <code>'-'</code> (<code>'\u002D'</code>) to
     * indicate a negative value. The resulting integer value is returned.
     * <p>
     * An exception of type <code>NumberFormatException</code> is
     * thrown if any of the following situations occurs:
     * <ul>
     * <li>The first argument is <code>null</code> or is a string of
     * length zero.
     * <li>The radix is either smaller than
     * {@link java.lang.Character#MIN_RADIX} or
     * larger than {@link java.lang.Character#MAX_RADIX}.
     * <li>Any character of the string is not a digit of the specified
     * radix, except that the first character may be a minus sign
     * <code>'-'</code> (<code>'\u002D'</code>) provided that the
     * string is longer than length 1.
     * <li>The value represented by the string is not a value of type
     * <code>int</code>.
     * </ul><p>
     * Examples:
     * <blockquote><pre>
     * parseInt("0", 10) returns 0
     * parseInt("473", 10) returns 473
     * parseInt("-0", 10) returns 0
     * parseInt("-FF", 16) returns -255
     * parseInt("1100110", 2) returns 102
     * parseInt("2147483647", 10) returns 2147483647
     * parseInt("-2147483648", 10) returns -2147483648
     * parseInt("2147483648", 10) throws a NumberFormatException
     * parseInt("99", 8) throws a NumberFormatException
     * parseInt("Kona", 10) throws a NumberFormatException
     * parseInt("Kona", 27) returns 411787
     * </pre></blockquote>
     * @param      s   the <code>String</code> containing the integer
     *                representation to be parsed
     * @param      radix   the radix to be used while parsing <code>s</code>.
     * @return     the integer represented by the string argument in the
     *             specified radix.
     * @exception NumberFormatException if the <code>String</code>
     *              does not contain a parsable <code>int</code>.
    public static int parseInt(String s, int radix)
          throws NumberFormatException
        if (s == null) {
            throw new NumberFormatException("null");
     if (radix < Character.MIN_RADIX) {
         throw new NumberFormatException("radix " + radix +
                             " less than Character.MIN_RADIX");
     if (radix > Character.MAX_RADIX) {
         throw new NumberFormatException("radix " + radix +
                             " greater than Character.MAX_RADIX");
     int result = 0;
     boolean negative = false;
     int i = 0, max = s.length();
     int limit;
     int multmin;
     int digit;
     if (max > 0) {
         if (s.charAt(0) == '-') {
          negative = true;
          limit = Integer.MIN_VALUE;
          i++;
         } else {
          limit = -Integer.MAX_VALUE;
         multmin = limit / radix;
         if (i < max) {
          digit = Character.digit(s.charAt(i++),radix);
          if (digit < 0) {
              throw NumberFormatException.forInputString(s);
          } else {
              result = -digit;
         while (i < max) {
          // Accumulating negatively avoids surprises near MAX_VALUE
          digit = Character.digit(s.charAt(i++),radix);
          if (digit < 0) {
              throw NumberFormatException.forInputString(s);
          if (result < multmin) {
              throw NumberFormatException.forInputString(s);
          result *= radix;
          if (result < limit + digit) {
              throw NumberFormatException.forInputString(s);
          result -= digit;
     } else {
         throw NumberFormatException.forInputString(s);
     if (negative) {
         if (i > 1) {
          return result;
         } else {     /* Only got "-" */
          throw NumberFormatException.forInputString(s);
     } else {
         return -result;
    }

Error message:can't convert int to int[]

Hi,
I am trying to build a java code which convert decimal to binary
but ,I found error message "can not convert int to int[]"
some line of code:
int i=12,n=0;
int arr[n]=i%2;
n++;
here I am trying to store remainder in an integer arrary.
how can i do this???????
guide me please
-shobhit singh

shobhit_onprob wrote:
i want to store some integer values in to an integer arraryDid you follow the address that was given to you? I doubt it, and even if you did, 2 minutes is not enough time to read, let alone understand, the tutorial.
Go back there, it describes all the basics you need.

Converting java's integer variable into mysql's tinyint datatype

I am using mysql database and to store the values of the table I used tinyint as datatype in the mysql. I have to convert java's integer data type to mysql's tinyint data type. how it is possible. please help me out.
Thanks ...

Do you have to use int?
The range of tinyint is -128 to 127, which matches the primitive byte data type in Java exactly. Maybe this primitive would be more suited to your needs? (sorry I have no advice on your actual question :p)
Illu

How to convert sequence to Integer?

Hello,
Can anybody help me in converting a sequence from oracle to integer? I wrote the below code but it doesn't seem to work.
public void setNextControlId() {
try {
ResultSet rset = statement.executeQuery("select SMARTSEQ.nextval from dual");
if ( rs.next() ) {
     int val = ((Integer) rs.getObject(1)).intValue();
     System.out.println(val);
rset.close();
//con.close();
} catch(java.sql.SQLException e) {
e.printStackTrace();
finally {
     // if ( con != null ) con.close();
}

Because the ResultSet object rs itselft is NOT null, it is the individual elements int it.
===================================
i ma wondering why is the extra step required?
if ( rs.next() )
{Object obj = rs.getObject(1)
why not
if (rs==null)
i know this is not working , but what is the purpose
of this null then ??????/

CAST Not working for me - Arithmetic overflow error converting int to data type numeric - error

GPM is DECIMAL(5,2)
PRICE is DECIMAL(11,4)
COST is DECIMAL(7,2)
Trying to update the Gross Profit Margin % field and I keep getting the "Arithmetic overflow error converting int to data type numeric" error.
UPDATE SMEMODETAIL SET SMD_GPM = (SMD_PRICE-SMD_COST) / SMD_PRICE * 100
FROM SMEMODETAIL WHERE SMD_PRICE<>0 AND SMD_QUANTITY<>0
Example record:
SMD_PRICE SMD_COST GPM%
1.8500 1.62 12.4324324324324300
I added cast and I still get the error.
How do I format to get this to work?
Thanks!

Hi GBerthume,
The error is caused by some value such as 1000.01 of the expression (SMD_PRICE-SMD_COST) / SMD_PRICE * 100 exceeds the
precision of the column(DECIMAL(5,2)). The example data doesn't cause the overflow error for the value of the expression is 12.43 which is in the scope of DECIMAL(5,2).
USE TestDB
CREATE TABLE SMEMODETAIL
SMD_PRICE DECIMAL(11,4),
SMD_COST DECIMAL(7,2),
SMD_GPM DECIMAL(5,2)
INSERT INTO SMEMODETAIL(SMD_PRICE,SMD_COST) SELECT 1.8500,1.62
UPDATE SMEMODETAIL SET SMD_GPM = (SMD_PRICE-SMD_COST) / SMD_PRICE * 100
FROM SMEMODETAIL WHERE SMD_PRICE<>0-- AND SMD_QUANTITY<>0
SELECT * FROM SMEMODETAIL
DROP TABLE SMEMODETAIL
The solution of your case can be either scale the DECIMAL(5,2) or follow the suggestion in Scott_morris-ga's to check and fix your data.
If you have any question, feel free to let me know.
Eric Zhang
TechNet Community Support

Can u tell me how to convert int value in to string

hi to all, can u tell me how to convert int value in to string.

hi to all, can u tell me how to convert int value in
to string.Even this way:
int number = 155;
String mystring = ""+155;
[\code]

Convert hexa to integer

Hello,
I have a flat file in which I get a value in hexadecimal format.
Can we convert it in integer format in ODI ? I did'nt find anything about that.
Thanks in advance
Marie

What is your target technology ?
There are ways to do it. One of the way is to create function
You can create ODI function to convert Hexadecimal to Integer.
For example if you are using Oracle as your staging or target technology .. you can use
Oracle you can use
SYS_OP_RAWTONUM('AA') or to_number('AA', 'xx').
Other can be directly using features of target or staging technologies to get the desired output.

Converting int[] to Integer[]

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