Converting to decimal number

Hi to all,
I am diplaying data from the DataControl on a page, these data is numbers and are shown as:
number1: 12.154
number2: 125.25
number3: 1.254
as seen with a decimal point, are not aligned and with more than two decimal numbers.
How can I make show like this?
number1: 12,15
number2: 125,25
number3: 1,25
numbers with decimal comma, aligned and only two decimal numbers. I saw that this is possible using UI Hints,but I can not get it, someone can help me?

krd12 wrote:
I am trying to convert a string with a lot of digits (ex 324.41897635) into a number and want to get back the same precision in the number as in the string. I tried the "Decimal String to Number" (get back no digits after decimal point ex 324) and "Frac/Exp String to Number" (get back three decimal places rounded ex 324.419)
Not a trivial exercise!
Here is 1 possible solution I've limited it to non-trivial digits (ext floats are only 15 digits precise on some OS's.) But you can see the steps necessary. I assume the radix symbol is "." but the vi could be modified to use"System Decimal Seperator"
Jeff
Attachments:
Max Str-Ext.vi ‏11 KB

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Hi,
Can any one help me to convert the fractional decimal number to its equivalent hex number and vice versa ?
if u have any code please share.
thanks
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neethukk wrote:
Can any one help me to convert the fractional decimal number to its equivalent hex number and vice versa ?
if u have any code please share.
This question is not clear at all.
"Fractional decimal" is not a data type, but a way of formatting in readable form using numeric characters and a decimal separator.
Same to "hex number", but only for integers.
What do you mean by "convert"? Do you want to keep the value the same or retain the bit pattern of the numeric data type?
Hexadecimal is for integers. Are you talking about fixed point?
We clearly need significantly more information. What are the input and output data types? What are you actually trying to do?
Do you have an example input and corresponding output?
LabVIEW Champion . Do more with less code and in less time .

Regarding Converting the Decimal number into rounded value...

Hi,
i have a decimal number as " 58240990.00 " , i wanted this to rounded value .
for example I am expecting to see 58241 for the above number.
shell we can do in any way.. if so please let me knw fast.. it is urgent..
thanks in advance.
thanks,
Suresh..

Dear Suresh,
Go through the following code chunk:
DATA : p TYPE p DECIMALS 2 VALUE '2.49'.
DATA i TYPE i.
i = CEIL( p ).
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About binary number and decimal number?

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You've already asked the same kind of thing before (http://forum.java.sun.com/thread.jsp?forum=31&thread=325249), and fsato4 answered. Here is the same thing, but decimal to binary.
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hi,
how to convert a decimal number
suppose i want to convert 500.00- to 500.
plz help me in resolving this.

Hi Ramya,
You can use Field symbol with CASTING operator to convert decimal to Numeric Type (Intergers). You can try with other Numeric type also.
data:wf_int type i,
wf_dec(10) type x.
field-symbols: <fs> type any.
wf_dec = '28'.
assign wf_dec to <fs> casting type i.
wf_int = <fs>.
write wf_int.
kindly reward if helpful.
cheers,
Hema.

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import java.io.*;
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catch(IOException e)     {}
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catch(Exception e)     {}
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     public void run()
          try     {
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               case SerialPortEvent.FE:
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Is it a float or a double?
For a float, the decimal should be 4 bytes (small numbers like 1.1 start with the byte 0x40). Convert these 4 bytes to an int, using byte-shifting would probably be easiest.
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Program to convert binary to decimal number?

I only know how to do a program that converts only 4 numbers, but it to convert any amount of digits the number enters, I think you need to use a loop or something, but I'm not sure how. Could someone please help me? This is my code so far:
import javax.swing.JOptionPane;
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I am not sure if this will help you. Check it out, run it and let me know if it helped.
import java.util.*;
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Use the rating system, otherwise its useless; and please don't forget to tip your waiters!
using LV 2010 SP 1, Windows 7
Attachments:
Convert Bit Array to Int.vi ‏8 KB

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thank you.

Hi
Try this function module:
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Round decimal number to two places

trying to round a decimal number to two places i.e. 1.98999 should round to 1.99.
-tried using math.round but it only rounds to nearest integer
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any advice is appreciated:)

coynerm wrote:
trying to round a decimal number to two places i.e. 1.98999 should round to 1.99.Agree.
-tried using math.round but it only rounds to nearest integerI advise against rounding in most newbie situations. Usually it's the display of the variable you want to change.
-tried using decimalformat class but that converts to string, and cast wont allow me to convert from string back to doubleOf course cast won't allow you to convert back. If you wanted to do that you'd use Double.parseDouble(stringVar); But we don't know why you are doing all this converting in the first place.
*is there a round method that allows you to specify decimal places?
*or is there an easy method to cast a string back to a double?Advice: Forgetting all this fooha with rounding, what in essence are you trying to achieve? Why all of this number manipulation in the first place? It will affect what should be the best answer.

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Hi all,
I am working on a C++ program that converts a decimal to a fraction, finds the lowest common multiple, multiplies the numerator by the denominator, then reduces the fraction again so the fraction will be 'numerator/1'.
I am using this code in a larger program to change a floating point slope value to a whole value for slope-intercept equations and standard form equations.
The program will run but I tested almost 500 numbers and 20 numbers made the program crash (it stalled and did not finish the equation, I had to close the terminal and open it up again... )
These 20 numbers I had problems with:
2.36, 7.36, 1.11, 1.001, 1.66, 1.88, 2.22, 2.13, 3.24, 3,26, 3.32, 3.43, 3.49, 3.51, 3.57, 3.68, 3.74, 3.76, 3.82
(I am sure there are more...)
I have tried c-style casting and dynamic and static casting to try to resolve this issue. Can someone help me out and point out why these certain numbers make the program crash and offer a possible sloution?
I tried debugging this program on gdb and keep on getting this frustrating message..
(gdb) break 16
No line 16 in file "init.c".
(gdb)
Here is the program's code:
//example.cc
#include <iostream>
#include "reduce.h"
#include "decimal-to-fraction.h"
using namespace std;
int main()
double deci;
double n, d;
while(1) {
cout << "Enter a decimal to convert to a fraction ('0' to quit): ";
cin >> deci;
cin.ignore(INT_MAX, '\n');
if(!deci) exit(0);
dec_to_frac(deci, n, d);
if (n * d != n){
cout << '\n' << deci << " = " << n << '/' << d << "\n\n";
cout<<'\n' << d << " x " << n;
n = d * n;
cout<< " = " << n << "\n\n";
cout<<'\n' << n << '/' << d;
reduce(n, d);
cout << " = " << n << '/' << d << "\n\n";
cout<<'\n' << n << "\n\n";
else
cout<<'\n' << deci<< "\n\n";
return 0;
#ifndef _REDUCE_H_
#error You must include "reduce.h" before this file
#endif /* def _REDUCE_H_ */
#ifndef _DECIMAL_TO_FRACTION_H_
#define _DECIMAL_TO_FRACTION_H_
void dec_to_frac(double decimal, double &numerator, double &denominator)
//numerator = static_cast<int >(decimal);
//numerator = (int )decimal;
numerator = decimal;
denominator = 1;
while(numerator != (int)numerator) {
numerator *= 10;
denominator *= 10;
reduce(numerator, denominator);
#endif /* def _DECIMAL_TO_FRACTION_H_ */
#ifndef _REDUCE_H_
#define _REDUCE_H_
void reduce(double &numer, double &denom)
int i;
for(i=2; i<=numer; ++i) {
if( ((numer/i) == ((int )(numer/i))) && ((denom/i) == ((int)(denom/i))) ) {
numer /= i;
denom /= i;
--i;
#endif /* def _REDUCE_H_ */

Okay, a few things ('cause I'm picky too): LCM == "least common multiple" or "lowest common multiple", it's really interchangable. LCD == lowest common denominator, which is when you're adding two fractions and want to find the lowest denom. Now that we have that out of the way...
Using ++i or i++ as the third expression in your for loop will make zero difference.
for (int i=2; i<=numer; ++i)
will have exactly the same effect as
for (int i=2; i<=numer; i++)
, though they may have slightly different performances. The reason for this is that the third expression (i++ or ++i) is evaluated after every iteration of the loop, meaning it doesn't happen until the end of the loop body is reached, and then it's evaluated independently, meaning all you end up with is 'i' incrementing.
As for this:
if( ((numer/i) == ((int )(numer/i))) && ((denom/i) == ((int)(denom/i))) ) {
becomes
if (numer % i == denom % i == 0) {
That's about right, it would look more like
if (numer %i == 0 && denom % i == 0)
- the other way would probably not behave the way you expect.
Some other tips:
numer and denom should be 'int' or 'long' - not double. You don't expect your numerator and denominator to have decimal points, so use integral types - using floating point 'double's is likely what's getting you into this trouble -- floating point arithmetic is inherently imprecise. You might have better luck parsing the input yourself and constructing the numerator from that instead of reading directly into a floating-point number.
I'm hacking around with your code right now for fun; I'll let you know if I find anything.
==edit==
Oh, something else I wanted to mention; to break on a line in gdb you type:
break filename:linenumber
ie.
break example.cc:16
Last edited by Cerebral (2007-06-03 02:43:42)

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Dear All;
I just want to get a decimal number (i.e. 2.5), i tried the
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Is there another function which returns decimals.?
Thank you;

DEar Ned;
I am getting the pixels of a scale then converting them into
a pH range (0-14). so, i want the pH reading upto one decimal as
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var ySlider:Number = this._y - 1 * 550;
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mcSlider.onRelease=onReleaseOutside= function():Void {
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