Converting single column content into rows

Hi All,
I have a table containing data in the following format
SNO Content
1 a,ab,aab,b,c
2 a,aac,aab,c,ccb,ee
3 bb,b,c
I have a requirement to convert this into following format
SNO Content
1 a
1 ab
1 aab
1 b
1 c
2 a
3 bb
3 b
3 c
How to acheive this in 10g? Is it possible in 9i?
Please share your thoughts.
Thanks in advance
Regards,
Subbu S

test@ORA92>
test@ORA92> @ver
BANNER
Oracle9i Enterprise Edition Release 9.2.0.1.0 - Production
PL/SQL Release 9.2.0.1.0 - Production
CORE    9.2.0.1.0       Production
TNS for 32-bit Windows: Version 9.2.0.1.0 - Production
NLSRTL Version 9.2.0.1.0 - Production
5 rows selected.
test@ORA92>
test@ORA92> select * from t;
       SNO CONTENT
         1 a,ab,aab,b,c
         2 a,aac,aab,c,ccb,ee
         3 bb,b,c
3 rows selected.
test@ORA92>
test@ORA92> select sno,
2         rtrim(substr(lst,
3                      instr(lst, ',', 1, iter.pos) + 1,
4                      instr(lst, ',', 1, iter.pos + 1) - instr(lst, ',', 1, iter.pos)),
5               ',') content
6    from (select sno, ',' || content || ',' lst from t) csv,
7         (select rownum pos from all_objects) iter
8   where iter.pos <= ((length(csv.lst) - length(replace(csv.lst, ','))) / length(',')) - 1
9   order by sno;
       SNO CONTENT
         1 a
         1 ab
         1 aab
         1 c
         1 b
         2 a
         2 aab
         2 ee
         2 ccb
         2 c
         2 aac
         3 bb
         3 c
         3 b
14 rows selected.
test@ORA92>
test@ORA92>Haven't tried this with a large number of rows, but I suspect it would be slow in that case. Regular expressions should make this simpler and more efficient in 10g.
Cheers,
pratz

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Edited by: Ashu_Neo on Dec 1, 2012 9:43 PM
-- Added comment

Converting single column content into rows

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